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authorNorbert Preining <norbert@preining.info>2021-06-06 03:02:43 +0000
committerNorbert Preining <norbert@preining.info>2021-06-06 03:02:43 +0000
commit4338972cc175be565a3441c4ae8a6aa0dfcbe9f9 (patch)
tree9ec52a5d0d9c8a00b1a6801cc82248c0c008465d /macros/latex/contrib/profcollege/latex/PfCEquationSymbole1.tex
parent4e703bdd2f304028698cd4ab92b0dda0b95a95a8 (diff)
CTAN sync 202106060302
Diffstat (limited to 'macros/latex/contrib/profcollege/latex/PfCEquationSymbole1.tex')
-rw-r--r--macros/latex/contrib/profcollege/latex/PfCEquationSymbole1.tex89
1 files changed, 59 insertions, 30 deletions
diff --git a/macros/latex/contrib/profcollege/latex/PfCEquationSymbole1.tex b/macros/latex/contrib/profcollege/latex/PfCEquationSymbole1.tex
index 3cc345c524..f8313606e1 100644
--- a/macros/latex/contrib/profcollege/latex/PfCEquationSymbole1.tex
+++ b/macros/latex/contrib/profcollege/latex/PfCEquationSymbole1.tex
@@ -14,14 +14,19 @@
\fi
\else
% si non, on est dans le cas ax=d
- \xintifboolexpr{#2=0}{%
- \xintifboolexpr{#5=0}{%
+ \xintifboolexpr{#2==0}{%
+ \xintifboolexpr{#5==0}{%
L'équation $0\times\useKV[ClesEquation]{Lettre}=0$ a une infinité de solutions.}{L'équation $0\times\useKV[ClesEquation]{Lettre}=\num{#5}$ n'a aucune solution.}%
}{%\else
- \xintifboolexpr{#5=0}{L'équation $\num{#2}\times\useKV[ClesEquation]{Lettre}=0$ a une unique solution : $\useKV[ClesEquation]{Lettre}=0$.}{%\else
+ \xintifboolexpr{#5==0}{L'équation $\num{#2}\times\useKV[ClesEquation]{Lettre}=0$ a une unique solution : $\useKV[ClesEquation]{Lettre}=0$.}{%\else
\begin{align*}%
- \xintifboolexpr{#2=1}{\useKV[ClesEquation]{Lettre}}{\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}}&=\num{#5}\\
+ \xintifboolexpr{#2==1}{\useKV[ClesEquation]{Lettre}}{\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}}&=\num{#5}\\
\useKV[ClesEquation]{Lettre}&=\frac{\num{#5}}{\num{#2}}%\\
+ %% decimal
+ \ifboolKV[ClesEquation]{Decimal}{%
+ \\\useKV[ClesEquation]{Lettre}&=\num{\fpeval{#5/#2}}%
+ }{}%
+% %%%
\ifboolKV[ClesEquation]{Entier}{%
\SSimpliTest{#5}{#2}%
\ifboolKV[ClesEquation]{Simplification}{%
@@ -41,24 +46,29 @@
\ifx\bla#2\bla%On échange en faisant attention à ne pas boucler : c doit être non vide
\EquaDeuxSymbole[#1]{#4}{#5}{#2}{#3}
\else%cas ax+b=d
- \xintifboolexpr{#2=0}{%
- \xintifboolexpr{#3=#5}{%b=d
+ \xintifboolexpr{#2==0}{%
+ \xintifboolexpr{#3==#5}{%b=d
L'équation $\num{#3}=\num{#5}$ a une infinité de solutions.}%
{%b<>d
