summaryrefslogtreecommitdiff
path: root/Master/texmf-dist/doc/latex/euclideangeometry/euclideangeometry-man.tex
blob: d439d7bc3a46efe5b721a83893082a7327d0a120 (plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
268
269
270
271
272
273
274
275
276
277
278
279
280
281
282
283
284
285
286
287
288
289
290
291
292
293
294
295
296
297
298
299
300
301
302
303
304
305
306
307
308
309
310
311
312
313
314
315
316
317
318
319
320
321
322
323
324
325
326
327
328
329
330
331
332
333
334
335
336
337
338
339
340
341
342
343
344
345
346
347
348
349
350
351
352
353
354
355
356
357
358
359
360
361
362
363
364
365
366
367
368
369
370
371
372
373
374
375
376
377
378
379
380
381
382
383
384
385
386
387
388
389
390
391
392
393
394
395
396
397
398
399
400
401
402
403
404
405
406
407
408
409
410
411
412
413
414
415
416
417
418
419
420
421
422
423
424
425
426
427
428
429
430
431
432
433
434
435
436
437
438
439
440
441
442
443
444
445
446
447
448
449
450
451
452
453
454
455
456
457
458
459
460
461
462
463
464
465
466
467
468
469
470
471
472
473
474
475
476
477
478
479
480
481
482
483
484
485
486
487
488
489
490
491
492
493
494
495
496
497
498
499
500
501
502
503
504
505
506
507
508
509
510
511
512
513
514
515
516
517
518
519
520
521
522
523
524
525
526
527
528
529
530
531
532
533
534
535
536
537
538
539
540
541
542
543
544
545
546
547
548
549
550
551
552
553
554
555
556
557
558
559
560
561
562
563
564
565
566
567
568
569
570
571
572
573
574
575
576
577
578
579
580
581
582
583
584
585
586
587
588
589
590
591
592
593
594
595
596
597
598
599
600
601
602
603
604
605
606
607
608
609
610
611
612
613
614
615
616
617
618
619
620
621
622
623
624
625
626
627
628
629
630
631
632
633
634
635
636
637
638
639
640
641
642
643
644
645
646
647
648
649
650
651
652
653
654
655
656
657
658
659
660
661
662
663
664
665
666
667
668
669
670
671
672
673
674
675
676
677
678
679
680
681
682
683
684
685
686
687
688
689
690
691
692
693
694
695
696
697
698
699
700
701
702
703
704
705
706
707
708
709
710
711
712
713
714
715
716
717
718
719
720
721
722
723
724
725
726
727
728
729
730
731
732
733
734
735
736
737
738
739
740
741
742
743
744
745
746
747
748
749
750
751
752
753
754
755
756
757
758
759
760
761
762
763
764
765
766
767
768
769
770
771
772
773
774
775
776
777
778
779
780
781
782
783
784
785
786
787
788
789
790
791
792
793
794
795
796
797
798
799
800
801
802
803
804
805
806
807
808
809
810
811
812
813
814
815
816
817
818
819
820
821
822
823
824
825
826
827
828
829
830
831
832
833
834
835
836
837
838
839
840
841
842
843
844
845
846
847
848
849
850
851
852
853
854
855
856
857
858
859
860
861
862
863
864
865
866
867
868
869
870
871
872
873
874
875
876
877
878
879
880
881
882
883
884
885
886
887
888
889
890
891
892
893
894
895
896
897
898
899
900
901
902
903
904
905
906
907
908
909
910
911
912
913
914
915
916
917
918
919
920
921
922
923
924
925
926
927
928
929
930
931
932
933
934
935
936
937
938
939
940
941
942
943
944
945
946
947
948
949
950
951
952
953
954
955
956
957
958
959
960
961
962
963
964
965
966
967
968
969
970
971
972
973
974
975
976
977
978
979
980
981
982
983
984
985
986
987
988
989
990
991
992
993
994
995
996
997
998
999
1000
1001
1002
1003
1004
1005
1006
1007
1008
1009
1010
1011
1012
1013
1014
1015
1016
1017
1018
1019
1020
1021
1022
1023
1024
1025
1026
1027
1028
1029
1030
1031
1032
1033
1034
1035
1036
1037
1038
1039
1040
1041
1042
1043
1044
1045
1046
1047
1048
1049
1050
1051
1052
1053
1054
1055
1056
1057
1058
1059
1060
1061
1062
1063
1064
1065
1066
1067
1068
1069
1070
1071
1072
1073
1074
1075
1076
1077
1078
1079
1080
1081
1082
1083
1084
1085
1086
1087
1088
1089
1090
1091
1092
1093
1094
1095
1096
1097
1098
1099
1100
1101
1102
1103
1104
1105
1106
1107
1108
1109
1110
1111
1112
1113
1114
1115
1116
1117
1118
1119
1120
1121
1122
1123
1124
1125
1126
1127
1128
1129
1130
1131
1132
1133
1134
1135
1136
1137
1138
1139
1140
1141
1142
1143
1144
1145
1146
1147
1148
1149
1150
1151
1152
1153
1154
1155
1156
1157
1158
1159
1160
1161
1162
1163
1164
1165
1166
1167
1168
1169
1170
1171
1172
1173
1174
1175
1176
1177
1178
1179
1180
1181
1182
1183
1184
1185
1186
1187
1188
1189
1190
1191
1192
1193
1194
1195
1196
1197
1198
1199
1200
1201
1202
1203
1204
1205
1206
1207
1208
1209
1210
1211
1212
1213
1214
1215
1216
1217
1218
1219
1220
1221
1222
1223
1224
1225
1226
1227
1228
1229
1230
1231
1232
1233
1234
1235
1236
1237
1238
1239
1240
1241
1242
1243
1244
1245
1246
1247
1248
1249
1250
1251
1252
1253
1254
1255
1256
1257
1258
1259
1260
1261
1262
1263
1264
1265
1266
1267
1268
1269
1270
1271
1272
1273
1274
1275
1276
1277
1278
1279
1280
1281
1282
1283
1284
1285
1286
1287
1288
1289
1290
1291
1292
1293
1294
1295
1296
1297
1298
1299
1300
1301
1302
1303
1304
1305
1306
1307
1308
1309
1310
1311
1312
1313
1314
1315
1316
1317
1318
1319
1320
1321
1322
1323
1324
1325
1326
1327
1328
1329
1330
1331
1332
1333
1334
1335
1336
1337
1338
1339
1340
1341
1342
1343
1344
1345
1346
1347
1348
1349
1350
1351
1352
1353
1354
1355
1356
1357
1358
1359
1360
1361
1362
1363
1364
1365
1366
1367
1368
1369
1370
1371
1372
1373
1374
1375
1376
1377
1378
1379
1380
1381
1382
1383
1384
1385
1386
1387
1388
1389
1390
1391
1392
1393
1394
1395
1396
1397
1398
1399
1400
1401
1402
1403
1404
1405
1406
1407
1408
1409
1410
1411
1412
1413
1414
1415
1416
1417
1418
1419
1420
1421
1422
1423
1424
1425
1426
1427
1428
1429
1430
1431
1432
1433
1434
1435
1436
1437
1438
1439
1440
1441
1442
1443
1444
1445
1446
1447
1448
1449
1450
1451
1452
1453
1454
1455
1456
1457
1458
1459
1460
1461
1462
1463
1464
1465
1466
1467
1468
1469
1470
1471
1472
1473
1474
1475
1476
1477
1478
1479
1480
1481
1482
1483
1484
1485
1486
1487
1488
1489
1490
1491
1492
1493
1494
1495
1496
1497
1498
1499
1500
1501
1502
1503
1504
1505
1506
1507
1508
1509
1510
1511
1512
1513
1514
1515
1516
1517
1518
1519
1520
1521
1522
1523
1524
1525
1526
1527
1528
1529
1530
1531
1532
1533
1534
1535
1536
1537
1538
1539
1540
1541
1542
1543
1544
1545
1546
1547
1548
1549
1550
1551
1552
1553
1554
1555
1556
1557
1558
1559
1560
1561
1562
1563
1564
1565
1566
1567
1568
1569
1570
1571
1572
1573
1574
1575
1576
1577
1578
1579
1580
1581
1582
1583
1584
1585
1586
1587
1588
1589
1590
1591
1592
1593
1594
1595
1596
1597
1598
1599
1600
1601
1602
1603
1604
1605
1606
1607
1608
1609
1610
1611
1612
1613
1614
1615
1616
1617
1618
1619
1620
1621
1622
1623
1624
1625
1626
1627
1628
1629
1630
1631
1632
1633
1634
1635
1636
1637
1638
1639
1640
1641
1642
1643
1644
1645
1646
1647
1648
1649
1650
1651
1652
1653
1654
1655
1656
1657
1658
1659
1660
1661
1662
1663
1664
1665
1666
1667
1668
1669
1670
1671
1672
1673
1674
1675
1676
1677
1678
1679
1680
1681
1682
1683
1684
1685
1686
1687
1688
1689
1690
1691
1692
1693
1694
1695
1696
1697
1698
1699
1700
1701
1702
1703
1704
1705
1706
1707
1708
1709
1710
1711
1712
1713
1714
1715
1716
1717
1718
1719
1720
1721
1722
1723
1724
1725
1726
1727
1728
1729
1730
1731
1732
1733
1734
1735
1736
1737
1738
1739
1740
1741
1742
1743
1744
1745
1746
1747
1748
1749
1750
1751
1752
1753
1754
1755
1756
1757
1758
1759
1760
1761
1762
1763
1764
1765
1766
1767
1768
1769
1770
1771
1772
1773
1774
1775
1776
1777
1778
1779
1780
1781
1782
1783
1784
1785
1786
1787
1788
1789
1790
1791
1792
1793
1794
1795
1796
1797
1798
1799
1800
1801
1802
1803
1804
1805
1806
1807
1808
1809
1810
1811
1812
1813
1814
1815
1816
1817
1818
1819
1820
1821
1822
1823
1824
1825
1826
1827
1828
1829
1830
1831
1832
1833
1834
1835
1836
1837
1838
1839
1840
1841
1842
1843
1844
1845
1846
1847
1848
1849
1850
1851
1852
1853
1854
1855
1856
1857
1858
1859
1860
1861
1862
1863
1864
1865
1866
1867
1868
1869
1870
1871
1872
1873
1874
1875
1876
1877
1878
1879
1880
1881
1882
1883
1884
1885
1886
1887
1888
1889
1890
1891
1892
1893
1894
1895
1896
1897
1898
1899
1900
1901
1902
1903
1904
1905
1906
1907
1908
1909
1910
1911
1912
1913
1914
1915
1916
1917
1918
1919
1920
1921
1922
1923
1924
1925
1926
1927
1928
1929
1930
1931
1932
1933
1934
1935
1936
1937
1938
1939
1940
1941
1942
1943
1944
1945
1946
1947
1948
1949
1950
1951
1952
1953
1954
1955
1956
1957
1958
1959
1960
1961
1962
1963
1964
1965
1966
1967
1968
1969
1970
1971
1972
1973
1974
1975
1976
1977
1978
1979
1980
1981
1982
1983
1984
1985
1986
1987
1988
1989
1990
1991
1992
1993
1994
1995
1996
1997
1998
1999
2000
2001
2002
2003
2004
2005
2006
2007
2008
2009
2010
2011
2012
2013
2014
2015
2016
2017
2018
2019
2020
2021
2022
2023
2024
2025
2026
2027
2028
2029
2030
2031
2032
2033
2034
2035
2036
2037
2038
2039
2040
2041
2042
2043
2044
2045
2046
2047
2048
2049
2050
2051
2052
2053
2054
2055
2056
2057
2058
2059
2060
2061
2062
2063
2064
2065
2066
2067
2068
2069
2070
2071
2072
2073
2074
2075
2076
2077
2078
2079
2080
2081
2082
2083
2084
2085
2086
2087
2088
2089
2090
2091
2092
2093
2094
2095
2096
2097
2098
2099
2100
2101
2102
2103
2104
2105
2106
2107
2108
2109
2110
2111
2112
2113
2114
2115
2116
2117
2118
2119
2120
2121
2122
2123
2124
2125
2126
2127
2128
2129
2130
2131
2132
2133
2134
2135
2136
2137
2138
2139
2140
2141
2142
2143
2144
2145
2146
2147
2148
2149
2150
2151
2152
2153
2154
2155
2156
2157
2158
2159
2160
2161
2162
2163
2164
2165
2166
2167
2168
2169
2170
2171
2172
2173
2174
2175
2176
2177
2178
2179
2180
2181
2182
2183
2184
2185
2186
2187
2188
2189
2190
2191
2192
2193
2194
2195
2196
2197
2198
2199
2200
2201
2202
2203
2204
2205
2206
2207
2208
2209
2210
2211
2212
2213
2214
2215
2216
2217
2218
2219
2220
2221
2222
2223
2224
2225
2226
2227
2228
2229
2230
2231
2232
2233
2234
2235
2236
2237
2238
2239
2240
2241
2242
2243
2244
2245
2246
2247
2248
2249
2250
2251
2252
2253
2254
2255
2256
2257
2258
2259
2260
2261
2262
2263
2264
2265
2266
2267
2268
2269
2270
2271
2272
2273
2274
2275
2276
2277
2278
2279
2280
2281
2282
2283
2284
2285
2286
2287
2288
2289
2290
2291
2292
2293
2294
2295
2296
2297
2298
2299
2300
2301
2302
2303
2304
2305
2306
2307
2308
2309
2310
2311
2312
2313
2314
2315
2316
2317
2318
2319
2320
2321
2322
2323
2324
2325
2326
2327
2328
2329
2330
2331
2332
2333
2334
2335
2336
2337
2338
2339
2340
2341
2342
2343
2344
2345
2346
2347
2348
2349
2350
2351
2352
2353
2354
2355
2356
2357
2358
2359
2360
2361
2362
2363
2364
2365
2366
2367
2368
2369
2370
2371
2372
2373
2374
2375
2376
2377
2378
2379
2380
2381
2382
2383
2384
2385
% !TEX encoding = UTF-8 Unicode
% !TEX TS-program = pdflatex

\documentclass[11pt,titlepage,a4paper]{article}\errorcontextlines=100
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[english]{babel}
\usepackage{lmodern,textcomp,mflogo}
\usepackage{amsmath,fancyvrb,graphicx,afterpage,etoolbox,trace}
\usepackage{enumitem,xspace,xcolor,euclideangeometry,pm-isomath}
\usepackage{url}
\providecommand\file{}
\renewcommand*\file[1]{{\normalfont\texttt{#1}}}
\providecommand\prog{}
\renewcommand*\prog[1]{{\normalfont\texttt{#1}}}
\newcommand*\conta[1]{\texttt{\slshape#1}}
\providecommand\cs{}
\renewcommand\cs[1]{{\normalfont\texttt{\char92#1}}}
\providecommand\meta{}
\renewcommand*\meta[1]{{\normalfont$\langle$\textit{#1}$\rangle$}}
\providecommand\marg{}
\renewcommand*\marg[1]{{\ttfamily \char123\meta{#1}\char125}}
\newcommand*\Marg[1]{{\normalfont\ttfamily\{#1\}}}\let\Arg\Marg
\providecommand\oarg{}
\renewcommand*\oarg[1]{{\ttfamily[\meta{#1}]}}
\newcommand*\Oarg[1]{{\ttfamily[#1]}}
\newcommand*\aarg[1]{{\ttfamily{<\meta{#1}>}}}
\newcommand*\Aarg[1]{{\ttfamily<#1>}}
\newcommand*\Bambiente[1]{\texttt{\char92begin\{#1\}}}
\newcommand*\Eambiente[1]{\texttt{\char92end\{#1\}}}
\newcommand*\garg[1]{\texttt{(\splitgarg#1,!)}}\let\parg\garg
\newcommand*\Garg[1]{\texttt{(#1)}}\let\Parg\Garg
  \def\secgarg#1,{#1}
  \def\splitgarg#1,#2!{%
     \ifstrequal{#2}{}{\meta{#1}}{\meta{#1},\meta{\secgarg#2}}}
\providecommand\pack{}
\renewcommand*\pack[1]{{\normalfont\textsf{#1}}}
\providecommand\opt{}
\renewcommand*\opt[1]{{\normalfont\textsl{#1}}}\let\opz\opt
\providecommand\env{}
\renewcommand*\env[1]{{\normalfont\textit{\bfseries#1}}}\let\amb\env

\providecommand*\ped[1]{\ensuremath{_{\mathrm{#1}}}}
\providecommand*\ap[1]{\ensuremath{^{\mathrm{#1}}}}
\providecommand*\unit[1]{\ensuremath{\,\mathrm{#1}}}
\providecommand*\sigla[1]{\textsc{\lowercase{#1}}}
\providecommand*\iu{\ensuremath{\mathrm{i}}}\let\gei\iu
\providecommand*\eu{\ensuremath{\mathop{\mathrm{e}}\nolimits}}

