summaryrefslogtreecommitdiff
path: root/Master/texmf-dist/doc/generic/pst-diffraction/pst-diffraction-docFR.tex
diff options
context:
space:
mode:
Diffstat (limited to 'Master/texmf-dist/doc/generic/pst-diffraction/pst-diffraction-docFR.tex')
-rw-r--r--Master/texmf-dist/doc/generic/pst-diffraction/pst-diffraction-docFR.tex312
1 files changed, 248 insertions, 64 deletions
diff --git a/Master/texmf-dist/doc/generic/pst-diffraction/pst-diffraction-docFR.tex b/Master/texmf-dist/doc/generic/pst-diffraction/pst-diffraction-docFR.tex
index f7203cd4c19..0f59dfe1556 100644
--- a/Master/texmf-dist/doc/generic/pst-diffraction/pst-diffraction-docFR.tex
+++ b/Master/texmf-dist/doc/generic/pst-diffraction/pst-diffraction-docFR.tex
@@ -1,4 +1,4 @@
-\documentclass[dvips,a4paper]{article}
+\documentclass[frenchb,dvips,a4paper]{article}
\usepackage[latin9]{inputenc}%
\usepackage[T1]{fontenc}
\usepackage[bmargin=2cm,tmargin=2cm]{geometry}
@@ -11,13 +11,26 @@
\usepackage{ccfonts}
\usepackage[euler-digits]{eulervm}
\usepackage[scaled=0.85]{luximono}
+\usepackage{xspace}
+\newcommand*\psp{\texttt{pspicture}\xspace}
\def\UrlFont{\small\ttfamily}
\makeatletter
\def\verbatim@font{\small\normalfont\ttfamily}
\makeatother
-\usepackage{prettyref}
+\usepackage{prettyref,multicol}
\usepackage{fancyhdr}
+\usepackage{showexpl}
+\lstdefinestyle{syntax}{backgroundcolor=\color{blue!20},numbers=none,xleftmargin=0pt,xrightmargin=0pt,
+ frame=single}
+\lstdefinestyle{example}{backgroundcolor=\color{red!20},numbers=none,xleftmargin=0pt,xrightmargin=0pt,
+ frame=single}
+\lstset{wide=true,language=PSTricks,
+ morekeywords={psdiffractionCircular,psdiffractionRectangle,psdiffractionTriangle}}
+
+\usepackage{babel}
+\usepackage[colorlinks,linktocpage]{hyperref}
+
\pagestyle{fancy}
\def\Lcs#1{{\ttfamily\textbackslash #1}}
\lfoot{\small\ttfamily\jobname.tex}
@@ -118,17 +131,18 @@ divers paramètres du montage.
Il y a trois commandes, l'une pour les ouvertures rectangulaires, l'autre
pour les ouvertures circulaires et la dernière pour une ouverture
triangulaire.
-\begin{verbatim}
+\begin{lstlisting}[style=syntax]
\psdiffractionRectangle[<liste de paramètres>]
\psdiffractionCircular[<liste de paramètres>]
\psdiffractionTriangle[<liste de paramètres>]
-\end{verbatim}
+\end{lstlisting}
+
Nous allons passer en revue ces différentes commandes et leurs paramètres.
\section{La couleur de la radiation}
La longueur d'onde est définie par le paramètres \texttt{[lambda=632]} (si
l'on veut du rouge de longueur d'onde~:~ $\lambda=632$~nm), cette valeur est donc en~nm. La
conversion de la longueur d'onde dans le système \texttt{rgb} est une adaptation en
-postscript de celle qu'on trouve sur~:
+postscript de celle qu'on trouve sur~:\\
\url{http://www.physics.sfasu.edu/astro/color.html}.
@@ -154,97 +168,230 @@ negativ avec \texttt{[colorMode=1]} ou cmyk couleur avec \texttt{[colorMode=2]}
rgb avec \texttt{[colorMode=3]}.
