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authorNorbert Preining <norbert@preining.info>2019-09-02 13:46:59 +0900
committerNorbert Preining <norbert@preining.info>2019-09-02 13:46:59 +0900
commite0c6872cf40896c7be36b11dcc744620f10adf1d (patch)
tree60335e10d2f4354b0674ec22d7b53f0f8abee672 /graphics/ketcindy/ketcindyfolder/doc/source/ketmanual/Fig/mxtex02.tex
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+%%% fig.tex 2016-4-25 8:55
+%%% fig.sce 2016-4-25 8:55
+{\unitlength=8mm%
+\begin{picture}%
+( 10.22000, 3.87000)( -0.61000, 2.03000)%
+\special{pn 8}%
+%
+\settowidth{\Width}{Decomposition into partial fractions}\setlength{\Width}{0\Width}%
+\settoheight{\Height}{Decomposition into partial fractions}\settodepth{\Depth}{Decomposition into partial fractions}\setlength{\Height}{-0.5\Height}\setlength{\Depth}{0.5\Depth}\addtolength{\Height}{\Depth}%
+\put(0.0500,5.0000){\hspace*{\Width}\raisebox{\Height}{Decomposition into partial fractions}}%
+%
+%
+\settowidth{\Width}{$\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\setlength{\Width}{0\Width}%
+\settoheight{\Height}{$\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\settodepth{\Depth}{$\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\setlength{\Height}{-0.5\Height}\setlength{\Depth}{0.5\Depth}\addtolength{\Height}{\Depth}%
+\put(0.0500,3.5000){\hspace*{\Width}\raisebox{\Height}{$\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}}%
+%
+%
+\end{picture}}% \ No newline at end of file