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+\documentclass[pdf,rico,slideColor,colorBG]{prosper}
+
+\usepackage{amsmath}
+\begin{document}
+\begin{slide}{The quest for $\pi$}
+\begin{itemize}
+\item The following formula computes $8$ correct digits per iteration
+ (Ramanujan):
+\end{itemize}
+ \begin{small}
+ \begin{equation*}
+ \frac{1}{\pi}=\sum_{n=0}^\infty \frac{(\frac{1}{4})_n(\frac{2}{4})_n(\frac{3}{4})_n}{n!^3}\bigl(2\sqrt{2}(1103+26390n)\bigr)\frac{1}{(99^2)^{2n+1}}
+ \end{equation*}
+ \end{small}
+\end{slide}
+
+\end{document}
+
+%%% Local Variables:
+%%% mode: latex
+%%% TeX-master: t
+%%% End: