diff options
Diffstat (limited to 'fonts/newcomputermodern/newcomputermodern-sample.tex')
-rw-r--r-- | fonts/newcomputermodern/newcomputermodern-sample.tex | 28 |
1 files changed, 15 insertions, 13 deletions
diff --git a/fonts/newcomputermodern/newcomputermodern-sample.tex b/fonts/newcomputermodern/newcomputermodern-sample.tex index a461d165f3..a01749d963 100644 --- a/fonts/newcomputermodern/newcomputermodern-sample.tex +++ b/fonts/newcomputermodern/newcomputermodern-sample.tex @@ -8,23 +8,23 @@ \RequirePackage{fontspec} \RequirePackage{unicode-math} \setmainfont[% -ItalicFont=NewCM10-Italic.otf,% +ItalicFont=NewCM10-BookItalic.otf,% BoldFont=NewCM10-Bold.otf,% BoldItalicFont=NewCM10-BoldItalic.otf,% -SmallCapsFeatures={Numbers=OldStyle}]{NewCM10-Regular.otf} +SmallCapsFeatures={Numbers=OldStyle}]{NewCM10-Book.otf} \setsansfont[% -ItalicFont=NewCMSans10-Oblique.otf,% +ItalicFont=NewCMSans10-BookOblique.otf,% BoldFont=NewCMSans10-Bold.otf,% BoldItalicFont=NewCMSans10-BoldOblique.otf,% -SmallCapsFeatures={Numbers=OldStyle}]{NewCMSans10-Regular.otf} +SmallCapsFeatures={Numbers=OldStyle}]{NewCMSans10-Book.otf} -\setmonofont[ItalicFont=NewCMMono10-Italic.otf,% +\setmonofont[ItalicFont=NewCMMono10-BookItalic.otf,% BoldFont=NewCMMono10-Bold.otf,% BoldItalicFont=NewCMMono10-BoldOblique.otf,% -SmallCapsFeatures={Numbers=OldStyle}]{NewCMMono10-Regular.otf} +SmallCapsFeatures={Numbers=OldStyle}]{NewCMMono10-Book.otf} -\setmathfont{NewCMMath-Regular.otf} +\setmathfont{NewCMMath-Book.otf} \newcommand{\tttextsc}[1]{{\ttscshape#1}} @@ -34,10 +34,12 @@ SmallCapsFeatures={Numbers=OldStyle}]{NewCMMono10-Regular.otf} \begin{document} + + \begin{theorem}[Dominated convergence of Lebesgue] Assume that $g$ is an -in\-te\-grable func\-tion defined on the measurable set $E$ and hat - $(f_n)_{n\in\mathbb N}$ is a sequence of mea\-sur\-able function so that +in\-te\-grable func\-tion defined on the measurable set $E$ and that + $(f_n)_{n\in\mathbb N}$ is a sequence of mea\-sur\-able functions so that $|f_n|\leq g$. If $f$ is a function so that $f_n\to f$ almost everywhere then $$\lim_{n\to\infty}\int f_n=\int f.$$ \end{theorem} @@ -82,8 +84,8 @@ $$\lim \int f_n =\int f.$$ \begin{theorem}[Dominated convergence of Lebesgue] Assume that $g$ is an -in\-te\-grable func\-tion defined on the measurable set $E$ and hat - $(f_n)_{n\in\mathbb N}$ is a sequence of mea\-sur\-able function so that +in\-te\-grable func\-tion defined on the measurable set $E$ and that + $(f_n)_{n\in\mathbb N}$ is a sequence of mea\-sur\-able functions so that $|f_n|\leq g$. If $f$ is a function so that $f_n\to f$ almost everywhere then $$\lim_{n\to\infty}\int f_n=\int f.$$ \end{theorem} @@ -128,8 +130,8 @@ $$\lim \int f_n =\int f.$$ \begin{theorem}[Dominated convergence of Lebesgue] Assume that $g$ is an -in\-te\-grable func\-tion defined on the measurable set $E$ and hat - $(f_n)_{n\in\mathbb N}$ is a sequence of mea\-sur\-able function so that +in\-te\-grable func\-tion defined on the measurable set $E$ and that + $(f_n)_{n\in\mathbb N}$ is a sequence of mea\-sur\-able functions so that $|f_n|\leq g$. If $f$ is a function so that $f_n\to f$ almost everywhere then $$\lim_{n\to\infty}\int f_n=\int f.$$ \end{theorem} |