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authorKarl Berry <karl@freefriends.org>2019-11-08 21:40:58 +0000
committerKarl Berry <karl@freefriends.org>2019-11-08 21:40:58 +0000
commitcee1b7f2580148a33ae6cc0631c56c7e35ce0bff (patch)
treef1f4b8c3cadb58d72d04bf20dcc136eae4f57a23 /Master/texmf-dist/doc/latex/jnuexam
parent69e924ee6c8d31ad1ad84dfe14dd724fe50553df (diff)
jnuexam (8nov19)
git-svn-id: svn://tug.org/texlive/trunk@52696 c570f23f-e606-0410-a88d-b1316a301751
Diffstat (limited to 'Master/texmf-dist/doc/latex/jnuexam')
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-a-a3input.pdfbin111416 -> 102199 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-a-a3split.pdfbin103007 -> 94090 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-a-empty.pdfbin100412 -> 91316 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-a.pdfbin118234 -> 104945 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-a.tex68
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-b-a3input.pdfbin111285 -> 102033 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-b-a3split.pdfbin102968 -> 93887 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-b-empty.pdfbin100270 -> 91140 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/exam-b.pdfbin118116 -> 104821 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/jnuexam.pdfbin65809 -> 74286 bytes
-rw-r--r--Master/texmf-dist/doc/latex/jnuexam/jnuexam.tex107
11 files changed, 120 insertions, 55 deletions
diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-a-a3input.pdf b/Master/texmf-dist/doc/latex/jnuexam/exam-a-a3input.pdf
index 5c185d3fc7d..c8ade766802 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-a-a3input.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-a-a3input.pdf
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diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-a-a3split.pdf b/Master/texmf-dist/doc/latex/jnuexam/exam-a-a3split.pdf
index f17c0ce2e38..de83638ce7d 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-a-a3split.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-a-a3split.pdf
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diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-a-empty.pdf b/Master/texmf-dist/doc/latex/jnuexam/exam-a-empty.pdf
index 846854d86dc..653325a6525 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-a-empty.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-a-empty.pdf
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diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-a.pdf b/Master/texmf-dist/doc/latex/jnuexam/exam-a.pdf
index c57592e6754..5eb115847a8 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-a.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-a.pdf
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diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-a.tex b/Master/texmf-dist/doc/latex/jnuexam/exam-a.tex
index 44bc600fae0..54b2d1ac404 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-a.tex
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-a.tex
@@ -39,10 +39,10 @@
\vfill
\begin{problem}
-已知二阶行列式 $\text{$\left|\begin{array}{cc}
+已知二阶行列式 $\left|\begin{array}{cc}
1 & 2\\
- 3 & x
-\end{array}\right|$=0}$,则 $x=$ \fillout{$-6$}.
+\end{array}\right|=0$,则 $x=$ \fillout{$-6$}.
