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|
%
% Copyright (c) 2022 Zeping Lee
% Released under the LaTeX Project Public License v1.3c License.
% Repository: https://gitee.com/zepinglee/exam-zh
%
\NeedsTeXFormat{LaTeX2e}
\RequirePackage{expl3}
\RequirePackage{xparse}
\ProvidesExplPackage {exam-zh-question} {2022-08-09} {v0.1.15}
{exam-zh question module}
\RequirePackage { amsthm }
\@ifpackageloaded { tcolorbox }
{ \tcbuselibrary { breakable } }
{ \RequirePackage [ most ] { tcolorbox } }
% \RequirePackage { zref-savepos }
\RequirePackage { xeCJKfntef }
% https://github.com/CTeX-org/forum/issues/264#issuecomment-1200087776
\disable@package@load { etex }
{
\cs_set_eq:NN \globcount \newcount
\cs_set_eq:NN \globdimen \newdimen
}
\RequirePackage { linegoal }
\ExplSyntaxOff
\usetikzlibrary{shapes.misc}
\ExplSyntaxOn
\NewDocumentCommand \questionsetup { m }
{ \keys_set:nn { exam-zh / question } { #1 } }
\NewDocumentCommand \fillinsetup { m }
{ \keys_set:nn { exam-zh / fillin } { #1 } }
% ulem 宏包重定义了 \emph,使用 \normalem 恢复
\normalem
% question 环境相关变量
% 计数器
\int_new:N \g__examzh_question_index_int
% 答案颜色
\tl_new:N \l__examzh_question_answer_color_tl
% 题目分数
\int_new:N \l__examzh_question_points_int
% 是否显示题目分数
\bool_new:N \l__examzh_question_show_points_bool
\bool_new:N \l__examzh_question_show_points_auto_bool
% 题目分数是否单独成段,解答题需要单独成段
\bool_new:N \l__examzh_question_points_separate_par_bool
% 是否显示括号
\bool_new:N \l__examzh_question_show_paren_bool
% 是否显示答案
\bool_new:N \l__examzh_question_show_answer_bool
\bool_new:N \l__examzh_question_show_fillin_answer_bool
\bool_new:N \l__examzh_question_show_paren_answer_bool
% 上下的间距
\skip_new:N \l__examzh_question_top_sep_skip
\skip_new:N \l__examzh_question_bottom_sep_skip
% label 的对齐
\tl_new:N \l__examzh_question_label_align_tl
\keys_define:nn { exam-zh }
{ question .meta:nn = { exam-zh / question } {#1} }
\keys_define:nn { exam-zh / question }
{
% 手动调整 question 环境的计数器
index .int_gset:N = \g__examzh_question_index_int ,
% 分数
points .int_set:N = \l__examzh_question_points_int ,
% 分数显示控制
show-points .choice: ,
show-points / auto .code:n =
{ \bool_set_true:N \l__examzh_question_show_points_auto_bool } ,
show-points / true .code:n =
{
\bool_set_true:N \l__examzh_question_show_points_bool
\bool_set_false:N \l__examzh_question_show_points_auto_bool
} ,
show-points / false .code:n =
{
\bool_set_false:N \l__examzh_question_show_points_bool
\bool_set_false:N \l__examzh_question_show_points_auto_bool
} ,
% 分数是否单独成段
points-separate-par .bool_set:N = \l__examzh_question_points_separate_par_bool ,
% 是否显示答案
% show-answer .bool_set:N = \l__examzh_question_show_answer_bool ,
show-answer .choice: ,
show-answer / true .code:n =
{
\bool_set_true:N \l__examzh_question_show_fillin_answer_bool
\bool_set_true:N \l__examzh_question_show_paren_answer_bool
},
show-answer / false .code:n =
{
\bool_set_false:N \l__examzh_question_show_fillin_answer_bool
\bool_set_false:N \l__examzh_question_show_paren_answer_bool
},
% 上方间距
top-sep .skip_set:N = \l__examzh_question_top_sep_skip ,
% 下方间距
bottom-sep .skip_set:N = \l__examzh_question_bottom_sep_skip ,
label .tl_set:N = \l__examzh_question_label_tl,
combine-fillin .bool_set:N = \l__examzh_question_combine_fillin_bool,
combine-fillin-args .tl_set:N = \l__examzh_question_combine_fillin_args_tl,
label-align .choices:nn =
{ left, center, right }
{ \tl_set_eq:NN \l__examzh_question_label_align_tl \l_keys_choice_tl }
}
\keys_set:nn { exam-zh / question }
{
index = 1,
points = 0 ,
show-points = auto ,
points-separate-par = false ,
show-answer = false ,
top-sep = .25em plus .25em minus .1em ,
bottom-sep = .25em plus .25em minus .1em ,
label = \arabic*.,
combine-fillin = false,
label-align = right
}
% 是否按照解答题的格式排版
\bool_new:N \l__examzh_question_problem_style_bool
% 选择题和填空题的题干
\NewDocumentEnvironment { question } { O { } +b }
{
\bool_set_false:N \l__examzh_question_problem_style_bool
\__examzh_question_begin:nn {#1}{#2}
}
{ \__examzh_question_end:nn {#1}{#2} }
% 解答题
\NewDocumentEnvironment { problem } { O { } +b }
{
\bool_set_true:N \l__examzh_question_problem_style_bool
\__examzh_question_begin:nn {#1}{#2}
}
{ \__examzh_question_end:nn {#1}{#2} }
\prg_generate_conditional_variant:Nnn \int_compare:nNn { xNn } { T }
\cs_new:Npn \__examzh_question_begin:nn #1#2
{
\par
% 根据是否按解答题方式排版来设置是否分数要分段
\bool_if:NTF \l__examzh_question_problem_style_bool
{ \keys_set:nn { exam-zh / question } { points-separate-par = true } }
{ \keys_set:nn { exam-zh / question } { points-separate-par = false } }
% \bool_if:NTF \l__examzh_question_combine_fillin_bool
% { \keys_set:nn { exam-zh / question } { label-align = left } }
% { \keys_set:nn { exam-zh / question } { label-align = right } }
% 设置键值
\keys_set:nn { exam-zh / question } { #1 }
% 题干计数器的值加一
\int_gincr:N \g__examzh_question_index_int
% 设置上方间距
% \addvspace { \l__examzh_question_top_sep_skip }
\vspace { \l__examzh_question_top_sep_skip }
% 严格禁止孤行和寡行
\int_set:Nn \clubpenalty { 10000 }
\int_set:Nn \widowpenalty { 10000 }
% 尽量避免在题目中间换行
\int_set:Nn \interlinepenalty { 301 }
% 这部分是仿照 source2e 中 enumerate 的定义写的
% \@enumdepth 主要控制 enumerate 不同层级的编号
% 这样设置后,在 question 中使用 enumerate 会调用 level 2 的编号
% 也就是 question 中的 enumerate 环境直接从第二层开始
\int_incr:N \@enumdepth
% 如果 show-points = auto 那么解答题显示分数,选择题和填空题不显示分数
% 这样设置考虑到选择题和填空题都是每道题一样的分数,在最开始的地方说明即可
% 而解答题不太一样
\bool_if:NT \l__examzh_question_show_points_auto_bool
{
\bool_if:NTF \l__examzh_question_problem_style_bool
{ \bool_set_true:N \l__examzh_question_show_points_bool }
{ \bool_set_false:N \l__examzh_question_show_points_bool }
}
% 使用列表环境输出
\list
{
% \int_use:N \g__examzh_question_index_int .