\providecommand\GetFileInfo{}
\makeatletter
\renewcommand*\GetFileInfo[1]{%
  \def\filename{#1}%
  \def\@tempb##1 v.##2 ##3\relax##4\relax{%
    \def\filedate{##1}\def\fileversion{##2}\def\fileinfo{##3}}%
  \edef\@tempa{\csname ver@#1\endcsname}%
  \expandafter\@tempb\@tempa\relax? ? \relax\relax}
\makeatother

\DeclareRobustCommand*{\Ars}{% for the bibliography
  \textsf{\lower -.48ex\hbox{\rotatebox{-20}{A}}\kern -.3em{rs}}%
  \kern -.05em\TeX\unskip\kern -.17em\lower -.357ex\hbox{nica}\xspace}
  

\definecolor{verdeguit}{rgb}{0, 0.40, 0}
\providecommand\GuIT{\mbox{\color{verdeguit}\def\I{\textcolor{black}{I}}%
  \fontfamily{lmr}\fontseries{m}\fontshape{sc}\selectfont
g\raisebox{-0.715ex}{\kern-0.26em u}\kern-0.13em\I\kern-0.14em t}\xspace}


\makeatletter
\AfterEndPreamble{%
\DeclareRobustCommand{\TeX}{T\kern-.1667em\lower.5ex\hbox{E}\kern-.125emX\@\xspace}
\DeclareRobustCommand{\LaTeX}{L\kern-.36em%
        {\sbox\z@ T%
         \vbox to\ht\z@{\hbox{\check@mathfonts
                              \fontsize\sf@size\z@
                              \math@fontsfalse\selectfont
                              A}%
                        \vss}%
        }%
        \kern-.15em%
        \TeX}}%
\makeatother

\DeclareRobustCommand*\TeXLive{\TeX\ Live\xspace}
\DeclareRobustCommand*\MiKTeX{MiK\TeX}
\DeclareRobustCommand*\MacTeX{Mac\TeX}
\DeclareRobustCommand*\pdfLaTeX{pdf\/\LaTeX}
\DeclareRobustCommand*\LuaLaTeX{Lua\LaTeX}
\DeclareRobustCommand*\XeLaTeX{X\ifdim\fontdimen1\font=0pt\kern-0.15em\fi
\lower.5ex\hbox{\rotatebox[origin=c]{180}{E}}%
\ifdim\fontdimen1\font=0pt\kern-0.15em\else\kern-0.275em\fi
\LaTeX}
\DeclareRobustCommand*\LaTeXe{\LaTeX\kern-0,25em\relax2\raisebox{-0.5ex}{$\epsilon$}\xspace}
\DeclareRobustCommand*\TikZ{Ti\emph{k}Z\xspace}
\DeclareRobustCommand*\TUGboat{\textsl{TUG\-boat}\xspace}

\def\hz{\hskip0pt}

\makeatletter
\newlength\Wboxu \newlength\Wboxd

% Caution!
%
% This is the latest version of the Esempio (Example) environment
% It differs from the previous ones because it accepts an optional
% first argument asterisk; if the asterisk is not specified, the
% environment produces the code and the typeset result side by side.
% If the asterisk is specified, the code is typeset first, and its typeset
% result is shown below the code.
% Very handy when the typeset result cannot be shrunk too much and/or
% when the code is really lengthy possibly with lines that are quite long.
% With reasonably short codes and lines that can be folded, the code font
% size can be specified even with a fractional size; obviously, the
% default value is \normalsize, but, if necessary, it can be specified
% with something such as [\setfontsize{8,25}] (if the unit of measure is
% not specified, pt is assumed; otherwise it is possible to specify
% something such as 2.33mm).
% When the asterisk is NOT specified, the \textwidth fraction for the
% code may be specified: default is (0.40); the remaining fraction minus
% \columnsep is used for the code typeset result.
% For some reasons the optional code is not so optional, although the
% argument descriptor is D()(0.40); it is not a burden to specify it
% every time:
%
% Warning!
% The \begin and \end statements must be on a line by themselves:
%
% Correct:
% \begin{Esempio}*[...](...)
% code
% \end{Esempio}
%
% Wrong:
% \begin{Esempio}*[...](...)
% code\end{Esempio}
%
% The code end-of-line characters are part of the code to be saved
% and reused

\DeclareDocumentEnvironment{Esempio}{ s O{\normalsize} D(){0.40} }%
{%
  \par%\addvspace{3.0ex plus 0.8ex minus 0.5ex}\vskip -\parskip
  \Wboxu=#3\textwidth
  \Wboxd=\dimexpr\linewidth-\columnsep-\Wboxu\relax
  \VerbatimOut{\jobname-temp.tex}%
}{%
  \endVerbatimOut
  \begin{minipage}{\linewidth}%
  \IfBooleanTF{#1}{\begin{minipage}{\linewidth}}{\begin{minipage}{\Wboxu}}%
  #2\relax
  \VerbatimInput{\jobname-temp.tex}
  \end{minipage}%
  \IfBooleanTF{#1}{\par\bigskip}{\hfill}%
  \IfBooleanTF{#1}{\begin{minipage}{\linewidth}}{\begin{minipage}{\Wboxd}}%
  \raggedleft
  \input{\jobname-temp}
  \end{minipage}
  \end{minipage}\par
}

\makeatother

\providecommand\setfontsize{}
\RenewDocumentCommand\setfontsize{m O{1.2}}{%
\fontsize{#1}{\fpeval{#2*#1}}\selectfont}

\NewDocumentEnvironment{ttsintassi}{O{}}{\begin{lrbox}{0}
\minipage{\dimexpr\linewidth-2\fboxrule-2\fboxsep}\ttfamily#1\obeylines}%
{\endminipage\end{lrbox}\center\fbox{\box0}\endcenter}
\let\ttsyntax\ttsintassi \let\endttsyntax\endttsintassi

\newcommand\heart[3]{%
\edef\X{\fpeval{#1*16*(sind(#2)^3)}}
\edef\Y{\fpeval{#1*(13*cosd(#2) - 5*cosd(2*#2) 
  - 2*cosd(3*#2) -cosd(4*#2)+2.4)}}
\CopyVect\X,\Y to#3}
\let\cuore\heart

\begin{document}\errorcontextlines=100

\begin{titlepage}
\thispagestyle{empty}
\centering
\textsc{\large Claudio Beccari}\\[2ex]
\texttt{claudio dot beccari at gmail dot com}

\vspace{\stretch{2}}

{\LARGE\scshape The \pack{euclideangeometry} package\\
{\large user manual}\par}

\vspace{\baselineskip}


\GetFileInfo{euclideangeometry.sty}
Version \fileversion\ of \filedate

\vspace*{\stretch{5}}
\end{titlepage}

 \begin{abstract}
 The \pack{euclideangeometry} package further extends the functionalities 
 of the \pack{curve2e} package, which, on turn, is an extension of the 
 \pack{pict2e} package for the standard \env{picture} environment as 
 defined in the \LaTeX\ kernel source file.

 The \pack{curve2e} package was upgraded in 2020 and again in 2023; some 
 material of this package, might have been included in the former pict2e 
 one, but it is so specific, that we preferred defining a standalone one; 
 this package takes care of requesting the packages it depends from.

 The purpose is to provide the tools to draw most of the geometrical
 constructions that a high school teacher or bachelor degree professor
 might need in order to teach (plane) geometry. The connection to Euclide 
 depends on the fact that in its times calculations were made with ruler, 
 compass, and, apparently, also with  the ellipsograph.

 The user of this package has available all the machinery provided by
 the \pack{pict2e} and \pack{curve2e} packages, in order to define new 
 functionalities and build macros that draw the necessary lines, circles, 
 and other such objects, as they would have done in the old times. 
 Actually just one macro is defined in this package to solve a linear 
 system of equations
 \end{abstract}
 
 \tableofcontents


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \section*{Warning}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
The \pack{euclideangeometry} package requires the advanced functionalities of the \LaTeX\!3 (L3) language; if such functionalities are not available for any reason (incomplete/basic installation of the \TeX system; legacy installation of the \TeX system; the \TeX system has not been updated; \dots) input of this package is stopped, the whole job is aborted, and a visible message is issued. 

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \section{Introduction}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 The \pack{picture} environment has been available since the very 
 beginning
 of \LaTeX in 1985. At that time it was really a simple environment
 that allowed to draw very simple line graphics with many limitations.
 When \LaTeX was upgraded from \LaTeX\!2.09 to \LaTeXe in 1994, Leslie
 Lamport announced an upgrade that eventually became available in 2003
 with package \pack{pict2e}; in 2006 I wrote the first version of the 
 \pack{curve2e} package  that added many more functionalities; both 
 packages were upgraded during these years; and now line graphics with 
 the \env{picture} environment can perform pretty well. The package 
 \pack{euclideangeometry} adds even more specific functionalities in order 
 to produce geometric drawings as they were possible in the old times, 
 when calculus and analytic geometry were not available.
 
 In these years other drawing programs were made available to the \TeX 
 community; \pack{PSTricks} and \pack{TikZ} are the most known ones, but 
 there are other less known packages, that perform very well; among the 
 latter I would like to mention \pack{xpicture}, that relies on 
 \pack{pict2e} and \pack{curve2e}, but extends the functionalities with a 
 very smart handling of coordinate systems, that allow to draw many line 
 drawings suitable for teaching geometry in high schools and introductory 
 courses in the university bachelor degree programs. It is worth 
 mentioning that an extension of \pack{TikZ}, called \pack{tkz-euclide}, 
 is also available in a complete and updated \TeX system installation; at 
 the moment its documentation needs some refinements, at least to 
 consistently use a single language, without switching from English 
 to French and viceversa. It aims at the same readership, but it allows 
 to do many more geometrical constructions, than \pack{euclideangeometry}. 
 The real difference is that \pack{euclideangemetry} may be easily 
 expanded without the need of knowing the complex machinery and coding  
 of the \pack{tkz-euclide} underlaying \pack{TikZ} package.
 
 This package \pack{euclideangeomery} apparently follows the same
 path of \pack{xpicture}, but it avoids defining a new user language
 interface; rather it builds new macros by using the same philosophy of
 the recent \pack{curve2e} package.
 
 It is worth mentioning that now \pack{curve2e} accepts coordinates in 
 both cartesian and  polar form; it allows to identify specific points of 
 the drawing with macros, so the same macro can be used over and over 
 again to address the same point. The package can draw lines, vectors, 
 arcs with no arrow tips, or with one arrow tip, or with arrow tips at 
 both ends, arcs included. The macros for drawing polylines, polygons, 
 circles, generic curves (by means of Bézier cubic or quadratic splines) 
 are already available; such facilities are documented and exemplified
 in the user manual of the \pack{curve2e} package. 

 In what follows there will be several figures drawn with this package;
 in the background there is a red grid where the meshes are
 10\,\cs{unitlenth} apart in both directions; they should help to
 understand the position of the various drawings on the picture canvas.
 This grid is useful also to the end user, while s/he is working on a 
 particular drawing, but when the drawing is finished, the user can 
 delete the grid command or comment out that line of code.
 For what regards the commands used to render the images, their 
 \emph{codes} can be found in the documented code file 
 \pack{euclideangeometry.pdf}.
 
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \section{Installing \pack{euclideangeometry}}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 You are not supposed to manually install package \pack{euclideangeometry}.
 In facts you have to work with a complete and updated/upgraded \TeX 
 installation, otherwise this package won't work; this means that
 you have done your updating after 2020-01-18. And this package is already
 present in any modern updated complete installation of the \TeX system.
 If \pack{curve2e} has a date earlier then 2020-01-018, the \pack{curve2e}
 itself  will load \pack{curve2ev161}, an older version, and this package 
 \pack{euclideangeomentry} will abort its own loading, besides
 aborting the whole job.
 
 We remember the package dependencies; the primary dependence is package
 \pack{curve2e} with a version date more recent or equal to 2020-01-18. 
 On turn \pack{curve2e} requires packages \pack{xparse} and 
 \pack{xfp}\footnote{Most functionalities of \pack{xfp} are already 
 included into the \LaTeXe kernel, but this package uses also some 
 functionalities that have not made their way to the kernel.}; 
 missing these two package, it loads its own previous version, that does 
 not use such packages, but their absence forbids it working, so that, 
 after a very visible error message, it directly aborts. 
 It also depends  on \pack{etoolbox}. The chain of dependencies of the 
 above first level packages may be controlled directly on those packages 
 documentation 

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \section{Loading \pack{euclideangeometry}}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 If you want to use the \pack{euclideangeometry} package, we suggest you 
 load it with the following command:
\begin{flushleft}\obeylines
\cs{usepackage}\oarg{options}\Marg{euclideangeomery}
\end{flushleft}
 The package will take care of managing the possible \meta{options}
 and to call \pack{curve2e} with such specified options; on turn
 \pack{curve2e} calls \pack{pict2e} passing on the \meta{options}; such
 \meta{options} are only those usable by \pack{pict2e} because neither
 \pack{curve2e} nor \pack{euclideangeometry} use any option. If the
 user is invoking \pack{euclideangeometry}, it is certain s/he does
 not want to use the modern extended  picture environment, not the native
 one; therefore the only meaningful possible options are
 \opt{latex} and \opt{pstricks}; such options influence only the shape
 of the arrow tips; with option \opt{latex} they are triangular,
 while with \opt{pstricks} they have the shape of a stealth
 aircraft. The difference is very small; therefore we imagine that
 even if these options are available, they might never be used.

 Nothing happens if the user forgets this mechanism; therefore if s/he
 loads \pack{curve2e} and/or \pack{pict2e}, before
 \pack{euclideangeomentry} the only problem that might arise is an
 “Option clash” error message; if two of these packages are selected
 with different arrow tips; not impossible, of course, by we deem
 it very unlikely.

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \section{Available commands}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

 The commands available with the first extension \pack{pict2e} to the 
 native \amb{picture} environment, maintain their names but do not 
 maintain the same restrictions; in particular there are the following 
 improvements.
\begin{enumerate}[noitemsep]
 \item Lines and vectors are drawn as usual by \cs{put}ting in place
 their forms, but their inclinations are not limited to a small set of
 slope parameters, originally specified with reciprocally
 prime single digit values not exceeding~6 for lines, and~4 for vectors;
 the length of these sloped objects is still their horizontal component;
 now, the slopes may be described with any signed fractional number not
 exceeding $2^{30}-1$ in absolute value; it still is a limited number of
 slopes, but their combinations are practically countless.
%
\item There is no restriction on the minimum length of lines and vectors.
%
\item Circles and dots can be drawn at any size, not at that dozen
 or so finite sizes that were accepted with the original environment.
%
\item Ovals may be specified the corner curvature; the default
 size of the quarter circles that make up the oval corners may be
 specified; if no specification is given the radius of such corners
 is the maximum that can fit into the oval; in practice it is
 half the shortest value between the oval height and width.

\item The quadratic Bézier splines do not require the specification
 of the number of dots that were used by the native environment to
 draw “arbitrary” curves; now they are drawn with continuous curved
 lines.
\end{enumerate}
 Some new commands were added by \pack{pict2e}
\begin{enumerate}[noitemsep]

\item The third degree (cubic) Bézier splines are sort of new; certainly
 now they are traced with continuous lines; if it is desired, it is
 possible to replace the continuous line with a number of dots so as
 to have a (unevenly) dotted curve. It suffices to specify the number 
 of dots the curve should be made with.

\item\cs{arc} and \cs{arc*} draw an arc or a filled circular sector,
 with their centers at the axes origin; therefore  they need to be put
 in place somewhere else by means of the usual \cs{put} command.

\item The new command \cs{Line} traces a segment from one given point
 to another point; it is very convenient to specify the end points
 instead of the slope the line must have to go from the starting
 to the ending point. The command does not require the \cs{put}
 command to put the segment in place; nevertheless it can be shifted
 somewhere else with \cs{put} if it becomes necessary.

\item The new command \cs{polyline} draws a sequence of connected
 segments that form a piecewise linear “curve”; the way segments are
 joined to one another depend from the “join” specifiers that
 \pack{pict2e} has introduced; they will be described further on.

\item \cs{polygon} and \cs{polygon*} produce closed paths as it would
 be possible when using \cs{polyline} and specifying its last point
 coincident with its first one of that curve. If the asterisk is used 
 the closed path is filled with the default color.
\end{enumerate}

 There were also the low level commands user interfaces to the various 
 drivers; these drivers really exist, but \pack{pict2e}
 knows how to detect the correct language of the necessary driver;
 the user is therefore allowed to pretend to ignore the existence
 of such drivers, and s/he can simply use these low level commands; their 
 names are almost self explanatory.
\begin{enumerate}[noitemsep]
\item \cs{moveto} Sets the start of a line to an initial point.

\item \cs{lineto} traces a segment up to a specified point.