L'équation $\num{#3}=\num{#5}$ n'a aucune solution.%
}%
}{%ELSE
- \xintifboolexpr{#3=0}{%ax+b=d
+ \xintifboolexpr{#3==0}{%ax+b=d
\EquaBaseSymbole[#1]{#2}{}{}{#5}%
}{%ax+b=d$ Ici
\begin{align*}
- \xintifboolexpr{#2=1}{\useKV[ClesEquation]{Lettre}}{\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=\num{#5}\\
- \ifboolKV[ClesEquation]{Bloc}{\Fdash{$\xintifboolexpr{#2=1}{\useKV[ClesEquation]{Lettre}}{\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}}$}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=\num{#5}\\}{}%
- \xdef\Coeffa{#2}\xdef\Coeffb{\fpeval{#5-#3}}\xintifboolexpr{\Coeffa=1}{\useKV[ClesEquation]{Lettre}}{\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}}&=\num{\Coeffb}%\\
- \xintifboolexpr{\Coeffa=1}{%
+ \xintifboolexpr{#2==1}{\useKV[ClesEquation]{Lettre}}{\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=\num{#5}\\
+ \ifboolKV[ClesEquation]{Bloc}{\Fdash{$\xintifboolexpr{#2==1}{\useKV[ClesEquation]{Lettre}}{\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}}$}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=\num{#5}\\}{}%
+ \xdef\Coeffa{#2}\xdef\Coeffb{\fpeval{#5-#3}}\xintifboolexpr{\Coeffa==1}{\useKV[ClesEquation]{Lettre}}{\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}}&=\num{\Coeffb}%\\
+ \xintifboolexpr{\Coeffa==1}{%
}{%\ifnum\cmtd>1
\\
\useKV[ClesEquation]{Lettre}&=\frac{\num{\Coeffb}}{\num{\Coeffa}}%\\
+ %% decimal
+ \ifboolKV[ClesEquation]{Decimal}{%
+ \\\useKV[ClesEquation]{Lettre}&=\num{\fpeval{\Coeffb/\Coeffa}}%
+ }{}%
+ %%%
\ifboolKV[ClesEquation]{Entier}{%
\SSimpliTest{\Coeffb}{\Coeffa}%
\ifboolKV[ClesEquation]{Simplification}{%
@@ -83,14 +93,14 @@
\EquaTroisSymbole[#1]{#4}{#5}{#2}{}%
\fi
\else
- \xintifboolexpr{#2=0}{%b=cx
+ \xintifboolexpr{#2==0}{%b=cx
\EquaBaseSymbole[#1]{#4}{}{}{#3}
}{%
- \xintifboolexpr{#4=0}{%ax+b=0
+ \xintifboolexpr{#4==0}{%ax+b=0
\EquaDeuxSymbole[#1]{#2}{#3}{}{0}
}{%ax+b=cx
- \xintifboolexpr{#2=#4}{%
- \xintifboolexpr{#3=0}{%ax=ax
+ \xintifboolexpr{#2==#4}{%
+ \xintifboolexpr{#3==0}{%ax=ax
L'équation $\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}=\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}$ a une infinité de solutions.}%
{%ax+b=ax
L'équation $\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}=\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}$ n'a aucune solution.%
@@ -103,8 +113,13 @@
\xdef\Coeffa{\fpeval{#2-#4}}\multido{\i=1+1}{\fpeval{\Coeffa-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=0\\
