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author | Norbert Preining <norbert@preining.info> | 2021-05-20 03:00:38 +0000 |
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committer | Norbert Preining <norbert@preining.info> | 2021-05-20 03:00:38 +0000 |
commit | 6d6c3b4ee419b9f485a213d2ece28b06e9ca2f7c (patch) | |
tree | 243789c085bcb650c397f86eeaaddbc45ca92dff /obsolete/macros/latex/contrib/alterqcm/examples/latex/example_2.tex | |
parent | 94c996b5f40175b4a858ddd1f19e3947198b9bd0 (diff) |
CTAN sync 202105200300
Diffstat (limited to 'obsolete/macros/latex/contrib/alterqcm/examples/latex/example_2.tex')
-rw-r--r-- | obsolete/macros/latex/contrib/alterqcm/examples/latex/example_2.tex | 45 |
1 files changed, 0 insertions, 45 deletions
diff --git a/obsolete/macros/latex/contrib/alterqcm/examples/latex/example_2.tex b/obsolete/macros/latex/contrib/alterqcm/examples/latex/example_2.tex deleted file mode 100644 index a314cdb7fe..0000000000 --- a/obsolete/macros/latex/contrib/alterqcm/examples/latex/example_2.tex +++ /dev/null @@ -1,45 +0,0 @@ -\documentclass[11pt]{article} -\usepackage[utf8]{inputenc}% sauf si vous avez changé l'encodage -%\usepackage[upright]{fourier}% je la préfère aux autres! -% fourier charge textcomp ainsi que [T1]{fontenc} -% et fournit l'essentiel des symboles de amssymb -% en cas de changement, il ne faut pas oublier -% de placer un \usepackage[T1]{fontenc} qui est fourni -% automatiquement par fourier. -\usepackage[T1]{fontenc} -\usepackage{lmodern} -\usepackage{amsmath,amssymb,stmaryrd,calc}%}% pour geqslant qui existe ds fourier -\usepackage{xkeyval} -\usepackage{multirow,longtable} -\usepackage[% - a4paper,% - textwidth=16cm, - top=2cm,% - bottom=2cm,% - headheight=25pt,% - headsep=12pt,% - footskip=25pt]{geometry}% - -\usepackage{alterqcm} -% on charge le package -% longtable en cas de débordement du tableau -% amsmath car les exemples sont des annales du bac en mathématiques. -\usepackage[frenchb]{babel} -\parindent=0pt -\begin{document} - - - -\begin{alterqcm}[lq=80mm,long] -\AQquestion{Parmi les propositions suivantes, quelle est celle qui permet d'affirmer que la fonction exponentielle admet pour asymptote la droite d'équation $y = 0$ ?} -{{$\displaystyle\lim_{x \to +\infty} \text{e}^x = + \infty$}, -{$\displaystyle\lim_{x \to -\infty} \text{e}^x = 0$}, -{$\displaystyle\lim_{x \to +\infty} \dfrac{\text{e}^x}{x} = + \infty$}} - -\AQquestion[]{exp$(\ln x) = x$ pour tout $x$ appartenant à } -{{$\mathbf{R}$}, -{$\big]0~;~+ \infty\big[$}, -{$\big[0~;~+\infty\big[$} -}\end{alterqcm} - -\end{document}
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