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+\section{Global Environment Options \tkzname{alterqcm}}
+
+\subsection{\tkzname{lq} : changing the width of the first column }
+\IoptEnv{alterqcm}{lq}
+
+\begin{alterqcm}[long,lq=110mm]
+\AQquestion{Of the following proposals, which one allows of
+ to assert that the exponential function admits for asymptote
+ the equation line $y = 0$ ?}
+{{$\displaystyle\lim_{x \to +\infty} \text{e}^x = + \infty$},
+{$\displaystyle\lim_{x \to -\infty} \text{e}^x = 0$},
+{$\displaystyle\lim_{x \to +\infty} \dfrac{\text{e}^x}{x} = + \infty$}}
+
+\AQquestion{exp$(\ln x) = x$ for any $x$ belonging to }
+{{$\mathbb{R}$},
+{$\big]0~;~+ \infty\big[$},
+{$\big[0~;~+\infty\big[$}
+}
+\end{alterqcm}
+
+\medskip
+Let's look at the code needed to get this table. We need to place
+\tkzcname{usepackage}\{alterqcm\} in the preamble. Note that only the width of the question column is provided |lq=100mm| and that this is optional. The number of propositions is here \textbf{3} but it can vary from one question to another.
+
+\begin{tkzexample}[code only,small]
+ \begin{alterqcm}[long,lq=110mm]
+ \AQquestion{Of the following proposals, which one allows of
+ to assert that the exponential function admits for asymptote
+ the equation line $y = 0$ ?}
+ {{$\displaystyle\lim_{x \to +\infty} \text{e}^x = + \infty$},
+ {$\displaystyle\lim_{x \to -\infty} \text{e}^x = 0$},
+ {$\displaystyle\lim_{x \to +\infty} \dfrac{\text{e}^x}{x} = + \infty$}}
+
+ \AQquestion[]{exp$(\ln x) = x$ for any $x$ belonging to }
+ {{$\mathbb{R}$},
+ {$\big]0~;~+ \infty\big[$},
+ {$\big[0~;~+\infty\big[$}
+ }
+ \end{alterqcm}\end{tkzexample}
+
+
+
+\subsection{\tkzname{pq} : global use }
+ \IoptEnv{alterqcm}{pq}
+
+This time, it is necessary to move several questions, I placed a pq=2mm globally, that is to say like this~:
+
+\tkzcname{begin\{alterqcm\}[lq=85mm,pq=2mm]}.
+
+\textbf{All} questions are affected by this option but some questions were well placed and should remain so, so locally I give them back a |pq=0mm|.
+
+\medskip
+\begin{alterqcm}[lq=85mm,pq=2mm]
+\AQquestion{A bivariate statistical series. The values of $x$ are 1, 2, 5, 7, 11, 13 and a least squares regression line equation of $y$ to $x$ is $y = 1.35x +22.8$. The coordinates of the mean point are :}
+{{$(6,5;30,575)$},
+{$(32,575 ; 6,5)$},
+{$(6,5 ; 31,575)$}}
+
+\AQquestion{For any real $x$, the number \[\dfrac{\text{e}^x - 1}{\text{e}^x + 2}\hskip12pt \text{equal to :} \] }
+{{$-\dfrac{1}{2}$},
+{$\dfrac{\text{e}^{-x} - 1}{\text{e}^{-x} + 2}$},
+{$\dfrac{1 - \text{e}^{-x}}{1 + 2\text{e}^{-x}}$}
+}
+\AQquestion{With I $= \displaystyle\int_{\ln 2}^{\ln 3} \dfrac{1}{\text{e}^x - 1}\,\text{d}x$ and J $ = \displaystyle\int_{\ln 2}^{\ln 3} \dfrac{\text{e}^x}{\text{e}^x - 1}\,\text{d}x$ \\ then the number I $-$ J equals}
+{{$\ln \dfrac{2}{3}$},
+{$\ln \dfrac{3}{2}$},
+{$\dfrac{3}{2}$}
+}
+\end{alterqcm}
+
+\begin{tkzexample}[code only,small]
+ \begin{alterqcm}[lq=85mm,pq=2mm]
+ \AQquestion{For any real $x$, the number \[\dfrac{\text{e}^x - 1}
+ {\text{e}^x + 2}\hskip12pt \text{equal to :} \] }
+ {{$-\dfrac{1}{2}$},
+ {$\dfrac{\text{e}^{-x} - 1}{\text{e}^{-x} + 2}$},
+ {$\dfrac{1 - \text{e}^{-x}}{1 + 2\text{e}^{-x}}$}}
+ \end{alterqcm}
+\end{tkzexample}
+
+
+\subsection{\tkzname{TF} : True or False}
+\IoptEnv{alterqcm}{TF}
+V or F in french vrai ou faux !