\__examzh_question_make_label:n
{
\bool_if:NT \l__examzh_question_combine_fillin_bool
{
\tl_if_blank:VTF \l__examzh_question_combine_fillin_args_tl
{ \fillin }
{
\use:x
{
\exp_not:N \fillin \l__examzh_question_combine_fillin_args_tl
}
}
}
\int_compare:xNnT { \g__examzh_question_index_int } < { 11 }
{ \phantom {1} }
\__examzh_question_the_label:
}
}
{
% 用 group 是为了防止 combine-fillin 的 type 影响了环境里面的 fillin 的type
\group_begin:
\dim_gset:Nn \topsep { 0pt }
\dim_gset:Nn \partopsep { 0pt }
\dim_gset:Nn \itemsep { 0pt }
\dim_gset:Nn \parsep { 0pt }
% \group_begin:
% 上面 \fillin 里面的设置是局部的,这样的问题是 question 的可选参数改 type 的时候不会影响 \l__examzh_fillin_type_str 的值
% 所以要把 \l__examzh_question_combine_fillin_args_tl 里关于 type 的选取出来
\__examzh_question_begin_fillin_type_set:
\__examzh_question_begin_labelsep_labelwidth_set:
% \group_end:
\bool_if:NTF \l__examzh_question_problem_style_bool
{
% 解答题是正文 + 缩进 2em 的效果
\bool_if:NTF \l__examzh_question_combine_fillin_bool
{
% 如果 combine 的话就和 question 一样的缩进
\dim_gset:Nn \leftmargin { 6em }
\dim_gset:Nn \itemindent { 0pt }
}
{
\dim_gset:Nn \leftmargin { 0pt }
\dim_gset:Nn \itemindent { 2em }
}
}
{
% 选择和填空题是悬挂效果
\bool_if:NTF \l__examzh_question_combine_fillin_bool
% {
% \str_case:VnF \l__examzh_question_label_align_tl
% {
% { left } { \dim_set:Nn \leftmargin { 8em } }
% }
{ \dim_gset:Nn \leftmargin { 6em } }
% }
{ \dim_gset:Nn \leftmargin { 2em } }
\dim_set:Nn \itemindent { 0pt }
}
\dim_gset_eq:NN \listparindent \itemindent
\group_end:
}
\item \relax
% 输出题目分数
\bool_if:NT \l__examzh_question_show_points_bool
{
% 如果设置了分数且 show-points 的 bool 是 true 的话就显示
\int_compare:nNnT { \l__examzh_question_points_int } > { 0 }
{ ( \int_use:N \l__examzh_question_points_int ~ 分 ) }
% 是否分段(解答题需要分段)
\bool_if:NT \l__examzh_question_points_separate_par_bool
% \par 分段之后使用 \nopagebreak 避免分页导致序号和分数出现在页面最后一行
{ \par \nopagebreak }
}
}
\int_new:N \l__examzh_question_begin_fillin_args_bracket_num_int
\cs_generate_variant:Nn \regex_count:nnN { nVN }
\prg_generate_conditional_variant:Nnn \regex_extract_once:nnN { nxN } { F }
\cs_new:Npn \__examzh_question_begin_fillin_type_set:
{
\regex_count:nVN { \[ } % \]
\l__examzh_question_combine_fillin_args_tl
\l__examzh_question_begin_fillin_args_bracket_num_int
\use_none:n { \] } % 消去 \[ 的高亮影响
% \int_use:N \l__examzh_question_begin_fillin_args_bracket_num_int
\int_compare:nNnT { \l__examzh_question_begin_fillin_args_bracket_num_int } = {2}
{
\regex_extract_once:nxNF { \[ (.*?) \] } { \l__examzh_question_combine_fillin_args_tl } \l_tmpa_seq { \fail }
\seq_pop_left:NN \l_tmpa_seq \l_tmpa_tl
% \seq_use:Nn \l_tmpa_seq {,}
\keys_set:nx { exam-zh / fillin } { \seq_use:Nn \l_tmpa_seq {,} }
}
}
\cs_new:Npn \__examzh_question_begin_labelsep_labelwidth_set:
{
\bool_if:NTF \l__examzh_question_combine_fillin_bool
{
\str_case:Vn \l__examzh_question_label_align_tl
{
{ left }
{
\str_case:VnF \l__examzh_fillin_type_str
{
{ paren }
{
% combin-left-paren
\dim_gset:Nn \labelsep { 2.8em }
\dim_gset:Nn \labelwidth { 4.2em }
}
{ line }
{
% combin-left-line
\dim_gset:Nn \labelsep { 2.4em }
\dim_gset:Nn \labelwidth { 3.8em }
}
}
{
% combin-left-paren/line 外的
\dim_gset:Nn \labelsep { 2.8em }
\dim_gset:Nn \labelwidth { 1.3em }
}
}
{ center }
{
\str_case:VnF \l__examzh_fillin_type_str
{
{ paren }
{
% combin-center-paren
\dim_gset:Nn \labelsep { 2em }
\dim_gset:Nn \labelwidth { 5em }
}
{ line }
{
% combin-center-line
\dim_gset:Nn \labelsep { 2.8em }
\dim_gset:Nn \labelwidth { 4em }
}
}
{
% combin-center-paren/line 外的
\dim_gset:Nn \labelsep { 2em }
\dim_gset:Nn \labelwidth { 1.3em }
}
}
{ right }
{
\dim_gset:Nn \labelsep { .7em }
\dim_gset:Nn \labelwidth { 1.3em }
}
}
}
{
\str_case:Vn \l__examzh_question_label_align_tl
{
{ left }
{
\dim_gset:Nn \labelsep { .7em }
\dim_gset:Nn \labelwidth { 1.8em }
}
{ center }
{
\dim_gset:Nn \labelsep { .7em }
\dim_gset:Nn \labelwidth { 1.3em }
}
{ right }
{
\dim_gset:Nn \labelsep { .7em }
\dim_gset:Nn \labelwidth { 1.3em }
}
}
}
}
\cs_new:Npn \__examzh_question_end:nn #1#2
{
#2
% 结束列表环境
\endlist
% 增加下方间距
% \addvspace { \l__examzh_question_bottom_sep_skip }
\vspace { \l__examzh_question_bottom_sep_skip }
}
% 处理 question / problem 的 label
\tl_new:N \l__examzh_question_counters_commands_set_tl
