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author | Karl Berry <karl@freefriends.org> | 2013-09-06 23:12:07 +0000 |
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committer | Karl Berry <karl@freefriends.org> | 2013-09-06 23:12:07 +0000 |
commit | fd742022c0774507d86404341cfe78973fa971c0 (patch) | |
tree | 669fa0210e8efea18d74feab1d3b8aa48415e70f /Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux | |
parent | 4f31616977a64aadc3deb973b68e86b672b938ba (diff) |
latex-referenz (6sep13)
git-svn-id: svn://tug.org/texlive/trunk@31584 c570f23f-e606-0410-a88d-b1316a301751
Diffstat (limited to 'Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux')
-rw-r--r-- | Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux | 36 |
1 files changed, 20 insertions, 16 deletions
diff --git a/Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux b/Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux index de5d01bb008..d0d4914f674 100644 --- a/Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux +++ b/Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux @@ -1,8 +1,10 @@ %% -%% Ein Beispiel der DANTE-Edition +%% Die DANTE-Edition +%% Ein Beispiel der LaTeX Referenz +%% 3. Auflage %% %% -%% Copyright (C) 2010 Herbert Voss +%% Copyright (C) 2013 Herbert Voss %% %% It may be distributed and/or modified under the conditions %% of the LaTeX Project Public License, either version 1.3 @@ -11,23 +13,25 @@ %% See http://www.latex-project.org/lppl.txt for details. %% %% -%%Run also: >> << +%% ==== % Show page(s) 1 %% -\documentclass[ngerman]{article} +%% +\documentclass[]{exaarticle} \pagestyle{empty} -\setlength\textwidth{190.324pt} -\usepackage{babel} +\setlength\textwidth{169.16928pt} +\usepackage[ngerman]{babel} \setlength{\parindent}{0em} - -\usepackage[utf8]{luainputenc} -\def\Laenge(#1,#2)(#3,#4){% - \directlua{% - tex.print(math.sqrt((#4-#2)^2+ - (#3-#1)^2))}} - +%StartShownPreambleCommands +\begingroup%-> normal. Buchstabe +\catcode`\%=12 +\gdef\Laenge(#1,#2)(#3,#4){\directlua{ + tex.print(string.format( + "%.3f",math.sqrt((#4-#2)^2 + +(#3-#1)^2)))}} +\endgroup +%StopShownPreambleCommands \begin{document} -Der Punkt $A(4,1)$ hat vom -Punkt $B(3.2,5.5)$ einen Abstand von -\Laenge(4,1)(3.2,5.5)\,LE. +Der Punkt $A(4,1)$ hat vom Punkt $B(3.2,5.5)$ +einen Abstand von \Laenge(4,1)(3.2,5.5)\,LE. \end{document} |