+There are only two proposals and the candidate must choose between \textbf{True} or \textbf{False} ou bien si vous préférez \textbf{Correct} and \textbf{Wrong}. This time the syntax has been streamlined. It is no longer necessary to write the list of proposals and it is enough to position \tkzname{VF} by placing in the options \tkzname{$VF$}.
+
+
+\begin{minipage}[t][][b]{.45\linewidth}
+Let $f$ be a function defined and derivable on the interval $\big[-3~;~+\infty\big[$, increasing over the intervals $\big[-3~;~-1\big]$ et $\big[2~;~+\infty\big[$ and decreasing over the interval $\big[-1~;~2\big]$.
+
+ We note $f'$ its derivative function over the interval $[-3~;~+\infty[$.
+
+The $\Gamma$ curve representative of the $f$ function is plotted below in an orthogonal coordinate system $\big(O,~\vec{\imath},~\vec{\jmath}\big)$.
+
+It passes through point A$(-3~;~0)$ and admits for asymptote the $\Delta$ line of equation $y = 2x -5$.
+\end{minipage}
+\hfill
+\begin{minipage}[t][][b]{.45\linewidth}
+\null
+\begin{tikzpicture}[scale=0.5,>=latex]
+ \draw[very thin,color=gray] (-3,-2) grid (10,8);
+ \draw[->] (-3,0) -- (10,0) node[above left] {\small $x$};
+ \foreach \x in {-3,-2,-1,1,2,...,9}
+ \draw[shift={(\x,0)}] (0pt,1pt) -- (0pt,-1pt)node[below] { $\x$};
+ \draw[->] (0,-2) -- (0,8) node[below right] {\small $y$};
+ \foreach \y/\ytext in {-2,-1,1,2,...,7}
+ \draw[shift={(0,\y)}] (1pt,0pt) -- (-1pt,0pt) node[left] { $\y$};
+ \draw (2,-1) -- (6,7);
+ \node[above right] at (-3,0) {\textbf{A}};
+ \node[above right] at (0,0) {\textbf{O}};
+ \node[below right] at (4,3) {$\mathbf{\Delta}$};
+ \node[above right] at (4,5) {$\mathbf{\Gamma}$};
+ \draw plot[smooth] coordinates{%
+ (-3,0)(-2,4.5)(-1,6.5)(0,5.5)(1,3.5)(2,3)(3,3.4)(4,4.5)(5,6)(6,7.75)};
+\end{tikzpicture}
+\end{minipage}
+
+
+\begin{alterqcm}[VF,lq=125mm]
+ \AQquestion{For all $x \in ]-3~;~2],~f'(x) \geqslant 0$.}
+ \AQquestion{The $F$ function has a maximum in $2$}
+ \AQquestion{$\displaystyle\int_{0}^2 f'(x)\,\text{d}x = - 2$}
+\end{alterqcm}
+
+\begin{tkzexample}[code only, small]
+ \begin{minipage}[t][][b]{.45\linewidth}
+ Let $f$ be a function defined and derivable on the interval $\big[-3~;~+\infty\big[$,
+ increasing over the interval $\big[-3~;~-1\big]$ and $\big[2~;~+\infty\big[$
+ and decreasing over the interval $\big[-1~;~2\big]$.
+
+ We note $f'$ its derivative function over the interval $[-3~;~+\infty[$.
+
+ The $\Gamma$ curve representative of the $f$ function is plotted below
+ in an orthogonal system $\big(O,~\with{\imath},~\jmath}\big)$.
+
+ It passes through the point A$(-3~;~0)$ and admits for asymptote the line
+ $\Delta$ of equation $y = 2x -5$.