\cs_new:Npn \__examzh_question_the_label:
{
\group_begin:
% 定义计数器相关的命令函数
\l__examzh_question_counters_commands_set_tl
% 输出处理后的 label
\l__examzh_question_label_tl
\group_end:
}
\cs_new:Npn \__examzh_question_make_label:n #1
{
\str_case:Vn \l__examzh_question_label_align_tl
{
{ left } { \rlap { #1 } \hss }
{ center } { \hss \clap { #1 } \hss }
{ right } { \hss \llap { #1 } }
}
}
\NewDocumentCommand \AddQuestionCounter { m m }
{
% 生成用户层命令
\tl_put_right:Nn \l__examzh_question_counters_commands_set_tl
{ \__examzh_process_counter:NNn #1 #2 { question } }
% 把核心函数存起来
\cs_set_eq:cN { __examzh_question_save_ \cs_to_str:N #1 : } #2
\cs_set_eq:cN { __examzh_question_save_ \cs_to_str:N #2 : } #2
}
\AddQuestionCounter \arabic \@arabic
\AddQuestionCounter \alph \@alph
\AddQuestionCounter \Alph \@Alph
\AddQuestionCounter \roman \@roman
\AddQuestionCounter \Roman \@Roman
\cs_new:Npn \__examzh_process_counter:NNn #1#2#3
% #1: \Alph
% #2: \@Alph
% #3: question / fillin
{
\cs_set:Npn #1 { \use:c { __examzh_ #3 _process_counter_aux:Nn } #2 }
\cs_set:Npn #2 { \use:c { __examzh_ #3 _process_counter_aux:Nn } #2 }
}
\cs_new:Npn \__examzh_question_process_counter_aux:Nn #1#2
{
\tl_if_eq:nnTF {#2} { * }
{
% \Alph*
\use:c { __examzh_question_save_ \cs_to_str:N #1 : }
{ \int_eval:n { \g__examzh_question_index_int - 1 } }
}
{
% \Alph{...}
\use:c { __examzh_question_save_ \cs_to_str:N #1 : }
{#2}
}
}
% 处理 fillin/no-answer-type = counter 的 label
\tl_new:N \l__examzh_fillin_counters_commands_set_tl
\cs_new:Npn \__examzh_fillin_the_label:
{
\group_begin:
% 定义计数器相关的命令函数
\l__examzh_fillin_counters_commands_set_tl
% 输出处理后的 label
\l__examzh_fillin_label_tl
\group_end:
}
\NewDocumentCommand \AddFillinCounter { m m }
{
% 生成用户层命令
\tl_put_right:Nn \l__examzh_fillin_counters_commands_set_tl
{ \__examzh_process_counter:NNn #1 #2 { fillin } }
% 把核心函数存起来
\cs_set_eq:cN { __examzh_fillin_save_ \cs_to_str:N #1 : } #2
\cs_set_eq:cN { __examzh_fillin_save_ \cs_to_str:N #2 : } #2
}
\AddFillinCounter \arabic \@arabic
\AddFillinCounter \alph \@alph
\AddFillinCounter \Alph \@Alph
\AddFillinCounter \roman \@roman
\AddFillinCounter \Roman \@Roman
\cs_new:Npn \__examzh_fillin_process_counter_aux:Nn #1#2
{
\tl_if_eq:nnTF {#2} { * }
{
% \Alph*
\use:c { __examzh_fillin_save_ \cs_to_str:N #1 : }
{ \int_eval:n { \g__examzh_fillin_no_answer_counter_int - 1 } }
}
{
% \Alph{...}
\use:c { __examzh_fillin_save_ \cs_to_str:N #1 : }
{#2}
}
}
% 使用中文字体直接输出 unicode 带圈数字
% \circlednumber 的参数既可以接受 LaTeX2e 的 <counter>,也可以直接接受 <intexpr>。
\NewDocumentCommand \circlednumber { s m }
{
\int_if_exist:cTF { c@ #2 }
{ \int_set_eq:Nc \l_tmpa_int { c@#2 } }
{ \int_set:Nn \l_tmpa_int { #2 } }
\IfBooleanTF {#1}
{
\exp_args:Nx \__examzh_tikz_circled_number:n { \int_use:N \l_tmpa_int }
}
{
\exp_args:Nx \__examzh_question_circled_number:n { \int_use:N \l_tmpa_int }
}
}
\cs_new:Npn \__examzh_circled_number:nn #1#2
{
\int_set:Nn \l_tmpa_int {#1}
\int_compare:nNnTF { \l_tmpa_int } = { 0 }
{ \int_set:Nn \l_tmpa_int { "24EA } }
{
\int_compare:nNnTF { \l_tmpa_int } < { 21 }
{ \int_add:Nn \l_tmpa_int { "245F } }
{
\int_compare:nNnTF { \l_tmpa_int } < { 36 }
{ \int_add:Nn \l_tmpa_int { "3250 } }
{
\int_compare:nNnTF { \l_tmpa_int } < { 51 }
{ \int_add:Nn \l_tmpa_int { "32B0 } }
{
\msg_error:nnn { exam-zh / #2 }
{ invalid-circled-number } { \int_use:N \l_tmpa_int }
}
}
}
}
\group_begin:
\CJKfamily+ { }
\symbol { \l_tmpa_int }
\group_end:
}
\msg_new:nnn { exam-zh / question } { invalid-circled-number }
{ Invalid~ circled~ number~ #1. }
\msg_new:nnn { exam-zh / fillin } { invalid-circled-number }
{ Invalid~ circled~ number~ #1. }
\cs_new:Npn \__examzh_question_circled_number:n #1
{ \__examzh_circled_number:nn {#1} { question } }
\cs_new:Npn \__examzh_fillin_circled_number:n #1
{ \__examzh_circled_number:nn {#1} { fillin } }
\AddQuestionCounter \circlednumber \__examzh_question_circled_number:n
\AddFillinCounter \circlednumber \__examzh_fillin_circled_number:n
% tikz 绘制带圈数字
\fp_new:N \l__examzh_tikz_circled_number_xscale_fp % 水平压缩系数
\fp_new:N \l__examzh_tikz_circled_number_yscale_fp % 垂直压缩系数
\dim_new:N \l__examzh_tikz_circled_number_total_hegiht_dim % 数字的总高度
\dim_new:N \l__examzh_tikz_circled_number_radius_dim % 半径