\end{problem}
\vfill
@@ -178,10 +178,10 @@
\begin{solution}
\everymath{\displaystyle}%
-原式$=\int\e^{2x}\,\sec^2 x\dx+2\int\e^{2x}\,\tan x\dx$ \score{2}
-\hspace{5em}${}=\int\e^{2x}\,\d(\tan x)+ 2\int\e^{2x}\,\tan x\dx$ \score{4}
-\hspace{5em}${}=\e^{2x}\,\tan x - 2\int\e^{2x}\,\tan x\dx+ 2\int\e^{2x}\,\tan x\dx$ \score{6}
-\hspace{5em}${}=\e^{2x}\,\tan x + C$ \score{8}
+原式 \? $=\int\e^{2x}\,\sec^2 x\dx+2\int\e^{2x}\,\tan x\dx$ \score{2}
+\+ $=\int\e^{2x}\,\d(\tan x)+ 2\int\e^{2x}\,\tan x\dx$ \score{4}
+\+ $=\e^{2x}\,\tan x - 2\int\e^{2x}\,\tan x\dx+ 2\int\e^{2x}\,\tan x\dx$ \score{6}
+\+ $=\e^{2x}\,\tan x + C$ \score{8}
\end{solution}
\vfill
@@ -220,7 +220,7 @@
\bigskip
\begin{solution}
-$A = \left|\begin{array}{cccc}
+$A \? = \left|\begin{array}{cccc}
0 & 1 & 2 & 3\\
1 & 2 & 3 & 0\\
2 & 3 & 0 & 1\\
@@ -235,7 +235,7 @@ $A = \left|\begin{array}{cccc}
- 1 & - 6 & 1\\
- 6 & - 8 & 2
\end{array}\right|$ \score{4}
-\qquad $= -\left|\begin{array}{ccc}
+\+ $= -\left|\begin{array}{ccc}
1 & 2 & 3\\
0 & - 4 & 4\\
0 & 4 & 20
@@ -255,11 +255,11 @@ x_2 x_3 + 9 x^2_3$ 化为标准形 $f = d_1 y^2_1 + d_2 y^2_2 + d_3 y^2_3$ .
\bigskip
\begin{solution}
-$f = x_1^2 + 2 x_1 x_2 - 6 x_1 x_3 + 2 x_2^2 - 12 x_2 x_3 + 9 x^2_3$ \par
-\qquad$= x_1^2 + 2 x_1 (x_2 - 3 x_3) + (x_2 - 3 x_3)^2 + x_2^2 - 6 x_2 x_3 $ \par
-\qquad$= (x_1 + x_2 - 3 x_3)^2 + x_2^2 - 6 x_2 x_3$ \score{3}
-\qquad$= (x_1 + x_2 - 3 x_3)^2 + x_2^2 - 2 x_2 \cdot 3 x_3 + (3 x_3)^2 - 9x_3^2$ \par
-\qquad$= (x_1 + x_2 - 3 x_3)^2 + (x_2 - 3 x_3)^2 - 9 x_3^2$ \score{6}
+$f \? = x_1^2 + 2 x_1 x_2 - 6 x_1 x_3 + 2 x_2^2 - 12 x_2 x_3 + 9 x^2_3$ \par
+ \+ $= x_1^2 + 2 x_1 (x_2 - 3 x_3) + (x_2 - 3 x_3)^2 + x_2^2 - 6 x_2 x_3 $ \par
+ \+ $= (x_1 + x_2 - 3 x_3)^2 + x_2^2 - 6 x_2 x_3$ \score{3}
+ \+ $= (x_1 + x_2 - 3 x_3)^2 + x_2^2 - 2 x_2 \cdot 3 x_3 + (3 x_3)^2 - 9x_3^2$ \par
+ \+ $= (x_1 + x_2 - 3 x_3)^2 + (x_2 - 3 x_3)^2 - 9 x_3^2$ \score{6}
令$y_1 = x_1 + x_2 - 3 x_3, y_2 = x_2 - 3 x_3, y_3 = x_3$, \newline
则$f = y_1^2 + y_2^2 - 9y_3^2$为标准形.\score{8}
\end{solution}
@@ -270,19 +270,19 @@ $f = x_1^2 + 2 x_1 x_2 - 6 x_1 x_3 + 2 x_2^2 - 12 x_2 x_3 + 9 x^2_3$ \par
\begin{problem}
设每发炮弹命中飞机的概率是0.2且相互独立,现在发射100发炮弹.\par
-\step 用切贝谢夫不等式估计命中数目$\xi$在10发到30发之间的概率.\par
-\step 用中心极限定理估计命中数目$\xi$在10发到30发之间的概率.
+(1) 用切贝谢夫不等式估计命中数目$\xi$在10发到30发之间的概率.\par
+(2) 用中心极限定理估计命中数目$\xi$在10发到30发之间的概率.
\end{problem}
\bigskip
\begin{solution}
$E\xi = n p = 100 \cdot 0.2 = 20, D\xi = n p q = 100 \cdot 0.2 \cdot 0.8 = 16$. \score{2}
-\step $P (10 < \xi < 30) = P (| \xi - E \xi | < 10) \ge 1 - \frac{D\xi}{10^2}
+(1) $P (10 < \xi < 30) = P (|\xi - E\xi| < 10) \ge 1 - \frac{D\xi}{10^2}
= 1 - \frac{16}{100} = 0.84$. \score{4}
-\step $P (10 < \xi < 30) \approx \Phi_0 \left( \frac{30 - 20}{\sqrt{16}}\right)
- - \Phi_0 \left( \frac{10 - 20}{\sqrt{16}} \right)$ \score{6}
-\qquad $= 2 \Phi_0 (2.5) - 1 = 2 \cdot 0.9938 - 1 =0.9876$ \score{8}
+(2) $P (10 < \xi < 30) \? \approx \Phi_0\left(\frac{30 - 20}{\sqrt{16}}\right)
+ - \Phi_0\left(\frac{10 - 20}{\sqrt{16}}\right)$ \score{6}
+ \+ $= 2 \Phi_0(2.5) - 1 = 2 \cdot 0.9938 - 1 =0.9876$ \score{8}
\end{solution}
\vfill
@@ -295,11 +295,11 @@ $E\xi = n p = 100 \cdot 0.2 = 20, D\xi = n p q = 100 \cdot 0.2 \cdot 0.8 = 16$.
\bigskip
\begin{solution}
-\step 待检假设 $H_0 : \mu = 3140$. \score{1}
-\step 选取统计量 $T = \frac{\bar{X}-\mu}{S / \sqrt{n}} \sim t(n-1)$. \score{3}
-\step 查表得到 $t_{\alpha} = t_{\alpha} (n - 1) = t_{0.01} (15) =2.947$. \score{5}
-\step 计算统计值 $t = \frac{\bar{x} - \mu_0}{s/\sqrt{n}} =\frac{3160-3140}{100/4} = 0.8$.\score{7}
-\step 由于 $| t | < t_{\alpha}$, 故接受 $H_0$, 即假设成立. \score{8}
+(1) 待检假设 $H_0 : \mu = 3140$. \score{1}
+(2) 选取统计量 $T = \frac{\widebar{X}-\mu}{S / \sqrt{n}} \sim t(n-1)$. \score{3}
+(3) 查表得到 $t_{\alpha} = t_{\alpha} (n - 1) = t_{0.01} (15) =2.947$. \score{5}
+(4) 计算统计值 $t = \frac{\widebar{x} - \mu_0}{s/\sqrt{n}} =\frac{3160-3140}{100/4} = 0.8$.\score{7}
+(5) 由于 $| t | < t_{\alpha}$, 故接受 $H_0$, 即假设成立. \score{8}
\end{solution}
\vfill
@@ -308,6 +308,8 @@ $E\xi = n p = 100 \cdot 0.2 = 20, D\xi = n p q = 100 \cdot 0.2 \cdot 0.8 = 16$.
\makepart{证明题}{共~2~小题,每小题~8~分,共~16~分}
+\renewcommand{\solutionname}{证} % 将“解”字改为“证”字
+
\begin{problem}
设数列$\{x_n\}$满足$x_1=\sqrt2$,$x_{n+1}=\sqrt{2+x_n}$.证明数列收敛,并求出极限.
\end{problem}
@@ -315,13 +317,13 @@ $E\xi = n p = 100 \cdot 0.2 = 20, D\xi = n p q = 100 \cdot 0.2 \cdot 0.8 = 16$.
\bigskip
\begin{solution}
-\step 事实上,由于$x_1<2$,且$x_k<2$时
+(1) 事实上,由于$x_1<2$,且$x_k<2$时
$$x_{k+1}=\sqrt{2+x_k}<\sqrt{2+2}=2,$$
由数学归纳法知对所有$n$都有$x_n<2$,即数列有上界.