+ \end{minipage}
+ \begin{minipage}[t][][b]{.45\linewidth}
+ \null
+\begin{tikzpicture}[scale=0.5,>=latex]
+ \draw[very thin,color=gray] (-3,-2) grid (10,8);
+ \draw[->] (-3,0) -- (10,0) node[above left] {\small $x$};
+ \foreach \x in {-3,-2,-1,1,2,...,9}
+ \draw[shift={(\x,0)}] (0pt,1pt) -- (0pt,-1pt)node[below] { $\x$};
+ \draw[->] (0,-2) -- (0,8) node[below right] {\small $y$};
+ \foreach \y/\ytext in {-2,-1,1,2,...,8}
+ \draw[shift={(0,\y)}] (1pt,0pt) -- (-1pt,0pt) node[left] { $\y$};
+ \draw (-0.5,-2) -- (10,8);
+ \node[above right] at (-3,0) {\textbf{A}};
+ \node[above right] at (0,0) {\textbf{O}};
+ \node[below right] at (4,3) {$\mathbf{\Delta}$};
+ \node[above right] at (4,5) {$\mathbf{\Gamma}$};
+ \draw plot[smooth] coordinates{%
+ (-3,0)(-2,4.5)(-1,6.5)(0,5.5)(1,3.5)(2,3)(3,3.4)(4,4.5)(5,6)(6,7.75)};
+ \end{tikzpicture}
+ \end{minipage}
+ \begin{alterqcm}[VF,lq=125mm]
+ \AQquestion{For all $x \in ]-\infty~;~2],~f'(x) \geqslant 0$.}
+ \AQquestion{The $F$ function has a maximum in $2$}
+ \AQquestion{$\displaystyle\int_{0}^2 f'(x)\:\text{d}x = - 2$}
+ \end{alterqcm}
+\end{tkzexample}
+
+\subsection{\tkzname{symb} : symbol change }
+\IoptEnv{alterqcm}{symb}
+
+ If your fonts don't have the symbol |$\square$| or |$\blacksquare$| you can use the one provided by the package or create one yourself. \tkzcname{altersquare}, \tkzcname{dingsquare} and \tkzcname{dingchecksquare} are provided by alterqcm.
+ Here is how these macros are defined.
+
+\begin{tkzexample}[code only,small]
+ \newcommand*{\altersquare}{\mbox{\vbox{\hrule\hbox to 6pt{\vrule height 5.2pt \hfil\vrule}\hrule}}}\end{tkzexample}
+
+\medskip you either get \altersquare\ or... :
+
+\begin{tkzexample}[code only,small]
+ \newcommand*{\dingsquare}{\ding{114}} \end{tkzexample}
+
+\medskip which results in \dingsquare\ and finally to replace |$\blacksquare$|
+
+\begin{tkzexample}[code only,small]
+ \newcommand*{\dingchecksquare}{\mbox{\ding{114}%
+ \hspace{-.7em}\raisebox{.2ex}[1ex]{\ding{51}}}} \end{tkzexample}
+
+\medskip Let it be \dingchecksquare\ as a result.
+
+
+\begin{tkzexample}[code only,small]
+
+ \begin{alterqcm}[lq=90mm,symb=\altersquare]
+ ... \end{alterqcm}\end{tkzexample}
+
+\medskip
+Full example :
+
+\medskip
+\begin{tkzexample}[vbox]
+ \begin{alterqcm}[VF,lq=125mm,symb = \dingsquare]
+ \AQquestion{For all $x \in ]-3~;~2],~f'(x) \geqslant 0$.}
+ \AQquestion{The $F$ function has a maximum in $2$}
+ \AQquestion{$\displaystyle\int_{0}^2 f'(x)\:\text{d}x = - 2$}
+ \end{alterqcm}\end{tkzexample}
+
+
+\subsection{\tkzname{pre, bonus, malus} : automatic presentation }
+\IoptEnv{alterqcm}{pre}\IoptEnv{alterqcm}{bonus}\IoptEnv{alterqcm}{malus}
+As you can see below, a presentation is given of the exercise with the grading.
+
+\bigskip
+\begin{minipage}[c][][t]{.45\linewidth}
+\begin{tkzexample}[code only,small]
+ \begin{alterqcm}[lq=6cm,pre=true,bonus=1,malus={0,5}]
+ \AQquestion{Question}
+ {{Proposition 1},
+ {Proposition 2}}
+ \end{alterqcm}\end{tkzexample}
+\end{minipage}\hfill
+\begin{minipage}[c][][t]{.45\linewidth}
+ \begin{alterqcm}[lq=3cm,pre=true,bonus=1,malus={0,5}]
+ \AQquestion{Question}
+ {{Proposition 1},
+ {Proposition 2}}
+ \end{alterqcm}
+\end{minipage}
+
+\vspace{1cm}
+
+\subsection{\tkzname{sep} : rule between proposals}
+\IoptEnv{alterqcm}{sep}
+
+\tkzname{sep=true} creates a rule between the proposals.
+
+\begin{minipage}[c][][t]{.45\linewidth}
+\begin{tkzexample}[code only,small]
+ \begin{alterqcm}[lq=3cm,sep=true]
+ \AQquestion{Question}
+ etc..