Par défaut les paramètres ont les valeurs suivantes :
-\begin{itemize}
- \item \texttt{[a=0.2e-3]} en m ;
- \item \texttt{[k=1]} ;
- \item \texttt{[f=5]} en m ;
- \item \texttt{[lambda=650]} en nm ;
- \item \texttt{[pixel=0.5]} ;
- \item \texttt{[contrast=38]}, valeur maximale ;
- \item \texttt{[colorMode=3]}.
-\end{itemize}
-\begin{center}
-\begin{pspicture}(-4,-4)(4,4)
+\begin{tabular}{@{}lll@{}}
+\texttt{[a=0.2e-3]} en m; & \texttt{[k=1]}; & \texttt{[f=5]} en m;\\
+\texttt{[lambda=650]} en nm; & \texttt{[pixel=0.5]}; & \texttt{[contrast=38]}, valeur maximale;\\
+\texttt{[colorMode=3]}; & \texttt{[IIID=false]}.
+\end{tabular}
+
+\bigskip
+\noindent
+\begin{pspicture}(-3.5,-3.5)(3.5,3.5)
\psdiffractionRectangle[f=2.5]
-\uput[270](0,-3.5){$\backslash$\texttt{psdiffractionRectangle[f=2.5]}}
\end{pspicture}
-\end{center}
-\begin{center}
-\begin{pspicture}(-2,-4.5)(2,4.5)
+\hfill
+\begin{pspicture}(-1.5,-2.5)(3.5,3.5)
+\psdiffractionRectangle[IIID,Alpha=30,f=2.5]
+\end{pspicture}
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-3.5,-3.5)(3.5,3.5)
+\psdiffractionRectangle[f=2.5]
+\end{pspicture}
+\hfill
+\begin{pspicture}(-1.5,-2.5)(3.5,3.5)
+\psdiffractionRectangle[IIID,Alpha=30,f=2.5]
+\end{pspicture}
+\end{lstlisting}
+
+
+
+\noindent\begin{pspicture}(-2,-4)(2,4)
\psdiffractionRectangle[a=0.5e-3,k=0.5,f=4,pixel=0.5,colorMode=0]
-\uput[270](0,-4.5){$\backslash$\texttt{psdiffractionRectangle[a=0.5e-3,k=0.5,f=4,colorMode=0]}}
\end{pspicture}
-\end{center}
-\begin{center}
-\begin{pspicture}(-4,-2.5)(4,3)
+\hfill
+\begin{pspicture}(0,-3)(4,4)
+\psdiffractionRectangle[IIID,a=0.5e-3,k=0.5,f=4,pixel=0.5,colorMode=0]
+\end{pspicture}
+
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-2,-4)(2,4)
+\psdiffractionRectangle[a=0.5e-3,k=0.5,f=4,pixel=0.5,colorMode=0]
+\end{pspicture}
+\hfill
+\begin{pspicture}(0,-3)(4,4)
+\psdiffractionRectangle[IIID,a=0.5e-3,k=0.5,f=4,pixel=0.5,colorMode=0]
+\end{pspicture}
+\end{lstlisting}
+
+
+
+\noindent
+\begin{pspicture}(-2.5,-2.5)(3.5,3)
\psdiffractionRectangle[a=0.5e-3,k=2,f=10,lambda=515,colorMode=1]
-\uput[270](0,-2){$\backslash$\texttt{psdiffractionRectangle[a=0.5e-3,k=2,f=10,lambda=515,colorMode=1]}}
\end{pspicture}
-\end{center}
-\begin{center}
-\begin{pspicture}(-4,-1)(4,1)
+\hfill
+\begin{pspicture}(-1.5,-2)(3.5,3)
+\psdiffractionRectangle[IIID,Alpha=20,a=0.5e-3,k=2,f=10,lambda=515,colorMode=1]