又由于
$$\frac{x_{n+1}}{x_n}=\sqrt{\frac{2}{x_n^2}+\frac{1}{x_n}}>\sqrt{\frac{2}{2^2}+\frac{1}{2}}=1,$$
所以数列单调增加.由极限存在准则II,数列必定收敛.\score{4}
-\step 设数列的极限为$A$,对递推公式两边同时取极限得到
+(2) 设数列的极限为$A$,对递推公式两边同时取极限得到
$$A=\sqrt{2+A}.$$
解得$A=2$,即数列$\{x_n\}$的极限为$2$.\score{8}
\end{solution}
@@ -329,29 +331,29 @@ $$A=\sqrt{2+A}.$$
\vfill
\begin{problem}
-设事件$A$和$B$相互独立,证明$A$和$\bar{B}$相互独立.
+设事件$A$和$B$相互独立,证明$A$和$\widebar{B}$相互独立.
\end{problem}
\bigskip
\begin{solution}
-$P (A \cdot \bar{B}) = P (A - B) = P (A - A B)$ \score{2}
-\qquad $= P (A) - P (A B) = P (A) - P (A) P (B)$ \score{4}
-\qquad $= P (A) (1 - P (B)) = P (A) P (\bar{B})$ \score{6}
-所以$A$和$\bar{B}$相互独立.\score{8}
+\? $P (A \cdot \widebar{B}) = P (A - B) = P (A - A B)$ \score{2}
+\< $= P (A) - P (A B) = P (A) - P (A) P (B)$ \score{4}
+\< $= P (A) (1 - P (B)) = P (A) P (\widebar{B})$ \score{6}
+所以$A$和$\widebar{B}$相互独立.\score{8}
\end{solution}
\vfill
\makedata{一些可能用到的数据} %附录数据
-\begin{tabu}{*{4}{X[l,$]}}
+\begin{tabularx}{\linewidth}{*{4}{>{$}X<{$}}}
\hline
\Phi_0(0.5)=0.6915 & \Phi_0(1)=0.8413 & \Phi_0(2)=0.9773 & \Phi_0(2.5)=0.9938 \\
t_{0.01}(8)=3.355 & t_{0.01}(9)=3.250 & t_{0.01}(15)=2.947 & t_{0.01}(16)=2.921 \\
\chi_{0.005}^2(8)=22.0 & \chi_{0.005}^2(9)=23.6 & \chi_{0.005}^2(15)=32.8 & \chi_{0.005}^2(16)=34.3 \\
\chi_{0.995}^2(8)=1.34 & \chi_{0.995}^2(9)=1.73 & \chi_{0.995}^2(15)=4.60 & \chi_{0.995}^2(16)=5.14 \\
\hline
-\end{tabu}
+\end{tabularx}
\end{document}
diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-b-a3input.pdf b/Master/texmf-dist/doc/latex/jnuexam/exam-b-a3input.pdf
index 9b0fd8d18df..7351872d942 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-b-a3input.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-b-a3input.pdf
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index c224b9ab33d..ff8a2e40bab 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-b-a3split.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-b-a3split.pdf
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diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-b-empty.pdf b/Master/texmf-dist/doc/latex/jnuexam/exam-b-empty.pdf
index 1b27aa32c81..9809fb34cc5 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-b-empty.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-b-empty.pdf
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diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-b.pdf b/Master/texmf-dist/doc/latex/jnuexam/exam-b.pdf
