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diff --git a/texmf-dist/doc/latex/eqexam/examples/test_matching.tex b/texmf-dist/doc/latex/eqexam/examples/test_matching.tex new file mode 100644 index 00000000..27317c65 --- /dev/null +++ b/texmf-dist/doc/latex/eqexam/examples/test_matching.tex @@ -0,0 +1,92 @@ +\documentclass{article} +\usepackage{amsmath} +\usepackage{graphicx} +\usepackage[forpaper,pointsonleft, +% online, +% compile with one of the following three options + nosolutions, +% answerkey, +% vspacewithsolns +]{eqexam} +%\usepackage[forpaper,pointsonleft,nosolutions]{eqexam} +%\usepackage[online,forpaper,pointsonleft,answerkey]{eqexam} + +\solAtEndFormatting{\eqequesitemsep{3pt}} + + +\title[T1]{Test 1} +\author{D. P. Story} +\subject{A Matching Problem} +\date{\thisterm, \the\year} +\keywords{Test 1, Section 001} + +\university +{% + NORTHWEST FLORIDA STATE COLLEGE\\ + Department of Mathematics +} +\email{storyd@nwfsc.edu} + +\hfuzz = .7pt + +\begin{document} +\maketitle + + +\begin{exam}{Part1} + +\begin{instructions} +Solve each of the problems without error. If you make an error, +points will be subtracted from your total score. +\end{instructions} + + +\begin{problem*}[\auto] +Match each of names on the left, with the corresponding names on the right. + +\begin{multicols}{2} +\begin{parts} +\item\label{dps}\PTs*{2}\fillin{.5in}{\ref{george}} Washington +\ifkeyalt +\begin{solution}[] +\fillin{.5in}{\ref{george}} Washington +\end{solution} +\fi +\item\PTs*{2}\fillin{.5in}{\ref{john}} Adams +\ifkeyalt +\begin{solution}[] +\fillin{.5in}{\ref{john}} Adams +\end{solution} +\fi +\item\PTs*{2}\fillin{.5in}{\ref{thomas}} Jefferson +\ifkeyalt +\begin{solution}[] +\fillin{.5in}{\ref{thomas}} Jefferson +\end{solution} +\fi + +\columnbreak + +\renewcommand{\thepartno}{\Alph{partno}} +\partsformat{\Alph{partno}.} + +% The above redefinitions are reset when we leave the group, when \end{parts} +% is completed. If the original definitions are needed to be reset before then +% execute the following commands: \defaultthepartno, \defaultpartsformat + +% \foritem{a} resets the partno counter back to 0, and displays (a), which +% has been redefined to A. + +\foritem{a}\label{john} John + +\item\label{thomas} Thomas + +\item\label{george} George + +\end{parts} +\end{multicols} +\end{problem*} + +\end{exam} + +\end{document} |