\item \cs{curveto} traces a third degree Bézier spline  up to the third 
 specified point, while using the other two ones as control 
 points.\footnote{If these terms are unfamiliar, please, read the \pack{pict2e} documentation.}

 \item \cs{circlearc} traces a circumference arc from the last line
 point to a specified destination; its center, its angle amplitude, its
 initial point are among the specified arguments, but the reader should
 check on the \pack{pict2e} documentation for the details.

\item[]\mbox{\bfseries Warning!} Notice that these commands produce
 just information to trace lines, but by themselves they do not trace 
 anything; in order to actually trace the curve or do other operations 
 with what has been done after the user finished describing the line to be 
 traced, the following low level commands must be used.

\item A \cs{closepath} is necessary if it is desired to
 join the last position to the initial one. But if the last point
 specified coincides with the very first one, a closed loop is
 effectively already completed.

\item If a \cs{strokepath} command is used the line is drawn.

\item If a \cs{fillpath} command is used, the line loop is filled with
 the current color. Notice, if the described line is not a closed loop,
 this filling command acts as if the line first and last points were
 joined by a straight line.

\end{enumerate}

 While describing a line with the above low level commands, or with
 the previous high level commands, lines and segments join and finish
 as described hereafter; the following commands must be used before 
 actually tracing a specific line made up with several joined lines or 
 curves. Notice that their effect is just visible with lines as thin as 
 1\,pt, and very visible with thicker lines.
\begin{enumerate}[noitemsep]
\item \cs{buttcap} truncates each line with a sharp cut perpendicular
 to the line axis exactly through the line end point (default).

\item \cs{roundcap} adds a semicircle to the very end of each line.

\item \cs{squarecap} adds a half square to the very end of each line.

\item \cs{miterjoin} joins two (generally straight) lines with a miter
 (or mitre) joint; this means that the borders of the line are prolonged
 until they meet; it is very nice when the junction angle is not far away
 from, or is larger than $90^\circ$. Apparently for \pack{pict2e} this
 type of joint is the default.

\item \cs{roundjoin} joins each (generally straight) line with
 an arc on the external part of the bend; it is good in most 
 circumstances.

\item \cs{beveljoin} joins two (generally straight) lines with a miter
 joint truncated with a sharp cut perpendicular to the bisector of the
 lines axes; with acute angles it is better than the miter joint, but
 when angles are very small, even this joint is not adequate.
\end{enumerate}

 Notice that \cs{buttcap} is the default, but in general it might be
 better to declare the \cs{roundcap} for the whole document.

 We do not go further in the description of the new \pack{pict2e}
 modified and new commands; the reader unfamiliar with programmable
 drawing and the \pack{pic2e} extensions can consult that package
 documentation. Actually all commands have been redefined or modified
 by \pack{curve2e} in order to render them at least compatible with
 both the cartesian and polar coordinates. In oder to have a better 
 understanding of these details, see figure~\ref{fig:joins}\footnote{The \cs{polyline} macro has the default join of type bevel; remember to specify a different join type if you want a different one.}.
 
 \begin{figure}[!htb] \centering
 \makebox[\textwidth]{\unitlength=0.009\textwidth
 \begin{picture}(130,50)
 \AutoGrid
 \linethickness{4mm}
 \buttcap\miterjoin
 \put(10,10){\polyline[\miterjoin](0,0)(30,0)(30,30)
 \put(0,-10){\makebox(30,10)[b]{\cs{buttcap},\cs{miterjoin}}}}
 \roundcap\roundjoin
 \put(50,10){\polyline[\roundjoin](0,0)(30,0)(30,30)
 \put(0,-10){\makebox(30,10)[b]{\cs{roundcap},\cs{roundjoin}}}}
 \squarecap\beveljoin
 \put(90,10){\polyline(0,0)(30,0)(30,30)
 \put(0,-10){\makebox(30,10)[b]{\cs{squarecap},\cs{beveljoin}}}}
 \end{picture}}
 \caption{Different caps and joins}\label{fig:joins}
 \end{figure}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%>>>
\section{\pack{curve2e} extensions}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 Again we do not enter into the details, because the user can read the
 new user manual \file{curve2e-manual.pdf} simply by entering and
 executing the \verb|texdoc curve2e-manual| command into a terminal or 
 command prompt window; this new manual is available with version~2.2.0 
 (or higher) of \pack{curve2e} and it contains the extensions and sample 
 codes for (simple) sample drawings; some examples are not so simple, but 
 show the power of this package upgrade.

 The most important two changes are $(a)$ the choice of different
 coordinates for addressing points on the drawing canvas, and $(b)$
 the possibility of using macros to identify specific points.
 As already mentioned, such changes have been applied also to most,
 if not all\footnote{I assume I have upgraded all such commands; if not,
 please, send me a bug notice; I will acknowledge your contribution.}
 commands defined by \pack{pict2e}.
 
 \pack{curve2e} defines a lot of operations the user can do with
 the point coordinates; this is done by assuming they are complex
 numbers, or vectors, or roto\-amplification operators, and making
 with such entities a lot of actions compatible with their “incarnation".
 For example multiplying a vector by a roto\`amplification operator,
 in spite the fact that internally they are both represented by ordered
 pairs of (generally) fractional numbers, means simply obtaining a new
 vector rotated and scaled with respect to the original one; the point
 addressed by the first vector, becomes another point in a different
 precise position.

 Below you see several examples of usage of such commands; but here space
 will be saved if a short list is made concerning these “complex number”
 operations.
 
 Remember the double nature of such complex numbers:
\[
z = x + \iu y = m\eu^{\iu \phi}
\]
 therefore addition and subtraction are simply done with
\[
z_1 \pm z_2 = x_1 \pm x_2 +\iu (y_1 \pm y_2)
\]
 Multiplications and divisions are simply done with
\begin{align*}
z_1 z_2 &=( m_1 m_2) \eu^{\iu(\phi_1 + \phi_2)} \\
z_1/z_2 &=( m_1/m_2) \eu^{\iu(\phi_1 - \phi_2)}
\end{align*}
 Squares and square roots\footnote{The square root of a complex number 
 has two complex values; here we do not go into the details on how 
 \pack{curve2e} choses which value. In practice, the 
 \pack{curve2e} macros that use square roots, work mostly on scalars to 
 find magnitudes that are always positive.} are simply done with:
\begin{align*}
z^2      &= m^2\eu^{\iu 2\phi}\\
\sqrt{z} &= \sqrt{m}\eu^{\iu\phi/2}
\end{align*}
 The complex conjugate of a complex number is shown with a superscript
 asterisk:
\[\text{if } z= x+\iu y \text{ then } z^\star = x- \iu y\]
 and from these simple formal rules many results can be obtained;
 and therefore several macros have been defined.

 But let us summarise. Here is a short list with a minimum of
 explanation of the commands functionalities introduced by
 \pack{curve2e}. The user notices that many commands rely on
 a delimited argument command syntax; the first arguments can
 generally be introduced with point macros, as well as numerical
 coordinates (no matter if cartesian or polar ones) while
 the output(s) should always be in form of point macro(s). Parentheses
 for delimiting the ordered pairs or the point macros are seldom
 required. On the other side, the variety of multiple optional
 arguments, sometimes requires the use of different delimiters,
 most often than not the signs~\texttt{<~>}, in addition to the
 usual brackets. These syntax functionalities are available with the
 \pack{xparse} and \pack{xfp} packages, that render the language~L3
 very useful and effective.

 Handling of complex numbers is done with the following commands.
 New commands to draw special objects, are also described.
\begin{enumerate}[noitemsep]
%
\item Cartesian and polar coordinates; they are distinguished by
 their separator; cartesian coordinates are the usual comma separated
 pair \meta{$x,y$}; polar coordinates are specified with a colon
 separated pair \meta{$\theta{:}\,\rho$}. In general they are
 specified within parentheses, but some commands require them without
 any parenthesis. In what follows a generic math symbol, such as for
 example $P_1$, is used to indicate a complex number that addresses
 a particular point, irrespective of the chosen coordinate type,
 or a macro  defined to contain those coordinates.

\item The complex number/vector operations already available with
 \pack{curve2e} are the following; we specify “macro” because in general
 macros are used, instead of explicit numerical values, but for input
 vector macros it is possible to use the comma or colon separated ordered
 pair; “versor” means “unit vector”; angles are always expressed in
 degrees; output quantities are everything that follows the key word
 \texttt{to}; output quantities are always supposed to be in the form
 of control sequences.
\begin{itemize}\setfontsize{9.5}
\item \cs{MakeVectorFrom}\meta{number,number}\texttt{to}\meta{vector macro}
\item \cs{CopyVect}\meta{vector macro} \texttt{to}\meta{vector macro}
\item \cs{ModOfVect}\meta{vector macro} \texttt{to}\meta{modulus macro}
\item \cs{DirOfVect}\meta{vector macro} \texttt{to}\meta{versor macro}
\item \cs{ModAndDirOfVect}\meta{vector macro} \texttt{to}\meta{modulus macro} \texttt{and}\meta{versor macro}
\item \cs{ModAndAngleOfVect}\meta{vector macro} \texttt{to}\meta{modulus macro} \texttt{and}\meta{angle macro}
\item {\setfontsize{8.75}\cs{DistanceAndDirOfVect}\meta{$P_1$}
    \texttt{minus}\meta{$P_2$} \texttt{to}\meta{distance macro}
    \texttt{and}\meta{versor macro}}
\item \cs{XpartOfVect}\meta{vector macro} \texttt{to}\meta{numerical macro}
\item \cs{YpartOfVect}\meta{vector macro} \texttt{to}\meta{numerical macro}
\item \cs{DirFromAngle}\meta{angle macro} \texttt{to}\meta{versor macro}
\item \cs{ArgOfVect}\meta{vector macro} \texttt{to}\meta{angle macro}
\item \cs{ScaleVect}\meta{vector macro} \texttt{by}\meta{scale factor}
    \texttt{to}\meta{vector macro}
\item \cs{ConjVect}\meta{vector macro} \texttt{to}\meta{conjugate vector macro}
\item \cs{SubVect}\meta{subtrahend vector} \texttt{from}\meta{minuend vector} \texttt{to}\meta{vector macro}
\item \cs{AddVect}\meta{1st vector} \texttt{and}\meta{2nd vector} \texttt{to}\meta{vector macro}
\item \cs{Multvect}\marg{1st vector}\meta{$\star$}\marg{2nd vector}\meta{$
    \star$}\meta{output vector macro}\newline the asterisks are optional;
    either one changes the \meta{2nd vector} into its complex conjugate
\item \cs{MultVect}\meta{1st vector}\meta{$\star$}\meta{2nd vector}
    \texttt{to}\meta{vector macro}\newline discouraged; maintained for backward compatibility; the only optional asterisk changes the \meta{2nd vector} into its complex conjugate
\item \cs{Divvect}\marg{dividend vector}\marg{divisor vector}\marg{output
    vector macro}
\item \cs{DivVect}\meta{dividend vector} \texttt{by}\meta{divisor vector}
    \texttt{to}\meta{vector macro}\newline maintained for backwards
    compatibility.
\end{itemize}

\item A new command \cs{segment}\parg{$P_1$}\parg{$P_2$} draws a line that
 joins the specified points.

\item Command \cs{Dashline}\parg{$P_1$}\parg{$P_2$}\marg{dash and gap length}
 draws a dashed line between the specified points; the
 \meta{dash length} is specified as a coefficient of
 \cs{unitlenth} so it is proportioned to the diagram scale. The gap
 between dashes is just as wide as the dashes; they are recomputed by
 the command in order to slightly adjust the \meta{dash and gap length} so
 that the line starts at point $P_1$ with a dash, and ends at $P_2$
 again with a dash.

\item Command \cs{Dotline}\parg{$P_1$}\parg{$P_2$}\marg{gap}\oarg{diameter}
 traces a dotted line between the specified points with dots \meta{gap}
 units apart, starting and ending with a dot at the specified points.
 Optionally the absolute diameter of the dots may be specified: a
 diameter of 1\,pt (default) is visible, but it might be too small;
 a diameter of 1\,mm is really very black, and may be too large; if
 the diameter is specified without dimensions they are assumed by
 default to be typographic points.

\item Command \cs{polyline}, \cs{polygon} and \cs{polygon*} are redefined
 to accept both coordinate kinds.

\item Commands \cs{VECTOR}\parg{$P_1$}\parg{$P_2$} and \cs{VVECTOR}, with the same syntax, draw vectors with one arrow tip at the end, or arrow tips at both ends respectively.

\item New commands \cs{Arc}\parg{center}\parg{start}\marg{angle} and,
 with the same syntax, \cs{VectorArc} and \cs{VectorARC} draw 
 arcs with the specified \meta{center},
 starting at point \meta{start}, with an aperture of \meta{angle}
 degrees (not radians). \cs{Arc} draws the arc without arrow tips;
 \cs{VectorArc} draws the arc with one arrow tip at the end point;
 \cs{VectorARC} draws an arc with arrow tips at both ends. \cs{VVectorArc} is an alias of \cs{VectorARC}.

\item Command \cs{multiput} has been redefined to accept optional
 arguments, besides the use of coordinates of both kinds. The new syntax
 is the following:
\begin{ttsyntax}[\setfontsize{10.5}]
\cs{multiput}\oarg{shift}\parg{origin}\parg{step}\marg{number}\marg{object}\oarg{handler}
\end{ttsyntax}
 where, if you neglect the first and the last (optional) arguments,
 you have the original syntax; the \meta{origin} point is where the 
 first \meta{object} is placed; \meta{step} is the displacement of a 
 new \meta{object} relative to the previous one; \meta{number} is the
 total number of \meta{object}s put in place by the command; it is 
 possible to specify the number trough an integer expression computed 
 with the \cs{inteval} function of the L3~language, accessed through 
 the \pack{xfp} package functionalities  already included into the 
 \LaTeX kernel. The new features are \meta{shift}, that is used to 
 displace the whole drawing somewhere else (in case some fine tuning is 
 required), and \meta{handler}; the latter is a powerful means to control 
 both the object to be set in place and its position; further on there 
 will be examples that show that the object can be put not only on 
 straight paths, but also un other curves, including parabolas, circles, 
 and other shapes.

\item Another version of repetitive commands \cs{xmultiput} is very
 similar to \cs{multiput} but the iterations are controlled in a
 different way so that it is possible also to draw continuous
 curves describing analytical functions even with parametric
 equations. Further on there will be some examples.

\item The \pack{xfp} package  is preloaded because not all functionalities have been made available in the \LaTeX\ kernel; among such functionalities  two two are very important, i.e. the L3 “functions”, \cs{fpeval} and \cs{inteval};  the latter executes expressions on integer numbers containing the usual
 operators \texttt{+, -, *, /}; the division quotient is rounded to the
 nearest (positive or negative) integer. The former operates with real
 fractional numbers and, in addition to the usual arithmetical operators 
 as \cs{inteval}, it can use many mathematical functions, from square 
 roots, to exponentials, logarithms, trigonometric and hyperbolic direct 
 and inverse functions\footnote{The implementation of inverse hyperbolic
 functions at the moment is on the L3~Team “to do” list.}, plus other 
 ones. Normally fractional numbers are operated on decimal strings, with 
 16 fractional places, and 14 integer places but the L3~functions accept 
 also  scientific notation. The user can specify truncation or rounding to 
 a specified number of digits. Such integer and fractional mathematical 
 operations are already integrated in most computations performed by 
 \pack{curve2e}.

\item \pack{curve2e} provides three more L3 functions: \cs{fptest}, \cs{fpwhiledo}, and  \cs{fpdowhile} with the following syntax:
\begin{ttsyntax}
\cs{fptest}\marg{test}\marg{true}\marg{false}
\cs{fpdowhile}\marg{test}\marg{actions}
\cs{fowhiledo}\marg{test}\marg{actions}
\end{ttsyntax}
 For all these macros the \meta{test} is a logical L3~expression; its 
 operands are logical constants, logical values, logical numeric 
 comparisons; its operators are the typical \texttt{||}, \texttt{\&\&}, 
 and \texttt{!}, respectively for OR, AND, and NOT. The logical numerical 
 comparisons are mathematical constants or expressions connected with 
 relation operators, such as \texttt{>, =, <}; such operators may be 
 negated with the NOT operator; therefore, for example, \texttt{!>} means 
 “not greater than”, therefore “lower or equal to”; such operators may be 
 coupled, for example \texttt{>=} makes a valid comparison and it is equal 
 to \texttt{!<}. 