\cs_new:Npn \__examzh_tikz_circled_number_aux:n #1
{
% 根据数字大小设置压缩系数
\fp_set:Nn \l__examzh_tikz_circled_number_xscale_fp
{
\int_compare:nNnTF {#1} < { 10 }
{ 0.9 }
{
\int_compare:nNnTF {#1} < { 100 }
{ 0.7 }
{ 0.5 }
}
}
\fp_set:Nn \l__examzh_tikz_circled_number_yscale_fp
{
\int_compare:nNnTF {#1} < { 10 }
{ 0.9 }
{
\int_compare:nNnTF {#1} < { 100 }
{ 0.8 }
{ 0.6 }
}
}
% 获取数字的高度
\hbox_set:Nn \l_tmpa_box {#1}
\dim_set:Nn \l__examzh_tikz_circled_number_total_hegiht_dim
{ \box_ht:N \l_tmpa_box + \box_dp:N \l_tmpa_box }
% 设置圆的半径
\dim_set:Nn \l__examzh_tikz_circled_number_radius_dim
{ \dim_eval:n { \l__examzh_tikz_circled_number_total_hegiht_dim / 2 + 0.34 ex } }
% 绘制
\tikz [ baseline ]
{
\node
[ inner~sep = 0pt, outer~sep = 0pt ]
at (0, \dim_use:N \l__examzh_tikz_circled_number_total_hegiht_dim / 2 )
{
\hbox_set:Nn \l_tmpa_box
{
\int_compare:nNnTF {#1} > {9}
{ \textbf {#1} }
{#1}
}
\makebox[0.35em][c]
{
% \scalebox { \fp_use:N \l__examzh_tikz_circled_number_xscale_fp }
% [ \fp_use:N \l__examzh_tikz_circled_number_yscale_fp ]
\box_scale:Nnn \l_tmpa_box
{ \fp_use:N \l__examzh_tikz_circled_number_xscale_fp }
{ \fp_use:N \l__examzh_tikz_circled_number_yscale_fp }
\box_use_drop:N \l_tmpa_box
}
};
\draw (0, \l__examzh_tikz_circled_number_total_hegiht_dim / 2 )
circle ( \l__examzh_tikz_circled_number_radius_dim );
}
}
\cs_new:Npn \__examzh_tikz_circled_number:n #1
{
\__examzh_tikz_circled_number_aux:n { \int_eval:n {#1} }
}
\AddQuestionCounter \tikzcirclednumber \__examzh_tikz_circled_number:n
\AddFillinCounter \tikzcirclednumber \__examzh_tikz_circled_number:n
% 选择题括号
% 控制括号是否右对齐
\bool_new:N \l__examzh_paren_type_hfill_bool
\keys_define:nn { exam-zh / paren }
{
show-answer .bool_set:N = \l__examzh_question_show_paren_answer_bool,
text-color .tl_set:N = \l__examzh_paren_text_color_tl ,
% 是否显示选择题的括号
show-paren .bool_set:N = \l__examzh_question_show_paren_bool ,
type .choice:,
type / hfill .code:n =
{
\bool_set_true:N \l__examzh_paren_type_hfill_bool
},
type / none .code:n =
{
\bool_set_false:N \l__examzh_paren_type_hfill_bool
},
}
\keys_set:nn { exam-zh / paren }
{
show-answer = false,
text-color = black,
show-paren = false,
type = hfill
}
\keys_define:nn { exam-zh }
{ paren .meta:nn = { exam-zh / paren } {#1} }
\NewDocumentCommand \paren { O { } }
{
% 如果开了 show answer 就默认 show paren
\bool_if:NT \l__examzh_question_show_paren_answer_bool
{ \bool_set_true:N \l__examzh_question_show_paren_bool }
\bool_if:NT \l__examzh_question_show_paren_bool
{
% 使括号单独成行时居于右侧
% \null -> \hbox{}
% 𝖅𝖊𝖕𝖎𝖓𝖌 𝕷𝖊𝖊, [Mar 19, 2022 at 22:47:07]:
% 这个写法是为了处理这样的情况:假设括号需要 3em 宽度,但是如果题干末尾只剩下了 2em 的空白,括号就必要另起一行,并且用 \hill 把括号推到最右侧
% 所以中间用了两个 \hfill
% 至于 \nobreak 和 \allowbreak 大概是为了能够同时处理「括号不换行」和「括号换行」两种情况
% 这里参考 source2e 的 \@dottedtocline(目录的格式)
% 控制是否 hfill 到行尾
\bool_if:NT \l__examzh_paren_type_hfill_bool
{
\nobreak \hfill \allowbreak
\null \nobreak \hfill \nobreak
}
\hbox:n
{
(
\hbox_to_wd:nn { 3em }
{
\bool_if:NT \l__examzh_question_show_paren_answer_bool
{ \hfill \__examzh_paren_print_answer:n {#1} \hfill }
}
) \kern -.4em
}
}
}
% “打印出”答案内容 因为 show 被用作“显示与否”的含义了,所以此处用 print
\cs_new:Npn \__examzh_fillin_print_answer:n #1
{
% \group_begin:
\tl_if_eq:NnF \l__examzh_fillin_text_color_tl { black }
{ \exp_args:NV \color \l__examzh_fillin_text_color_tl }
#1
% \group_end:
}
\cs_new:Npn \__examzh_paren_print_answer:n #1
{
\group_begin:
\tl_if_eq:NnF \l__examzh_paren_text_color_tl { black }
{ \exp_args:NV \color \l__examzh_paren_text_color_tl }
#1
\group_end:
}
% fillin 的下划线样式控制
\str_new:N \l__examzh_fillin_type_str
% fillin type = paren 的括号类型
\bool_new:N \l__examzh_fillin_paren_banjiao_bool
% fillin 的 width 设置断行时是自动铺满行还是严格按照长度来
\bool_new:N \l__examzh_fillin_width_fill_bool
% 不显示答案时显示的类型
\str_new:N \l__examzh_fillin_no_answer_type_str
% no-answer-type = counter 的计数器
\int_new:N \g__examzh_fillin_no_answer_counter_int
\keys_define:nn { exam-zh / fillin }
{
type .code:n =
{
\str_set:Nn \l__examzh_fillin_type_str {#1}
},
show-answer .bool_set:N = \l__examzh_question_show_fillin_answer_bool,
width .dim_set:N = \l__examzh_fillin_F_width_dim,
width-type .choice:,
width-type / fill .code:n =
{ \bool_set_true:N \l__examzh_fillin_width_fill_bool },
