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authorKarl Berry <karl@freefriends.org>2013-09-06 23:12:07 +0000
committerKarl Berry <karl@freefriends.org>2013-09-06 23:12:07 +0000
commitfd742022c0774507d86404341cfe78973fa971c0 (patch)
tree669fa0210e8efea18d74feab1d3b8aa48415e70f /Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux
parent4f31616977a64aadc3deb973b68e86b672b938ba (diff)
latex-referenz (6sep13)
git-svn-id: svn://tug.org/texlive/trunk@31584 c570f23f-e606-0410-a88d-b1316a301751
Diffstat (limited to 'Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux')
-rw-r--r--Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux36
1 files changed, 20 insertions, 16 deletions
diff --git a/Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux b/Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux
index de5d01bb008..d0d4914f674 100644
--- a/Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux
+++ b/Master/texmf-dist/doc/latex/latex-referenz/01-04-2.lux
@@ -1,8 +1,10 @@
%%
-%% Ein Beispiel der DANTE-Edition
+%% Die DANTE-Edition
+%% Ein Beispiel der LaTeX Referenz
+%% 3. Auflage
%%
%%
-%% Copyright (C) 2010 Herbert Voss
+%% Copyright (C) 2013 Herbert Voss
%%
%% It may be distributed and/or modified under the conditions
%% of the LaTeX Project Public License, either version 1.3
@@ -11,23 +13,25 @@
%% See http://www.latex-project.org/lppl.txt for details.
%%
%%
-%%Run also: >> <<
+%% ====
% Show page(s) 1
%%
-\documentclass[ngerman]{article}
+%%
+\documentclass[]{exaarticle}
\pagestyle{empty}
-\setlength\textwidth{190.324pt}
-\usepackage{babel}
+\setlength\textwidth{169.16928pt}
+\usepackage[ngerman]{babel}
\setlength{\parindent}{0em}
-
-\usepackage[utf8]{luainputenc}
-\def\Laenge(#1,#2)(#3,#4){%
- \directlua{%
- tex.print(math.sqrt((#4-#2)^2+
- (#3-#1)^2))}}
-
+%StartShownPreambleCommands
+\begingroup%-> normal. Buchstabe
+\catcode`\%=12
+\gdef\Laenge(#1,#2)(#3,#4){\directlua{
+ tex.print(string.format(
+ "%.3f",math.sqrt((#4-#2)^2
+ +(#3-#1)^2)))}}
+\endgroup
+%StopShownPreambleCommands
\begin{document}
-Der Punkt $A(4,1)$ hat vom
-Punkt $B(3.2,5.5)$ einen Abstand von
-\Laenge(4,1)(3.2,5.5)\,LE.
+Der Punkt $A(4,1)$ hat vom Punkt $B(3.2,5.5)$
+einen Abstand von \Laenge(4,1)(3.2,5.5)\,LE.
\end{document}