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% https://tex.stackexchange.com/q/466584
\documentclass{article}
\usepackage{xsim}
\usepackage{needspace}
\usepackage{tasks}
\DeclareExerciseEnvironmentTemplate{exandsol}{%
\par\vspace{\baselineskip}
\Needspace*{2\baselineskip}
\noindent\sffamily
\textbf{\XSIMmixedcase{\GetExerciseName}~\GetExerciseProperty{counter}}%
\GetExercisePropertyT{subtitle}{\hspace{3em}{\small#1}}\par
\normalfont
}{}
\DeclareExerciseEnvironmentTemplate{flushright}{%
\begin{flushright}
\begin{minipage}{.4\linewidth}
\textsf{Solutions:}\par\normalfont
}{%
\end{minipage}%
\end{flushright}%
}
\xsimsetup{
exercise/within = section ,
exercise/template = exandsol ,
solution/template = flushright ,
solution/print = true
}
\renewcommand*\theexercise{\thesection-\arabic{exercise}}
\newcommand\QA[2]{\IfInsideSolutionTF{#2}{#1}}
\newcommand*\answer[1]{%
\begingroup
\def\ExerciseType{exercise}%
\IfSolutionPrintT{\printsolution{exercise}{#1}}%
\endgroup
}
\begin{document}
\setcounter{section}{1}
\setcounter{exercise}{30}
\begin{exercise}[ID=one,solution,subtitle=Factorize as much as possible the following expressions.]
\begin{tasks}
\task \QA{$(2x-3)^2 - (3x-2)^2 =$}{$-(x+5)(5x-1)$}
\task \QA{$(x^2-25) - 2(5-x)(x+6) =$}{$(x+5)(3x-17)$}
\task \QA{$2x(x+2) + (x+1)^2 + 2 =$}{$3(x+1)^2$}
\end{tasks}
\end{exercise}
\answer{one}
\end{document}
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