+\end{alterqcm}\end{tkzexample}
+\end{minipage}\hfill
+\begin{minipage}[c][][t]{.45\linewidth}
+ \begin{alterqcm}[lq=3cm,sep=true]
+ \AQquestion{Question}
+ {{Proposition 1},
+ {Proposition 2}}
+ \end{alterqcm}
+\end{minipage}
+
+\subsection{\tkzname{num, numstyle} : deletion and style of numbering }
+\IoptEnv{alterqcm}{num}\IoptEnv{alterqcm}{numstyle}
+\subsubsection{\tkzname{num=false}}
+\tkzname{num=false} makes the numbering of the questions disappear.
+
+\begin{minipage}[c][][t]{.45\linewidth}
+\begin{tkzexample}[code only, small]
+ \begin{alterqcm}[lq=3cm,num=false]
+ \AQquestion{Question}
+ etc...
+ \end{alterqcm}
+\end{tkzexample}
+\end{minipage}\hfill
+\begin{minipage}[c][][t]{.45\linewidth}
+ \begin{alterqcm}[lq=3cm,num=false]
+ \AQquestion{Question}
+ {%
+ {Proposition 1},
+ {Proposition 2}}
+ \end{alterqcm}
+\end{minipage}
+
+\subsubsection{\tkzname{numstyle}}
+
+\tkzname{numstyle}=\tkzcname{alph} changes the style of question numbering. The usual styles are valid here.
+
+\begin{minipage}[c][][t]{.45\linewidth}
+\begin{tkzexample}[code only, small]
+ \begin{alterqcm}[lq=3cm,numstyle=\alph]
+ \AQquestion{Question}
+ etc...
+ \end{alterqcm}
+\end{tkzexample}
+\end{minipage}
+\hfill
+\begin{minipage}[c][][t]{.45\linewidth}
+ \begin{alterqcm}[lq=3cm,numstyle=\alph]
+ \AQquestion{Question}
+ {%
+ {Proposition 1},
+ {Proposition 2}}
+ \end{alterqcm}
+\end{minipage}
+
+\subsection{\tkzname{title, tone, ttwo} : deletion and modification of the title line }
+\IoptEnv{alterqcm}{title}\IoptEnv{alterqcm}{tone}\IoptEnv{alterqcm}{ttwo}
+
+\tkzname{title=false} deletes the column headings.
+
+\begin{minipage}[c][][t]{.45\linewidth}
+\begin{tkzexample}[code only,vbox]
+ \begin{alterqcm}[lq=3cm,title=false]
+ \AQquestion{Question}
+ etc...
+ \end{alterqcm}\end{tkzexample}
+\end{minipage}\hfill
+\begin{minipage}[c][][t]{.45\linewidth}
+ \begin{alterqcm}[lq=3cm,title=false]
+ \AQquestion{Question}
+ {%
+ {Proposition 1},
+ {Proposition 2}%
+ }
+ \end{alterqcm}
+\end{minipage}
+
+
+\medskip
+\tkzname{tone=titre n°1} and \tkzname{ttwo=titre n°2} change the table headers
+
+\begin{minipage}[c][][t]{.45\linewidth}
+\begin{tkzexample}[code only]
+ \begin{alterqcm}[lq=3cm,tone=titre n°1,ttwo=titre n°2]
+ \AQquestion{Question}
+ etc...
+ \end{alterqcm}\end{tkzexample}
+\end{minipage}\hfill
+\begin{minipage}[c][][t]{.45\linewidth}
+ \begin{alterqcm}[lq = 3cm,tone = titre n°1,ttwo = titre n°2]
+ \AQquestion{Question}
+ {{Proposition 1},
+ {Proposition 2}
+ }
+ \end{alterqcm}
+\end{minipage}
+
+\subsection{\tkzname{noquare} : square suppression }
+\IoptEnv{alterqcm}{nosquare}
+
+\tkzname{nosquare=true} fait disparaître le carré ou encore la numérotation des propositions.
+
+\begin{minipage}[c][][t]{.45\linewidth}
+\begin{tkzexample}[code only,small]
+ \begin{alterqcm}[lq=3cm,nosquare=true]
+ \AQquestion{Question}
+ etc...
+ \end{alterqcm}\end{tkzexample}
+\end{minipage}\hfill
+\begin{minipage}[c][][t]{.45\linewidth}
+ \begin{alterqcm}[lq=3cm,nosquare=true]
+ \AQquestion{Question}
+ {%
+ {Proposition 1},
+ {Proposition 2}
+ }
+ \end{alterqcm}
+\end{minipage}
+
+\medskip
+\tkzname{numprop=true} number the proposals and \tkzname{propstyle= ...} changes the numbering style.
