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author | Karl Berry <karl@freefriends.org> | 2020-06-06 21:17:25 +0000 |
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committer | Karl Berry <karl@freefriends.org> | 2020-06-06 21:17:25 +0000 |
commit | 551fe15ca11050a7caa257e04c7c1fb71670bce9 (patch) | |
tree | 2f68c52588c9f4f569ed7b6de1ecfa9d00cb1219 /Master/texmf-dist/doc/latex/einfuehrung/09-07-60.ltx | |
parent | c8375e36ae4c62d7fbadda045786e139456237e8 (diff) |
rm einfuehrung, author request
git-svn-id: svn://tug.org/texlive/trunk@55445 c570f23f-e606-0410-a88d-b1316a301751
Diffstat (limited to 'Master/texmf-dist/doc/latex/einfuehrung/09-07-60.ltx')
-rw-r--r-- | Master/texmf-dist/doc/latex/einfuehrung/09-07-60.ltx | 48 |
1 files changed, 0 insertions, 48 deletions
diff --git a/Master/texmf-dist/doc/latex/einfuehrung/09-07-60.ltx b/Master/texmf-dist/doc/latex/einfuehrung/09-07-60.ltx deleted file mode 100644 index d7fc46f3ae9..00000000000 --- a/Master/texmf-dist/doc/latex/einfuehrung/09-07-60.ltx +++ /dev/null @@ -1,48 +0,0 @@ -%% -%% Ein Beispiel der DANTE-Edition -%% -%% 1. Auflage -%% -%% Beispiel 09-07-60 auf Seite 468. -%% -%% Copyright (C) 2011 Herbert Voss -%% -%% It may be distributed and/or modified under the conditions -%% of the LaTeX Project Public License, either version 1.3 -%% of this license or (at your option) any later version. -%% -%% See http://www.latex-project.org/lppl.txt for details. -%% -%% -%% ==== -% Show page(s) 1 -%% -%% -\documentclass[]{exaarticle} -\pagestyle{empty} -\setlength\textwidth{352.81416pt} -\usepackage[utf8]{inputenc} -\setcounter{equation}{72} -\renewcommand\theequation{9.\arabic{equation}} -\AtBeginDocument{\setlength\parindent{0pt}} -\StartShownPreambleCommands -\usepackage{amsmath} -\newcommand*\diff{\mathop{}\!\mathrm{d}} -\StopShownPreambleCommands -\begin{document} -\begin{align} -A_{1} - &= \left|\int_0^1(f(x)-g(x))\diff x\right| +\left| \int _1^2(g(x)-h(x))\diff x - \right|\nonumber\\ - &= \left|\int_0^1(x^2-3x)\diff x\right| +\left| \int _1^2(x^2-5x+6)\diff x - \right|\nonumber -\intertext{Jetzt werden die Stammfunktionen der beiden Integrale - gebildet und anschließend die Werte berechnet:} - &= \left|\frac{x^3}{3}-\frac{3}{2}x^2\right|_0^1+\left| \frac{x^3}{3}- - \frac{5}{2}x^2+6x\right|_1^2\nonumber\\ - &= \left|\frac{1}{3}-\frac{3}{2}\right| +\left| \frac{8}{3}- \frac{20}{2}+12- - \left(\frac{1}{3}-\frac{5}{2}+6\right) \right| \nonumber\\ - &= \left|-\frac{7}{6}\right| +\left| \frac{28}{6}-\frac{23}{6} \right| =\frac{7}{6}+ - \frac{5}{6}=2\,\text{FE} -\end{align} -\end{document} |