+\end{pspicture}
+
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-2.5,-2.5)(3.5,3)
+\psdiffractionRectangle[a=0.5e-3,k=2,f=10,lambda=515,colorMode=1]
+\end{pspicture}
+\hfill
+\begin{pspicture}(-1.5,-2)(3.5,3)
+\psdiffractionRectangle[IIID,Alpha=20,a=0.5e-3,k=2,f=10,lambda=515,colorMode=1]
+\end{pspicture}
+\end{lstlisting}
+
+
+\noindent
+\begin{pspicture}(-3.5,-1)(3.5,1)
\psdiffractionRectangle[a=0.5e-3,k=20,f=10,pixel=0.5,lambda=450]
-\uput[270](0,-0.5){$\backslash$\texttt{psdiffractionRectangle[a=0.5e-3,k=20,f=10,lambda=450]}}
\end{pspicture}
-\end{center}
+\hfill
+\begin{pspicture}(-3.5,-1)(3.5,4)
+\psdiffractionRectangle[IIID,Alpha=10,a=0.5e-3,k=20,f=10,pixel=0.5,lambda=450]
+\end{pspicture}
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-3.5,-1)(3.5,1)
+\psdiffractionRectangle[a=0.5e-3,k=20,f=10,pixel=0.5,lambda=450]
+\end{pspicture}
+\hfill
+\begin{pspicture}(-3.5,-1)(3.5,4)
+\psdiffractionRectangle[IIID,Alpha=10,a=0.5e-3,k=20,f=10,pixel=0.5,lambda=450]
+\end{pspicture}
+\end{lstlisting}
\section{Diffraction par deux ouverture rectangulaire}
-%\begin{shaded}
-%This simulation was provided by Julien
-%\textsc{Cubizolles}.
-%\end{shaded}
+\begin{shaded}
+This simulation was provided by Julien \textsc{Cubizolles}.
+\end{shaded}
+
\begin{center}
+\noindent
\begin{pspicture}(-4,-1)(4,1)
\psdiffractionRectangle[a=0.5e-3,k=10,f=10,pixel=0.5,lambda=650,twoSlit,s=2e-3]
-\uput[270](0,-0.5){$\backslash
-$\texttt{psdiffractionRectangle[a=0.5e-3,k=10,f=10,pixel=0.5,lambda=650,twoSlit,s=2e-3]}}
\end{pspicture}
\end{center}
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-4,-1)(4,1)
+\psdiffractionRectangle[a=0.5e-3,k=10,f=10,pixel=0.5,lambda=650,twoSlit,s=2e-3]
+\end{pspicture}
+\end{lstlisting}
+
+\begin{center}
+\begin{pspicture}(-2,-1)(4,4)
+\psdiffractionRectangle[IIID,Alpha=20,a=0.5e-3,k=10,f=10,pixel=0.5,lambda=650,twoSlit,s=2e-3]
+\end{pspicture}
+\end{center}
+
+\begin{lstlisting}[pos=t,style=example,wide=false]
+\begin{pspicture}(-2,-1)(4,4)
+\psdiffractionRectangle[IIID,Alpha=20,a=0.5e-3,k=10,f=10,pixel=0.5,lambda=650,twoSlit,s=2e-3]
+\end{pspicture}
+\end{lstlisting}
+
\section{Diffraction par une ouverture circulaire}
On donnera le rayon du trou : \texttt{[r=1e-3]}, $r=1$ mm par défaut. Les
variations de l'intensité sont superposées à la figure de diffraction dans
le premier quadrant (le maximum au centre a été écrêté).
