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\documentclass[a4paper,12pt]{report}
\usepackage{german,ochem}
\begin{document}
Als Beispiel f"ur ein gleitendes Reaktionsschema soll die Synthese
der Chrysanthemums"aure in Schema~\ref{chrysanth} dienen.
\begin{schema}
\begin{chemistry}[darv1]
set("rArrowExtend",18)
joinv(2,B)
{ joinv(2,B)
{ formula(T,B)
{ bond(30,=; -30; 30)
branch { bond(150); bond(30) atom("OH",L); } bond(-30)
}
arrow(-90){ text(T,L){formula(C,C){atom("HBr")}}}
formula(T,B)
{ atom("Br") bond(30; -30; 30,=)
branch { bond(90); } bond(-30)
};
formula(T,B,"Tosylchlorid",V,24)
{ ring(){ 2: bond(r); 5: bond(r) atom("SO$_2$Cl",L); }
}
arrow(-90)
{ text(T,L){formula(C,C){atom("NaOH")}}
text(B,L){formula(C,C){atom("Zn")}}
}
formula(T,B)
{ ring(){ 2: bond(r); 5: bond(r) atom("SO$_2$Na",L); }
};
}
arrow(-90){} % 80%
formula(T,B)
{ ring(){ 2: bond(r);
5: bond(r) atom("SO$_2$",L,R) bond(30; -30; 30,=)
branch{bond(90);} bond(-30); }
};
formula(T,B,"3-Methylbutens""aure",V,24)
{ bond(30) branch{ bond(90); } bond(-30,=; 30) atom("COOH",L)
}
arrow(-90){ text(T,L){formula(C,C){atom("CH$_3$OH")}}}
formula(T,B)
{ bond(30) branch{ bond(90); } bond(-30,=; 30) atom("CO$_2$CH$_3$",L)
};
}
arrow(-90){ text(T,L){formula(C,C){atom("NaOCH$_3$")}}}
formula(T,B)
{ ring()
{ 3: bond(r);
0: bond(r) atom("S")
branch { bond(180,=C) atom("O");
bond(0,=C) atom("O"); }
bond(-90)
saveXY(#1)
bond(-150) bond(150,=)
branch { bond(-150); bond(90); }
restoreXY(#1)
bond(-30) branch { bond(-150);
bond(-30); }
bond(30)
branch{ bond(90,s,S) atom("$\ominus$"); }
bond(-30) atom("CO$_2$CH$_3$",L);
}
}
bracket()
arrow(-90,10){}
arrow(-90,10){ text(T,L){formula(C,C){atom("KOH")}}}
formula(T,B,"\textit{trans}-Chrysanthemums""aure",V,24)
{ ring(,,H,,3,90)
{ 1: bond(r,<.) atom("COOH",L);
2: bond(150,<<) bond(-150,=) branch{ bond(-90); bond(150); };
0: bond(t);
0: bond(b);
}
}
\end{chemistry}
\caption{Chemie mit \LaTeX: Die Synthese der Chrysanthemums"aure als
Beispiel f"ur die Anwendung von \texttt{ochem.sty}.\label{chrysanth}}
\end{schema}
\end{document}
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