index 8a378a7e3d8..69dd16f1879 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/exam-b.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/exam-b.pdf
Binary files differ
diff --git a/Master/texmf-dist/doc/latex/jnuexam/jnuexam.pdf b/Master/texmf-dist/doc/latex/jnuexam/jnuexam.pdf
index 79517e4623c..dac435686dd 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/jnuexam.pdf
+++ b/Master/texmf-dist/doc/latex/jnuexam/jnuexam.pdf
Binary files differ
diff --git a/Master/texmf-dist/doc/latex/jnuexam/jnuexam.tex b/Master/texmf-dist/doc/latex/jnuexam/jnuexam.tex
index f41fb784f6c..bfc98e08349 100644
--- a/Master/texmf-dist/doc/latex/jnuexam/jnuexam.tex
+++ b/Master/texmf-dist/doc/latex/jnuexam/jnuexam.tex
@@ -5,9 +5,7 @@
\usepackage[UTF8,noindent]{ctex}
\usepackage{arev}
-\usepackage{ragged2e}
-\usepackage{listings}
-\usepackage{tabu}
+\usefonttheme{professionalfonts}
\makeatletter
@@ -28,39 +26,45 @@
\setlength{\parskip}{7pt plus 1pt minus 1pt}
-\justifying
-\let\oldraggedright\raggedright
-\let\raggedright\justifying
-
-\lstset{
- basicstyle=\ttfamily\color{blue!50!red}
-}
-
-\lstnewenvironment{code}{}{}
-
\setbeamersize{text margin left=8mm,text margin right=8mm}
-\newenvironment{framex}{\begin{frame}[fragile=singleslide,environment=framex]}{\end{frame}}
+\setbeamercolor{normal text}{bg=gray!20}
\setbeamertemplate{frametitle}{\strut\insertframetitle\strut\par}
\setbeamertemplate{navigation symbols}{}
+\newcommand{\cdotfill}{\leavevmode\xleaders\hbox to 0.5em{\hss$\cdot$\hss}\hfill\kern0pt\relax}
+
+\usepackage{tabularx}
+
\newcommand{\ulinefill}[1]{\xleaders\hbox{\underline{\vphantom{#1}\kern1pt}}\hfill\kern0pt}
\newcommand{\fillbox}[1]{\ulinefill{#1}\underline{#1}\ulinefill{#1}}
-\setbeamercolor{normal text}{bg=gray!20}
-
\setbeamertemplate{title page}{%
\renewcommand{\arraystretch}{2}%
\usebeamerfont{title}
- \begin{tabu}{|X|}
+ \begin{tabularx}{\linewidth}{|X|}
\hline
模板名称:\fillbox{\usebeamercolor[fg]{title}\inserttitle} \\
模板作者:\fillbox{\insertauthor} \\
所在单位:\fillbox{\insertinstitute} \\
更新日期:\fillbox{\the\year}年\fillbox{\the\month}月\fillbox{\the\day}日\\
\hline
- \end{tabu}%
+ \end{tabularx}%
+}
+
+\usepackage{ragged2e}
+
+\justifying
+\let\oldraggedright\raggedright
+\let\raggedright\justifying
+
+\usepackage{fancyvrb}
+
+\newenvironment{framex}{\begin{frame}[fragile=singleslide,environment=framex]}{\end{frame}}
+
+\DefineVerbatimEnvironment{code}{Verbatim}{%
+ formatcom=\color{blue!50!red}%
}
\begin{document}
@@ -136,6 +140,22 @@