+
+
\begin{center}
-\begin{pspicture}(-5,-5)(5,5)
+\begin{pspicture}(-3.5,-3.5)(3.5,3.5)
\psdiffractionCircular[r=0.5e-3,f=10,pixel=0.5,lambda=520]
-\uput[270](0,-5){$\backslash$\texttt{psdiffractionCircular[r=0.5e-3,f=10,lambda=520]}}
+\end{pspicture}
+%
+\begin{pspicture}(-3.5,-1.5)(3.5,3.5)
+\psdiffractionCircular[IIID,r=0.5e-3,f=10,pixel=0.5,lambda=520]
\end{pspicture}
\end{center}
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-3.5,-3.5)(3.5,3.5)
+\psdiffractionCircular[r=0.5e-3,f=10,pixel=0.5,lambda=520]
+\end{pspicture}
+%
+\begin{pspicture}(-3.5,-1.5)(3.5,3.5)
+\psdiffractionCircular[IIID,r=0.5e-3,f=10,pixel=0.5,lambda=520]
+\end{pspicture}
+\end{lstlisting}
+
+
+
\section{Diffraction par deux trous circulaires}
Les deux trous sont identiques, outre le rayon commun des trous on fixera la
demi-distance entre les centres des deux trous avec : \texttt{[d]} et pour
ce cas de figure on activera l'option \texttt{[twoHole]}. On notera que
les temps de calculs d'allongent\ldots
-\begin{center}
-\begin{pspicture}(-5,-5)(5,4)
+
+
+\begin{pspicture}(-3,-3.5)(3.5,3.5)
\psdiffractionCircular[r=0.5e-3,f=10,d=3e-3,lambda=515,twoHole]
-\uput[270](0,-4){$\backslash$\texttt{psdiffractionCircular[r=0.5e-3,f=10,d=3e-3,lambda=515,twoHole]}}
\end{pspicture}
-\end{center}
-\begin{center}
-\begin{pspicture}(-6,-6)(6,6)
+%
+\begin{pspicture}(-3.5,-1.5)(3.5,3.5)
+\psdiffractionCircular[IIID,r=0.5e-3,f=10,d=3e-3,lambda=515,twoHole]
+\end{pspicture}
+
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-3,-3.5)(3.5,3.5)
+\psdiffractionCircular[r=0.5e-3,f=10,d=3e-3,lambda=515,twoHole]
+\end{pspicture}
+%
+\begin{pspicture}(-3.5,-1.5)(3.5,3.5)
+\psdiffractionCircular[IIID,r=0.5e-3,f=10,d=3e-3,lambda=515,twoHole]
+\end{pspicture}
+\end{lstlisting}
+
+
+\hspace*{-1cm}%
+\begin{pspicture}(-3,-3)(3.5,4)
\psdiffractionCircular[r=0.5e-3,f=10,d=2e-3,lambda=700,twoHole,colorMode=0]
-\uput[270](0,-5){$\backslash$\texttt{psdiffractionCircular[r=0.5e-3,f=10,d=2e-3,lambda=700,twoHole,colorMode=0]}}
\end{pspicture}
-\end{center}
+%
+\begin{pspicture}(-3.5,-2)(3.5,3.5)
+\psdiffractionCircular[IIID,r=0.5e-3,f=10,d=2e-3,lambda=700,twoHole,colorMode=0]
+\end{pspicture}
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-3.5,-3)(3.5,4)
+\psdiffractionCircular[r=0.5e-3,f=10,d=2e-3,lambda=700,twoHole,colorMode=0]
+\end{pspicture}
+%
+\begin{pspicture}(-3.5,-2)(3.5,3.5)
+\psdiffractionCircular[IIID,r=0.5e-3,f=10,d=2e-3,lambda=700,twoHole,colorMode=0]
+\end{pspicture}
+\end{lstlisting}
+
Le cas limite d'obtention de franges se vérifie avec $\displaystyle d
-=\frac{a}{1.22}$. Voir~:
+=\frac{a}{1.22}$. Voir~:\\
+\url{http://www.unice.fr/DeptPhys/optique/diff/trouscirc/diffrac.html}).
-\url{http://www.unice.fr\DeptPhys\optique\optique.html}.
-\begin{center}
-\begin{pspicture}(-5,-6)(5,5)
+\hspace*{-1cm}%
+\begin{pspicture}(-3,-3.5)(3,3.5)
\psdiffractionCircular[r=0.5e-3,f=10,d=4.1e-4,lambda=632,twoHole]
-\uput[270](0,-5){$\backslash$\texttt{psdiffractionCircular[r=0.5e-3,f=10,d=4.1e-4,lambda=632,twoHole]}}
\end{pspicture}
-\end{center}
+%
+\begin{pspicture}(-3.5,-1.5)(3.5,3)
+\psdiffractionCircular[IIID,r=0.5e-3,f=10,d=4.1e-4,lambda=632,twoHole]
+\end{pspicture}
+
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-3,-3.5)(3,3.5)
+\psdiffractionCircular[r=0.5e-3,f=10,d=4.1e-4,lambda=632,twoHole]
+\end{pspicture}
+%
+\begin{pspicture}(-3.5,-1.5)(3.5,3)
+\psdiffractionCircular[IIID,r=0.5e-3,f=10,d=4.1e-4,lambda=632,twoHole]
+\end{pspicture}
+\end{lstlisting}
+
+
\section{Diffraction par un trou triangulaire équilatéral}
Le triangle équilatéral est défini par sa hauteur \texttt{[h]} en m. Pour le
@@ -253,33 +400,70 @@ triangle, on peut obtenir la figure en niveaux de gris avec l'option
\textsc{Airy}, on la trouve dans le livre d'Henri \textsc{Bouasse} sur la
diffraction, pages 114 et 115.
