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-% This file is public domain.
-%
-% Test math displays.
-%
-\ifx\undefined\eplain \input eplain \fi
-
-%\loggingall
-
-A simple one, done with plain, for comparison (it should come out
-centered). Because of the way that \TeX's modes work, you should never
-leave a blank line (i.e., cause a par command) before a display. When
-\TeX\ sees a \$ in vertical mode, it switches to horizontal mode; but
-then when the display starts, it goes back to vertical mode, thus
-causing an extraneous blank line before the display. (Plain \TeX\ sets
-abovedisplayskip to about a baselineskip, so you are going to get one
-blank line from that (unless the line above the display is short, in
-which case aboveshortdisplayskip is used, which is 3pt or some such);
-but if a par intervenes between the end of the paragraph and the
-beginning of the display, you get a second one.)
-$$x = y + z$$
-
-After a centereddisplays:
-\centereddisplays
-$$d+e+f$$
-
-Now starting leftdisplays.
-\leftdisplays
-
-No equation number:
-$$A = B + C$$
-
-Do another leftdisplays.
-\leftdisplays
-$$a+n=m$$
-
-Equation number on right:
-$$D = E + F\eqno (r)$$
-
-Equation number on left:
-$$G = H + I\leqno (l)$$
-
-Using eqdef:
-$$J = K + L\eqdef{hello}$$
-
-Here is one done with displaylines:
-$$\displaylines{x=1\cr}$$
-
-Let's do those again, indented by one inch plus the paragraph indentation:
-{\leftdisplayindent = 1in
- No equation number:
- $$A = B + C$$
-
- Equation number on right:
- $$D = E + F\eqno (r)$$
-
- Equation number on left:
- $$G = H + I\leqno (l)$$
-
- Using eqdef:
- $$J = K + L\eqdef{hello}$$
-
- Here is one done with displaylines:
- $$\displaylines{x=1\cr}$$
-}
-
-\hrule
-\smallskip
-The rule above just makes it easier to see the margins.
-
-Another displaylines, this one should end up on the right.
-$$\displaylines{\hfill y=2\cr}$$
-
-A displaylines with an eqno:
-$$\displaylines{x=1 \eqno{d}\cr}$$
-
-A displaylines with an eqdef:
-$$\displaylines{x=1 \eqdef{eqdef-displ}\cr}$$
-
-{\leftskip = 14pt
-An indented displaylines with an eqdef:
-$$\displaylines{x=1 \eqdef{eqdef-displ}\cr}$$
-
-}
-
-Here is one with done with eqalign (the ='s should line up):
-$$\eqalign{
- a+b&=c\cr
- dq+er&=f\cr
-}$$
-
-An eqalign with a noalign inside:
-$$\eqalign{
- a+b&=c\cr
- g+h&=i\cr
-}$$
-
-And one with eqalignno:
-$$\eqalignno{
- a+b&=c&(1)\cr
- d+e&=f&(1*)\cr
- g+h&=i&\eqdef{eqdef-2}\cr
-}$$
-
-An eqalignno with a noalign inside:
-$$\eqalignno{
- a+b&=c&(1)\cr
-\noalign{and}
- g+h&=i&\eqdef{eqdef-2}\cr
-}$$
-
-And one (indented more) with leqalignno:
-{\leftdisplayindent = 1in
-$$\leqalignno{
- a+b&=c&(1)\cr
- dt+eg&=f&(1*)\cr
- g+h&=i&\eqdef{eqdef-3}\cr
-}$$
-}
-
-A cases, from p.175 of the TeXbook.
-$$
- |x| = \cases{x, &if $x\ge0$;\cr
- -x, &otherwise.\cr
-}$$
-
-A pmatrix, from p.176.
-$$\pmatrix{
- x-\lambda&1&0\cr
- 0&x-\lambda&1\cr
- 0&0&x-\lambda\cr
-}$$
-
-
-The rule below just makes it easier to see the margins.
-\smallskip
-\hrule
-\bigskip
-
-Back to centered displays now.
-\centereddisplays
-
-No equation number:
-$$A = B + C$$
-
-Equation number on right:
-$$D = E + F\eqno (r)$$
-
-Equation number on left:
-$$G = H + I\leqno (l)$$
-
-Using eqdef:
-$$J = K + L\eqdef{hello}$$
-
-Here is one done with displaylines:
-$$\displaylines{x=1\cr}$$
-
-\hrule
-\smallskip
-The rule above just makes it easier to see the margins.
-
-Another displaylines, this one should end up on the right.
-$$\displaylines{\hfill y=2\cr}$$
-
-Here is one with done with eqalign (the ='s should line up):
-$$\eqalign{
- a+b&=c\cr
- dq+er&=f\cr
-}$$
-
-And one with eqalignno:
-$$\eqalignno{
- a+b&=c&(1)\cr
- d+e&=f&(1*)\cr
- g+h&=i&\eqdef{eqdef-2}\cr
-}$$
-
-An eqalignno with a noalign inside:
-$$\eqalignno{
- a+b&=c&(1)\cr
-\noalign{and}
- g+h&=i&\eqdef{eqdef-2}\cr
-}$$
-
-And one (indented more) with leqalignno:
-{\leftdisplayindent = 1in
-$$\leqalignno{
- a+b&=c&(1)\cr
- dt+eg&=f&(1*)\cr
- g+h&=i&\eqdef{eqdef-3}\cr
-}$$
-}
-
-The rule below just makes it easier to see the margins.
-\smallskip
-\hrule
-\bigskip
-
-
-A cases, from p.175 of the TeXbook.
-$$
- |x| = \cases{x, &if $x\ge0$;\cr
- -x, &otherwise.\cr
-}$$
-
-A pmatrix, from p.176.
-$$\pmatrix{
- x-\lambda&1&0\cr
- 0&x-\lambda&1\cr
- 0&0&x-\lambda\cr
-}$$
-
-Now after a second centereddisplays:
-\centereddisplays
-$$a + b = c$$
-\end