+
+Default, \tkzname{propstyle=\textbackslash alph}
+
+\begin{minipage}[c][][t]{.45\linewidth}
+\begin{tkzexample}[code only,small]
+ \begin{alterqcm}[lq=3cm,numprop = true,propstyle = \Roman]
+ \AQquestion{Question}
+ etc...
+ \end{alterqcm}\end{tkzexample}
+\end{minipage}\hfill
+\begin{minipage}[c][][t]{.45\linewidth}
+ \begin{alterqcm}%
+ [lq=3cm,
+ numprop = true,
+ propstyle = \Roman]
+ \AQquestion{Question}
+ {%
+ {Proposition 1},
+ {Proposition 2}%
+ }
+ \end{alterqcm}
+\end{minipage}
+
+\subsection{\tkzname{alea} : random positioning of proposals }
+\IoptEnv{alterqcm}{alea}
+
+It is preferable between two compilations to delete the auxiliary files.
+
+\textcolor{red}{\lefthand} Be careful, in random mode, it is not possible to obtain an answer corresponding to the initial assignment.
+
+\begin{tkzexample}[small]
+ \begin{alterqcm}[lq=55mm,alea]
+ \AQquestion[pq=1mm]{If the $f$ function is strictly increasing on $\mathbf{R}$ then the equation $f(x) = $0 admits :}
+ {{At least one solution},%
+ {At most one solution},%
+ {Exactly one solution}}
+ \end{alterqcm}
+\end{tkzexample}
+
+\subsection{\tkzname{english}, \tkzname{german}, \tkzname{greek}, \tkzname{italian}, \tkzname{russian}, \tkzname{chinese}\ and \tkzname{unknown} : language change }
+\IoptEnv{alterqcm}{english}\IoptEnv{alterqcm}{german}\IoptEnv{alterqcm}{french}
+
+The order given above is that of creation.
+Thanks to Apostolos Syropoulos and Anastasios Dimou for enabling the use of Greek language.
+
+ \begin{tkzexample}[code only,small]
+ \begin{alterqcm}[language=french,lq=55mm,alea]
+ \end{tkzexample}
+
+ \begin{alterqcm}[language=french,lq=55mm,alea]
+ \AQquestion[pq=1mm]{If the $f$ function is strictly increasing on $\mathbf{R}$
+ then the equation equation $f(x) = $0 admits...}
+ {{At least one solution},%
+ {At most one solution},%
+ {Exactly one solution}}
+ \end{alterqcm}
+
+ \begin{tkzexample}[code only,small]
+ \begin{alterqcm}[language=german,lq=55mm,alea] \end{tkzexample}
+
+\begin{alterqcm}[language=german,lq=55mm,alea]
+\AQquestion[pq=1mm]{Wenn die Funktion $f$ %
+ auf $\mathbf{R}$ streng monoton wächst, dann
+hat die Gleichung $f(x) = 0$:}
+{{mindestens ein Lösung},%
+{höchstens eine Lösung},%
+{genau eine Lösung}}
+\end{alterqcm}
+
+
+\begin{alterqcm}[language=chinese,VF,lq=125mm,symb = \dingsquare,pre=true]
+\def\aq@pre{对于以下提出的各个问题,仅有一个答案是正确的,请选择你认为正确的答案(不需要提供理由)。}
+ \AQquestion{$x \in ]-3~;~2]$的情形下,$f'(x) \geq 0$。}
+ \AQquestion{$F$ 函数的最大值为$2$。}
+ \AQquestion{$\displaystyle\int_{0}^2 f’(x)\:\text{d}x = - 2$}
+ \end{alterqcm}
+
+ \begin{alterqcm}[language=chinese,pre=true]
+ \AQquestion{问题}{%
+ {选择1},
+ {选择2},
+ {选择3}}
+ \end{alterqcm}
+
+
+There's a section devoted solely to the "greek" option.
+
+
+How to use \tkzname{unknown} : You need to call the package with the option "unknown" then yo need to redefine some macros.
