summaryrefslogtreecommitdiff
path: root/texmf-dist/doc/support/ketcindy/source/ketmanual/Fig/mxtex02.tex
blob: ca72d2d36609ce5afcf8e98476026206e0624481 (plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
%%% fig.tex 2016-4-25 8:55
%%% fig.sce 2016-4-25 8:55
{\unitlength=8mm%
\begin{picture}%
(  10.22000,   3.87000)(  -0.61000,   2.03000)%
\special{pn 8}%
%
\settowidth{\Width}{部分分数への分解 $\frac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\frac{8}{x+2}-\frac{1}{x+1}+x-3$}\setlength{\Width}{0\Width}%
\settoheight{\Height}{部分分数への分解 $\frac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\frac{8}{x+2}-\frac{1}{x+1}+x-3$}\settodepth{\Depth}{部分分数への分解 $\frac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\frac{8}{x+2}-\frac{1}{x+1}+x-3$}\setlength{\Height}{-0.5\Height}\setlength{\Depth}{0.5\Depth}\addtolength{\Height}{\Depth}%
\put(0.0500,5.0000){\hspace*{\Width}\raisebox{\Height}{部分分数への分解 $\frac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\frac{8}{x+2}-\frac{1}{x+1}+x-3$}}%
%
%
\settowidth{\Width}{部分分数への分解 $\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\setlength{\Width}{0\Width}%
\settoheight{\Height}{部分分数への分解 $\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\settodepth{\Depth}{部分分数への分解 $\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\setlength{\Height}{-0.5\Height}\setlength{\Depth}{0.5\Depth}\addtolength{\Height}{\Depth}%
\put(0.0500,3.0000){\hspace*{\Width}\raisebox{\Height}{部分分数への分解 $\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}}%
%
%
\end{picture}}%