width-type / normal .code:n =
{ \bool_set_false:N \l__examzh_fillin_width_fill_bool },
color .tl_set:N = \l__examzh_fillin_color_tl,
text-color .tl_set:N = \l__examzh_fillin_text_color_tl,
no-answer-type .choices:nn =
{ blacktriangle, counter, none }
{ \str_set:Nx \l__examzh_fillin_no_answer_type_str { \l_keys_choice_tl } },
no-answer-counter-index .int_gset:N = \g__examzh_fillin_no_answer_counter_int,
no-answer-counter-label .tl_set:N = \l__examzh_fillin_label_tl,
paren-type .choice:,
paren-type / banjiao .code:n =
{ \bool_set_true:N \l__examzh_fillin_paren_banjiao_bool },
paren-type / quanjiao .code:n =
{ \bool_set_false:N \l__examzh_fillin_paren_banjiao_bool },
}
\keys_set:nn { exam-zh / fillin }
{
type = line,
show-answer = false,
width = 3em,
color = black,
text-color = black,
no-answer-type = blacktriangle,
no-answer-counter-index = 1,
no-answer-counter-label = \arabic*,
paren-type = banjiao,
width-type = fill,
}
\keys_define:nn { exam-zh }
{ fillin .meta:nn = { exam-zh / fillin } {#1} }
\dim_new:N \l__examzh_question_answer_depth_dim
% 填空命令
% \fillin \fillin[] \fillin[][] 在 show-answer = false 的情况下
% no-answer-type = blacktriangle 就显示黑色三角形
% no-answer-type = counter :计数器(设计来源于完形填空)
% no-answer-type = none :不显示
\NewDocumentCommand \fillin { s O{} o }
{
\group_begin:
\IfNoValueTF {#3}
{
\bool_if:NTF \l__examzh_question_show_fillin_answer_bool
{
% 显示答案
\IfBooleanTF {#1}
{
% \fillin*[]
\__examzh_fillin_breakline:n {#2}
}
{
% \fillin[]
\__examzh_fillin:n {#2}
}
}
{
% 不显示答案
\__examzh_fillin_no_answer_typeset:
}
}
{
\keys_set:nn { exam-zh / fillin } {#2}
\bool_if:NTF \l__examzh_question_show_fillin_answer_bool
{
% 显示答案
\IfBooleanTF {#1}
{
% \fillin*[][]
\__examzh_fillin_breakline:n {#3}
}
{
% \fillin[][]
\__examzh_fillin:n {#3}
}
}
{
% 不显示答案
\__examzh_fillin_no_answer_typeset:
}
}
\group_end:
\space \ignorespaces
}
\msg_new:nnn { exam-zh / fillin } { no-such-noanswertype }
{
There~is~no~such~noanswertype~named~#1!\\
Please~read~the~manual~carefully!
}
\cs_new:Npn \__examzh_fillin_no_answer_typeset:
{
\str_case:VnF \l__examzh_fillin_no_answer_type_str
{
{ blacktriangle } { \__examzh_fillin_no_answer_typeset_blacktriangle: }
{ counter } { \__examzh_fillin_no_answer_typeset_counter: }
{ none } { \__examzh_fillin_no_answer_typeset_none: }
}
{
\msg_error:nnx { exam-zh / fillin } { no-such-noanswertype }
{ \l__examzh_fillin_no_answer_type_str }
}
}
\cs_new:Npn \__examzh_fillin_no_answer_typeset_blacktriangle:
{
\__examzh_fillin_without_judge:n { \__examzh_fillin_blacktriangle: }
}
\cs_new:Npn \__examzh_fillin_no_answer_typeset_counter:
{
\int_gincr:N \g__examzh_fillin_no_answer_counter_int
\__examzh_fillin_without_judge:n
{ \__examzh_fillin_the_label: }
% { \int_eval:n { \g__examzh_fillin_no_answer_counter_int - 1 } }
}
\cs_new:Npn \__examzh_fillin_no_answer_typeset_none:
{
\__examzh_fillin_output_F:
}
\cs_new:Npn \__examzh_fillin_without_judge:n #1
{
% \ULdepth 是 \uline 的下划线的深度
\dim_set:Nn \ULdepth { 0.3em }
% lazy 版本是指需要判断时才去获取当前用于判断的 bool 值
% 而不是类似于“提前展开”,和项子越在 LaTeX3 的 b站视频里讲到的 lazy evaluation 想法相同
\hbox_set:Nn \l_tmpa_box { \__examzh_fillin_print_answer:n {#1} }
\dim_set:Nn \l__examzh_question_answer_depth_dim
{ \box_dp:N \l_tmpa_box }
\__examzh_fillin_output_T:
}
\cs_new:Npn \__examzh_fillin:n #1
{
% \ULdepth 是 \uline 的下划线的深度
\dim_set:Nn \ULdepth { 0.3em }
% lazy 版本是指需要判断时才去获取当前用于判断的 bool 值
% 而不是类似于“提前展开”,和项子越在 LaTeX3 的 b站视频里讲到的 lazy evaluation 想法相同
\bool_lazy_and:nnTF
{ \bool_if_p:N \l__examzh_question_show_fillin_answer_bool }
{ \bool_not_p:n { \tl_if_empty_p:n {#1} } }
{
\hbox_set:Nn \l_tmpa_box { \__examzh_fillin_print_answer:n {#1} }
\dim_set:Nn \l__examzh_question_answer_depth_dim
{ \box_dp:N \l_tmpa_box }
\__examzh_fillin_output_T:
}
{
\__examzh_fillin_output_F:
}
}
\cs_new:Npn \__examzh_fillin_breakline:n #1
{
\bool_lazy_and:nnTF
{ \bool_if_p:N \l__examzh_question_show_fillin_answer_bool }
{ \bool_not_p:n { \tl_if_empty_p:n {#1} } }
{
\tl_set:Nn \l_tmpa_tl { \__examzh_fillin_print_answer:n {#1} }
\__examzh_fillin_output_breakline_T:
}
{
\__examzh_fillin_output_F:
}
}
\msg_new:nnn { exam-zh } { no-fillin-type }
{
There~is~no~type~of~\fillin~named~#1!\\
Please~read~the~manual~for~more~details.
