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+%%
+%% An UIT Edition example
+%%
+%% Example 06-02-12 on page 84.
+%%
+%% Copyright (C) 2010 Herbert Voss
+%%
+%% It may be distributed and/or modified under the conditions
+%% of the LaTeX Project Public License, either version 1.3
+%% of this license or (at your option) any later version.
+%%
+%% See http://www.latex-project.org/lppl.txt for details.
+%%
+%%
+%% ====
+% Show page(s) 1
+%%
+\documentclass[]{exaarticle}
+\pagestyle{empty}
+\setlength\textwidth{375.57637pt}
+\AtBeginDocument{\setlength\parindent{0pt}}
+\usepackage[english]{babel}
+\usepackage[utf8]{inputenc}
+\setcounter{section}{6}
+\StartShownPreambleCommands
+\usepackage{amsmath} \usepackage[amsmath,thmmarks]{ntheorem}
+\theoremsymbol{\ensuremath{\triangle}}
+\theoremprework{\bigskip\hrule} \theorempostwork{\hrule\bigskip}
+\newtheorem{example}{example}[section]
+\StopShownPreambleCommands
+\begin{document}
+Normal text before the new environment.
+\begin{example} Use of the transformation theorem:
+\begin{align*}
+ [z^n]C(z) &= [z^n]\biggl[\frac{e^{3/4}}{\sqrt{1-z}}+e^{-3/4}(1-z)^{1/2}+
+ \frac{e^{-3/4}}{4}(1-z)^{3/2}+O\Bigl((1-z)^{5/2}\Bigr)\biggr]\\[5pt]
+ &= \frac{e^{-3/4}}{\sqrt{\pi n}}-\frac{5e^{-3/4}}{8\sqrt{\pi n^3}}+
+ \frac{e^{-3/4}}{128\sqrt{\pi n^5}}+O\biggl(\frac{1}{\sqrt{\pi n^7}}\biggr)
+\end{align*}
+\end{example}
+\end{document}