\end{framex}
\begin{framex}
+\frametitle{判断题目}
+\begin{code}
+\makepart{判断题}{题数分值}
+
+\begin{problem}
+第一道判断题描述。\true
+\end{problem}
+
+\begin{problem}
+第二道判断题描述。\false
+\end{problem}
+\end{code}
+其中 \verb!\true! 和 \verb!\false! 命令分别表示正确和错误。
+\end{framex}
+
+\begin{framex}
\frametitle{填空题目}
\begin{code}
\makepart{填空题}{题数分值}
@@ -243,6 +263,15 @@
\end{framex}
\begin{framex}
+\frametitle{解答名称}
+通过重新定义 \verb!\solutionname! 命令,可以改变 \verb!solution! 环境的名称。
+比如下面例子将“解答”二字改为“证明”:
+\begin{code}
+\renewcommand{\solutionname}{证明}
+\end{code}
+\end{framex}
+
+\begin{framex}
\frametitle{评分命令}
计算题和证明题等主观题的排版方法是完全一样的。在编写这些主观题的解答时,
可以用 \verb!\score! 命令给出各步骤得分。比如:
@@ -256,6 +285,40 @@ $2+2=4$ \score{8}
\end{framex}
\begin{framex}
+\frametitle{对齐命令}
+此文档类提供几个对齐命令,用于在不同行之间对齐。比如
+\vskip1em\hrule
+我们有$(a+b)^2 = (a+b)(a+b)$ \par
+\leavevmode\phantom{我们有$(a+b)^2$}${}= a^2 + 2ab + b^2$ \cdotfill 2分
+\vskip0.6em\hrule\vskip1em
+\begin{code}
+我们有$(a+b)^2 \? = (a+b)(a+b)$ \\
+ \+$= a^2+2ab+b^2$ \score{2}
+\end{code}
+第一个公式内部的 \verb!\?! 保存当前水平位置,
+而第二个公式前面的 \verb!\+! 表示跳到之前保存的位置。
+\par
+这两个对齐命令 \verb!\?! 和 \verb!\+! 需要编译两次才能生效。
+\end{framex}
+
+\begin{framex}
+\frametitle{对齐命令}
+此文档类提供几个对齐命令,用于在不同行的对齐。比如
+\vskip1em\hrule
+我们有$(a+b)^2 = (a+b)(a+b)$ \par
+\leavevmode\phantom{我们\,}${}= a^2 + 2ab + b^2$ \cdotfill 2分
+\vskip0.6em\hrule\vskip1em
+\begin{code}
+我们有 \? $(a+b)^2 = (a+b)(a+b)$ \\
+ \< $= a^2+2ab+b^2$ \score{2}
+\end{code}
+第一行公式前面的 \verb!\?! 保存当前水平位置,
+而第二行公式前面的 \verb!\<! 表示跳到之前保存位置的左侧(左移一个等号的宽度)。
+\par
+这两个对齐命令 \verb!\?! 和 \verb!\<! 需要编译两次才能生效。
+\end{framex}
+
+\begin{framex}
\frametitle{其它题型}
除了上述四种题型之外,其它题型可以用下面方式编写:
\begin{code}
@@ -308,7 +371,7 @@ $2+2=4$ \score{8}
\frametitle{竖直空白}
在试卷的各个小题后面,可以留下一些竖直空白。本文档类支持下列这些竖直空白命令:\par
\renewcommand{\arraystretch}{1.3}%
-\begin{tabu}{XX}
+\begin{tabularx}{\linewidth}{l<{\qquad}X}
\hline
\texttt{\string\smallskip} & 竖直小空白 \\
\hline
@@ -318,7 +381,7 @@ $2+2=4$ \score{8}
\hline
\texttt{\string\vfill} & 竖直填充 \\
\hline
-\end{tabu}
+\end{tabularx}\par
当然,竖直空白命令可以连续使用多个,以得到所需的空白。
\end{framex}
@@ -329,7 +392,7 @@ $2+2=4$ \score{8}
分别只对 A 卷和 B 卷有效。
\par
\renewcommand{\arraystretch}{1.3}%
-\begin{tabu}{XX[2]}
+\begin{tabularx}{\linewidth}{l<{\qquad}X}
\hline
\texttt{\string\newpage} & 分页,对A卷和B卷均有效 \\
\hline
@@ -337,7 +400,7 @@ $2+2=4$ \score{8}
\hline
\texttt{\string\newpageb} & 分页,仅对B卷有效 \\
\hline
-\end{tabu}
+\end{tabularx}\par
在试卷中\alert{不要}使用其他分页命令,比如 \verb!\clearpage! 等。
\end{framex}