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+
+\documentclass{article}
+
+\usepackage{amsmath,amsthm}
+\usepackage[letterpaper,text={5.95in,9in}]{geometry}
+
+\pagestyle{empty}
+\setlength{\parindent}{0cm}
+
+\usepackage{arev}
+
+\theoremstyle{definition}
+\newtheorem{theorem}{Theorem}
+
+\begin{document}
+
+\begin{theorem}[Residue Theorem]
+Let $f$ be analytic in the region $G$ except for the isolated singularities $a_1,a_2,\ldots,a_m$. If $\gamma$ is a closed rectifiable curve in $G$ which does not pass through any of the points $a_k$ and if $\gamma\approx 0$ in $G$ then
+\[
+\frac{1}{2\pi i}\int_\gamma f = \sum_{k=1}^m n(\gamma;a_k) \text{Res}(f;a_k).
+\]
+\end{theorem}
+
+Another nice theorem from complex analysis is
+
+\begin{theorem}[Maximum Modulus]
+Let $G$ be a bounded open set in $\mathbb{C}$ and suppose that $f$ is a continuous function on $G^-$ which is analytic in $G$. Then
+\[
+\max\{|f(z)|:z\in G^-\}=\max \{|f(z)|:z\in \partial G \}.
+\]
+\end{theorem}
+
+\newcommand{\abc}{abcdefghijklmnopqrstuvwxyz}
+\newcommand{\ABC}{ABCDEFGHIJKLMNOPQRSTUVWXYZ}
+\newcommand{\alphabeta}{\alpha\beta\gamma\delta\epsilon\varepsilon\zeta\eta\theta\vartheta\iota\kappa\lambda\mu\nu\xi o\pi\varpi\rho\sigma\varsigma\tau\upsilon\phi\varphi\chi\psi\omega}
+\newcommand{\AlphaBeta}{\Gamma\Delta\Theta\Lambda\Xi\Pi\Sigma\Upsilon\Phi\Psi\Omega}
+
+\ABC \qquad $\ABC$
+
+\abc \qquad $\abc$ \quad $\ell\wp\aleph\infty\propto\emptyset\nabla\partial$
+
+$\AlphaBeta$ \qquad $\alphabeta$ \qquad $01234567890$
+
+\end{document}