diff options
Diffstat (limited to 'macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-lines.tex')
-rw-r--r-- | macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-lines.tex | 36 |
1 files changed, 22 insertions, 14 deletions
diff --git a/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-lines.tex b/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-lines.tex index cc4177dd9f..4d42e3d571 100644 --- a/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-lines.tex +++ b/macros/latex/contrib/tkz/tkz-euclide/doc/latex/TKZdoc-euclide-lines.tex @@ -25,9 +25,9 @@ arguments & example & explanation \\ \toprule options & default & definition \\ \TOline{mediator}{}{perpendicular bisector of a line segment} -\TOline{perpendicular=through\dots}{mediator}{perpendicular to a straight line passing through a point} +\TOline{perpendicular=through\dots}{mediator}{perpendicular to a line passing through a point} \TOline{orthogonal=through\dots}{mediator}{see above } -\TOline{parallel=through\dots}{mediator}{parallel to a straight line passing through a point} +\TOline{parallel=through\dots}{mediator}{parallel to a line passing through a point} \TOline{bisector}{mediator}{bisector of an angle defined by three points} \TOline{bisector out}{mediator}{exterior angle bisector} \TOline{symmedian}{mediator}{symmedian from a vertex } @@ -59,7 +59,7 @@ options & default & definition \\ Based on a figure from O. Reboux with pst-eucl by D Rodriguez. \begin{tkzexample}[latex=7cm,small] -\begin{tikzpicture}[scale=.6] +\begin{tikzpicture}[scale=.75] % necessary \tkzInit[xmin=-6,ymin=-4,xmax=6,ymax=6] \tkzClip @@ -80,7 +80,7 @@ Based on a figure from O. Reboux with pst-eucl by D Rodriguez. Based on a figure from O. Reboux with pst-eucl by D Rodriguez. It is not necessary to name the two points that define the mediator. -\begin{tkzexample}[latex=7cm,small] +\begin{tkzexample}[latex=8cm,small] \begin{tikzpicture}[scale=.6] \tkzInit[xmin=-6,ymin=-4,xmax=6,ymax=6] \tkzClip @@ -112,11 +112,13 @@ It is not necessary to name the two points that define the mediator. Archimedes' Book of Lemmas proposition 1 \begin{tkzexample}[latex=7cm,small] - \begin{tikzpicture}[scale=.75] + \begin{tikzpicture} \tkzDefPoints{0/0/O_1,0/1/O_2,0/3/A} \tkzDefPoint(15:3){F} - \tkzInterLC(F,O_1)(O_1,A) \tkzGetSecondPoint{E} - \tkzDefLine[parallel=through O_2](E,F) \tkzGetPoint{x} + \tkzDefPointBy[symmetry=center O_1](F) + \tkzGetPoint{E} + \tkzDefLine[parallel=through O_2](E,F) + \tkzGetPoint{x} \tkzInterLC(x,O_2)(O_2,A) \tkzGetPoints{D}{C} \tkzDrawCircles(O_1,A O_2,A) \tkzDrawSegments[new](O_1,A E,F C,D) @@ -169,10 +171,12 @@ Archimedes' Book of Lemmas proposition 1 \subsubsection{ With option \tkzname{euler}} % (fold) \label{sub:eulerline} \begin{tkzexample}[latex=7 cm,small] -\begin{tikzpicture} +\begin{tikzpicture}[scale=.75] \tkzDefPoints{0/0/A,6/0/B,0.8/4/C} -\tkzDefLine[euler](A,B,C) \tkzGetPoints{h}{e} -\tkzDefTriangleCenter[circum](A,B,C) \tkzGetPoint{o} +\tkzDefLine[euler](A,B,C) +\tkzGetPoints{h}{e} +\tkzDefTriangleCenter[circum](A,B,C) +\tkzGetPoint{o} \tkzDrawPolygon[teal](A,B,C) \tkzDrawPoints[red](A,B,C,h,e,o) \tkzDrawLine[add= 2 and 2](h,e) @@ -205,18 +209,22 @@ The tangent is not drawn. With option \tkzname{at}, a point of the tangent is g \begin{tkzexample}[latex=7cm,small] \begin{tikzpicture}[scale=1,rotate=-30] \tkzDefPoints{0/0/Q,0/2/A,6/-1/O} -\tkzDefLine[tangent from = O](Q,A) \tkzGetPoints{R}{S} -\tkzInterLC[near](O,Q)(Q,A) \tkzGetPoints{M}{N} +\tkzDefLine[tangent from = O](Q,A) +\tkzGetPoints{R}{S} +\tkzInterLC[near](O,Q)(Q,A) +\tkzGetPoints{M}{N} \tkzDrawCircle(Q,M) \tkzDrawSegments[new,add = 0 and .2](O,R O,S) \tkzDrawSegments[gray](N,O R,Q S,Q) \tkzDrawPoints(O,Q,R,S,M,N) \tkzMarkAngle[gray,-stealth,size=1](O,R,Q) \tkzFindAngle(O,R,Q) \tkzGetAngle{an} -\tkzLabelAngle(O,R,Q){$\pgfmathprintnumber{\an}^\circ$} +\tkzLabelAngle(O,R,Q){% + $\pgfmathprintnumber{\an}^\circ$} \tkzMarkAngle[gray,-stealth,size=1](O,S,Q) \tkzFindAngle(O,S,Q) \tkzGetAngle{an} -\tkzLabelAngle(O,S,Q){$\pgfmathprintnumber{\an}^\circ$} +\tkzLabelAngle(O,S,Q){% + $\pgfmathprintnumber{\an}^\circ$} \tkzLabelPoints(Q,O,M,N,R) \tkzLabelPoints[above,text=red](S) \end{tikzpicture} |