}
\cs_new:Npn \__examzh_fillin_output_T:
{
\str_case:VnF \l__examzh_fillin_type_str
{
{ line } { \__examzh_fillin_uline_T: }
{ paren } { \__examzh_fillin_paren_T: }
{ circle } { \__examzh_fillin_circle_T: }
{ blank } { \__examzh_fillin_blank_T: }
{ rectangle } { \__examzh_fillin_rectangle_T: }
}
{
\msg_error:nnx { exam-zh } { no-fillin-type }
{ \l__examzh_fillin_type_str }
}
}
\cs_new:Npn \__examzh_fillin_output_breakline_T:
{
\str_case:VnF \l__examzh_fillin_type_str
{
{ line } { \__examzh_fillin_uline_breakline_T: }
{ paren } { \__examzh_fillin_paren_breakline_T: }
{ blank } { \__examzh_fillin_blank_breakline_T: }
}
{
\msg_error:nnx { exam-zh } { no-breakable-fillin-type }
{ \l__examzh_fillin_type_str }
}
}
\msg_new:nnn { exam-zh } { no-breakable-fillin-type }
{
The~type~:~#1~ cannot~be~used~in~breakable~fillin~cmd.
}
\cs_new:Npn \__examzh_fillin_output_F:
{
\str_case:VnF \l__examzh_fillin_type_str
{
{ line } { \__examzh_fillin_uline_F: }
{ paren } { \__examzh_fillin_paren_F: }
{ circle } { \__examzh_fillin_circle_F: }
{ blank } { \__examzh_fillin_blank_F: }
{ rectangle } { \__examzh_fillin_rectangle_F: }
}
{
\msg_error:nnx { exam-zh } { no-fillin-type }
{ \l__examzh_fillin_type_str }
}
}
\cs_new:Npn \__examzh_fillin_uline_T:
{
\uline
{
\hspace* { 0.5em plus .5em minus .5em }
\dim_compare:nNnTF { \l__examzh_question_answer_depth_dim } > { 0.2em }
{
\dim_sub:Nn \l__examzh_question_answer_depth_dim { 0.2em }
\raisebox { \l__examzh_question_answer_depth_dim }
{ \box_use_drop:N \l_tmpa_box }
}
{ \box_use_drop:N \l_tmpa_box }
\hspace* { 0.5em plus .5em minus .5em }
}
}
\cs_new:Npn \__examzh_fillin_uline_F:
{
% \uline { \hspace* { \l__examzh_fillin_F_width_dim } }
\__examzh_fillin_breakable_hspace:NN \CJKunderline \allowbreak
}
% \cs_new:Nn \__examzh_fillin_uline:
% {
% \bgroup
% \color{ \l__examzh_fillin_text_color_tl }
% \markoverwith{\textcolor{black}{\rule[-0.7ex]{2pt}{0.4pt}}}
% \ULon
% xeCJKfntef.sty
% xeCJK: 修复下划线中数学公式的错误处理
% https://github.com/CTeX-org/ctex-kit/commit/ad44c6674bb377653544349f23b7c629bc9e4677
\RenewDocumentCommand \CJKunderline { s t- s o }
{
\xeCJK_ulem_group_begin:
\xeCJK_fntef_boot:nnNNNn { underline } { uline } #1#2#3 {#4}
\xeCJK_fntef_initial:nnn
{ \l__xeCJK_uline_depth_tl }
{ \l__xeCJK_uline_sep_tl }
{
\l__xeCJK_uline_format_tl
\tex_vrule:D
height \dim_eval:n { \l__xeCJK_uline_thickness_tl }
depth \c_zero_dim
width .2em
}
% 给 CJKunderline 加了颜色控制
\color { \l__examzh_fillin_text_color_tl }
\xeCJK_ulem_on:n
}
% }
\cs_new:Npn \__examzh_fillin_uline_breakline_T:
{
\CJKunderline*
% \uline
% \__examzh_fillin_uline:
{
\hspace* { 0.5em plus .5em minus .5em }
% \color{ \l__examzh_fillin_text_color_tl }
\l_tmpa_tl
% 答案很长时,不能完全显示,答案很长时,不能完全显示
\hspace* { 0.5em plus .5em minus .5em }
}
}
\cs_new:Npn \__examzh_fillin_paren_T:
{
\bool_if:NTF \l__examzh_fillin_paren_banjiao_bool
{
(
\hspace* { 0.5em plus .5em minus .5em }
\group_begin:
\box_use_drop:N \l_tmpa_box
\group_end:
\hspace* { 0.5em plus .5em minus .5em }
)
}
{
(
\hspace* { 0.5em plus .5em minus .5em }
\group_begin:
\box_use_drop:N \l_tmpa_box
\group_end:
\hspace* { 0.5em plus .5em minus .5em }
)
}
}
\cs_new:Npn \__examzh_fillin_paren_breakline_T:
{
\bool_if:NTF \l__examzh_fillin_paren_banjiao_bool
{
(
\hspace* { 0.5em plus .5em minus .5em }
\group_begin:
\l_tmpa_tl
\group_end:
\hspace* { 0.5em plus .5em minus .5em }
)
}
{
(
\hspace* { 0.5em plus .5em minus .5em }
\group_begin:
\l_tmpa_tl
\group_end:
\hspace* { 0.5em plus .5em minus .5em }
)
}
}
\box_new:N \c__examzh_banjiao_right_brace_box
\box_new:N \c__examzh_quanjiao_right_brace_box
\hbox_set:Nn \c__examzh_banjiao_right_brace_box { ) }
\hbox_set:Nn \c__examzh_quanjiao_right_brace_box { ) }
\dim_const:Nn \c__examzh_banjiao_right_brace_width_dim % (
{ \box_wd:N \c__examzh_banjiao_right_brace_box }
\dim_const:Nn \c__examzh_quanjiao_right_brace_width_dim % (
{ \box_wd:N \c__examzh_quanjiao_right_brace_box }
\cs_new:Npn \__examzh_fillin_paren_F:
{
\bool_if:NTF \l__examzh_fillin_paren_banjiao_bool
{
( \__examzh_fillin_breakable_hspace:NN \use:n \nobreak \kern-\c__examzh_banjiao_right_brace_width_dim ) \allowbreak
}
{
( \__examzh_fillin_breakable_hspace:NN \use:n \nobreak \kern-\c__examzh_quanjiao_right_brace_width_dim )\allowbreak
}
}
\cs_new:Npn \__examzh_fillin_blank_T:
{
\hspace* { 0.5em plus .5em minus .5em }
\group_begin:
\box_use_drop:N \l_tmpa_box
\group_end:
\hspace* { 0.5em plus .5em minus .5em }
}
