summaryrefslogtreecommitdiff
path: root/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-pointsSpc.tex
diff options
context:
space:
mode:
Diffstat (limited to 'macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-pointsSpc.tex')
-rw-r--r--macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-pointsSpc.tex13
1 files changed, 4 insertions, 9 deletions
diff --git a/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-pointsSpc.tex b/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-pointsSpc.tex
index fa18a677b6..15529b33eb 100644
--- a/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-pointsSpc.tex
+++ b/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-pointsSpc.tex
@@ -138,7 +138,7 @@ arguments & default & example \\
\end{tabular}
\medskip
-$AB=a$, $BC=b$ and $\frac{AC}{AB} = \frac{AB}{BC} =\phi$
+$AB=a$, $BC=b$ and $\dfrac{AC}{AB} = \dfrac{AB}{BC} =\phi$
\end{NewMacroBox}
\subsubsection{Use the golden ratio to divide a line segment}
@@ -236,14 +236,12 @@ This time $M$ is simply the center of gravity of the triangle.
\subsection{\tkzname{Internal and external Similitude Center}}
The centers of the two homotheties in which two circles correspond are called external and internal centers of similitude. You can use \tkzcname{tkzDefIntSimilitudeCenter} and \tkzcname{tkzDefExtSimilitudeCenter} but the next macro is better.
-\begin{NewMacroBox}{tkzDefSimilitudeCenter}{\oarg{options}\parg{O,A}\parg{O',B} or \parg{O,r}\parg{O',r'}}%
+\begin{NewMacroBox}{tkzDefSimilitudeCenter}{\oarg{options}\parg{O,A}\parg{O',B}}%
\begin{tabular}{lll}%
arguments & example & explanation \\
\midrule
\TAline{\parg{pt1,pt2}\parg{pt3,pt4}}{$(O,A)(O',B)$} {$r=OA,r'=O'B$}
-\TAline{\parg{pt1,r1}\parg{pt2,r2}}{$(A,1)(B,2)$} {}
-
\end{tabular}
\medskip
@@ -253,9 +251,6 @@ options & default & definition \\
\midrule
\TOline{ext}{ext}{external center}
\TOline{int}{ext}{internal center}
-
-\TOline{node}{node}{Circles are defined by two points: center and point on the circle}
-\TOline{R}{node}{Circles are defined by the center and the radius}
\end{tabular}
\end{NewMacroBox}
@@ -322,12 +317,12 @@ You can use \tkzcname{tkzDefBarycentricPoint} to find a homothetic center
\subsection{ \tkzname{Harmonic division} with \tkzcname{tkzDefHarmonic}}
%<---------------------------------------------------------------------->
-\begin{NewMacroBox}{tkzDefHarmonic}{\oarg{options}\parg{pt1,pt2,pt3} or \parg{pt1,pt2}}%
+\begin{NewMacroBox}{tkzDefHarmonic}{\oarg{options}\parg{pt1,pt2,pt3} or \parg{pt1,pt2,k}}%
\begin{tabular}{lll}%
options & default & definition \\
\midrule
-\TOline{both}{both}{\parg{A,B} we look for C and D such that $(A,B;C,D) = -1$ }
+\TOline{both}{both}{\parg{A,B,2} we look for C and D such that $(A,B;C,D) = -1$ and CA=2CB }
\TOline{ext}{both}{\parg{A,B,C} we look for D such that $(A,B;C,D) = -1$}
\TOline{int}{both}{\parg{A,B,D} we look for C such that $(A,B;C,D) = -1$}
\end{tabular}