\item The above tests are very useful to control both \cs{fptest} and
 \cs{fpdowhile} and \cs{fpwhiledo}. The logical \meta{test} result lets 
 \cs{fptest} execute only the \meta{true} or the \meta{false} code. 
 Before using \cs{fpdowhile} or \cs{fpwhiledo}  the \meta{test} expression 
 must be initialised to be \texttt{true}; the \meta{actions} should 
 contain some code to be iteratively executed, but they must contain some 
 assignments, typically a change in an iteration counter, such that 
 eventually the \meta{test} logical expression becomes \texttt{false}. 
 Lacking this assignments, the loop continues to infinity, or better, 
 until a fatal error message is issued that informs that the program 
 working memory is exhausted.
 
 \item
 The difference between \cs{fpdowhile} and \cs{fpwhiledo} is the order 
 in which the \meta{test} and the first\meta{action} are executed; in 
 facts \cs{fpdowhile} first does the \meta{action} then the \meta{test}, 
 while  \cs{fpwhiledo} first executes the \meta{test} then the 
 \meta{action}. 
 Since the modification  of the test logical value is done by the commands 
 contained in the \meta{actions} this switching of the \meta{test} and 
 \meta{action} produces different results. By adjusting the \meta{test} it 
 is possible to get the same results, but the expressiveness of the 
 \meta{test} may be easier to understand in one way rather than the other.
 Some of the examples show such different \meta{test} syntaxes.

\item Such new commands are already used to code the \cs{multiput} and
 \cs{xmultiput} commands, but they are available also to the user who can
 operate in a very advanced way; further on, some examples will show
 certain advanced drawings.

\item General curves can be drawn by \pack{pic2e} command \cs{curve}
 that is sort of difficult to use, because the user has to specify
 also the control points of the third order Bézier splines. Some other
 new commands are available with \pack{curve2e}, that are supposed
 to be easier to use; they are described in the following items.

\item The new command \cs{Curve} joins a sequence of third order
 splines by simply specifying the node-direction coordinates; i.e. at the
 junction of two consecutive splines, in an interpolation node the
 final previous spline tangent has the same direction as that 
 at the second spline first node; if a change of direction is required, an
 optional new direction can be specified. Therefore this triplet of
 information has the following syntax:
\begin{center}
 \parg{node}\aarg{direction}\oarg{new direction}
\end{center}
 Evidently the \meta{new direction} is specified only for the nodes
 that correspond to a cusp. A variation of the command arguments is
 available by optionally specifying the “looseness” of the curve:
\begin{center}
\parg{node}\aarg{direction\texttt{;}start\texttt{,}end}\oarg{\dots}
\end{center}
 where \meta{start} is the spline starting “looseness” and \meta{end}
 is the spline ending one. These (generally different) values
 are an index of how far the control point is from the adjacent node.
 With this functionality the user has a very good control on the curve
 shape and curvature. The optional new direction at a cusp point has the 
 sane extended syntax

\item A similar command \cs{Qurve} works almost the same way, but it
 traces a quadratic Bézier spline; this one is specified only with two
 nodes an a single control point, therefore is less configurable than
 cubic splines; the same final line may require several quadratic splines
 when just a single cubic spline might do the same job. Notice also that
 quadratic splines are just parabolic arcs, therefore without inflection 
 points, while a cubic spline can have one inflexion point. 

\item A further advanced variation is obtained with the new
 \cs{CurveBetween} command that creates a single cubic spline between two
 given points with the following syntax:
\begin{flushleft}
\cs{CurveBetween}\meta{node1} \texttt{And}\meta{node2} \texttt{WithDirs}\meta{dir1}
    \texttt{And}\meta{dir2}
\end{flushleft}

\item A similar variant command is defined with the following syntax:
\begin{flushleft}\ttfamily
 \cs{CbezierBetween}\meta{node1} And\meta{node2} WithDirs\meta{dir1}
    And\meta{dir2}\\ 
\qquad UsingDists\meta{dist1} And\meta{dist2}
\end{flushleft}
 Usage examples are shown in section~\ref{sec:examples}
\end{enumerate}


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\section{ Euclidean geometry commands}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%%% In questa sezione ci vorrebbero esempi per ogni singolocomando!!!

 With the already large available power of \pack{curve2e} there was a push
 towards specialised applications; the first of which was, evidently, 
 geometry;  that kind of geometry that was used in the ancient times when
 mathematicians did not have available the sophisticated means they
 have today; they did not even have a positional numerical notation, that
 arrived in the “western world” we are familiar with, just by
 the XI-XII century; before replacing the roman numbering system, another
 couple of centuries passed by; real numbers with the notation we use
 today with a decimal separator, had to wait till the XVI century (at
 least); many things that naw are taught in elementary school were
 still a sort of magic until the end of XVIII century.

 Even a simple algebraic second degree equation was a problem.
 In facts the Renaissance was the artistic period when the classical
 proportions were brought back to the artists who could not solve the
 simple equation where a segment of unit length is divided in two
 unequal parts $x$  and $1-x$ such that the following proportion exists
 among the various parts and the whole segment:
\[
\frac{x}{1} = \frac{1-x}{x} \Longrightarrow x = \frac{1}{x} - 1
\]
 today we cam solve the problem by manipulating that simple proportion
 to get
\[
 x^2 + x -1 = 0
\]
 and we know that the equation has two solution of opposite signs, and 
 that their magnitudes are the reciprocal of one another. Since we are
 interested in their magnitudes, we adapt the solutions in the form
\begin{equation}
 x_{1,2} = \frac{\sqrt{5} \pm 1}{2}= \sqrt{1+0.5^2}\pm 0.5 \Longrightarrow
\begin{cases}x_1=1.618\ldots\\x_2=0.618\ldots \end{cases}\label{equ:aureo}
\end{equation}
 The larger number is called the \emph{golden number} and the smaller
 one the \emph{golden section}. 

 Luca Pacioli, by the turn of centuries XV–XVI, was the tutor of
 Guidu\-baldo, the son and heir of Federico di Montefeltro, Duke of
 Urbino\footnote{If you never visited this Renaissance city and its Ducal
 Palace, consider visiting it; it is one of the many UNESCO Heritage
 places.}; he wrote the famous book \emph{De Diuina Proportione} that
 contained also the theory of the golden section accompanied by beautiful
 drawings of many Platonic solids and other non convex ones, drawn by
 Leonardo da Vinci. Everything was executed with perfect etchings, even
 the construction of the golden section; in its basic form\footnote{The 
 third  formula in equation~\eqref{equ:aureo} is written in such a way as 
 to explain the graphical construction in figure~\ref{fig:aureo}.} it is
 reproduced in figure~\ref{fig:aureo}. 
\begin{figure}
\begin{Esempio}[\setfontsize{7}](0.40)
\unitlength=0.005\linewidth
\begin{picture}(170,140)(0,-70)
\AutoGrid
\VECTOR(0,0)(170,0)
\Pbox(170,0)[t]{x}[0]
\Pbox(100,0)[t]{\mathrm{1}}[2]
\Pbox(0,0)[r]{O}[2]
\Arc(100,0)(50,0){-90}
\segment(100,0)(100,70)
\segment(0,0)(100,50)
\Pbox(50,0)[tr]{\mathrm{0.5}}[2]
\ModAndAngleOfVect100,50 to\M and\A 
\Arc(0,0)(\M,0){\A}\Pbox(\M,0)[bl]{C}[2]
\Arc(\M,0)(\M,-50){90}
\Arc(\M,0)(\M,-50){-90}
\Pbox(\fpeval{\M-50},0)[b]{\mathit{x_2}}[3]
\Pbox(\fpeval{\M+50},0)[b]{\mathit{x_1}}[3]
\put(\M,0){\Vector(-70:50)}
\Pbox(120,-25)[bl]{\mathit{r}=\mathrm{0.5}}[0]
\thicklines
\segment(0,0)(100,0)
\end{picture}
\end{Esempio}
\caption{The golden section $x_2$ and the golden number $x_1$}\label{fig:aureo}
\end{figure}

 By the way figure~\ref{fig:aureo} shows also the code that is used
 for the drawing done completely with the facilities available just with \pack{curve2e}. It is also a usage example of several commands. 

 Illiteracy was very widespread; books were expensive and were
 common just in the wealthy people mansions.

 Mathematicians in the classical times B.C. up to the artists in the
 Renaissance, had no other means but to use geometrical constructions with
 ruler and compass. Even today in schools where calculus is not yet
 taught as a normal subject, possibly not in certain high school degree
 courses, but certainly not in elementary and junior high schools, the
 instructors have to recourse to geometrical constructions. Sometimes, as
 in Italy, access to public universities is open with no restrictions to
 all students with a high school diploma for degree courses that are 
 more vocational than cultural. Therefore such students in some university 
 degree courses have to frequent upgrading courses in order to master some 
 more mathematics compared to what they studied during their basic 
 education.

 The instructors nowadays very often prepare some booklets with their
 lessons; such documents, especially in electronic form, are a good help
 for many students. And \LaTeX is used to write such documents.
 Therefore this extension module is mostly dedicated to such instructors.

 The contents of this module is not exhaustive; it just shows a way to
 use the \pack{curve2e} facilities to extend it to be suited for the
 kind of geometry they teach.
 
 Here we describe the new commands provided by this package; then in
 section~\ref{sec:examples} we show their usage by means of examples.

\begin{enumerate}[noitemsep]
%
\item Command \cs{polyvector} is simple extension of the \cs{polyline} command introduced by \pack{pict2e}: its syntax is identical to that of \cs{polyline}; it draws a polyline with an arrow tip at the last segment; it turns out to be very handy while drawing block diagrams. See figure~\ref{fig:vectors}.
%
\item Command \cs{IntersectionOfLines} is a fundamental one; its syntax is
 the following:
\begin{ttsyntax}\setfontsize{9.5}%
\cs{IntersecionOfLines}\parg{point1}\parg{dir1} and\parg{point2}\parg{dir2} to\meta{vector}
\end{ttsyntax}
 were each line is identified with its \meta{point} and its \emph{direction}; \meta{vector} is the complex number that identifies the coordinates of the intersection point; the intersection coordinates go to the output \meta{vector}.

\begin{Esempio}[\normalsize](0.40)
\unitlength=0.01\linewidth
\begin{picture}(100,30)
\AutoGrid
\Dashline(0,0)(100,30){2}
\Dashline(100,0)(0,30){2}
 \IntersectionOfLines%
  (0,0)(10,3)and%
  (100,0)(-10,3)to\P 
\Pbox(\P)[b]{P}[3]
\end{picture}
\end{Esempio}
%
\item A second command\cs{IntersectionOfSegments} does almost the same
 work, but the coordinates of a segment end points define also its 
 direction, which is the argument of the difference of the terminal nodes 
 of each segment; the syntax therefore is the following:
\begin{ttsyntax}
\cs{IntersectionOfSegments}\parg{point11}\parg{point12} 
\qquad and\parg{point21}\parg{point22}to\meta{intersection point}
\end{ttsyntax}
 Again the intersection point coordinates go to the output \meta{intersection point}.
 The first segment is between points 11 and 12, and, similarly, the second
 segment is between points 21 and 22.
 \begin{Esempio}[\normalsize](0.40)
\unitlength=0.01\linewidth
\begin{picture}(100,30)
\AutoGrid
\segment(0,0)(100,30)
\segment(0,30)(100,0)
 \IntersectionOfSegments%
  (0,0)(100,30)and%
  (100,0)(0,30)to\P
\Pbox(\P)[b]{P}[3]
\end{picture}
\end{Esempio}
%
\item \label{item:CircleWithCenter}Another “intersection” command is
 \cs{IntersectionsOfLine} to  determine both intersections of a line 
 with a circle. The syntax is:
 \begin{ttsyntax}
\cs{IntersectionsOfLine}\parg{point1}\parg{point2}
\qquad WithCircle\parg{center}\marg{radius}to\meta{int1} and\meta{int2}
\end{ttsyntax}
 where \meta{point1} and \meta{point2} identify a segment joining such 
 points, and therefore a specific line with the segment direction 
 and passing through a given point; the segment should cross the circle;
 this circle is identified with its 
 \meta{center} and \meta{radius}; the intersection points \meta{int1} and 
 \meta{int2} are the coordinates of the intersection points; if the line 
 and circle do not intersect, a warning message is issued, shown in the 
 console and written to the \file{.log} file; the intersection points are 
 assigned the default values \texttt{0,0}, which evidently produce strange 
 results in the output document, so as to remind the user to give a look 
 to the \file{.log} file and to review his/her data.
\begin{Esempio}[\normalsize](0.40)
\unitlength=0.01\linewidth\raggedleft
\begin{picture}(60,40)(-10,0)
\AutoGrid
\def\Radius{20}%
\Circlewithcenter 20,20 radius\Radius
\segment(10,0)(50,40)
\IntersectionsOfLine(10,0)(50,40)%
  WithCircle(20,20)(20)%
  to\Pu and\Pd
\Pbox(\Pu)[b]{P_1}[3]
\Pbox(\Pd)[l]{P_2}[3]
\end{picture}
\end{Esempio}
\medskip
%
\item It is difficult to numerically determine the coordinates of the 
 intersection points of two circles; it becomes easier if one of the 
 intersections is known; to this end, a macro to draw a circle with a 
 given center and passing through a given point is handy:
\begin{ttsyntax}
 \cs{CircleThrough}\meta{point}WithCenter\marg{center}
\end{ttsyntax}
 draws such circumference.\\[1ex]
 \begin{Esempio}[\normalsize](0.40)
 \unitlength=0.01\linewidth\raggedleft
 \begin{picture}(60,40)
 \AutoGrid
 \CopyVect10,15to\P
 \Pbox(\P)[tr]{P}[2]
 \Pbox(30,20)[b]{C}[2]
 \def\Ce{30,20}\relax
 \CircleThrough\P WithCenter\Ce
 \end{picture}
 \end{Esempio}
 \medskip
%
\item With the above macro it becomes easy to draw two circumferences 
 with different centers and passing through the same point; therefore 
 it becomes easy to determine the other intersection point by means of the 
 following macro:
\begin{ttsyntax}
\cs{Segment}\parg{endpoint1}\parg{endpoint2}SymmetricPointOf\meta{p1} 
 to\meta{p2}
\end{ttsyntax}
 The computation is simple, because the second intersection is the 
 symmetrical point \meta{p2} of \meta{p1} with respect to the segment 
 that joins the centers of the given circles intersecting one another 
 in \meta{p1}.
 The following small example displays how to find point $P_2$ symmetrical to $P_1$ with respect to a given line.\\[1ex]
 \begin{Esempio}[\normalsize](0.40)
 \raggedleft\unitlength=0.01\linewidth
 \begin{picture}(60,30)
 \AutoGrid
 \segment(0,0)(60,30)
 \CopyVect40,5to\Pu
 \Segment(0,0)(60,30)%
   SymmetricPointOf\Pu to\Pd
 \Pbox(\Pu)[b]{P_1}[2]
 \Pbox(\Pd)[t]{P_2}[2]
 \end{picture}
 \end{Esempio}
\medskip
%
\item It would be interesting to solve the same problem with help of 
 the following macro relating to right triangles identified with their 
 hypothenuse and one of its legs; the other leg is found by means of this 
 macro:
\begin{ttsyntax}
\cs{LegFromHypothenuse}\meta{length1} AndOtherLeg\meta{length2} 
 to\marg{length3}
\end{ttsyntax}
In facts, the intersection points of two circles define their common 
  chord; this chord and the two circle centers define two isosceles 
  triangles with the same base, the chord; therefore the segment joining 
  the circle centers, coincides with the chord axis and divides each 
  isosceles triangle in two right triangles, where the hypotenuse is one 
  of two radii and the first leg is the distance from the chord middle 
  point, intersection of the chord and the segment joining the circle 
  centers; at this point the distance of the second point intersection 
  from the chord middle point and the coordinates of the second 
  intersection may be easily computed; of course this is a much clumsier
  way to determine the second intersection, but it is useful to solve this 
  right triangle easy problem. See figure~\ref{fig:2circle-intersections} 
  where such right triangle legs are used for several tasks.
%
\item Command \cs{ThreePointCircle} draws a circle that goes through three
 given points; the syntax is the following:
\begin{ttsyntax}
 \cs{ThreePointCircle}\meta{$\star$}\parg{point1}\parg{point2}\parg{point3}
\end{ttsyntax}
 A sub product of this macro is formed by the vector \cs{C} that contains
 the coordinates of the center of the circle, that might be useful even
 if the circle is not drawn; the optional asterisk, if present, does not
 draw the circle, but its center is available. See figure~\ref{fig:circumcenter}, where this construction has been used.
 
