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+\documentclass{article}
+\begin{document}
+Although this equation looks very complicated, it should not present
+any great difficulties:
+\[ \int\frac{\sqrt{(ax+b)^3}}{x}\,dx = \frac{2\sqrt{(ax+b)^3}}{3}
+ + 2b\sqrt{ax+b} + b^2\int\frac{dx}{x\sqrt{ax+b}} \]
+The same applies to $\int^8_{-1}(dx/\sqrt[3]{x}) = \frac{3}{2}(8^{2/3} +
+ 1^{2/3}) = 15/2$
+\end{document}