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+%&platex --translate-file=il2-pl
+\documentclass[a4paper,11pt]{article}
+\usepackage{polski}
+\usepackage{tgpagella}
+\usepackage{qpxmath}
+\pagestyle{empty}
+%
+\begin{document}
+%
+\noindent
+%
+Matematyka
+w~tekście: $\sum_{\alpha\rightarrow\infty}\frac{a+1}{a-b^4}$
+i~dalej ($f_m,f_n)=(f_{r_{k-1}}, f_{r_k})$. I~jeszcze $x^{4m}+y^{4m}=z^{4m}$,
+gdzie $m\xgeq 1$.
+$\cal A + \cal G$. ${\varGamma}+\Phi$. Cyfry nautyczne
+\oldstylenums{0123456789}.
+
+ Litera $g$ posiada odmianę, której możemy użyć pisząc
+ \verb+\varg+: $\varg$.
+ Użycie pakietu z~opcją \verb+[altg]+ spowoduje, że domyślnie zostanie
+ użyte $\varg$ a~pisząc \verb+\varg+ otrzymamy $g$.
+
+$$A,\dots,Z\quad a,\dots,z\quad \Gamma, \dots,\Omega\quad
+ \varGamma, \dots, \varOmega\quad
+ \alpha,\dots,\omega$$%\quad \varg \varv \varw \vary,\quad gvwy$$
+\smallskip
+$$\aleph_\alpha\times\aleph_\beta=\aleph_\beta\iff \alpha\le \beta$$
+\smallskip
+$$\forall \varepsilon >\alpha, \Gamma_\alpha\hookrightarrow
+ \Gamma_\varepsilon$$
+$$|x-a| < \delta \Rightarrow |f(x)-l| < \varepsilon$$
+\smallskip
+$$\underbrace {V \times \cdots \times V}_k \times
+ \underbrace {V \times \cdots \times V}_l \rightarrow
+ \underbrace {V \times \cdots \times V}_{k+l}$$
+\smallskip
+$$\{x\mid x \ne x\} = \emptyset\qquad (A\cap B)^\circ\subset A^\circ
+ \cap B^\circ$$
+%
+\begin{eqnarray*}
+\omega &=& \nu+v(x,y)\,dx + w(x,y)\,dy+d\varPsi\\
+ d\omega &=& d\nu+ \left(\frac{\partial w}{\partial x}-
+ \frac{\partial v}{\partial y}\right) dx\wedge dy
+\end{eqnarray*}
+%
+$$\hat x+\widehat X+\widehat{xy}+\widehat{xyz}+\vec A$$
+\smallskip
+$$R_{ijkl}=-R_{jikl}=-R_{ijlk}=R_{klij}$$
+\smallskip
+$$f(x)=\cases{|x|&$x>a$\cr -|x|&$x\le a$\cr}$$
+\smallskip
+$$\int_{-\infty}^\infty e^{-x\cdot\,x}\,dx=\sqrt\pi$$
+\smallskip
+$$ X=\sum_i \xi^i \frac{\partial}{\partial x^i}+\sum_j
+ x^j\frac{\partial}{\partial \dot x^j}$$
+\smallskip
+$$\prod_{j\ge0}\biggl(\sum_{k\ge0}a_{jk}z^k\biggr)
+ =\sum_{n\ge0}z^n\,\Biggl(\sum_
+ {\scriptstyle k_0,k_1,\ldots\ge0\atop
+ \scriptstyle k_0+k_1+\cdots=n}
+ a_{0k_0}a_{1k_1}\ldots\,\Biggr)$$
+\smallskip
+$$\int_0^\infty\frac{t-ib}{t^2+b^2}e^{iat}\,dt=e^{ab}E_1(ab),\qquad a,b>0$$
+
+\end{document}