\item Alternatively
\begin{ttsyntax}\setfontsize{9.65}%
 \cs{ThreePointCircleCenter}\parg{point1}\parg{point2}\parg{point3}to\meta{center vector}
\end{ttsyntax}
 computes the three point circle center assigning its coordinates to
 \meta{center vector}.
%
\item Command \cs{CircleWithCenter} draws a circle given its center and it
 radius; in facts the syntax is the following:
\begin{ttsyntax}
\cs{CircleWithCenter}\meta{center} Radius\meta{Radius}
\end{ttsyntax}
 This macro does not require the \cs{put} command to put the circle
 in place; it is very handy when the radius value is saved into a macro. %
\item A similar macro \cs{Circlewithcenter} does almost the same; its
 syntax is the following:
\begin{ttsyntax}
\cs{Circlewithcenter}\meta{center} radius\meta{radius}
\end{ttsyntax}
 Apparently these two commands do the same, but, no, they behave
 differently: in the former command the \meta{Radius} is a vector the
 modulus of which is computed and used as the radius; in the latter
 command the \meta{radius} is a scalar and (its magnitude) is directly
 used. See item~\ref{item:CircleWithCenter} of this enumeration where this 
 command was used.

%
\item The command with syntax:
\begin{ttsyntax}
\cs{AxisOf}\meta{point1} and\meta{point2} to \meta{point3} and\meta{point4}
\end{ttsyntax}
 is used to determine the axis of a segment; the given
 segment is specified with its end points \meta{point1} and \meta{point2}
 and the axis is determined by point \meta{point3} and \meta{point4};
 actually \meta{point3} is the middle point of the given segment.\\[1ex]
 \begin{Esempio}[\normalsize](0.40)
 \raggedleft
 \unitlength=0.01\linewidth
 \begin{picture}(50,30)
 \AutoGrid
 \segment(10,0)(40,30)
 \AxisOf 10,0 and 40,30 to\Pu\Pd
 \Dashline(\Pu)(\Pd){1}
 \Pbox(10,0)[br]{P_1}[2]
 \Pbox(40,30)[tl]{P_2}[2]
 \Pbox(\Pu)[tl]{P_3}[2]
 \Pbox(\Pd)[t]{P_4}[2]
 \end{picture}
 \end{Esempio}
\medskip
%
\item These two commands with syntax:
\begin{ttsyntax}
\cs{SegmentCenter}\parg{point1}\parg{point2}to\meta{center}
\cs{MiddlePointOf}\parg{point1}\parg{point2}to\meta{center}
\end{ttsyntax}
 determine just the middle point between two given points. They are
 totally equivalent, aliases to one another; sometimes it is more
 convenient to use a name, sometimes the other; it helps reading the
 code and maintaining it.
%
\item Given a triangle  and a specific vertex, it is possible to determine
 the middle point of the opposite side; it is not very difficult, but it
 is very handy to have all the necessary elements to draw the median line.
 The simple syntax is the following:
\begin{ttsyntax}
\cs{TriangleMedianBase}\meta{vertex} on\meta{base1} and\meta{base2}
\qquad to\meta{base middle point}
\end{ttsyntax}

A similar command \cs{TriangleHeightBase} is used to determine the
 intersection of the height segment from one vertex to the opposite side;
 with triangles that have an obtuse angle, the height base might lay
 externally to one of the bases adjacent to such an angle. The syntax is
 the following
\begin{ttsyntax}
\cs{TriangleHeigthtBase}\meta{vertex} on\meta{base1} and\meta{base2} to\meta{height base}
\end{ttsyntax}

 Similarly there is the \cs{TriangleBisectorBase} macro with
 a similar syntax:
\begin{ttsyntax}
\cs{TriangleBisectorBase}\meta{vertex} on\meta{base1} and\meta{base2}
\qquad to\meta{bisector base}
\end{ttsyntax}
See figure~\ref{fig:MHBlines} that contains all three special lines: the median (M) the height (H) and the bisector (B) lines.%%%%!!!!!!!!!
%
\item A triangle \emph{barycenter} is the point where its median lines
 intersect; command \cs{TriangleBarycenter} determines its coordinates
 with the following syntax.
\begin{ttsyntax}
\cs{TriangleBarycenter}\parg{vertex1}\parg{vertex2}\parg{vertex3} to\meta{barycenter}
\end{ttsyntax}
%
\item A triangle \emph{orthocenter} is the point where its height lines
 intersect; command \cs{TriangleOrthocenter} determines its coordinates
 with the following syntax:
\begin{ttsyntax}
\cs{TriangleOrthocenter}\parg{vertex1}\parg{vertex2}\parg{vertex3} to\meta{orthocenter}
\end{ttsyntax}
%
\item A triangle \emph{incenter} is the point where its bisector lines
 intersect; command \cs{TriangleIncenter} determines its coordinates
 with the following syntax:
\begin{ttsyntax}
\cs{TriangleIncenter}\parg{vertex1}\parg{vertex2}\parg{vertex3} to\meta{incenter}
\end{ttsyntax}
%
\item The distance of a specified point from a given segment or line is
 computed with the following command
\begin{ttsyntax}
\cs{DistanceOfPoint}\meta{point} from\parg{point1}\parg{point2} to\meta{distance}
\end{ttsyntax}
 where \meta{point} specifies the point and \meta{point1} and \meta{point2}
 identify two points on a segment or a line; \meta{distance} is a scalar
 value.
%
\item In a construction that will be examined in section~\ref{sec:examples}
 we need to determine an ellipse axis if the other axis and the focal
 distance are know; actually it solves the relation
\begin{equation}a^2= b^2 +c^2\label{equ:axes-foci}\end{equation}
 that connects such three quantities; $a$ is always the largest of the
 three quantities; therefore the macro tests if the first entry is larger
 than the second one: if is is, it computes a Pytagorean difference,
 otherwise the user should pay attention to use as the first entry the
 smaller among $b$ and $c$, so as to compute a Pytagorean sum. The command
 is the following:
\begin{ttsyntax}
\cs{AxisFromAxisAndFocus}\meta{axis or focus} and\meta{focus or axis} 
\qquad to\meta{other axis or focus}
\end{ttsyntax}
 The word “axis” stands for “semi axis length”; the word “focus" stands
 for “focal semi distance”; actually the macro works equally well with
 full lengths, instead of half lengths; it is important not to mix
 full and half lengths. Such lengths are expressed as factors of
 \cs{unitlength}, not as absolute values. This command is described 
 again when dealing with the specific problem referred to at the 
 beginning of this list item;  the description is going to be more 
 detailed and another macro is added to avoid possible errors.\\[1ex]
\begin{Esempio}[\setfontsize{9.25}](0.40)
\raggedleft\unitlength=0.01\linewidth
\begin{picture}(80,60)(-40,-30)
\AutoGrid
\ellisse{40}{30}
\CopyVect\fpeval{sqrt(700)},0to\Focus
\segment(0,0)(0,30)
\segment(0,0)(\Focus)
\segment(\Focus)(0,30)
\Pbox(0,0)[tr]{O}[2]
\Pbox(\Focus)[t]{F}[2]
\Pbox(0,15)[r]{b}[0pt]
\Pbox(15,0)[t]{c}[0pt]
\Pbox(14,14)[bl]{a}[0pt]
\end{picture}
\end{Esempio}
\medskip
%
\item Given a segment, i.e. the coordinates of its end points, it is
 useful to have a macro that computes its length; at the same time it is
 useful to to compute its direction; this operation is not the same as to
 compute modulus and argument of a vector, but consists in computing such
 quantities from the difference of the vectors pointing to the segment
 end points. Possibly better names should be devised for such macros, for 
 example \cs{DistanceBetweenPoints...} and \cs{AngleOf..} But I could not 
 find anything really more expressive.  These two macros are the 
 following:
\begin{ttsyntax}
\cs{SegmentLength}\parg{point1}\parg{point2} to\meta{length}
\cs{SegmentArg}\parg{point1}\parg{point2} to\meta{angle}
\end{ttsyntax}
 The \meta{angle} is computed in the interval $-180^\circ < \phi \leq
 +180^\circ$; it represents the with respect to the positive real axis of 
 the vector that goes from \meta{point1} to \meta{point2}, therefore the 
 user must pay attention to the order s/he enters the end point 
 coordinates.
%
\item The next command \cs{SymmetricalPointOf} is used to find the
 reflection of a specified point with respect to a fixed point; of course
 the latter is the middle point of the couple, but the unknown to be
 determined is not the center of a segment, but one of its end points.
 The syntax is the following: In a sense this macro completes the \cs{AxisOf} by finding the other extremity of the axis.
\begin{ttsyntax}
\cs{SymmetricalPointOf}\meta{point1} respect\meta{fixed} to\meta{point2}
\end{ttsyntax}
%
\item  Command \cs{RegPolygon} draws a regular polygon inscribed within
 a circle of given radius and center, with a specified number of sides;
 optional arguments allow to  specify color and thickness of the sides,
 or the polygon interior color; this macro operates differently from the 
 one for drawing ellipses, that draws simultaneously an ellipse with
 the border of a color and the interior of another one; with this macro 
 the  user who wants to achieve this effect must superimpose to polygons
 with different settings; but it would not be too difficult to arrange a 
 new  macro or to modify this one in order to get “bicolor” polygons.
 It is not necessary for the purpose of this package, therefore we
 let the user express his/her phantasy by creating other macros. The 
 actual syntax is the following:
\begin{ttsyntax}
\cs{RegPolygon}\meta{$\star$}\parg{center}\marg{radius}\marg{sides}\oarg{angle}\aarg{settings}
\end{ttsyntax}
 The initial optional asterisk specifies if the interior has to be
 coloured; if yes, the \meta{settings} refer to the color of the
 interior; if not, the \meta{settings} refer to the thickness and
 color of the sides; no \meta{settings} imply sides drawn with the
 default line thickness, generally the one corresponding to \cs{thinlines},
 and the default color (generally black) for the sides or the interior.
 By default the first vertex is set to an angle of $0^\circ$ with
 respect to the \meta{center}; the optional \meta{angle} modifies
 this value to what is necessary for a particular polygon. The
 \meta{center} itself is optional, in the sense that if it is not
 specified the center lays in the origin of the \env{picture} axes; if 
 this argument is specified, the polygon center is displaced accordingly.
 The number of sides in theory may be very high, but it is not wise
 to exceed a couple of dozen sides; if the number of sides is too
 high, a polygon (completely contained in an A4 page) may become 
 undistinguishable from a circumference.
 Some examples are shown in figures~\ref{fig:pentagon} 
 and~\ref{fig:filled-pentagon}.
%
\item {\tolerance=3000 Several macros are dedicated to ellipses; their names are spelled
 in Italian, “ellisse”, because the name “ellipse” is already taken by
 other packages; with Italian command names there should be no
 interference with other packages, or the risk is reduced to
 a minimum. The various macros are \cs{ellisse}, \cs{Sellisse},
 \cs{Xellisse}, \cs{XSellisse}, \cs{EllisseConFuoco} \cs{EllisseSteiner};
 the last two control sequence names are aliased with the corresponding
 English ones \cs{EllipseWithFocus} and \cs{SteinerEllipse}. For the
 other four ones it is wise to avoid English names for the reasons
 explained above. After all the Italian  and the English names are very
 similar and are pronounced almost identically.\par}

 {\tolerance=3000 Actually \cs{ellisse} is practically a shorthand for 
 \cs{Sellisse} because some optional arguments are already fixed, but the 
 meaning of \cs{fillstroke} depends on the presence or absence of an 
 initial asterisk; similarly \cs{Xellisse} is a sort of a shorthand for
 \cs{XSellisse}; in facts those commands, that contain  an ‘S’ in their 
 names, can optionally perform also the affine \emph{shear} 
 transformation, while those without the ‘S’ do not execute such 
 transformation. Figure~\ref{fig:shear} displays a normal ellipse  with 
 its bounding rectangle, and the same ellipse to which the shear affine 
 transformation  is applied; the labeled points represent the third order 
 Bézier spline nodes and control points.\par}
\begin{figure}[!htb]
\dimendef\Wmp=2000 \Wmp=\dimexpr(\textwidth-\columnsep)/2\relax
\begin{minipage}{\Wmp}\centering
\unitlength=0.007\linewidth
\begin{picture}(100,70)(-50,-35)
\XSellisse(0,0){50}{25}*
\end{picture}
\end{minipage}
\hfill
\begin{minipage}{\Wmp}\centering
\unitlength=0.007\linewidth
\begin{picture}(100,70)(-50,-35)
\XSellisse(0,0)<20>{50}{25}*
\end{picture}
\end{minipage}
\caption{The effect of shearing an ellipse with its bounding rectangle}\label{fig:shear}
\end{figure}
%
\item The syntax of those six commands are the following:
\begin{ttsyntax}
\cs{Sellisse}\meta{$\star$}\marg{semiaxis-h}\marg{semiaxis-v}\oarg{shear}
\cs{ellisse}\meta{$\star$}\marg{semiaxis-h}\marg{semiaxis-v}
\cs{XSellisse}\meta{$\star$}\parg{center}\oarg{angle}\%
\qquad \aarg{shear}\marg{semiaxis-h}\marg{semiaxis-v}\meta{$\star$}\%
\qquad \oarg{settings1}\oarg{settings2}
\cs{Xellisse}\meta{$\star$}\parg{center}\oarg{angle}\marg{semiaxis-h}\%
\qquad\marg{semiaxis-v}\oarg{settings1}\marg{settings2}
\cs{EllipseWithFocus}\meta{$\star$}\parg{vertex1}\parg{vertex2}\parg{vertex3}\parg{focus}
\cs{SteinerEllipse}\meta{$\star$}\parg{vertex1}\parg{vertex2}\parg{vertex3}\oarg{diameter}
\end{ttsyntax}
 All require the semi axis lengths; the \meta{semiaxis-h} and
 \meta{semiaxis-v} refer to the semi axes before possible rotation by
 \meta{angle} degrees, and do not make assumptions on which axis is the
 larger one. The optional parameter \meta{shear} is the angle in degrees
 by which the vertical coordinate lines are slanted by effect of shearing. 
 If \meta{shear}, that by default equals zero, is not set
 to another value, the asterisks of command \cs{Sellisse} and
 \cs{XSellisse} do not have any effect. Otherwise the asterisk of
 \cs{Sellisse} forces to draw the ellipse bounding box (rectangle before
 shearing, parallelogram after shearing) as shown together with some
 marked special points (the vertices, spline nodes and control points
 of the quarter circle or quarter ellipse Bézier splines) in 
 figure~\ref{fig:shear}.
 For \cs{ellisse} the asterisk implies filling, instead of stroking the
 ellipse contour.
 The \meta{setting}~1 and~2 refer to the color filling and/or border
 color, and contour thickness, as already explained. For the
 \cs{EllipseWithFocus}, the \meta{focus} contains the coordinates
 of one of the two ellipse foci; such coordinates should point to
 some position \emph{inside} the triangle. The \cs{SteinerEllipse}
 requires less data, in the sense that such ellipse is unique; it
 is the ellipse internally tangent to the triangle at its side middle
 points. See detailed examples in the following section.
%
\end{enumerate}


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\section{Examples}\label{sec:examples}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 Here we can show some examples of the advanced \pack{curve2e} commands
 and of what can be done with this \pack{euclideangeometry} extension.

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Straight and curved vectors}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 
 Figure~\ref{fig:vectors} shows some vectors and vector arcs with the
 code used to draw them; some points are described with cartesian
 coordinates and some with polar ones.

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{8.5}](0.45)
\unitlength=0.01\linewidth
\begin{picture}(100,60)
\AutoGrid
\put(0,30){\vector(1,2){10}}
\put(20,30){\Vector(10,20)}
\VECTOR(40,30)(50,50)
\VVECTOR(60,30)(70,60)
\Arc(100,60)(100,40){-90}
\VectorArc(0,0)(0:20){90}
\VectorARC(100,0)(0:80){-90}
\polyvector(30,0)(35,10)(55,20)(60,0)
\end{picture}
\end{Esempio}
\caption{Some vectors and vector arcs}\label{fig:vectors}
\end{figure}


\begin{figure*}[!tb]
\begin{Esempio}*[\setfontsize{10}](0.40)
\centering
\unitlength=0.006\linewidth\begin{picture}(120,90)
%
\RegPolygon(9,20){20}{6}<\linethickness{3pt}\color{red}> 
\RegPolygon(55,20){20}{7}[90]
\RegPolygon(100,20){20}{8}[22.5]<\linethickness{0.5ex}\color{blue}>
%
\put(0,50){%
  \RegPolygon(9,20){20}{3}\RegPolygon(9,20){20}{3}[30]
  \RegPolygon(9,20){20}{3}[60]\RegPolygon(9,20){20}{3}[90]
%
  \RegPolygon*(55,20){20}{4}<\color{green}>
  \RegPolygon(55,20){20}{4}<\linethickness{1ex}>
%
  \RegPolygon*(100,20){20}{4}[45]<\color{orange}>
  \RegPolygon(100,20){20}{4}[45]<\linethickness{1ex}\color{blue}>
}
\end{picture}
\end{Esempio}
\caption{A variety of polygons and their codes}\label{fig:variety-of-polygons}
\end{figure*}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Polygons}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 Figures~\ref{fig:pentagon} and~\ref{fig:filled-pentagon} display
 a normal and a color filled pentagon with their codes.
 Figure~\ref{fig:variety-of-polygons} shows a variety of polygons
 with their codes.

