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author | Norbert Preining <norbert@preining.info> | 2019-09-02 13:46:59 +0900 |
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committer | Norbert Preining <norbert@preining.info> | 2019-09-02 13:46:59 +0900 |
commit | e0c6872cf40896c7be36b11dcc744620f10adf1d (patch) | |
tree | 60335e10d2f4354b0674ec22d7b53f0f8abee672 /macros/latex/contrib/prosper/contrib/rico.tex |
Initial commit
Diffstat (limited to 'macros/latex/contrib/prosper/contrib/rico.tex')
-rw-r--r-- | macros/latex/contrib/prosper/contrib/rico.tex | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/macros/latex/contrib/prosper/contrib/rico.tex b/macros/latex/contrib/prosper/contrib/rico.tex new file mode 100644 index 0000000000..6b712f675c --- /dev/null +++ b/macros/latex/contrib/prosper/contrib/rico.tex @@ -0,0 +1,22 @@ +\documentclass[pdf,rico,slideColor,colorBG]{prosper} + +\usepackage{amsmath} +\begin{document} +\begin{slide}{The quest for $\pi$} +\begin{itemize} +\item The following formula computes $8$ correct digits per iteration + (Ramanujan): +\end{itemize} + \begin{small} + \begin{equation*} + \frac{1}{\pi}=\sum_{n=0}^\infty \frac{(\frac{1}{4})_n(\frac{2}{4})_n(\frac{3}{4})_n}{n!^3}\bigl(2\sqrt{2}(1103+26390n)\bigr)\frac{1}{(99^2)^{2n+1}} + \end{equation*} + \end{small} +\end{slide} + +\end{document} + +%%% Local Variables: +%%% mode: latex +%%% TeX-master: t +%%% End: |