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diff --git a/texmf-dist/doc/support/ketcindy/source/ketmanual/Fig/mxtex02.tex b/texmf-dist/doc/support/ketcindy/source/ketmanual/Fig/mxtex02.tex deleted file mode 100644 index ca72d2d3..00000000 --- a/texmf-dist/doc/support/ketcindy/source/ketmanual/Fig/mxtex02.tex +++ /dev/null @@ -1,18 +0,0 @@ -%%% fig.tex 2016-4-25 8:55 -%%% fig.sce 2016-4-25 8:55 -{\unitlength=8mm% -\begin{picture}% -( 10.22000, 3.87000)( -0.61000, 2.03000)% -\special{pn 8}% -% -\settowidth{\Width}{部分分数への分解 $\frac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\frac{8}{x+2}-\frac{1}{x+1}+x-3$}\setlength{\Width}{0\Width}% -\settoheight{\Height}{部分分数への分解 $\frac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\frac{8}{x+2}-\frac{1}{x+1}+x-3$}\settodepth{\Depth}{部分分数への分解 $\frac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\frac{8}{x+2}-\frac{1}{x+1}+x-3$}\setlength{\Height}{-0.5\Height}\setlength{\Depth}{0.5\Depth}\addtolength{\Height}{\Depth}% -\put(0.0500,5.0000){\hspace*{\Width}\raisebox{\Height}{部分分数への分解 $\frac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\frac{8}{x+2}-\frac{1}{x+1}+x-3$}}% -% -% -\settowidth{\Width}{部分分数への分解 $\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\setlength{\Width}{0\Width}% -\settoheight{\Height}{部分分数への分解 $\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\settodepth{\Depth}{部分分数への分解 $\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}\setlength{\Height}{-0.5\Height}\setlength{\Depth}{0.5\Depth}\addtolength{\Height}{\Depth}% -\put(0.0500,3.0000){\hspace*{\Width}\raisebox{\Height}{部分分数への分解 $\dfrac{x^3}{\left(x+1\right)\,\left(x+2\right)}=\dfrac{8}{x+2}-\dfrac{1}{x+1}+x-3$}}% -% -% -\end{picture}}%
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