+
+\begin{tkzexample}[code only,small]
+\usepackage[unknown]{alterqcm}
+% userdefined language: unknown=spanish
+\def\aqlabelforquest{Preguntas}%
+\def\aqlabelforrep{Respuestas}%
+\def\aqtextfortrue{\textbf{V}}
+\def\aqtextforfalse{\textbf{F}}
+\def\txttv{V}% V(erdadero)
+\def\txttf{F}% F(also)
+\def\aqfoottext{Continúa en la página siguiente\dots}
+\def\aqpretxt{\vspace*{6pt}Para cada una de las preguntas siguientes, sólo una de las respuestas propuestas es verdadera. Debe elegir la respuesta correcta sin justificación.}%
+\def\aqpretxtVF{Para cada una de las afirmaciones de abajo, marque la casilla \textbf{V} (la afirmación es verdadera) o la casilla \textbf{F} (la afirmación es falsa).}%
+
+\begin{alterqcm}[language=unknown]
+ \AQquestion{Question}{%
+ {Proposition 1},
+ {Proposition 2},
+ {Proposition 3}}
+\end{alterqcm}
+
+ \end{tkzexample}
+\begingroup
+\def\aqlabelforquest{Preguntas}%
+\def\aqlabelforrep{Respuestas}%
+\def\aqtextfortrue{\textbf{V}}
+\def\aqtextforfalse{\textbf{F}}
+\def\txttv{V}% V(erdadero)
+\def\txttf{F}% F(also)
+\def\aqfoottext{Continúa en la página siguiente\dots}
+\def\aqpretxt{\vspace*{6pt}Para cada una de las preguntas siguientes, sólo una de las respuestas propuestas es verdadera. Debe elegir la respuesta correcta sin justificación.}%
+\def\aqpretxtVF{Para cada una de las afirmaciones de abajo, marque la casilla \textbf{V} (la afirmación es verdadera) o la casilla \textbf{F} (la afirmación es falsa).}%
+
+ \begin{alterqcm}[language=unknown]
+ \AQquestion{Question}{%
+ {Proposition 1},
+ {Proposition 2},
+ {Proposition 3}}
+ \end{alterqcm}
+ \endgroup
+
+
+\newpage
+\subsection{\tkzname{long} : use of longtable}
+\IoptEnv{alterqcm}{long}\Ienv{longtable}
+
+A table can arrive at the end of the page and be cut or simply be very long.
+This option allows you to use instead of a \tkzname{tabular} an environnement \tkzname{longtable}.
+
+
+Here is an example from Pascal Bertolino.
+
+\begin{alterqcm}[lq=80mm,long]
+
+%--------------------------------------------------------------
+\AQquestion{What was the precursor language of the C language?}
+{{Fortran},
+ {language B},
+ {Basic}}
+
+%--------------------------------------------------------------
+\verbdef\argprop|int a = 3 ^ 4 ;|
+\AQquestion{\argprop}
+{{raises 3 to the power of 4},
+ {makes an exclusive OR between 3 and 4},
+ {is not a C}}
+
+%--------------------------------------------------------------
+\AQquestion{What is the correct syntax to shift the integer 8 bits to the left? \texttt{a} ?}
+{{\texttt{b = lshift(a, 8) ;}},
+ {\texttt{b = 8 << a ;}},
+ {\texttt{b = a << 8 ;}}}
+
+%--------------------------------------------------------------
+\verbdef\argprop|{ printf ("hello") ; return 0 ; \}|
+\AQquestion{The complete program : \\
+ \texttt{int main() \\
+ ~~\argprop}}
+{{display \texttt{hello}},
+ {gives an error to the compilation},
+ {gives an error in execution}}
+
+%--------------------------------------------------------------
+\verbdef\arg|float tab[10]|
+\verbdef\propa|*tab|\global\let\propa\propa
+\verbdef\propb|&tab|\global\let\propb\propb
+\verbdef\propc|tab|\global\let\propc\propc
+\AQquestion{Let's say the statement \arg ; \\The first real in the table is \ldots}
+{{\propa},
+ {\propb},
+ {\propc}}
+
+%--------------------------------------------------------------
+\AQquestion{The line \texttt{printf("\%c", argv[2][0]) ;} of \texttt{main} of \texttt{monProg} run like this :
+\texttt{monProg parametre }}
+{{displays \texttt{p}},
+ {displays nothing},
+ {can cause a crash}}
+%--------------------------------------------------------------
+\AQquestion{What is the memory size of a \texttt{long int} ?}
+{{4 octets},
+ {8 octets},
+ {it depends \ldots}}
+%--------------------------------------------------------------
+\AQquestion{Following the declaration \texttt{int * i} ;}
+{{\texttt{*i} is an address},
+ {\texttt{*i} is an integer},
+ {\texttt{*i} is a pointer}}
+%--------------------------------------------------------------
+\AQquestion{One of the following choices is not a standard library of the C}
+{{\texttt{stdlib}},
+ {\texttt{stdin}},
+ {\texttt{math}}}
+ %--------------------------------------------------------------
+\end{alterqcm}
+
+The beginning of the code is simply
+
+\begin{tkzltxexample}[small]
+ \begin{alterqcm}[lq=80mm,long]
+ \AQquestion{What was the precursor language of the C language?}
+ {{Fortran},
+ {language B},
+ {Basic}}
+ \end{alterqcm}
+\end{tkzltxexample}
+
+\medskip
+It is possible to modify the text that is placed at the end of the table. Just modify the command \tkzcname{aqfoottext}.