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{10}](0.8)
\unitlength=0.5mm
\begin{picture}(40,32)(-20,-17)
\polyline(90:20)(162:20)(234:20)(306:20)(378:20)(90:20)
\end{picture}
\end{Esempio}
\caption{A normal polygon drawn with \cs{polyline}}
\label{fig:pentagon}
\end{figure}


\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{10}](0.8)
\unitlength=.5mm
\begin{picture}(40,32)(-20,-20)
\color{magenta}
\polygon*(90:20)(162:20)(234:20)(306:20)(378:20)
\end{picture}
\end{Esempio}
\caption{A filled polygon drawn with \cs{polygon}}
\label{fig:filled-pentagon}
\end{figure}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \subsection{Dashed and dotted lines}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 For dashed lines it is mandatory to specify the dash length, that 
 is just as long as the gap between dashes. For dotted lines it is 
 mandatory to specify the dot gap.
 For dotted lines it is also possible to specify the dot size;
 it can be specified with an explicit unit of measure, or, if no unit is
 specified, it is assumed to be “points”. The \cs{Dotline} takes care
 of transforming the implied or the explicit dimension in multiples of
 \cs{unitlength}. Figure~\ref{fig:DashDot} shows some examples with their
 codes.

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{10}](0.45)
\unitlength=0.02\linewidth
\begin{picture}(40,40)
\AutoGrid
\Dashline(0,0)(40,10){4}
\put(0,0){\circle*{1}}
\Dashline(40,10)(0,25){4}
\put(40,10){\circle*{1}}
\Dashline(0,25)(20,40){4}
\put(0,25){\circle*{1}}
\put(20,40){\circle*{1}}
\Dotline(0,0)(40,40){2}[2]
\end{picture}
\end{Esempio}
\caption{Dashed and dotted lines}\label{fig:DashDot}
\end{figure}


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Generic curves}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
With the \cs{Curve} macro it is possible to make line art or filled shapes. The hearts drawn in figure~\ref{fig:hearts} show the same shape, the first just stroked and the second color filled. 

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{9}](0.65)
\unitlength=8mm\relax
\begin{picture}(5,5)
\put(0,0){\framebox(5,5){}}\thicklines\roundcap
\Curve(2.5,0)<0.1,1>(5,3.5)<0,1>%
  (4,5)<-1,0>(2.5,3.5)<-0.01,-1.2>[-0.01,1.2]%
  (1,5)<-1,0>(0,3.5)<0,-1>(2.5,0)<0.1,-1>
\end{picture}
\end{Esempio}

\vspace*{2\baselineskip}

\begin{Esempio}[\setfontsize{9}](0.65)
\unitlength=8mm\relax
\begin{picture}(5,5)
\put(0,0){\framebox(5,5){}}\thicklines\roundcap
\color{orange}\relax
\Curve*(2.5,0)<0.1,1>(5,3.5)<0,1>%
(4,5)<-1,0>(2.5,3.5)<-0.01,-1.2>[-0.01,1.2]%
(1,5)<-1,0>(0,3.5)<0,-1>(2.5,0)<0.1,-1>
\end{picture}
\end{Esempio}
\caption{A stroked and a filled heart shaped contour}
\label{fig:hearts}
\end{figure}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{The \cs{multiput} command}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

 The new \cs{multiput} and \cs{xmultiput} commands are extensions of the 
 original \cs{multiput} macro; both are used to put a number of objects 
 according to a discrete law; but they can produce surprising effects. 
 Figure~\ref{fig:multiput} displays several examples. As it possible 
 to see, the black dots are evenly distributed along the canvas diagonal; 
 the green filled squares are along a sloping down line inclined by 
 $15^\circ$ as specified by the polar coordinates of the \meta{increment}; 
 the blue filled triangles are distributed along a parabola; the red 
 stroked diamonds are distributed along a half sine wave.\enlargethispage*{\baselineskip}

\noindent\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{8}](0.55)
\unitlength=0.01\linewidth
\begin{picture}(100,100)
\AutoGrid
\multiput(0,0)(10,10){11}{\circle*{2}}
\color{blue!70!white}
\multiput(0,0)(10,0){11}{%
\RegPolygon*{2}{3}<\color{blue!70!white}>}%
  [\GetCoord(\R)\X\Y
  \edef\X{\fpeval{\X+10}}
  \edef\Y{\fpeval{(\X/10)**2}}
  \CopyVect\X,\Y to\R]
\multiput(0,0)(10,1){11}{%
\RegPolygon{2}{4}<\color{magenta}>}%
  [\GetCoord(\R)\X\Y
   \edef\X{\fpeval{\X+10}}
   \edef\Y{\fpeval{sind(\X*1.8)*100}}
   \CopyVect\X,\Y to\R]
\multiput(50,50)(-15:5){11}{%
\RegPolygon*{2}{4}[45]<\color{green!60!black}>}
\end{picture}
\end{Esempio}
\caption{Some examples of the \meta{handler} optional argument}
\label{fig:multiput}
\end{figure}

 Another interesting construction is a clock quadrant; this is shown
 in figure~\ref{fig:orologio}

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{9.5}](0.525)
\unitlength=0.0095\linewidth
\begin{picture}(100,100)
\AutoGrid
\put(50,50){\thicklines\circle{100}}
\xmultiput[50,50](60:35)(-30:1){12}%
  {\makebox(0,0){\circle*{2}}}%
    [\MultVect\R by\D to\R]% 
\xmultiput[50,50](60:40)(-30:1){12}%
  {\ArgOfVect\R to\Ang
    \rotatebox{\fpeval{\Ang-90}}%
    {\makebox(0,0)[b]{%
       \Roman{multicnt}}}}%
      [\Multvect{\R}{\D}\R]
\thicklines\put(50,50){\circle*{4}}
\put(50,50){\Vector(37.5:30)}
\put(50,50){\Vector(180:33)}
\end{picture}
\end{Esempio}
\caption{Usage example of the \texttt{\string\xmultiput} command}
\label{fig:orologio}
\end{figure}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \subsection{Drawing mathematical functions}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

 Figure~\ref{fig:iperbole} shows an equilateral hyperbola; since it
 has asymptotes, the drawing must be carefully done avoiding overflows, 
 and parts of drawing out of the \env{picture} area. Nevertheless
 the possibility of describing mathematical functions in terms of L3
 functions (in spite of the same name, they are completely different
 things) makes it possible to exploit the \meta{settings} argument to
 do the job with \cs{xmultiput}.

\begin{figure*}[!tp]
\begin{Esempio}[\setfontsize{9}](0.5)
\unitlength=0.008\linewidth
\begin{picture}(100,100)
\AutoGrid
\VECTOR(0,0)(100,0)\Pbox(100,0)[tr]{x}[0]
\VECTOR(0,0)(0,100)\Pbox(0,100)[tr]{y}[0]
\Pbox(0,0)[r]{O}[3pt]
\thicklines
\moveto(10,100)\countdef\I=2560 \I=11
\xmultiput(0,0)(1,0){101}%
  {\lineto(\I,\fpeval{1000/\I})}%
  [\advance\I by1 \value{multicnt}=\I]
\strokepath
\end{picture}
\end{Esempio}
\caption{An equilateral hyperbola drawn with a thinly sampled piecewise
 continuous line}\label{fig:iperbole}
\end{figure*}

 A more complicated drawing can be done by expressing the function to draw
 with parametric equations; the idea is to code the math formulas
\[\begin{cases}
x(t) = f_1(t)\\
y(t) = f_2(t)
\end{cases}\]
because it is easy to code the $x$ and the $y$ component and use the
 \cs{fpdowhile} command to trace the curve with a piecewise continuous
 line; actually a continuous line with a piecewise continuous derivative;
 it is important to sample the curve in a sufficiently dense way.
 A heart shaped mathematical function taken from the internet%
 \footnote{\url{http://mathworld.wolfram.com/HeartCurve.html} reports 
 several formulas, including the cardioid, but the one we use here is 
 a different function.} is the following
\begin{align*}
x(t) &= \sin^3(t)\\
y(t) &= \dfrac{13\cos(t)-5\cos(2t)-2\cos(3t)-\cos(4t)}{16}
\end{align*}
 Figure~\ref{fig:math-heart} displays the graph, and its code, and, most
 important, the L3 definition of the parametric equations. Compared to
 the previous equations we applied a scale factor and added the final
 term \texttt(2.4) in order to shift a little bit the drawing so as to
 vertically center it . 

\begin{figure*}[!tbp]
\begin{minipage}{\textwidth}
\def\codefraction{0.5}
\dimendef\Wuno=2000 \Wuno=\codefraction\textwidth
\dimendef\Wdue=2002 \Wdue=\dimexpr\textwidth-\columnsep-\Wuno\relax
\begin{minipage}{\Wuno}\setfontsize{6.9}%
\begin{verbatim}
%              Parametric equations of the "heart"
\providecommand\heart[3]{%
\edef\X{\fpeval{#1*16*(sind(#2)^3)}}
\edef\Y{\fpeval{#1*(13*cosd(#2) - 5*cosd(2*#2) 
  - 2*cosd(3*#2) -cosd(4*#2)+2.4)}}
\CopyVect\X,\Y to#3}
%
%                                         Drawing
\unitlength=0,005\linewidth
\begin{picture}(200,200)(-100,-100)
\AutoGrid
\VECTOR(-100,0)(100,0)\Pbox(100,0)[tr]{x}[0]
\VECTOR(0,-100)(0,100)\Pbox(0,100)[tl]{y}[0]
\Pbox(0,0)[tr]{O}\linethickness{1pt}\bgroup
\edef\scala{\fpeval{100/16}}
\countdef\I=2560 \I=0\roundjoin
\fpdowhile{\I !>360}{\heart\scala\I\Punto
\ifnum\I=0 \moveto(\Punto)\else \lineto(\Punto)\fi
\advance\I by 3}\strokepath\egroup
\end{picture}\end{verbatim}
\end{minipage}
\hfill
\begin{minipage}{\Wdue}\raggedleft
\setfontsize{8}%
%
\providecommand\heart[3]{%
\edef\X{\fpeval{#1*16*(sind(#2)^3)}}
\edef\Y{\fpeval{#1*(13*cosd(#2) - 5*cosd(2*#2) 
  - 2*cosd(3*#2) -cosd(4*#2)+2.4)}}
\CopyVect\X,\Y to#3}
%
\unitlength=0,005\linewidth
\begin{picture}(200,200)(-100,-100)
\AutoGrid
\VECTOR(-100,0)(100,0)\Pbox(100,0)[tr]{x}[0]
\VECTOR(0,-100)(0,100)\Pbox(0,100)[tl]{y}[0]
\Pbox(0,0)[tr]{O}\linethickness{1pt}\bgroup
\edef\scala{\fpeval{100/16}}
\countdef\I=2560 \I=0\roundjoin
\fpdowhile{\I !>360}{\heart\scala\I\Punto
\ifnum\I=0 \moveto(\Punto)\else \lineto(\Punto)\fi
\advance\I by 3}\strokepath\egroup
\end{picture}
\end{minipage}
\end{minipage}
\caption{A heart shaped mathematical function drawn with a thinly sampled
 piecewise continuous line}\label{fig:math-heart}
\end{figure*}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{ Intersections involving circles}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Determining the intersection of two circles is difficult; algebraically it requires the solution of second degree equations whose coefficients are sort of complicated expressions of the centers and radii; furthermore such equations might not have real roots. The problems are much simpler even geometrically when one circle is intersected by a line, and when two circles share a common point. In the first case there are two intersections, possibly coincident, if the centers distance is shorter than the sum of their radii; in the second case its easy to determine the chord common to both circles and the problem of finding the second intersection becomes that of finding the second end point of the chord.

Figure~\ref{fig:circle-and-line} shows the simple geometrical construction that leads to the determination of the intersections; one of the lines is tangent to the circle and the intersection points $P_3$ and $P_4$ coincide.

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{9}](0,40)
\unitlength=0.007\linewidth
\begin{picture}(100,100)
\AutoGrid
\IntersectionsOfLine(100,50)(0,20)%
  WithCircle(40,40){30}to\Puno and\Pdue
\Pbox(\Puno)[tl]{P_1}[2]
\Pbox(\Pdue)[t]{P_2}[2]
\Dotline(\C)(\Pt){2}[1.5]
\Dotline(\C)(\Pq){2}[1.5]
\Pbox(\Int)[t]{M}[2]
\Dotline(\C)(\Int){2}[1.5]
%
\IntersectionsOfLine(0,70)(100,70)%
  WithCircle(40,40){30}to\Ptre and\Pquat
\Pbox(\Ptre)[bl]{P_3}[2]
\Pbox(\Pquat)[br]{P_4}[2]
\IntersectionsOfLine(0,40)(100,100)%
  WithCircle(40,40){30}to\Pcin and\Psei
\Pbox(\Pcin)[br]{P_5}[2]
\Pbox(\Psei)[t]{P_6}[2]
\end{picture}
\end{Esempio}
\caption{Intersection of a circle with several lines}\label{fig:circle-and-line}
\end{figure}

Figure~\ref{fig:two-intersecting-circles} shows the geometrical construction to determine the second intersection point $P_2$ of two circles that already have a first common point $P_1$. The common chord and the segment joining the centers are not shown, but the code, although with “strange” point names, shows all the steps necessary to find the second intersection point


\begin{figure}[!htb]\centering
\begin{Esempio}[\setfontsize{9}](0.40)
\unitlength0.007\linewidth
\begin{picture}(100,100)
\AutoGrid
\edef\PCCuno{30,40}
\edef\PCCdue{70,60}
\edef\PCCzero{40,55}
\Pbox(\PCCuno)[t]{C_1}[2]
\Pbox(\PCCdue)[t]{C_2}[2]
\Pbox(\PCCzero)[l]{P_1}[2.5]
\CircleThrough\PCCzero WithCenter\PCCuno
\CircleThrough\PCCzero WithCenter\PCCdue
\Segment(\PCCuno)(\PCCdue)%
  SymmetricPointOf\PCCzero to\PCCquat
\Pbox(\PCCquat)[l]{P_2}[2.5]
\end{picture}
\end{Esempio}
\caption{Second intersection point $P_2$ of two circles sharing a first intersection point $P_1$}\label{fig:two-intersecting-circles}
\end{figure}

The following macro allows to determine both intersections, if they exist, of two generic circles; of course the macro is a little more complicated than the above macro that has to find the second intersection when one is already known. Even the reasoning behind the macro is quite different and slightly “creative”. 

In facts the reasoning is to avoid any or most analytical computations; analytically it would be quite simple to set up a system of two second degree polynomial equations; after processing such a system it is necessary to solve a second degree equation, but in order to control if there are intersections it should be necessary to discuss the value and sign of the discriminant; it is nothing special when doing all this by hand, but it involves a complicated code in terms of the \LaTeX\ language.

It is much simpler to reason geometrically; imagine to draw  two circles; let $a>0$ be the distance of their centers\footnote{If $a=0$ the circles are concentric and do not intersect.}, and let $R_1$ and $R_2$ be their radii. Then if
\[
|R_1 - R_2| \leq a \leq R_1 + R_2
\]
the intersections do exist, even if it is possible that the circles are tangent to one another and the two intersection points become a (double) one; this takes place when either ‘equals’ sign applies. If the left boundary is not satisfied the centers are too close to one another and the internal circle is too small compared to the external one. On the opposite if the upper bound is not satisfied the second circle is outside the first one and too far away.

The macro controls the above range, and if the the input data do not satisfy the range boundaries, there are no intersections: a warning message is issued, but computations go on with non sense values for both output coordinates; may be other errors are produced, but in any case the successive drawing lines will not be acceptable; a good sign to the user who may have not noticed the warning message in his/her console, but is immediately “forced” to consult this manual and find out this explanation; s/he will then review his/her code in oder to change the drawing data.

If the data cope with the above range, the computations go on along this simple reasoning, that it drawn in the left part of figure~\ref{fig;Intersections-of-two-circles}. There you see the segment that joins the two centers, and the intersection points to be found. They are the end points of the chord common to both circles; using as vertices the two centers and such chord as the base, two isosceles triangles are formed; the segment joining the centers bisects both triangles forming four right triangles where the hypotenuse is formed by the pertinent radius, and one leg is half the chord; with reference to the triangles $IC_1P_1$  and $IC_2P_1$, Pythagoras' theorem lets us determine the relation between the common leg $IP_1$ and the other triangle sides; this is the small analytical computation we have to execute, so as to compute the distance $c$ from the center $C_1$ and the common leg length $h$. These two values are sufficient, together with the direction of segment $C_1C_2$ to find the intersection points coordinates.