+
\begin{center}
\begin{pspicture}(-1,-1)(1,1)
\pspolygon*(0,0)(1;150)(1;210)
\pcline{|-|}(-0.732,-1)(0,-1)
\Aput{$h$}
\end{pspicture}
-
-\vspace{1cm}
-$\backslash$\texttt{psdiffractionTriangle[f=10,h=1e-3,contrast=38,colorMode=]}
+\end{center}
\makebox[\linewidth]{%
-\begin{pspicture}(-3,-3)(3,3)
+\begin{pspicture}(-3,-3)(3,2.5)
\psdiffractionTriangle[f=10,h=1e-3,lambda=515,contrast=38]
-\uput[270](0,-2.5){default color mode (>1)}
\end{pspicture}
-%
-\begin{pspicture}(-3,-3)(3,3)
+\quad
+\begin{pspicture}(-3,-3)(3,2.5)
\psdiffractionTriangle[f=10,h=1e-3,colorMode=1,contrast=38,lambda=515]
-\uput[270](0,-2.5){\texttt{colorMode=1}}
\end{pspicture}
-%
-\begin{pspicture}(-3,-3)(3,3)
+\quad
+\begin{pspicture}(-3,-3)(3,2.5)
\psdiffractionTriangle[f=10,h=1e-3,colorMode=0,contrast=38,lambda=515]
-\uput[270](0,-2.5){\texttt{colorMode=0}}
\end{pspicture}}
-\end{center}
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-3,-3)(3,2.5)
+\psdiffractionTriangle[f=10,h=1e-3,lambda=515,contrast=38]
+\end{pspicture}
+\quad
+\begin{pspicture}(-3,-3)(3,2.5)
+\psdiffractionTriangle[f=10,h=1e-3,colorMode=1,contrast=38,lambda=515]
+\end{pspicture}
+\quad
+\begin{pspicture}(-3,-3)(3,2.5)
+\psdiffractionTriangle[f=10,h=1e-3,colorMode=0,contrast=38,lambda=515]
+\end{pspicture}
+\end{lstlisting}
+
+
+\makebox[\linewidth]{%
+\begin{pspicture}(-3,-2)(3,3.5)
+\psdiffractionTriangle[IIID,f=10,h=1e-3,lambda=515,contrast=38]
+\end{pspicture}
+\quad
+\begin{pspicture}(-3,-2)(3,3.5)
+\psdiffractionTriangle[IIID,f=10,h=1e-3,colorMode=1,contrast=38,lambda=515]
+\end{pspicture}
+\quad
+\begin{pspicture}(-3,-2)(3,3.5)
+\psdiffractionTriangle[IIID,f=10,h=1e-3,colorMode=0,contrast=38,lambda=515]
+\end{pspicture}}
+
+\begin{lstlisting}[style=example]
+\begin{pspicture}(-3,-2)(3,3.5)
+\psdiffractionTriangle[IIID,f=10,h=1e-3,lambda=515,contrast=38]
+\end{pspicture}
+\quad
+\begin{pspicture}(-3,-2)(3,3.5)
+\psdiffractionTriangle[IIID,f=10,h=1e-3,colorMode=1,contrast=38,lambda=515]
+\end{pspicture}
+\quad
+\begin{pspicture}(-3,-2)(3,3.5)
+\psdiffractionTriangle[IIID,f=10,h=1e-3,colorMode=0,contrast=38,lambda=515]
+\end{pspicture}
+\end{lstlisting}