diff options
Diffstat (limited to 'Master/texmf-dist/doc/generic/pst-eucl/pst-eucl-doc.tex')
-rw-r--r-- | Master/texmf-dist/doc/generic/pst-eucl/pst-eucl-doc.tex | 107 |
1 files changed, 82 insertions, 25 deletions
diff --git a/Master/texmf-dist/doc/generic/pst-eucl/pst-eucl-doc.tex b/Master/texmf-dist/doc/generic/pst-eucl/pst-eucl-doc.tex index c3b6bed35c5..164e8a6ad3d 100644 --- a/Master/texmf-dist/doc/generic/pst-eucl/pst-eucl-doc.tex +++ b/Master/texmf-dist/doc/generic/pst-eucl/pst-eucl-doc.tex @@ -9,7 +9,6 @@ \usepackage[mathscr]{eucal} \def\eV{e.\kern-1pt{}V\kern-1pt} - \lstset{pos=l,wide=false,basicstyle=\footnotesize\ttfamily,explpreset={language=[PSTricks]{TeX}}} % \def\Argsans#1{$\langle$#1$\rangle$} @@ -488,16 +487,22 @@ For example: \pstTriangleOC[PosAngle=90,PointSymbol=*,PointName=X]{A}{B}{C}[X] \end{lstlisting} -The macros \Lcs{pstTriangleGC}, \Lcs{pstTriangleHC} and \Lcs{pstTriangleEC} are used to draw the barycenter $G$, the orthocentre $H$ and the escenter $E$ of the triangle $ABC$. +The macros \Lcs{pstTriangleGC}, \Lcs{pstTriangleHC}, \Lcs{pstTriangleEC}, \Lcs{pstTriangleNC}, \Lcs{pstTriangleLC} +are used to draw the barycenter $G$, the orthocentre $H$, the escenter $E$, the nine points circle center +and the Lemonie point (or symmedian point) of the triangle $ABC$. \begin{BDef} \Lcs{pstTriangleGC}\OptArgs\Largb{A}\Largb{B}\Largb{C}\Largb{G}\OptArg{$M_1$}\OptArg{$M_2$}\\ \Lcs{pstTriangleHC}\OptArgs\Largb{A}\Largb{B}\Largb{C}\Largb{H}\OptArg{$H_1$}\OptArg{$H_2$}\\ -\Lcs{pstTriangleEC}\OptArgs\Largb{A}\Largb{B}\Largb{C}\Largb{E}\OptArg{$T_1$} +\Lcs{pstTriangleEC}\OptArgs\Largb{A}\Largb{B}\Largb{C}\Largb{E}\OptArg{$T_1$}\\ +\Lcs{pstTriangleNC}\OptArgs\Largb{A}\Largb{B}\Largb{C}\Largb{N}\OptArg{$M_1$}\OptArg{$M_2$}\OptArg{$M_3$}\\ +\Lcs{pstTriangleLC}\OptArgs\Largb{A}\Largb{B}\Largb{C}\Largb{L}\OptArg{$S_1$}\OptArg{$S_2$}\OptArg{$S_3$} \end{BDef} -You can use the options of node like as \verb|PointName=...|, \verb|PosAngle=...|, \verb|PointSymbol=...| to control the output nodes $G,H,E$. But if you give the optional output parameters $M_1,M_2$, or $H_1,H_2$ or $T_1$, then you should pass the option value in list like as \verb|PointName={...}|, \verb|PosAngle={...}|, \verb|PointSymbol={...}|. -For example, +You can use the options of node like as \verb|PointName=...|, \verb|PosAngle=...|, \verb|PointSymbol=...| +to control the output nodes $G,H,E$. But if you give the optional output parameters $M_1,M_2$, or $H_1,H_2$ +or $T_1$, then you should pass the option value in list like as \verb|PointName={...}|, +\verb|PosAngle={...}|, \verb|PointSymbol={...}|. For example, \begin{LTXexample}[width=6cm,pos=l] \begin{pspicture}[showgrid=true](-3,-3)(3,2) @@ -505,11 +510,13 @@ For example, \pstGeonode[PosAngle=90](0,1){A} \pstGeonode[PosAngle=-90](-1,-0.6){B} \pstGeonode[PosAngle=-90](1.5,-0.6){C} -\pstTriangleGC[PointSymbol={*,none,*},PosAngle={150,-80,30}]{A}{B}{C}{G}[M_1][M_2] -\pstTriangleHC[PointSymbol={*,*,none},PosAngle={-30,-100,30}]{A}{B}{C}{H}[H_1][H_2] -\pstTriangleEC[PointSymbol={*,none},PosAngle={90,30}]{A}{B}{C}{E_1}[T_1] +\pstTriangleGC[PointSymbol={*,none,*},PosAngle={-30,-80,30},PointNameSep=0.22cm]{A}{B}{C}{G}[M_1][M_2] +\pstTriangleHC[PointSymbol={*,*,none},PosAngle={160,-120,30},PointNameSep=0.22cm]{A}{B}{C}{H}[H_1][H_2] +\pstTriangleEC[PointSymbol={*,*},PosAngle={90,-40}]{A}{B}{C}{E_1}[T_1] \pstTriangleEC[PointSymbol=*,PosAngle=0]{B}{C}{A}{E_2} \pstTriangleEC[PointSymbol=*,PosAngle=180]{C}{A}{B}{E_3} +\pstTriangleNC[PointSymbol=*,PosAngle=40,linestyle=dashed,linecolor=cyan!60]{A}{B}{C}{N} +\pstTriangleLC[PointSymbol=*,PosAngle=200,linecolor=green!80,PointNameSep=0.22cm]{A}{B}{C}{L} \pstLineAB{A}{B}\pstLineAB{B}{C}\pstLineAB{C}{A} \pstCircleOA[linestyle=dashed,linecolor=gray!40]{E_1}{T_1}[30][150] \pstLineAB[linestyle=dashed,linecolor=blue!40]{A}{M_1} @@ -533,8 +540,9 @@ right angle: \begin{sloppypar} -Valid optional arguments are \Lkeyword{RightAngleType}, \Lkeyword{RightAngleSize}, - \Lkeyword{RightAngleSize}, and \Lkeyword{RightAngleDotDistance} +The valid optional arguments controlling this command, excepting the ones which +controlled the line, are \Lkeyword{RightAngleType}, \Lkeyword{RightAngleSize}, +\Lkeyword{RightAngleSize}, and \Lkeyword{RightAngleDotDistance}. \end{sloppypar} The symbol is controlled by the parameter \Lkeyword{RightAngleType} @@ -546,18 +554,12 @@ The symbol is controlled by the parameter \Lkeyword{RightAngleType} \item \Lkeyval{suisseromand} : swiss romand symbol (given P. Schnewlin). \end{compactitem} -\begin{sloppypar} -The only parameters controlling this command, excepting the ones which -controlled the line, is \Lkeyword{RightAngleSize} which defines the size -of the symbol \DefaultVal{0.28 unit} and \Lkeyword{RightAngleDotDistance}. For a -right angle style \Lkeyval{german} or \Lkeyval{swissromand} the distance of the dot +The optional argument \Lkeyword{RightAngleSize} defines the size of the symbol \DefaultVal{0.28 unit}. + +For a right angle style \Lkeyval{german} or \Lkeyval{swissromand} the distance of the dot is preset to 0.5 (\Lkeyval{german}) or 0.45 (\Lkeyval{swissromand}), relative to the radius. -It can be controlled by the optional argument \Lkeyword{RightAngleDotDistance} which is +However, it can be controlled by the optional argument \Lkeyword{RightAngleDotDistance} which is preset to 1. A greater value moves the dot away from the reference point. -\end{sloppypar} - - - For other angles, there is the command: @@ -568,8 +570,7 @@ For other angles, there is the command: \begin{sloppypar} Valid optional arguments are \Lkeyword{MarkAngleRadius}, \Lkeyword{LabelAngleOffset}, - \Lkeyword{MarkAngleType} and - \Lkeyword{Mark} +\Lkeyword{MarkAngleType} and \Lkeyword{Mark}. % The \Lkeyword{label} can be any valid \TeX\ box, it is put at \Lkeyword{LabelSep} \DefaultVal{1 unit} of the node in the direction of the bisector of the angle @@ -1172,13 +1173,13 @@ Another example is for \Lcs{pstDistMul}, the old code like as \begin{lstlisting} \pstCircleOA[DistCoef=1 3 div,Radius=\pstDistAB{A}{B}]{O}{} \pstCircleOA[DistCoef=1 3 div,Radius=\pstDistAB{A}{B}]{A}{B}{O}{}{I}{J} -\pstInterCC[DistCoef=1 3 div,RadiusA=\pstDistAB{A}{B},DistCoef=none,RadiusA=\pstDistAB{C}{D}]{O1}{}{O2}{}{I}{J} +\pstInterCC[DistCoef=1 3 div,RadiusA=\pstDistAB{A}{B},DistCoef=none,RadiusB=\pstDistAB{C}{D}]{O1}{}{O2}{}{I}{J} \end{lstlisting} could be simplified to \begin{lstlisting} \pstCircleOA[Radius=\pstDistMul{A}{B}{1 3 div}]{O}{} \pstInterLC[Radius=\pstDistMul{A}{B}{1 3 div}]{A}{B}{O}{}{I}{J} -\pstInterCC[RadiusA=\pstDistMul{A}{B}{1 3 div},RadiusA=\pstDistAB{C}{D}]{O1}{}{O2}{}{I}{J} +\pstInterCC[RadiusA=\pstDistMul{A}{B}{1 3 div},RadiusB=\pstDistAB{C}{D}]{O1}{}{O2}{}{I}{J} \end{lstlisting} \vspace{10pt}\noindent{}{\Large{\textbf{Important}}}! @@ -1366,7 +1367,7 @@ so you can't omit the parameter $A$. The direction to find node $X$ is anti-clockwise by default. The parameter \Lkeyword{CurvAbsNeg}\DefaultVal{false} can change this behavior. -At last, the chord length $L$ chouldn't large than the diameter of the circle, +At last, the chord length $L$ shouldn't large than the diameter