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# tkz-euclide — for euclidean geometry
-
-Release 5.04c 2023/10/26
+Release 5.05c 2024/01/16
## Description
@@ -64,6 +63,7 @@ Other examples, in French, are on my site.
## History
+- 5.05c Correction of the documentation.
- 5.04c Some files have been renamed.
@@ -107,8 +107,7 @@ Complement in the documentation for the macro `\tkzDefCircle[R](....)`. You can
Thus `\tkzDrawSquare(A,B)` becomes `\tkzDefSquare(A,B)` `\tkzGetPoints{C}{D}` then
`\tkzDrawPolygon(A,B,C,D)` ;
-
-
+
If you want to draw a circle, you can't do so \tkzDrawCircle[R](A,1) . First you have to define the point through which the circle passes, so you have to do
`\tkzDefCircle[R](A,1)` `\tkzGetPoint{a}` and finally `\tkzDrawCircle(A,a)` . Another possibilty is to define a point on the circle `\tkzDefShiftPoint[A](1,O){a}` ;
@@ -150,32 +149,24 @@ Complement in the documentation for the macro `\tkzDefCircle[R](....)`. You can
Correct allocation for gold sublime and euclide triangles;
-
I added the option " next to" for the intersections LC and CC;
-
Correction option isoceles right;
-
`\tkzDefMidArc(O,A,B)` gives the middle of the arc center $O$ from $A$ to $B$;
Good news : Some useful tools have been added. They are present on an experimental basis and will undoubtedly need to be improved;
-
The options "orthogonal from and through" depend now of `tkzDefCircleBy`
-
`\tkzDotProduct(A,B,C)` computes the scalar product in an orthogonal reference system of the vectors $\overrightarrow{A,B}$ and $\overrightarrow{A,C}$.
`\tkzDotProduct(A,B,C)=aa'+bb' if vec{AB} =(a,b) and vec{AC} =(a',b')`
-
`\tkzPowerCircle(A)(B,C)` power of point $A$ with respect to the circle of center $B$ passing through $C$;
-
`\tkzDefRadicalAxis(A,B)(C,D)` Radical axis of two circles of center $A$ and $C$;
-
Some tests : `\tkzIsOrtho(A,B,C)` and `\tkzIsLinear(A,B,C)` The first indicates whether the lines AB and AC are orthogonal. The second indicates whether the points $A$, $B$ and $C$ are aligned;
`\tkzIsLinear(A,B,C)` if A, B, C are aligned then \tkzLineartrue