\ifboolKV[ClesEquation]{Bloc}{\Fdash{\mathcolor{Csymbole}{$\multido{\i=1+1}{\fpeval{\Coeffa-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}$}}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=0\\}{}
\xdef\Coeffb{\fpeval{0-#3}}\multido{\i=1+1}{\fpeval{\Coeffa-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}&=\num{\Coeffb}%\\
- \xintifboolexpr{\Coeffa=1}{}{%\ifnum\cmtd>1
+ \xintifboolexpr{\Coeffa==1}{}{%\ifnum\cmtd>1
\\\useKV[ClesEquation]{Lettre}&=\frac{\num{\Coeffb}}{\num{\Coeffa}}%\\
+ %% decimal
+ \ifboolKV[ClesEquation]{Decimal}{%
+ \\\useKV[ClesEquation]{Lettre}&=\num{\fpeval{\Coeffb/\Coeffa}}%
+ }{}%
+ %%%
\ifboolKV[ClesEquation]{Entier}{%
\SSimpliTest{\Coeffb}{\Coeffa}%
\ifboolKV[ClesEquation]{Simplification}{%
@@ -118,8 +133,13 @@
\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=\multido{\i=1+1}{\fpeval{#4-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}\\
\mathcolor{Csymbole}{\useKV[ClesEquation]{Lettre}\multido{\i=1+1}{\fpeval{#2-1}}{+\useKV[ClesEquation]{Lettre}}}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=\mathcolor{Csymbole}{\useKV[ClesEquation]{Lettre}\multido{\i=1+1}{\fpeval{#2-1}}{+\useKV[ClesEquation]{Lettre}}}\multido{\i=1+1}{\fpeval{#4-#2}}{+\useKV[ClesEquation]{Lettre}}\\
\xdef\Coeffb{#3}\xdef\Coeffa{\fpeval{#4-#2}}\xintifboolexpr{#3>0}{\num{#3}}{-\num{\fpeval{0-#3}}}&=\multido{\i=1+1}{\fpeval{\Coeffa-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}% \\
- \xintifboolexpr{\Coeffa=1}{}{%\ifnum\cmtd>1
+ \xintifboolexpr{\Coeffa==1}{}{%\ifnum\cmtd>1
\\\frac{\num{\Coeffb}}{\num{\Coeffa}}&=\useKV[ClesEquation]{Lettre}%\\
+ %% decimal
+ \ifboolKV[ClesEquation]{Decimal}{%
+ \\\num{\fpeval{\Coeffb/\Coeffa}}&=\useKV[ClesEquation]{Lettre}%
+ }{}%
+ %%%
\ifboolKV[ClesEquation]{Entier}{%
\SSimpliTest{\Coeffb}{\Coeffa}%
\ifboolKV[ClesEquation]{Simplification}{%
@@ -135,14 +155,13 @@
\fi
}%
-
\newcommand{\ResolEquationSymbole}[5][]{%
\useKVdefault[ClesEquation]%
\setKV[ClesEquation]{#1}%
\setKV[ClesEquation]{Fleches=false,FlecheDiv=false,Terme=false,Decomposition=false}
- \xintifboolexpr{#2=0}{%
- \xintifboolexpr{#4=0}{%
- \xintifboolexpr{#3=#5}{%b=d
+ \xintifboolexpr{#2==0}{%
+ \xintifboolexpr{#4==0}{%
+ \xintifboolexpr{#3==#5}{%b=d
L'équation $\num{#3}=\num{#5}$ a une infinité de solutions.}%
{%b<>d
L'équation $\num{#3}=\num{#5}$ n'a aucune solution.%
@@ -152,24 +171,24 @@
\EquaDeuxSymbole[#1]{#4}{#5}{#2}{#3}%
}%
}{%
- \xintifboolexpr{#4=0}{%ax+b=0x+d
+ \xintifboolexpr{#4==0}{%ax+b=0x+d
\EquaDeuxSymbole[#1]{#2}{#3}{}{#5}%
}
{%ax+b=cx+d$
- \xintifboolexpr{#3=0}{%
- \xintifboolexpr{#5=0}{%ax=cx