+
+\begin{tkzltxexample}[small]
+ \def\aqfoottext{continued on next page\ldots}
+\end{tkzltxexample}
+
+\subsection{\tkzname{numbreak} : split a mcq }
+This option allows either to continue the numbering of the previous table.
+This option was necessary before the use of the \tkzname{long} option.
+ for tables split by a page break. It can now be used
+ for a series of tables grouped together to obtain a single MCQ.
+
+\begin{alterqcm}[lq=80mm,title=false,num=false,long]
+ \AQquestion{What was the precursor language of the C language?}
+ {{Fortran},
+ {language B},
+ {Basic}}
+
+\verbdef\argprop|int a = 3 ^ 4 ;|
+\AQquestion{\argprop}
+ {{raises 3 to the power of 4},
+ {makes an exclusive OR between 3 and 4},
+ {is not a C-instruction}}
+\end{alterqcm}
+
+\begin{alterqcm}[lq=80mm,title=false,num=false,numbreak=2,long]
+\AQquestion{After the declaration \texttt{int * i} ;}
+{{\texttt{*i} is an address},
+ {\texttt{*i} is an integer},
+ {\texttt{*i} is a pointer}}
+
+\AQquestion{One of the following choices is not a standard C library}
+{{\texttt{stdlib}},
+ {\texttt{stdin}},
+ {\texttt{math}}}
+\end{alterqcm}
+
+the code for the beginning is :
+
+\begin{tkzltxexample}[small]
+ \begin{alterqcm}[lq=80mm,title=false,num=false,long]
+ \AQquestion{What was the precursor language of the C language?}
+ {{Fortran},
+ {language B},
+ {Basic}}
+
+ \verbdef\argprop|int a = 3 ^ 4 ;|
+ \AQquestion{\argprop}
+ {{raises 3 to the power of 4},
+ {makes an exclusive OR between 3 and 4},
+ {is not a C-instruction}}
+ \end{alterqcm}
+\end{tkzltxexample}
+
+For the second part, we set \tkzname{numbreak} to $2$ because the first board had $2$ questions. In a future version, we will not have to count the questions anymore.
+
+\begin{tkzltxexample}[small]
+ \begin{alterqcm}[lq=80mm,title=false,num=false,numbreak=2,long]
+ \AQquestion{Following the declaration \texttt{int * i} ;}
+ {{\texttt{*i} is an address},
+ {\texttt{*i} is an integer},
+ {\texttt{*i} is a pointer}}
+
+ \AQquestion{One of the following choices is not a standard C library}
+ {{\texttt{stdlib}},
+ {\texttt{stdin}},
+ {\texttt{math}}}
+ \end{alterqcm}
+\end{tkzltxexample}
+
+\subsection{\tkzname{correction} : Correction of a mcq}
+ \IoptEnv{alterqcm}{correction}
+
+ It is possible to create an answer key by using the \tkzname{correction} option and indicating the correct answer(s) using a local parameter \tkzname{br}.
+ Here is an example:
+
+ \begin{alterqcm}[VF,lq=125mm,correction,
+ symb = \dingsquare,
+ corsymb = \dingchecksquare]
+ \AQquestion[br=1]{For all $x \in ]-3~;~2],~f'(x) \geqslant 0$.}
+ \AQquestion[br=2]{The $F$ function has a maximum in $2$}
+ \AQquestion[br=2]{$\displaystyle\int_{0}^2 f'(x)\:\text{d}x = - 2$}
+ \end{alterqcm}
+
+ \begin{tkzltxexample}[]
+ \begin{alterqcm}[VF,lq=125mm,correction,
+ symb = \dingsquare,
+ corsymb = \dingchecksquare]
+ \AQquestion[br=1]{For all $x \in ]-3~;~2],~f'(x) \geqslant 0$.}
+ \AQquestion[br=2]{The $F$ function has a maximum in $2$}
+ \AQquestion[br=2]{$\displaystyle\int_{0}^2 f'(x)\:\text{d}x = - 2$}
+ \end{alterqcm}
+\end{tkzltxexample}
+
+\subsection{Modification du symbole \tkzname{corsymb}}
+ \IoptEnv{alterqcm}{corsymb}
+
+\tkzcname{dingchecksquare} is provided by alterqcm.