of the circle, else we will put the node $X$ at origin. \begin{LTXexample}[width=6cm,pos=l] @@ -2003,6 +2004,34 @@ when you pass it to \Lcs{pstGeneralEllipse}, PostScript will lookup the value of \vspace{10pt} +The Macro \Lcs{pstGeneralEllipseFFN} is used to define a General Ellipse by the given focus nodes $F_1$, $F_2$, and one node $N$ on it. +It just calculate the center $O$, major radius $a$, minor radius $b$ and the rotation angle $\theta$ of the major axis, +then you can pass them into macro \Lcs{pstGeneralEllipse} to draw this ellipse. + +\begin{BDef} +\Lcs{pstGeneralEllipseFFN}\OptArgs\Largb{$F_1$}\Largb{$F_2$}\Largb{O}\Largb{Rab}\Largb{$\theta$} +\end{BDef} + +The output parameter \texttt{O}, the output parameter \texttt{Rab} and the output parameter \texttt{$\theta$} +are same with \Lcs{pstGeneralEllipseFle}. + +\begin{LTXexample}[width=6cm,pos=l] +\begin{pspicture}[showgrid=true](0,0)(4,4) +\psset{dotscale=0.5}\psset{PointSymbol=*}\footnotesize +\pstGeonode[PosAngle=-90](1,1){F_1} +\pstGeonode[PosAngle=-90](3,3){F_2} +\pstGeonode[PosAngle=-90](1,3){F_3} +\pstGeonode[PosAngle=-90](3,1){F_4} +\pstGeonode[PosAngle=90](2,3){N} +\pstGeneralEllipseFFN[linecolor=red!30,CodeFig=true]{F_1}{F_2}{N}{O}{R1}{angle1} +\pstGeneralEllipse[linecolor=red!30](O)(R1)[angle1] +\pstGeneralEllipseFFN[linecolor=blue!30,CodeFig=true]{F_3}{F_4}{N}{O}{R2}{angle2} +\pstGeneralEllipse[linecolor=blue!30](O)(R2)[angle2] +\end{pspicture} +\end{LTXexample} + +\vspace{10pt} + The Macro \Lcs{pstGeneralEllipseCoef} is used to define a General Ellipse by the quadratic curve equation $ax^2+bxy+cy^2+dx+ey+f=0$, it just calculate the center $O$, major radius $a$, minor radius $b$ and the rotation angle $\theta$ of the major axis, then you can pass them into macro \Lcs{pstGeneralEllipse} to draw this ellipse. @@ -3443,6 +3472,34 @@ when you pass it to \Lcs{pstGeneralHyperbola}, PostScript will lookup the value \vspace{10pt} +The Macro \Lcs{pstGeneralHyperbolaFFN} is used to define a General Hyperbola by the given focus nodes $F_1$, $F_2$, and one node $N$ on it. +It just calculate the center $O$, major radius $a$, minor radius $b$ and the rotation angle $\theta$ of the major axis, +then you can pass them into macro \Lcs{pstGeneralHyperbola} to draw this hyperbola. + +\begin{BDef} +\Lcs{pstGeneralHyperbolaFFN}\OptArgs\Largb{$F_1$}\Largb{$F_2$}\Largb{O}\Largb{Rab}\Largb{$\theta$} +\end{BDef} + +The output parameter \texttt{O}, the output parameter \texttt{Rab} and the output parameter \texttt{$\theta$} +are same with \Lcs{pstGeneralHyperbolaFle}. + +\begin{LTXexample}[width=6cm,pos=l] +\begin{pspicture}[showgrid=true](0,0)(4,4) +\psset{dotscale=0.5}\psset{PointSymbol=*}\footnotesize +\pstGeonode[PosAngle=-90](1,1){F_1} +\pstGeonode[PosAngle=-90](3,3){F_2} +\pstGeonode[PosAngle=-90](1,3){F_3} +\pstGeonode[PosAngle=-90](3,1){F_4} +\pstGeonode[PosAngle=90](2,3){N} +\pstGeneralHyperbolaFFN[linecolor=red!30,CodeFig=true]{F_1}{F_2}{N}{O}{R1}{angle1} +\pstGeneralHyperbola[linecolor=red!30](O)(R1)[angle1][65] +\pstGeneralHyperbolaFFN[linecolor=blue!30,CodeFig=true]{F_3}{F_4}{N}{O}{R2}{angle2} +\pstGeneralHyperbola[linecolor=blue!30](O)(R2)[angle2][65] +\end{pspicture} +\end{LTXexample} + +\vspace{10pt} + The Macro \Lcs{pstGeneralHyperbolaCoef} is used to define a General Hyperbola by the quadratic curve equation $ax^2+bxy+cy^2+dx+ey+f=0$, it just calculate the center $O$, real radius $a$ and imaginary radius $b$ and the rotation angle $\theta$ of the real axis, then you can pass them into macro \Lcs{pstGeneralHyperbola} to draw this hyperbola. |