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+\documentclass{article}
+\usepackage[fleqn]{amsmath}
+%\usepackage[pointsonleft,nototals,forpaper,useforms,vspacewithsolns]{eqexam}
+\usepackage[pointsonleft,nototals,forpaper,useforms,solutionsonly]{eqexam}
+
+\solAtEndFormatting{\eqequesitemsep{3pt}}
+
+\subject[MC]{My Course}
+\title[T1]{Test 1}
+\author{Dr.\ D. P. Story}
+\date{\thisterm, \the\year}
+\duedate{2012/04/28}
+\keywords{My Course, Exam \nExam, {\thisterm} semester, \theduedate, at AcroTeX.Net}
+
+%
+% Compile the file with the vspacewithsolns option to create the .sol auxiliary file
+% that contains a listing of all the solutions, like so
+% \usepackage[pointsonleft,nototals,forpaper,useforms,vspacewithsolns]{eqexam}
+% then compile with the solutionsonly option, like so
+% \usepackage[pointsonleft,nototals,forpaper,useforms,solutionsonly]{eqexam}
+%
+\encloseProblemsWith{theseproblems}
+
+\begin{document}
+
+\maketitle
+
+\begin{exam}{myProblems}
+
+\ifsolutionsonly
+\begin{instructions}[Solutions.]
+The solutions to Test~1.
+\end{instructions}
+\belowsqskip{\par} % removes the skip after the exam env
+\else
+\begin{instructions}
+Solve each problem and box in your final $\boxed{\text{answer}}$.
+\end{instructions}
+\fi
+
+\begin{theseproblems}
+
+\begin{problem*}[3ea]
+\leadinitem
+ It is well known that \fillin{1in}{Newton} and
+ \fillin{1in}{Leibniz} are jointly credited as the founders
+ of modern calculus.
+\ifkeyalt
+\begin{solution}
+ It is well known that \fillin{1in}{Newton} and
+ \fillin{1in}{Leibniz} are jointly credited as the founders
+ of modern calculus.
+\end{solution}
+\fi
+
+\begin{parts}
+\item \TF{T} (True `T' or False `F') The area of a circle is $\pi r^2$.
+\ifkeyalt
+\begin{solution}
+\item\TF{T} The area of a circle is $\pi r^2$.
+\end{solution}
+\fi
+
+\item Suppose the \emph{discriminant} of a quadratic equation is
+\emph{negative}, which statement describes the roots to
+the equation?
+\begin{answers}{2}
+\bChoices
+ \Ans0 There is only one real root\eAns
+ \Ans0 There are two distinct real roots\eAns
+ \Ans1 There are two complex roots\eAns
+ \Ans0 None of these\eAns
+\eChoices
+\end{answers}
+\ifkeyalt
+\begin{solution}[]
+\parbox[t]{\linewidth}{\sqTabPos{t}%
+\begin{answers}{2}
+\bChoices
+ \Ans0 There is only one real root\eAns
+ \Ans0 There are two distinct real roots\eAns
+ \Ans1 There are two complex roots\eAns
+ \Ans0 None of these\eAns
+\eChoices
+\end{answers}}%
+\adjDisplayBelow
+\end{solution}
+\fi
+\end{parts}
+\end{problem*}
+
+\begin{problem}[8]
+In the space below, solve the quadratic equation
+$ 2x^2 - 3x + 2 = 0 $ using any valid method.
+\begin{solution}[1.5in]
+We use the quadratic formula:
+\begin{equation*}
+ x = \frac{3 \pm \sqrt{9-4\cdot2\cdot2}}{2\cdot2}
+ = \frac{3 \pm \sqrt{-7}}{4}
+ = \boxed{ \frac{3 \pm \sqrt{7}\,\imath}{4} }
+\end{equation*}
+\end{solution}
+\end{problem}
+
+\begin{problem}[8]
+Find the equation of the line perpendicular to $ 3x - 5y = 2 $ and passing
+through the point $P(1,7)$. Leave your answer in the general form.
+\[
+ \text{Ans:\quad}
+ \fillin[boxed,boxsize=Large]{2in}{5x+3y=26}
+\]
+\begin{solution}[.5in]\ifkeyalt$ \text{Ans:\quad}
+ \fillin[boxed,boxsize=Large]{2in}{5x+3y=26}$\\[3pt]\fi
+Apparently the given line has slope $m=3/5$, so $ m_{\perp}=-5/3$. The rest
+is left to the reader.
+\end{solution}
+\end{problem}
+
+\end{theseproblems}
+\end{exam}
+\end{document}