+ Here is how this macro is defined.
+
+\begin{tkzexample}[code only,small]
+ \newcommand*{\dingchecksquare}{\mbox{\ding{114}%
+ \hspace{-.7em}\raisebox{.2ex}[1ex]{\ding{51}}}} \end{tkzexample}
+
+\medskip Let's consider checksquare as a result.
+
+\begin{tkzexample}[code only,small]
+ \begin{alterqcm}[lq=90mm,symb=\altersquare,corsymb=\dingchecksquare]
+ ...
+ \end{alterqcm}
+\end{tkzexample}
+
+\medskip
+Full example :
+
+\medskip
+ \begin{alterqcm}[VF,lq=125mm,correction,
+ symb = \dingsquare,
+ corsymb = \dingchecksquare]
+ \AQquestion[br=1]{For all $x \in ]-3~;~2],~f'(x) \geqslant 0$.}
+ \AQquestion[br=2]{The $F$ function has a maximum in $2$}
+ \AQquestion[br=2]{$\displaystyle\int_{0}^2 f'(x)\:\text{d}x = - 2$}
+ \end{alterqcm}
+
+
+\begin{tkzexample}[code only]
+ \begin{alterqcm}[VF,lq=125mm,correction,
+ symb = \dingsquare,
+ corsymb = \dingchecksquare]
+ \AQquestion[br=1]{For any $x \in ]-3~;~2],~f'(x) \geqslant 0$.}
+ \AQquestion[br=2]{The $F$ function has a maximum in $2$}
+ \AQquestion[br=2]{$\displaystyle\int_{0}^2 f'(x)\:\text{d}x = - 2$}
+ \end{alterqcm}
+\end{tkzexample}
+
+\subsection{\tkzname{br=\{\ldots\}} : corrected with several correct answers}
+\Iopt{AQquestion}{br}
+
+A list of correct answers is given
+\begin{tkzexample}[vbox,small]
+\begin{alterqcm}[correction]
+\AQquestion[br={1,3}]{Question}
+{%
+{Proposition 1},
+{Proposition 2},
+{Proposition 3}%
+}
+\end{alterqcm}
+\end{tkzexample}
+
+\subsection{\tkzname{transparent} : creation of a transparent slide showing the answers.}
+ \IoptEnv{alterqcm}{transparent}
+
+ This macro makes it possible to create a document identical to the original but without the questions and with a circle indicating the good proposals.
+
+ \begin{tkzexample}[vbox,small]
+ \begin{alterqcm}[transparent,correction,corsymb=\dingchecksquare,lq=100mm]
+ \AQquestion[br=2,pq=3mm]{Which of the following proposals is that
+ which allows us to affirm that the exponential function admits for asymptote the equation line $y = 0$ ?}
+ {{$\displaystyle\lim_{x \to +\infty} \dfrac{\text{e}^x}{x} = + \infty$},
+ {$\displaystyle\lim_{x \to +\infty} \text{e}^x = + \infty$},
+ {$\displaystyle\lim_{x \to -\infty} \text{e}^x = 0$}
+ }
+
+ \AQquestion[br={1,3}]{exp$(\ln x) = x$ for any $x$ belonging to }
+ {{$\mathbf{R}$},
+ {$\big]0~;~+ \infty\big[$},
+ {$\big[0~;~+\infty\big[$}
+ }
+
+ \AQquestion[br={1,2}]{exp$(\ln x) = x$ for any $x$ belonging to }
+ {{$\mathbf{R}$},
+ {$\big]0~;~+ \infty\big[$},
+ {$\big[0~;~+\infty\big[$}
+ }\AQquestion[br=2,pq=3mm]{Which of the following proposals is that
+ which allows us to affirm that the exponential function admits for asymptote
+ the equation line $y = 0$ ?}
+ {{$\displaystyle\lim_{x \to +\infty} \dfrac{\text{e}^x}{x} = + \infty$},
+ {$\displaystyle\lim_{x \to +\infty} \text{e}^x = + \infty$},
+ {$\displaystyle\lim_{x \to -\infty} \text{e}^x = 0$}
+ }
+ \end{alterqcm}
+\end{tkzexample}
+\endinput \ No newline at end of file