\cs_new:Npn \__examzh_fillin_blank_breakline_T:
{
\hspace* { 0.5em plus .5em minus .5em }
\group_begin:
\l_tmpa_tl
\group_end:
\hspace* { 0.5em plus .5em minus .5em }
}
\cs_new:Npn \__examzh_fillin_blank_F:
{
% \hspace* { \l__examzh_fillin_F_width_dim }
\__examzh_fillin_breakable_hspace:NN \use:n \allowbreak
}
\tikzset
{
fillin-circle/.style =
{
rounded~rectangle~west~arc = convex,
draw, rounded~rectangle,
color = \l__examzh_fillin_color_tl, text = \l__examzh_fillin_text_color_tl
}
}
\cs_new:Npn \__examzh_fillin_circle_T:
{
\hspace* { .5em minus .5em }
\tikz[baseline=-3pt]
{
\node [fillin-circle] at (0,0)
{ \box_use_drop:N \l_tmpa_box };
}
\hspace* { .5em minus .5em }
}
\cs_new:Npn \__examzh_fillin_circle_F:
{
\hspace* { 0.5em plus .5em minus .5em }
\tikz[baseline=-3pt]
{
\node [fillin-circle] at (0,0)
{ \phantom{t} };
}
\hspace* { 0.5em plus .5em minus .5em }
}
\cs_new:Npn \__examzh_fillin_rectangle_T:
{
\hspace* { .5em minus .5em }
\begin{tikzpicture}[baseline = -3pt]
\node[draw, color = \l__examzh_fillin_color_tl, text = \l__examzh_fillin_text_color_tl]
{ \box_use_drop:N \l_tmpa_box };
\end{tikzpicture}
\hspace* { .5em minus .5em }
}
\cs_new:Npn \__examzh_fillin_rectangle_F:
{
\hspace* { 0.5em plus .5em minus .5em }
\begin{tikzpicture}[baseline = -3pt]
\node[draw, color = \l__examzh_fillin_color_tl, text = \l__examzh_fillin_text_color_tl]
{ \phantom{a} };
\end{tikzpicture}
\hspace* { 0.5em plus .5em minus .5em }
}
% 通过循环来达到自动断行的空白下划线
\cs_generate_variant:Nn \dim_sub:Nn { NV }
\cs_generate_variant:Nn \dim_add:Nn { NV }
\cs_generate_variant:Nn \dim_set:Nn { NV, Nx }
% 用来检测是否处于 list 环境中
\bool_new:N \l__if_list_bool
\int_new:N \l__list_depth_int
\cs_generate_variant:Nn \dim_set:Nn { Nx }
\AddToHook { cmd / list / after }
{
\bool_set_true:N \l__if_list_bool
\int_incr:N \l__list_depth_int
\dim_if_exist:cF { l__list_leftmargin_ \int_to_roman:n { \l__list_depth_int } _dim }
{
\dim_new:c { l__list_leftmargin_ \int_to_roman:n { \l__list_depth_int } _dim }
}
% 用来储存相应层级的 \leftmargin 值
\dim_set_eq:cN { l__list_leftmargin_ \int_to_roman:n { \l__list_depth_int } _dim } \leftmargin
}
\AddToHook { cmd / endlist / before }
{ \int_zero:N \l__list_depth_int }
\cs_new:Npn \__examzh_fillin_breakable_hspace:NN #1#2
% #1: CJKunderline / use:n
% #2: \allowbreak
{
% 比较 \l__examzh_fillin_F_width_dim 和 linegoal
\dim_compare:nNnTF { \l__examzh_fillin_F_width_dim } > { \linegoal }
{
% 超过 linegoal 就排一段 linegoal,然后 \l__examzh_fillin_F_width_dim 减去 linegoal 长度
\dim_set:NV \l_tmpa_dim \linegoal
% 是否处于 list 环境中
\bool_if:NTF \l__if_list_bool
{
% 加上 1 到 当前层级的 leftmargin 才能让 list 中的 linegoal 正常
\int_step_inline:nn { \l__list_depth_int }
{
\dim_add:Nn \l_tmpa_dim { \dim_use:c { l__list_leftmargin_ \int_to_roman:n { ##1 } _dim } }
}
#1 { \hspace { \l_tmpa_dim } }
}
{
% 正文中
#1 { \hspace { \linegoal } }
}
\dim_sub:NV \l__examzh_fillin_F_width_dim \l_tmpa_dim
\dim_while_do:nNnn { \l__examzh_fillin_F_width_dim } > { \linewidth }
{
% 循环:\l__examzh_fillin_F_width_dim 和 \linewidth 比较,大的话就排一个,然后减掉 linewidth
\\ #1 { \hspace* { \linewidth } }
\dim_sub:Nn \l__examzh_fillin_F_width_dim { \linewidth }
}
% \\ #1 { \hspace* { \linewidth } }
\dim_compare:nNnT { \l__examzh_fillin_F_width_dim } < { \linewidth }
{
% 最后一行是否 fill
\bool_if:NTF \l__examzh_fillin_width_fill_bool
{
\\ #1 { \hspace* { \linewidth } }
}
{
\\ #1 { \hspace* { \l__examzh_fillin_F_width_dim } }
}
}
}
{
#1 { \hspace* { \l__examzh_fillin_F_width_dim } }
}
#2
}
\dim_new:N \l__examzh_blacktriangle_length_dim
\dim_set:Nn \l__examzh_blacktriangle_length_dim { .7em }
\cs_new:Npn \__examzh_fillin_blacktriangle:
{
\tikz[rounded~corners=0.5pt,baseline=0pt]
{
\fill[] (0,0) -- ++(60\c_colon_str \l__examzh_blacktriangle_length_dim) -- ++(-60\c_colon_str \l__examzh_blacktriangle_length_dim) -- cycle ;
}
}
\str_new:N \l__examzh_solution_blank_type_str
\keys_define:nn { exam-zh / solution }
{
show-solution .bool_set:N = \l__examzh_solution_show_bool,
show-qed .bool_set:N = \l__examzh_solution_show_qed_bool,
qedsymbol .tl_set:N = \l__examzh_solution_qedsymbol_tl,
label-content .tl_set:N = \l__examzh_solution_label_content_tl,
label-punct .tl_set:N = \l__examzh_solution_label_punct_tl,
score-showleader .bool_set:N = \l__examzh_score_show_leader_bool,
score-pre-content .tl_set:N = \l__examzh_score_pre_content_tl,
score-post-content .tl_set:N = \l__examzh_score_post_content_tl,
score-format .tl_set:N = \l__examzh_score_format_tl,