+ \xintifboolexpr{#3==0}{%
+ \xintifboolexpr{#5==0}{%ax=cx
\EquaTroisSymbole[#1]{#2}{0}{#4}{}%
}%
{%ax=cx+d
\EquaTroisSymbole[#1]{#4}{#5}{#2}{}%
}%
}%
- {\xintifboolexpr{#5=0}{%ax+b=cx
+ {\xintifboolexpr{#5==0}{%ax+b=cx
\EquaTroisSymbole[#1]{#2}{#3}{#4}{}%
}%
{%ax+b=cx+d -- ici
- \xintifboolexpr{#2=#4}{%
- \xintifboolexpr{#3=#5}{%b=d
+ \xintifboolexpr{#2==#4}{%
+ \xintifboolexpr{#3==#5}{%b=d
L'équation $\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}=\multido{\i=1+1}{\fpeval{#4-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#5>0}{+\num{#5}}{-\num{\fpeval{0-#5}}}$ a une infinité de solutions.}%
{%b<>d
L'équation $\multido{\i=1+1}{\fpeval{#2-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}=\multido{\i=1+1}{\fpeval{#4-1}}{\useKV[ClesEquation]{Lettre}+}\useKV[ClesEquation]{Lettre}\xintifboolexpr{#5>0}{+\num{#5}}{-\num{\fpeval{0-#5}}}$ n'a aucune solution.%
@@ -185,8 +204,13 @@
\Fdash{$\mathcolor{Csymbole}{\useKV[ClesEquation]{Lettre}\multido{\i=1+1}{\fpeval{\Coeffa-1}}{+\useKV[ClesEquation]{Lettre}}}$}\xintifboolexpr{#3>0}{+\num{#3}}{-\num{\fpeval{0-#3}}}&=\num{#5}\\
}{}%
\xdef\Coeffb{\fpeval{#5-#3}}\useKV[ClesEquation]{Lettre}\multido{\i=1+1}{\fpeval{\Coeffa-1}}{+\useKV[ClesEquation]{Lettre}}&=\num{\Coeffb}%\\
- \xintifboolexpr{\Coeffa=1}{}{%\ifnum\cmtd>1
- \\\useKV[ClesEquation]{Lettre}&=\frac{\num{\Coeffb}}{\num{\Coeffa}}\tikzmark{H-\theNbequa}%\\
+ \xintifboolexpr{\Coeffa==1}{}{%\ifnum\cmtd>1
+ \\\useKV[ClesEquation]{Lettre}&=\frac{\num{\Coeffb}}{\num{\Coeffa}}%\\
+ %% decimal
+ \ifboolKV[ClesEquation]{Decimal}{%
+ \\\useKV[ClesEquation]{Lettre}&=\num{\fpeval{\Coeffb/\Coeffa}}%
+ }{}%
+ %%%
\ifboolKV[ClesEquation]{Entier}{%
\SSimpliTest{\Coeffb}{\Coeffa}%
\ifboolKV[ClesEquation]{Simplification}{%
@@ -204,8 +228,13 @@
\num{#3}&=\Fdash{$\mathcolor{Csymbole}{\useKV[ClesEquation]{Lettre}\multido{\i=1+1}{\fpeval{\Coeffa-1}}{+\useKV[ClesEquation]{Lettre}}}$}\xintifboolexpr{#5>0}{+\num{#5}}{-\num{\fpeval{0-#5}}}\\
}{}%
\xdef\Coeffb{\fpeval{#3-#5}}\num{\Coeffb}&=\useKV[ClesEquation]{Lettre}\multido{\i=1+1}{\fpeval{\Coeffa-1}}{+\useKV[ClesEquation]{Lettre}}%\\
- \xintifboolexpr{\Coeffa=1}{}{%\ifnum\cmtd>1
+ \xintifboolexpr{\Coeffa==1}{}{%\ifnum\cmtd>1
\\\frac{\num{\Coeffb}}{\num{\Coeffa}}&=\useKV[ClesEquation]{Lettre}%\\
+ %% decimal
+ \ifboolKV[ClesEquation]{Decimal}{%
+ \\\num{\fpeval{\Coeffb/\Coeffa}}&=\useKV[ClesEquation]{Lettre}%
+ }{}%
+ %%%
\ifboolKV[ClesEquation]{Entier}{%
\SSimpliTest{\Coeffb}{\Coeffa}%
\ifboolKV[ClesEquation]{Simplification}{%