The syntax il the following
\begin{ttsyntax}
\cs{TwoCirclesIntersections}\parg{C1}\parg{C2}withradii\marg{R1} and\marg{R2} to\meta{P1} and\meta{P2}
\end{ttsyntax}
The symbols are self explanatory; as usual, input data (those entered before the keyword \texttt{to}) may be control sequences (defined with the necessary data), or explicit data; on the opposite the output ones must be control sequences.

\begin{figure}[!htb]
\begin{minipage}{0.475\linewidth}
\unitlength0.01\linewidth
\begin{picture}(100,100)(-50,-50)
\AutoGrid
\VECTOR(-50,0)(50,0) \Pbox(50,0)[tr]{x}[0]
\VECTOR(0,-50)(0,50) \Pbox(0,50)[l]{y}[0]
\edef\Kuno{-10,-10}\edef\RKuno{30}%
\edef\Kdue{20,10}\edef\RKdue{20}
\thicklines
\Circlewithcenter\Kuno radius\RKuno
\Circlewithcenter\Kdue radius\RKdue
\thinlines
\TwoCirclesIntersections(\Kuno)(\Kdue)withradii\RKuno and\RKdue to\Puno and\Pdue 
\Pbox(\Kuno)[br]{C_1}[4]         \Pbox(\Kdue)[bl]{C_2}[4]
\Pbox(\Puno)[tl]{P_1}[4]        \Pbox(\Pdue)[bc]{P_2}[4]
\put(\Kuno){\Vector(-45:\RKuno)}\Pbox(5,-27)[bl]{R_1}[0]
\put(\Kdue){\Vector(-45:\RKdue)}\Pbox(25, 3)[bl]{R_2}[0]
                                \Pbox(\CI)[t]{I}[4]
%
\segment(\Kuno)(\Kdue)\segment(\Puno)(\Pdue)
\segment(\Kuno)(\Pdue)\segment(\Kdue)(\Pdue)
\segment(\Kuno)(\Puno)\segment(\Puno)(\Kdue)
\end{picture}
\end{minipage}
\hfill
\begin{minipage}{0.475\linewidth}
\unitlength0.01\linewidth
\begin{picture}(100,100)(-50,-50)
\AutoGrid
\VECTOR(-50,0)(50,0) \Pbox(50,0)[tr]{x}[0]
\VECTOR(0,-50)(0,50) \Pbox(0,50)[l]{y}[0]
\edef\Kuno{-10,-10}\edef\RKuno{30}%
\edef\Kdue{20,10}\edef\RKdue{20}
\thicklines
\Circlewithcenter\Kuno radius\RKuno
\Circlewithcenter\Kdue radius\RKdue
\thinlines
\TwoCirclesIntersections(\Kuno)(\Kdue)withradii\RKuno and\RKdue to\Puno and\Pdue 
\Pbox(\Kuno)[b]{C_1}[4] \Pbox(\Kdue)[b]{C_2}[4]
\Pbox(\Puno)[tl]{P_1}[4] \Pbox(\Pdue)[b]{P_2}[4]
\put(\Kuno){\Vector(-45:\RKuno)}\Pbox(5,-27)[bl]{R_1}[0]
\put(\Kdue){\Vector(-45:\RKdue)}\Pbox(25,3)[bl]{R_2}[0]
\end{picture}
\end{minipage}
\caption{Intersections of two generic circles}\label{fig;Intersections-of-two-circles}\label{fig:2circle-intersections}
\end{figure}

The code for drawing figure~\ref{fig;Intersections-of-two-circles} is the following.

\begin{Verbatim}
\begin{minipage}{0.475\linewidth}% Geometrical construction
\unitlength0.01\linewidth
\begin{picture}(100,100)(-50,-50)
\AutoGrid
\VECTOR(-50,0)(50,0) \Pbox(50,0)[tr]{x}[0]
\VECTOR(0,-50)(0,50) \Pbox(0,50)[l]{y}[0]
\edef\Kuno{-10,-10}\edef\RKuno{30}%
\edef\Kdue{20,10}\edef\RKdue{20}
\thicklines
\Circlewithcenter\Kuno radius\RKuno
\Circlewithcenter\Kdue radius\RKdue
\thinlines
\TwoCirclesIntersections(\Kuno)(\Kdue)withradii\RKuno 
   and\RKdue to\Puno and\Pdue 
\Pbox(\Kuno)[br]{C_1}[4]        \Pbox(\Kdue)[bl]{C_2}[4]
\Pbox(\Puno)[tl]{P_1}[4]        \Pbox(\Pdue)[bc]{P_2}[4]
\put(\Kuno){\Vector(-45:\RKuno)}\Pbox(5,-27)[bl]{R_1}[0]
\put(\Kdue){\Vector(-45:\RKdue)}\Pbox(25, 3)[bl]{R_2}[0]
                                \Pbox(\CI)[t]{I}[4]
%
\segment(\Kuno)(\Kdue)\segment(\Puno)(\Pdue)
\segment(\Kuno)(\Pdue)\segment(\Kdue)(\Pdue)
\segment(\Kuno)(\Puno)\segment(\Puno)(\Kdue)
\end{picture}
\end{minipage}
\hfill
\begin{minipage}{0.475\linewidth}% Clean final result
\unitlength0.01\linewidth
\begin{picture}(100,100)(-50,-50)
\AutoGrid
\VECTOR(-50,0)(50,0) \Pbox(50,0)[tr]{x}[0]
\VECTOR(0,-50)(0,50) \Pbox(0,50)[l]{y}[0]
\edef\Kuno{-10,-10}\edef\RKuno{30}%
\edef\Kdue{20,10}\edef\RKdue{20}
\thicklines
\Circlewithcenter\Kuno radius\RKuno
\Circlewithcenter\Kdue radius\RKdue
\thinlines
\TwoCirclesIntersections(\Kuno)(\Kdue)withradii\RKuno 
   and\RKdue to\Puno and\Pdue 
\Pbox(\Kuno)[b]{C_1}[4] \Pbox(\Kdue)[b]{C_2}[4]
\Pbox(\Puno)[tl]{P_1}[4] \Pbox(\Pdue)[b]{P_2}[4]
\put(\Kuno){\Vector(-45:\RKuno)}\Pbox(5,-27)[bl]{R_1}[0]
\put(\Kdue){\Vector(-45:\RKdue)}\Pbox(25,3)[bl]{R_2}[0]
\end{picture}
\end{minipage}
\end{Verbatim}


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Triangles and their special lines}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

 Triangles have special lines; they are the median, the height, and the
 bisector lines. They join each vertex with a specific point of the
 apposite side, respectively with the middle point, the intersection 
 with the side perpendicular line, and the intersection with the bisector 
 line. Figure~\ref{fig:MHBlines}  displays the construction of the three 
 special lines relative to a specific vertex. Thanks to the macros 
 described earlier in the preceding section, this drawing is particularly 
 simple; most of the code is dedicated to labelling the various points and 
 to assign coordinate values to the macros that are going to be used 
 in a symbolic way. The generic triangle (not a regular polygon) requires 
 one line of code, and the determination of the intersections of the lines
 with the suitable triangle side, and their tracing requires two code 
 lines each.

\begin{figure}[!tb]\centering
\begin{Esempio}[\setfontsize{6.9}](0.4)
\unitlength=0.008\linewidth
\begin{picture}(100,100)(0,-10)
\AutoGrid
\def\Puno{0,0} \def\Pdue{0,80} \def\Ptre{100,55}
 {\thicklines\polygon(\Puno)(\Pdue)(\Ptre)}%
 \Pbox(\Puno)[tc]{P_1}[2]
\Pbox(\Pdue)[bc]{P_2}[2]\Pbox(\Ptre)[bc]{P_3}[2]
% Median
 \TriangleMedianBase\Puno on \Pdue and \Ptre to\M
 \Pbox(\M)[bc]{M}[2]\segment(\Puno)(\M)
% Height
 \TriangleHeightBase\Puno on \Pdue and\Ptre to\H
 \Dotline(\Puno)(\H){2}[1.5]\Pbox(\H)[bc]{H}[1.5]
% Bisector
 \TriangleBisectorBase\Puno on\Pdue and\Ptre to\B
 \Dashline(\Puno)(\B){1.5}\Pbox(\B)[b]{B}[2]
\end{picture}
\end{Esempio}
\caption{A triangle with the median, the height, and the bisector lines
 from a specific vertex}\label{fig:MHBlines}
\end{figure}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \subsection{Special triangle centers}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 Three triangle special lines of the same kind intersect each
 other in a special point; the median lines intersect in the
 \emph{barycenter}, the height lines in the \emph{orthocenter}, the 
 bisector lines in the \emph{incenter}; these centers may be those of 
 special circles: see figures~\ref{fig:barycenter} 
 to~\ref{fig:circumcenter};  the \emph{incircle}, centred in the incenter,
 has a special name, because it has the property of being tangent to all
 three triangle sides; there is also the circumcircle that passes
 through the three vertices, its center is the intersection of the
 three side axes. 
 Figures~\ref{fig:barycenter}, \ref{fig:orthocenter}, \ref{fig:incenter},
 and~\ref{fig:circumcenter} display the necessary constructions and,
 possibly, also the special circles they are centers of. There is also the \emph{nine point circle}, figure~\ref{fig:9point-circle}. It is worth noting the alla centers fall inside the various triangles, except the orthocenter that falls outside when the triangle is obtuse.

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{6.5}](0.45)
\unitlength=0.008\linewidth
\begin{picture}(100,100)(0,-10)
\AutoGrid
\def\Puno{0,0}\def\Pdue{0,80}\def\Ptre{100,55}
{\linethickness{0.6pt}\polygon(\Puno)(\Pdue)(\Ptre)}%
\Pbox(\Puno)[tl]{P_1}[1.5]%
\Pbox(\Pdue)[bl]{P_2}[1.5]\Pbox(\Ptre)[bc]{P_3}[1.5]
 \TriangleMedianBase\Puno on\Pdue and \Ptre to\Mu
 \TriangleMedianBase\Pdue on\Ptre and \Puno to\Md
 \TriangleMedianBase\Ptre on\Puno and \Pdue to\Mt
\Dotline(\Puno)(\Mu){3}[1.5]
\Dotline(\Pdue)(\Md){3}[1.5]
\Dotline(\Ptre)(\Mt){3}[1.5]
\IntersectionOfSegments(\Puno)(\Mu)and(\Pdue)(\Md)to\C
\Pbox(\C)[t]{B}[2]
\end{picture}
\end{Esempio}
\caption{Determination of the barycenter}\label{fig:barycenter}
\end{figure}

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{6.5}](0.45)
\unitlength=0.008\linewidth
\begin{picture}(100,100)(0,-10)
\AutoGrid
\def\Puno{0,0}\def\Pdue{0,80}\def\Ptre{100,55}
{\linethickness{0.6pt}\polygon(\Puno)(\Pdue)(\Ptre)}%
\Pbox(\Puno)[tl]{P_1}[1.5]%
\Pbox(\Pdue)[bl]{P_2}[1.5]\Pbox(\Ptre)[bc]{P_3}[1.5]
 \TriangleHeightBase\Puno on\Pdue and \Ptre to\Hu
 \TriangleHeightBase\Pdue on\Ptre and \Puno to\Hd
 \TriangleHeightBase\Ptre on\Puno and \Pdue to\Ht
\Dotline(\Puno)(\Hu){3}[1.5]
\Dotline(\Pdue)(\Hd){3}[1.5]
\Dotline(\Ptre)(\Ht){3}[1.5]
\IntersectionOfSegments(\Puno)(\Hu)and(\Pdue)(\Hd)to\C
\Pbox(\C)[t]{H}[2]
\end{picture}
\end{Esempio}
\caption{Determination of the orthocenter}\label{fig:orthocenter}
\end{figure}

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{6}](0.45)
\unitlength=0.008\linewidth
\begin{picture}(100,100)(0,-10)
\AutoGrid
\def\Puno{0,0}\def\Pdue{0,80}\def\Ptre{100,55}
{\linethickness{0.6pt}%
  \polygon(\Puno)(\Pdue)(\Ptre)}%
\Pbox(\Puno)[tl]{P_1}[1.5]%
\Pbox(\Pdue)[bl]{P_2}[1.5]
\Pbox(\Ptre)[bc]{P_3}[1.5]
 \TriangleBisectorBase\Puno on\Pdue and \Ptre to\Iu
 \TriangleBisectorBase\Pdue on\Ptre and \Puno to\Id
 \TriangleBisectorBase\Ptre on\Puno and \Pdue to\It
\Dotline(\Puno)(\Iu){3}[1.5]
\Dotline(\Pdue)(\Id){3}[1.5]
\Dotline(\Ptre)(\It){3}[1.5]
\IntersectionOfSegments(\Puno)(\Iu)%
  and(\Pdue)(\Id)to\C
\Pbox(\C)[t]{I}[2]
\DistanceOfPoint\C from(\Puno)(\Pdue)to\R
\Circlewithcenter\C radius\R
\end{picture}
\end{Esempio}
\caption{Determination of the incenter and of the incircle}\label{fig:incenter}
\end{figure}

\begin{figure}[!htb]
\begin{Esempio}*[\normalsize](0.45)
\unitlength=0.007\linewidth\centering
\begin{picture}(110,110)(-5,0)
\AutoGrid
\CopyVect20,10to\Pu \Pbox(\Pu)[t]{P_1}
\CopyVect10,90to\Pd \Pbox(\Pd)[br]{P_2}
\CopyVect100,70to\Pt \Pbox(\Pt)[l]{P_3}
{\linethickness{0.6pt}\polygon(\Pu)(\Pd)(\Pt)}%
\AxisOf\Pd and\Pu to\Mu\Du \segment(\Mu)(\Du)
\AxisOf\Pu and\Pt to\Md\Dd \segment(\Md)(\Dd)
\AxisOf\Pt and\Pd to\Mt\Dt\segment(\Mt)(\Dt)
\IntersectionOfSegments(\Mu)(\Du)and(\Md)(\Dd)to\C
\ThreePointCircle*(\Pu)(\Pd)(\Pt)
\Pbox(\C)[l]{C}[3.5]
\end{picture}
\end{Esempio}
\caption{Determination of the circumcenter and of the circumcircle}\label{fig:circumcenter}
\end{figure}

\begin{figure}
\begin{Esempio}*[\small](0.40)
\unitlength=0.007\linewidth\centering
\begin{picture}(100,100)(0,-10)
\AutoGrid
\CopyVect20,0to\Pu \Pbox(\Pu)[t]{P_1}[2pt]
\CopyVect10,80to\Pd \Pbox(\Pd)[b]{P_2}[2pt]
\CopyVect100,60to\Pt \Pbox(\Pt)[b]{P_3}[2pt]
{\polygon(\Pu)(\Pd)(\Pt)\ignorespaces}
\TriangleMedianBase\Pu on\Pd and\Pt to\Pmu\Pbox(\Pmu)[bl]{M_1}[2pt]
\TriangleMedianBase\Pd on\Pt and\Pu to\Pmd\Pbox(\Pmd)[tl]{M_2}[2pt]
\TriangleMedianBase\Pt on\Pu and\Pd to\Pmt \Pbox(\Pmt)[tr]{M_3}[2pt]
 \ThreePointCircle(\Pmu)(\Pmd)(\Pmt)
 \TriangleHeightBase\Pu on\Pd and\Pt to\Phu\Pbox(\Phu)[b]{H_1}[2pt]
 \TriangleHeightBase\Pd on\Pt and\Pu to\Phd\Pbox(\Phd)[tl]{H_2}[2pt]
 \TriangleHeightBase\Pt on\Pu and\Pd to\Pht\Pbox(\Pht)[br]{H_3}[2pt]
 \segment(\Pu)(\Phu) \segment(\Pd)(\Phd) \segment(\Pt)(\Pht)
 \SubVect\Pu from\Phu to\DirHu  \SubVect\Pd from\Phd to\DirHd
 \SubVect\Pt from\Pht to\DirHt
 \IntersectionOfLines(\Pu)(\DirHu)and(\Pt)(\DirHt)to\Po
 \Pbox(\Po)[tl]{O}[2pt]
 \MiddlePointOf(\Po)(\Pu)to\Pou \Pbox(\Pou)[l]{O_1}[2pt]
 \MiddlePointOf(\Po)(\Pd)to\Pod \Pbox(\Pod)[b]{O_2}[2pt]
 \MiddlePointOf(\Po)(\Pt)to\Pot \Pbox(\Pot)[bl]{O_3}[2pt]
 \ThreePointCircle*(\Pou)(\Pod)(\Pot)
 \end{picture}
\end{Esempio}
\caption{The nine point circle with its code}\label{fig:9point-circle}
\end{figure}
 
 Given the triangle with vertices $P_1, P_2, P_3$, the nine point circle is shown in figure~\ref{fig:9point-circle} with its code. The nine point are the triples of $(a)$ the height base point if the height lines; $(b)$ the middle points of the fraction of each height line between each vertex and the orthocenter; $(c)$ the middle points of the sides. It goes by itself that any point triple among the three ones of the nine point circle is good to draw he final circle.