text-color .tl_set:N = \l__examzh_solution_text_color_tl,
blank-type .choices:nn =
{ none, manual, hide }
{
\str_set:Nx \l__examzh_solution_blank_type_str { \l_keys_choice_tl }
},
blank-vsep .skip_set:N = \l__examzh_solution_blank_vsep_skip,
top-sep .skip_set:N = \l__examzh_solution_top_sep_skip,
bottom-sep .skip_set:N = \l__examzh_solution_bottom_sep_skip,
parbreak .bool_set:N = \l__examzh_solution_par_break_bool,
}
\keys_set:nn { exam-zh / solution }
{
show-solution = false,
show-qed = true,
qedsymbol = $\square$,
label-content = {解答},
label-punct = {},
score-showleader = true,
score-pre-content = {},
score-post-content = 分,
score-format = \color{red},
text-color = black,
blank-type = none,
blank-vsep = 12ex plus 1ex minus 1ex,
top-sep = .25em plus .25em minus .1em,
bottom-sep = 0pt,
parbreak = false
}
\keys_define:nn { exam-zh }
{ solution .meta:nn = { exam-zh / solution } {#1} }
% 解答题环境
\NewDocumentEnvironment { solution } { O{ } +b }
{
% \addvspace { \l__examzh_solution_top_sep_skip }
\vspace { \l__examzh_solution_top_sep_skip }
\keys_set:nn { exam-zh / solution } {#1}
% 放在这是使得 \examsetup 设置 qedsymbol 可以放在正文区
\cs_set_eq:NN \qedsymbol \l__examzh_solution_qedsymbol_tl
\bool_if:NTF \l__examzh_solution_show_bool
{
\__examzh_solution_print_answer:n {#2}
}
{
\str_case:VnF \l__examzh_solution_blank_type_str
{
{ none } { }
{ manual } { \addvspace { \l__examzh_solution_blank_vsep_skip } }
{ hide } { \__examzh_solution_simply_hide_solution:n {#2} }
}
{}
}
\par
% \mode_leave_vertical:
% \addvspace { \l__examzh_solution_bottom_sep_skip }
\vspace { \l__examzh_solution_bottom_sep_skip }
}
{}
\cs_new:Npn \__examzh_solution_simply_hide_solution:n #1
{
\begin{tcolorbox}
[
invisible,
frame~hidden,
breakable,
opacityback = 0,
opacityframe = 0,
size = minimal,
width = \linewidth
]
#1
\end{tcolorbox}
}
\cs_new:Npn \__examzh_solution_print_answer:n #1
{
\par
\pushQED { \qed }
% \normalfont \topsep6 \p@ \@plus6 \p@ \relax
% \trivlist
% \item \relax
\group_begin:
% \hspace* { 2\ccwd }
\bfseries \l__examzh_solution_label_content_tl
\@addpunct { \l__examzh_solution_label_punct_tl }
\group_end:
\hspace{0.5em}
% \ignorespaces
% 是否要新起一段开始
\bool_if:NT \l__examzh_solution_par_break_bool { \par }
% \group_begin:
\begingroup
\color { \l__examzh_solution_text_color_tl } #1
\endgroup
% \group_end:
\bool_if:NT \l__examzh_solution_show_qed_bool
{ \popQED }
% \endtrivlist
% \@endpefalse
}
% https://github.com/CTeX-org/forum/issues/256#issuecomment-1172319787
\zref@require@unique
\NewDocumentCommand { \score } { O{} m }
{
\group_begin:
\keys_set:nn { exam / question } {#1}
\mode_if_math:TF
{
\__examzh_score_math_version:n { #2 }
}
{
\__examzh_score_text_version:n { #2 }
}
\group_end:
}
\cs_new:Npn \__examzh_score_math_version:n #1
{
\bool_if:NTF \l__examzh_score_show_leader_bool
{
\__examzh_math_cdotfill:n
{
\group_begin:
\l__examzh_score_format_tl
\l__examzh_score_pre_content_tl
#1
\l__examzh_score_post_content_tl
\group_end:
}
}
{
\__examzh_math_nodotfill:n
{
{
\group_begin:
\l__examzh_score_format_tl
\l__examzh_score_pre_content_tl
#1
\l__examzh_score_post_content_tl
\group_end:
}
}
}
}
\cs_new:Npn \__examzh_score_text_version:n #1
{
\bool_if:NTF \l__examzh_score_show_leader_bool
{
\group_begin:
\__examzh_cdotfill:
\l__examzh_score_format_tl
\l__examzh_score_pre_content_tl #1 \l__examzh_score_post_content_tl
\group_end:
}
{
\hfill
\group_begin:
\l__examzh_score_format_tl
\l__examzh_score_pre_content_tl #1 \l__examzh_score_post_content_tl
\group_end:
}
\par \noindent \ignorespaces
}
% 仿照 latex.ltx, line 651 的 \dotfill
\cs_new:Npn \__examzh_cdotfill:
{
\mode_leave_vertical:
\cleaders
\hbox_to_wd:nn { .44em } { \hss $\cdot$ \hss }
\hfill \kern\z@
}
\cs_new_protected:Npn \__examzh_math_nodotfill:n #1
{
\stepcounter { zref@unique }
\hbox_overlap_right:n
{
\zsaveposx { \thezref@unique L }
\zref@ifrefundefined { \thezref@unique R }
{ }
{
\skip_horizontal:n
{
\zposx { \thezref@unique R } sp
- \zposx { \thezref@unique L } sp
}
}
}
\tag * { \zsaveposx { \thezref@unique R } #1 }
}
\cs_new_protected:Npn \__examzh_math_cdotfill:n #1
{
\stepcounter { zref@unique }
\hbox_overlap_right:n
{
\zsaveposx { \thezref@unique L }
\zref@ifrefundefined { \thezref@unique R }
{ }
{
\cleaders
\hbox_to_wd:nn { .44em } { \hss $\cdot$ \hss }
\skip_horizontal:n
{
\zposx { \thezref@unique R } sp
- \zposx { \thezref@unique L } sp
}
}
}
\tag * { \zsaveposx { \thezref@unique R } #1 }
}
|