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% !TeX root = tcolorbox.tex
% include file of tcolorbox.tex (manual of the LaTeX package tcolorbox)
\clearpage
\section{Recording}\label{sec:recording}
The package provides some macros and options to take \emph{records} during
compilation. This is done by \LaTeX\ file operations to save some data
to a file for later usage. The main application scenario is depicted in
\Vref{sec:recording-exercises} where
informations about example solutions are recorded and read again
in \Vref{sec:recording-solutions}.
\subsection{Makros}\label{sec:recording-makros}
\begin{docCommand}[doc new=2014-11-28]{tcbstartrecording}{\oarg{file name}}
Opens a file denoted by \meta{file name} for writing the records.
The default file name is |\jobname.records|.
See \Vref{sec:recording-exercises} for an example application.
\end{docCommand}
\begin{docCommand}[doc new=2014-11-28]{tcbrecord}{\marg{content}}
Records any \meta{content} to the record file.
\refCom{tcbrecord} is implemented as |\immediate\write|.
\refCom{tcbstartrecording} has to be called before; otherwise, \refCom{tcbrecord}
is silently ignored.
\begin{dispListing}
\tcbrecord{\string\solution{\thetcbcounter}{solutions/exercise-\thetcbcounter.tex}}
\end{dispListing}
\end{docCommand}
\begin{docCommand}[doc new=2014-11-28]{tcbstoprecording}{}
Closes the current record file which was opened by \refCom{tcbstartrecording}
before.
\end{docCommand}
\begin{docCommand}[doc new=2014-11-28]{tcbinputrecords}{\oarg{file name}}
Opens a file denoted by \meta{file name} for reading the records via |\input|.
The default file name is the name of the last used record file for saving.
\refCom{tcbstoprecording} has to be called before.
\end{docCommand}
\subsection{Options}\label{sec:recording-options}
\begin{docTcbKey}[][doc new=2014-11-28]{record}{=\meta{content}}{style, no default}
Records any \meta{content} to the record file, see \refCom{tcbrecord}.
This key can be used several times to write several lines.
\begin{dispListing}
record={\string\solution{\thetcbcounter}{solutions/exercise-\thetcbcounter.tex}}
\end{dispListing}
\end{docTcbKey}
\begin{docTcbKey}[][doc new=2014-11-28]{no recording}{}{}
Disables \refCom{tcbrecord} and \refKey{/tcb/record} inside the current
group.
\end{docTcbKey}
\clearpage
\subsection{Example: Exercises}\label{sec:recording-exercises}
The following application example creates exercises and their corresponding
solutions. Each pair is generated inside a single |tcolorbox| where the
solution is given below \refCom{tcblower}. For every example, the solution part
is saved by \refKey{/tcb/savelowerto} to a file. The saving is recorded using
\refKey{/tcb/record}. To enlighten the possibilities, the second exercise
has no solution. Finally, the solutions are input in \Vref{sec:recording-solutions}.
\inputpreamblelisting{L}
\begin{dispListing*}{breakable,before upper=}
\tcbstartrecording
\begin{exercise}
Compute the derivative of the following function:
\begin{equation*}
f(x)=\sin((\sin x)^2)
\end{equation*}
\tcblower
The derivative is:
\begin{align*}
f'(x) &= \left( \sin((\sin x)^2) \right)'
=\cos((\sin x)^2) 2\sin x \cos x.
\end{align*}
\end{exercise}
\begin{exercise}[no solution]
It holds:
\begin{equation*}
\frac{d}{dx}\left(\ln|x|\right) = \frac{1}{x}.
\end{equation*}
\end{exercise}
\begin{exercise}
Compute the derivative of the following function:
\begin{equation*}
f(x)=(\sin(\sin x))^2
\end{equation*}
\tcblower
The derivative is:
\begin{align*}
f'(x) &= \left( (\sin(\sin x))^2 \right)'
=2\sin(\sin x)\cos(\sin x)\cos x.
\end{align*}
\end{exercise}
\begin{exercise}
Compute the derivative of the following function:
\begin{equation*}
f(x)=\sqrt{x^3-6x^2+2x}
\end{equation*}
\tcblower
The derivative is:
\begin{align*}
f'(x) &= \left( \sqrt{x^3-6x^2+2x} \right)'
= \frac{3x^2-12x+2}{2\sqrt{x^3-6x^2+2x}}.
\end{align*}
\end{exercise}
\begin{exercise}
Compute the derivative of the following function:
\begin{equation*}
f(x)=\left(\frac{2+3x}{1-2x}\right)^3
\end{equation*}
\tcblower
The derivative is:
\begin{align*}
f'(x) &= \left( \left(\frac{2+3x}{1-2x}\right)^3 \right)'
= 3 \left(\frac{2+3x}{1-2x}\right)^2 \frac{(1-2x)3-(2+3x)(-2)}{(1-2x)^2}
= \frac{21(2+3x)^2}{(1-2x)^4}.
\end{align*}
\end{exercise}
\begin{exercise}
Compute the derivative of the following function:
\begin{equation*}
f(x)=\frac{\cos x}{(\tan 2x)^2}
\end{equation*}
\tcblower
The derivative is:
\begin{align*}
f'(x) &= \left( \frac{\cos x}{(\tan 2x)^2} \right)'
= \left( \frac{\cos x (\cos 2x)^2}{(\sin 2x)^2} \right)'\\
&= \frac{(\sin 2x)^2 [(-\sin x)(\cos 2x)^2+(\cos x)4\cos 2x (-\sin 2x)]
- \cos x (\cos 2x)^2 4\sin 2x \cos 2x}{(\sin 2x)^4}\\
&= -\frac{\cos(2x) [\sin x \sin 2x \cos 2x+ 4\cos x(\sin 2x)^2
+ 4 \cos x (\cos 2x)^2]}{(\sin 2x)^3}\\
&= -\frac{\cos(2x) [\sin x \sin 2x \cos 2x+ 4\cos x]}{(\sin 2x)^3}.
\end{align*}
\end{exercise}
\begin{exercise}
Compute the derivative of the following function:
\begin{equation*}
f(x)=\cos((2x^2+3)^3)
\end{equation*}
\tcblower
The derivative is:
\begin{align*}
f'(x) &= \left( \cos((2x^2+3)^3) \right)'
=-\sin((2x^2+3)^3) 3(2x^2+3)^2 2\cdot 2x\\
&=-12x(2x^2+3)^2\sin((2x^2+3)^3).
\end{align*}
\end{exercise}
\begin{exercise}
Compute the derivative of the following function:
\begin{equation*}
f(x)=(x^2+1)\sqrt{x^4+1}
\end{equation*}
\tcblower
The derivative is:
\begin{align*}
f'(x) &= \left( (x^2+1)\sqrt{x^4+1} \right)'
= 2x\sqrt{x^4+1} + \frac{2x^3(x^2+1)}{\sqrt{x^4+1}}.
\end{align*}
\end{exercise}
\tcbstoprecording
\end{dispListing*}
\tcbusetemp
\subsection{Example: Solutions}\label{sec:recording-solutions}
This concludes the example given in \Vref{sec:recording-exercises}.
Now, the saved and recorded solutions are included.
\begin{dispListing*}{breakable,before upper=}
\tcbinputrecords
\end{dispListing*}
\tcbusetemp
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