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diff --git a/Master/texmf-dist/doc/latex/math-e/06-14-3.ltx b/Master/texmf-dist/doc/latex/math-e/06-14-3.ltx new file mode 100644 index 00000000000..907e1ad5aae --- /dev/null +++ b/Master/texmf-dist/doc/latex/math-e/06-14-3.ltx @@ -0,0 +1,45 @@ +%% +%% An UIT Edition example +%% +%% Example 06-14-3 on page 116. +%% +%% Copyright (C) 2010 Herbert Voss +%% +%% It may be distributed and/or modified under the conditions +%% of the LaTeX Project Public License, either version 1.3 +%% of this license or (at your option) any later version. +%% +%% See http://www.latex-project.org/lppl.txt for details. +%% +%% +%% ==== +% Show page(s) 1 +%% +\documentclass[]{exaarticle} +\pagestyle{empty} +\setlength\textwidth{375.57637pt} +\usepackage[utf8]{inputenc} +\setcounter{equation}{74} +\renewcommand\theequation{6.\arabic{equation}} +\AtBeginDocument{\setlength\parindent{0pt}} +\StartShownPreambleCommands +\usepackage{amsmath} +\newcommand*\diff{\mathop{}\!\mathrm{d}} +\StopShownPreambleCommands +\begin{document} +\begin{align} +A_{1} + &= \left|\int_0^1(f(x)-g(x))\diff x\right| +\left| \int _1^2(g(x)-h(x))\diff x + \right|\nonumber\\ + &= \left|\int_0^1(x^2-3x)\diff x\right| +\left| \int _1^2(x^2-5x+6)\diff x + \right|\nonumber +\intertext{Now the antiderivative of the two integrals is determined and the + values calculated:} + &= \left|\frac{x^3}{3}-\frac{3}{2}x^2\right|_0^1+\left| \frac{x^3}{3}- + \frac{5}{2}x^2+6x\right|_1^2\nonumber\\ + &= \left|\frac{1}{3}-\frac{3}{2}\right| +\left| \frac{8}{3}- \frac{20}{2}+12- + \left(\frac{1}{3}-\frac{5}{2}+6\right) \right| \nonumber\\ + &= \left|-\frac{7}{6}\right| +\left| \frac{28}{6}-\frac{23}{6} \right| =\frac{7}{6}+ + \frac{5}{6}=2\,\text{FE} +\end{align} +\end{document} |