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--
-- luatexja/compat.lua
--
luatexbase.provides_module({
name = 'luatexja.compat',
date = '2011/06/03',
version = '0.1',
description = 'Partial implementation of primitives of pTeX',
})
module('luatexja.compat', package.seeall)
local err, warn, info, log = luatexbase.errwarinf(_NAME)
luatexja.load_module('base'); local ltjb = luatexja.base
luatexja.load_module('stack'); local ltjs = luatexja.stack
-- \kuten, \jis, \euc, \sjis, \ucs, \kansuji
function to_kansuji(num)
if not num then num=0; return
elseif num<0 then
num = -num; tex.write('-')
end
local s = ""
while num~=0 do
s = utf.char(
ltjs.get_penalty_table(luatexja.stack_table_index.KSJ + num%10,
'', tex.getcount('ltj@@stack'))) .. s
num=math.floor(num/10)
end
tex.write(s)
end
-- \ucs: 単なる identity
function from_ucs(i)
if type(i)~='number' then
ltjb.package_error('luatexja',
"invalid character code (".. tostring(i) .. ")",
"I'm going to use 0 instead of that illegal character code.")
i=0
end
tex.write(i)
end
-- \kuten: 面区点 (それぞれで16進2桁を使用)=> Unicharacter code 符号位置
function from_kuten(i)
if type(i)~='number' then
ltjb.package_error('luatexja',
"invalid character code (".. tostring(i) .. ")",
"I'm going to use 0 instead of that illegal character code.")
i=0
end
tex.write(tostring(luatexja.jisx0208.table_jisx0208_uptex[i] or 0))
end
-- \euc: EUC-JP による符号位置 => Unicharacter code 符号位置
function from_euc(i)
if type(i)~='number' then
ltjb.package_error('luatexja',
"invalid character code (".. tostring(i) .. ")",
"I'm going to use 0 instead of that illegal character code.")
i=0
elseif i>=0x10000 or i<0xa0a0 then
i=0
end
from_kuten(i-0xa0a0)
end
-- \jis: ISO-2022-JP による符号位置 => Unicharacter code 符号位置
function from_jis(i)
if (type(i)~='number') or i>=0x10000 or i<0 then
ltjb.package_error('luatexja',
"invalid character code (".. tostring(i) .. ")",
"I'm going to use 0 instead of that illegal character code.")
i=0
end
from_kuten(i-0x2020)
end
-- \sjis: Shift_JIS による符号位置 => Unicharacter code 符号位置
function from_sjis(i)
if (type(i)~='number') or i>=0x10000 or i<0 then
ltjb.package_error('luatexja',
"invalid character code (".. tostring(i) .. ")",
"I'm going to use 0 instead of that illegal character code.")
tex.write('0'); return
end
local c2 = math.floor(i/256)
local c1 = i%256
local shift_jisx0213_s1a3_table = {
{ [false]= 1, [true]= 8},
{ [false]= 3, [true]= 4},
{ [false]= 5, [true]=12},
{ [false]=13, [true]=14},
{ [false]=15 } }
if c2 >= 0x81 then
if c2 >= 0xF0 then -- this if block won't be true
if (c2 <= 0xF3 or (c2 == 0xF4 and c1 < 0x9F)) then
c2 = 0x100 + shift_jisx0213_s1a3_table[c2 - 0xF0 + 1][(0x9E < c1)];
else -- 78<=k<=94
c2 = c2 * 2 - 413 + 0x100; if 0x9E < c1 then c2=c2+1 end
end
else
if c2<=0x9f then i=0x101 else i=0x181 end
c2 = c2 + c2 - i; if 0x9E < c1 then c2=c2+1 end
end
if c1 < 0x9F then
if c1>0x7f then i=0x40 else i=0x3f end
c1 = c1 - i
else
c1 = c1 - 0x7e
end
from_kuten(c2*256+c1)
end
end
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