 
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsection{Triangles and ellipses}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

There are some situations where an ellipse should be inserted within a triangle with some constraints. Some examples are described in the following sub subsections.

The following examples require some new simple macros, described in the 
 previous sections; some more more examples can be made that require more 
 complex macros. Even these macros are just examples. For other 
 applications it is probably necessary to add even more macros.
 
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsubsection{The Steiner ellipse}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

 Let us proceed with the construction of the Steiner ellipse: given a
 triangle, there exists only one ellipse that is internally tangent to
 the side mid-points.
 
 The geometrical construction goes on this way; suppose you have to draw
 the Steiner ellipse of triangle $T$; finding the side middle points
 has already been shown, but the process to build the ellipse is still
 to be found. So let us chose a side to work as the base of triangle $T$,
 and perform an affine shear transformation parallel to the base 
 so as to move the vertex of triangle $T$, opposite to the base, on the
 base axis, we get another triangle $T_1$ that is isosceles; if it is
 not yet so, let us make another compression/expansion affine
 transformation, so as to get an equilateral triangle $T_2$; this last
 triangle is particularly simple to handle, because its Steiner ellipse
 reduces to its incircle. If we apply in reverse order the above
 transformations we get the Steiner ellipse we were looking for.
 The only difficult part is the affine shear transformation. 

 The L3 functions we already created take care of all such
 transformations, but with an optional asterisk we can draw the
 intermediate passages where triangles $T_2$ and $T_1$ have their base
 shifted and rotated to be horizontal, so that some translations and
 rotations are also necessary. Figure~\ref{fig:Steiner-finale} displays
 the final result and the code necessary to build it.

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{8}](0.5)
\unitlength=0.01\linewidth
\begin{picture}(100,110)
\AutoGrid
\SteinerEllipse(10,10)(90,20)(60,105)[2]
\end{picture}
\end{Esempio}
\caption{The Steiner ellipse of a given triangle}
\label{fig:Steiner-finale}
\end{figure}

 With just the addition of an asterisk we can draw the whole geometrical
 construction; see figure~\ref{fig:Steiner-intermedio}

\begin{figure}[!htb]
\begin{Esempio}[\setfontsize{8}](0.5)
\unitlength=0.01\linewidth
\begin{picture}(100,110)(0,-10)
\AutoGrid
\SteinerEllipse*(10,10)(90,20)(60,105)[2]
\end{picture}
\end{Esempio}
\caption{The construction of the Steiner ellipse of a given triangle}
\label{fig:Steiner-intermedio}
\end{figure}


\begin{figure}[!tbp]\centering
\begin{Esempio}*[\setfontsize{8.2}](0.40)
\unitlength=0.005\linewidth
\begin{picture}(170,160)(-60,-80)
\AutoGrid
\VECTOR(0,-80)(0,80)\Pbox(0,80)[r]{y}[0]
\VECTOR(-60,0)(110,0)\Pbox(110,0)[t]{x}[0]
% Ellipse with given semi axes
\edef\A{40}\edef\B{30}\Xellisse{\A}{\B}[\thicklines]
% Point P on the ellipse
\edef\X{\fpeval{\A*cosd(120)}}\edef\Y{\fpeval{\B*sind(120)}}
\edef\P{\X,\Y}\Pbox(\P)[b]{P}[3]
% Foci coordinates
\edef\C{\fpeval{sqrt(\A**2-\B**2)}}
\CopyVect-\C,0 to\F \CopyVect\C,0 to\Fp\Pbox(\Fp)[t]{F'}[3]
\Pbox(\F)[t]{F}[3]\Pbox(0,0)[tr]{O}[3]
% Director circumference
\edef\Raggio{\fpeval{2*\A}}
\Circlewithcenter\Fp radius\Raggio \Pbox(80,60)[tr]{\ISOGamma{lmss}}[0]
% Tangent construction
\SegmentLength(\P)(\F)to\raggio
\Circlewithcenter\P radius\raggio \Pbox(-10,50)[bl]{\ISOgamma{lmss}}[0]
\SegmentArg(\Fp)(\P)to\Arg\AddVect\Fp and\Arg:\Raggio to\S
\segment(\Fp)(\S)\Pbox(\S)[br]{S}[3]
\segment(\F)(\S)\SegmentCenter(\F)(\S)to\M
\Pbox(\M)[r]{M}[3]\SegmentArg(\F)(\S)to\Arg
% Tangent
\edef\Arg{\fpeval{\Arg-90}}
\AddVect\M and \Arg:50 to\D \Pbox(\D)[l]{D}[3]
\segment(\M)(\D)
\end{picture}
\end{Esempio}
\caption{The director circumference}\label{fig:diretriz}
\end{figure}


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsubsection{The tangent to an ellipse}\label{ssec:diretriz}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Ellipses have many interesting properties. One that I was not able to find anywhere in the documentation I examined (of course not the totality  of available documents on ellipses) except an on-line document written in Portuguese by Sergio Alvez,
\begin{flushleft}\setfontsize{10}% 
\url{https://docplayer.com.br/345411-Elipses-inscritas-num-triangulo.html}\end{flushleft} 
is the \emph{director circumference}, literal translation of the Portuguese definition \emph{circunfência diretriz}.

Consider an ellipse with its foci $F$ en $F'$, and a generic point $P$ on its contour.
Trace a segment from $F\,P$  and another segment for $P\,F'$; these segments measure the distances from point $P$ to each focus: their sum is the length of the main ellipse axis $2a$, where $a$ is the semi axis. Now lengthen the segment $P\,F'$ to point $S$ by the length of $F\,P$; the length of $S\,F'$ is therefore equal to $2a$; now trace the circumference with center in $F'$ and radius $2a$; this is the \emph{director circumference}, that is labelled with~$\Gamma$.

By construction, then, the circle $\gamma$ centred in $P$ and radius equal to $F\,P$ is tangent to $\Gamma$ in $S$ and passes through $F$. This allows to say that:
\begin{itemize}[noitemsep]
\item the ellipse is the locus of the centres of all circles passing through  focus $F$ and internally tangent to the circle $\Gamma$ centred in the other focus $F'$ and with radius $2a$;
\item the axis of segment $S\,F$ is tangent to the ellipse;
\item the tangency point is the point $P$;
\item since this axis  passes through the midpoint $M$ of segment $S\,F$ and it is perpendicular to it, the segment $M\,P$ determines the direction of the tangent to the ellipse;
\item notice that points $S$ and $F$ are symmetrical with respect to the tangent in point $P$.
\end{itemize}
Such properties can be viewed and controlled in figure~\ref{fig:diretriz}.

Of course the geometrical construction of figure~\ref{fig:diretriz} can be used also in reverse order; for example it may be given a line to play the role of the tangent, a point on  this line to play the role of tangency, and a point not belonging to the line to play the role of a focus, then it is possible to find the other focus laying on a horizontal line passing through the given focus. It suffices to find the symmetrical point of the first focus with respect with the given line, and to draw a line passing through this symmetrical point and the point of tangency that intersects the  horizontal line through the first focus, concluding that this is the second focus and that the ellipse major axis length is that of the segment joining this second focus with the above mentioned symmetrical point.

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\subsubsection{A triangle internally tangent ellipse given one of its foci}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

 It is possible to draw an ellipse that is internally tangent to
 a triangle if one of its foci is specified; without this specification
 the problem is not definite, and the number of such ellipses is 
 countless.
 But with the focus specification, just one ellipse exists with that
 tangency constraint. It suffices to find the other focus and at least
 one point of tangency, because the focal distance and the sum of
 distances of that tangency point from the foci, is sufficient to
 determine all the parameters required to draw the ellipse.
 
 As seen in the previous subsection~\ref{ssec:diretriz}, it is sufficient to find the three symmetrical points of the given focus with respect to the three sides, i.e. the three lines that pass through the triangle vertices; and the constructions gives simultaneously the major axis length and the three tangency points, therefore all the elements required to draw the ellipse to be drawn.

\begin{figure}[!tb]\centering
\begin{Esempio}[\setfontsize{7}](0.375)
\unitlength=0.0065\linewidth
\begin{picture}(150,150)(-30,-20)
\AutoGrid
\EllipseWithFocus%
  (10,40)(110,10)(0,110)(20,60)
\end{picture}
\end{Esempio}
\caption{An ellipse internally tangent to a triangle, given a focus}
\label{fig:ellisse-interna-finale}
\end{figure}

\begin{figure}[!tb]
\begin{Esempio}*[\normalsize](0.375)
\unitlength0.0065\linewidth
\begin{picture}(150,150)(-30,-20)
\AutoGrid
\EllipseWithFocus*%
  (10,40)(110,10)(0,110)(20,60)
\end{picture}
\end{Esempio}
\caption{Construction of the ellipse of figure~\ref{fig:ellisse-interna-finale}}\label{fig:ellisse-interna}
\end{figure}


 The geometrical construction, with help of what has been explained in 
 subsection~\ref{ssec:diretriz}, is easy; the steps to follow, therefore 
 are the following:\enlargethispage*{\baselineskip}
\begin{itemize}[noitemsep]

\item draw the triangle and the given focus $\mathsf{F}$;

\item find the symmetrical points $\mathsf S_i$ of this 
focus with respect to the sides of the triangle;

\item use these three points $\mathsf S_i$ as the vertices of a triangle
 with which to draw its circumcircle that turns to be the \emph{director circumference}; actually only its center is of
 interest, because it represents the second focus $\mathsf F'$; the
 inter focal distance  $2c$; is just le length of vector $F' -F$;

\item join with segments each symmetrical point $\mathsf S_i$ with the
 second focus $\mathsf F'$ and find their intersections $\mathsf T_i$
 with the triangle sides; they represent the tangency points of the
 ellipse to be drawn;

\item the radius of the director circumference is the ellipse major axis;

\item equation~\eqref{equ:axes-foci} allows to find the second axis
 length; the segment that joins the foci has the required inclination
 of the main axis; its middle point is the ellipse center; therefore all
 necessary pieces of information to draw the ellipse are known.

\end{itemize}
 Figures~\ref{fig:ellisse-interna-finale} and~\ref{fig:ellisse-interna}
 display the construction steps and the final result.
 
 \begin{figure}
\begin{Esempio}*[\setfontsize{8.5}](0.40)
\begin{minipage}{0.475\linewidth}\unitlength=0.00815\linewidth
\begin{picture}(120,120)(-10,-10)
\AutoGrid
\polygon(0,0)(0,100)(100,100)(100,0)
{\color{black!10!white}
\polygon*(0,60)(0,0)(60,0)(60,60)
\polygon*(0,60)(40,60)(40,100)(0,100)}
\linethickness{2pt}
\polygon(0,60)(0,0)(60,0)(60,60)
\polygon(0,60)(40,60)(40,100)(0,100)
\linethickness{1pt}
{\color{red}\polygon(60,0)(100,60)(60,60)
\polygon(40,60)(40,100)(100,60)
\Pbox(75,45)[cc]{T_1}[0pt]\Pbox(60,0)[t]{C_1}[3pt]
\Pbox(55,75)[cc]{T_2}[0pt]\Pbox(40,100)[b]{C_2}[3pt]}
\Pbox(20,100)[b]{a}[0pt]\Pbox(70,100)[b]{b}[0pt]
\Pbox(100,80)[l]{a}[0pt]\Pbox(100,30)[l]{b}[0pt]
\Pbox(30,0)[t]{b}[0pt]  \Pbox(80,0)[t]{a}[0pt]
\Pbox(0,30)[r]{b}[0pt]  \Pbox(0,80)[r]{a}[0pt]
\Pbox(70,80)[bl]{c}[0pt]\Pbox(80,30)[tl]{c}[0pt]
\end{picture}
\end{minipage}
\hfill
\begin{minipage}{0.475\linewidth}\unitlength=0.00815\linewidth
\begin{picture}(120,120)(-10,-10)
\AutoGrid
\polyline(60,0)(100,0)(100,100)(40,100)
\Pbox(20,100)[b]{a}[0pt]\Pbox(70,100)[b]{b}[0pt]
\Pbox(100,80)[l]{a}[0pt]\Pbox(100,30)[l]{b}[0pt]
\Pbox(30,0)[t]{b}[0pt]  \Pbox(80,0)[t]{a}[0pt]
\Pbox(0,20)[r]{a}[0pt]  \Pbox(0,70)[r]{b}[0pt]
{\color{black!10!white}\polygon*(60,0)(100,60)(40,100)(0,40)}%
{\thicklines\color{red}\polygon(60,0)(100,60)(40,100)(0,40)
\Pbox(15,80)[cc]{T_2}[0pt]\Pbox(60,0)[t]{C_1}[3pt]
\Pbox(20,15)[cc]{T_1}[0pt]\Pbox(40,100)[b]{C_2}[3pt]
\polyline(40,100)(0,100)(0,0)(60,0)}
\Pbox(70,80)[tr]{c}[0pt]\Pbox(80,30)[br]{c}[0pt]
\Pbox(20,70)[tl]{c}[0pt]\Pbox(30,20)[bl]{c}[0pt]
\end{picture}
\end{minipage}
\end{Esempio}
\caption{Two squares partitioned in differente ways}
\label{fig:two squares}
\end{figure}



 
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \subsection{A simple proof of Pythagoras' theorem} 
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 Euclide at his time could not use the algebra symbology we use today; he did not have even an effective way to write numbers; in his time in Greece and in the Near East the numbers were written with letters, the usual alphabetic letters; the Greek alphabet of 24 letters, was extended with three more symbols, stigma (\stigma), qoppa (\qoppa) and sampi (\sampi), for a total of 27 seven symbols divided in three groups of 9 symbols. The first group represented the modern values from~1 to~9, the second group  represented the values from~10 to~90, the last group represented the values from~100 to~900. therefore they could easily write numbers up to~999‘, an apex denoting the fact that the letter string meant a number, not a word. For the thousands they used the same symbols preceded by an inverted  apex.so they could arrive to ‚9‚9‚9 999‘. The same use of letters for denoting numbers, was in use also among the Phoenicians and the Palestinians; the Kabala is a practice that suggests special informations to those that can interpret such letter/number signs. But it was practically impossible to do any serious calculations, in any case no square roots. This is why geometry was the only means to make “impossible” calculations.
 
The “Elements” by Euclide contain many theorems and statements that are demonstrated with geometrical constructions; The demonstration of Pythagoras' theorem to my eyes appears too complicated and difficult to understand; the geometrical construction developed hereafter is particularly ingenious and simple to understand.

Assume you have a square triangle of legs $a$ and $b$ and hypothenuse $c$; the theorem states that the area of the square built on the hypotenuse equals the sum of the areas of the squares built on each leg.

Let us prepare two similar squares of equal areas partitioned in differente ways. See figure~\ref{fig:two squares}.
In both images you see the overall squares have side lengths equal to the sum of the right triangle legs; in the left image the grey squares have side lengths equalling each right triangle leg respectively. The overall square contains also two rectangles with side lengths $a$ and $b$ so that the diagonal equals the right triangle hypothenuse. 

These diagonals, therefore, partition the respective rectangles in two right triangles with the same dimensions of the original right triangle. In particular two of such triangles are labeled $T_1$ and $T_2$ and the vertices labeled $C_1$ and $C_2$ are emphasised. Let us now  rotate both labelled  triangles around their labelled vertices so as to obtain the right image, where the overall square has the same sides as the original one, although  partitioned in a slightly differente way; their areas are the same; but in this second image the grey square has its side equal to the original right triangle hypothenuse; since the four right triangles contained in the overall squares of both images are equal, thus the sum of their areas are he same; therefore the grey areas in each image are the same and this means that the area of the square built on the hypotenuse  equals the sum of the area of the squares built on the legs of the original right triangle. Pythagoras' theorem is proved without any use of algebra.


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \section{Conclusion}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 We have shown that the \amb{picture} environment, extended with
 this package \pack{euclideangeometry} (that takes care of loading
 \pack{curve2e} and \pack{pict2e}) can make important diagrams that
 certainly were not foreseen by Leslie Lamport when he first wrote the
 code for the initial \env{picture} environment.
 
 The reader can easily understand that this package is far from being
 exhaustive for all geometrical problems to be solved with ruler and
 compass; it shows a way to add more commands to approach further 
 problems; if any author, who creates new commands, would like to 
 contribute more macros to this package, I will be happy to integrate 
 his/her contribution to a new version of this package; depending on the 
 contribution, I would be very happy to add its author name to this  
 package author list; for  simpler contributions each contributor will be 
 duly acknowledged.\enlargethispage*{\baselineskip}

 Creating new macros to solve more problems is pleasant; the more
 difficult the problem, the greater the satisfaction in solving it.


\begin{center}\bfseries
 Enjoy using \LaTeX and its possible applications!
\end{center}

\end{document}