% \iffalse meta-comment % %% File: l3fp-expo.dtx Copyright (C) 2011-2018 The LaTeX3 Project % % It may be distributed and/or modified under the conditions of the % LaTeX Project Public License (LPPL), either version 1.3c of this % license or (at your option) any later version. The latest version % of this license is in the file % % https://www.latex-project.org/lppl.txt % % This file is part of the "l3kernel bundle" (The Work in LPPL) % and all files in that bundle must be distributed together. % % ----------------------------------------------------------------------- % % The development version of the bundle can be found at % % https://github.com/latex3/latex3 % % for those people who are interested. % %<*driver> \documentclass[full,kernel]{l3doc} \begin{document} \DocInput{\jobname.dtx} \end{document} % % \fi % % \title{The \textsf{l3fp-expo} package\\ % Floating point exponential-related functions} % \author{^^A % The \LaTeX3 Project\thanks % {^^A % E-mail: % \href{mailto:latex-team@latex-project.org} % {latex-team@latex-project.org}^^A % }^^A % } % \date{Released 2018-10-26} % % \maketitle % % \begin{documentation} % % \end{documentation} % % \begin{implementation} % % \section{\pkg{l3fp-expo} implementation} % % \begin{macrocode} %<*initex|package> % \end{macrocode} % % \begin{macrocode} %<@@=fp> % \end{macrocode} % % \begin{macro}[EXP] % { % \@@_parse_word_exp:N , % \@@_parse_word_ln:N , % } % Unary functions. % \begin{macrocode} \cs_new:Npn \@@_parse_word_exp:N { \@@_parse_unary_function:NNN \@@_exp_o:w ? } \cs_new:Npn \@@_parse_word_ln:N { \@@_parse_unary_function:NNN \@@_ln_o:w ? } % \end{macrocode} % \end{macro} % % \subsection{Logarithm} % % \subsubsection{Work plan} % % As for many other functions, we filter out special cases in % \cs{@@_ln_o:w}. Then \cs{@@_ln_npos_o:w} receives a positive normal % number, which we write in the form $a\cdot 10^{b}$ with $a\in[0.1,1)$. % % \emph{The rest of this section is actually not in sync with the code. % Or is the code not in sync with the section? In the current code, % $c\in [1,10]$ is such that $0.7\leq ac < 1.4$.} % % We are given a positive normal number, of the form $a\cdot 10^{b}$ % with $a\in[0.1,1)$. To compute its logarithm, we find a small integer % $5\leq c < 50$ such that $0.91 \leq a c / 5 < 1.1$, and use the % relation % \begin{equation*} % \ln (a \cdot 10^b) = b \cdot \ln (10) - \ln (c/5) + \ln (ac/5). % \end{equation*} % The logarithms $\ln(10)$ and $\ln(c/5)$ are looked up in a table. The % last term is computed using the following Taylor series of $\ln$ near % $1$: % \begin{equation*} % \ln\left(\frac{ac}{5}\right) % = \ln\left(\frac{1+t}{1-t}\right) % = 2t\left(1 + t^2 \left(\frac{1}{3} + t^2 \left(\frac{1}{5} % + t^2 \left(\frac{1}{7} + t^2 \left( \frac{1}{9} + \cdots % \right)\right)\right)\right)\right) % \end{equation*} % where $t=1-10/(ac+5)$. We can now see one reason for the choice of % $ac\sim 5$: then $ac+5=10(1-\epsilon)$ with $-0.05<\epsilon\leq % 0.045$, hence % \begin{equation*} % t = \frac{\epsilon}{1-\epsilon} % = \epsilon (1+\epsilon)(1+\epsilon^2)(1+\epsilon^4)\ldots, % \end{equation*} % is not too difficult to compute. % % \subsubsection{Some constants} % % \begin{variable} % { % \c_@@_ln_i_fixed_tl , % \c_@@_ln_ii_fixed_tl , % \c_@@_ln_iii_fixed_tl , % \c_@@_ln_iv_fixed_tl , % \c_@@_ln_vi_fixed_tl , % \c_@@_ln_vii_fixed_tl , % \c_@@_ln_viii_fixed_tl , % \c_@@_ln_ix_fixed_tl , % \c_@@_ln_x_fixed_tl, % } % A few values of the logarithm as extended fixed point numbers. % Those are needed in the implementation. It turns out that we don't % need the value of $\ln(5)$. % \begin{macrocode} \tl_const:Nn \c_@@_ln_i_fixed_tl { {0000}{0000}{0000}{0000}{0000}{0000};} \tl_const:Nn \c_@@_ln_ii_fixed_tl { {6931}{4718}{0559}{9453}{0941}{7232};} \tl_const:Nn \c_@@_ln_iii_fixed_tl {{10986}{1228}{8668}{1096}{9139}{5245};} \tl_const:Nn \c_@@_ln_iv_fixed_tl {{13862}{9436}{1119}{8906}{1883}{4464};} \tl_const:Nn \c_@@_ln_vi_fixed_tl {{17917}{5946}{9228}{0550}{0081}{2477};} \tl_const:Nn \c_@@_ln_vii_fixed_tl {{19459}{1014}{9055}{3133}{0510}{5353};} \tl_const:Nn \c_@@_ln_viii_fixed_tl{{20794}{4154}{1679}{8359}{2825}{1696};} \tl_const:Nn \c_@@_ln_ix_fixed_tl {{21972}{2457}{7336}{2193}{8279}{0490};} \tl_const:Nn \c_@@_ln_x_fixed_tl {{23025}{8509}{2994}{0456}{8401}{7991};} % \end{macrocode} % \end{variable} % % \subsubsection{Sign, exponent, and special numbers} % % \begin{macro}[EXP]{\@@_ln_o:w} % The logarithm of negative numbers (including $-\infty$ and $-0$) % raises the \enquote{invalid} exception. The logarithm of $+0$ is % $-\infty$, raising a division by zero exception. The logarithm of % $+\infty$ or a \texttt{nan} is itself. Positive normal numbers call % \cs{@@_ln_npos_o:w}. % \begin{macrocode} \cs_new:Npn \@@_ln_o:w #1 \s_@@ \@@_chk:w #2#3#4; @ { \if_meaning:w 2 #3 \@@_case_use:nw { \@@_invalid_operation_o:nw { ln } } \fi: \if_case:w #2 \exp_stop_f: \@@_case_use:nw { \@@_division_by_zero_o:Nnw \c_minus_inf_fp { ln } } \or: \else: \@@_case_return_same_o:w \fi: \@@_ln_npos_o:w \s_@@ \@@_chk:w #2#3#4; } % \end{macrocode} % \end{macro} % % \subsubsection{Absolute ln} % % \begin{macro}[EXP]{\@@_ln_npos_o:w} % We catch the case of a significand very close to $0.1$ or to $1$. % In all other cases, the final result is at least $10^{-4}$, and % then an error of $0.5\cdot 10^{-20}$ is acceptable. % \begin{macrocode} \cs_new:Npn \@@_ln_npos_o:w \s_@@ \@@_chk:w 10#1#2#3; { %^^A todo: ln(1) should be "exact zero", not "underflow" \exp_after:wN \@@_sanitize:Nw \int_value:w % for the overall sign \if_int_compare:w #1 < 1 \exp_stop_f: 2 \else: 0 \fi: \exp_after:wN \exp_stop_f: \int_value:w \@@_int_eval:w % for the exponent \@@_ln_significand:NNNNnnnN #2#3 \@@_ln_exponent:wn {#1} } % \end{macrocode} % \end{macro} % % \begin{macro}[EXP]{\@@_ln_significand:NNNNnnnN} % \begin{syntax} % \cs{@@_ln_significand:NNNNnnnN} \meta{X_1} \Arg{X_2} \Arg{X_3} \Arg{X_4} \meta{continuation} % \end{syntax} % This function expands to % \begin{syntax} % \meta{continuation} \Arg{Y_1} \Arg{Y_2} \Arg{Y_3} \Arg{Y_4} \Arg{Y_5} \Arg{Y_6} |;| % \end{syntax} % where $Y = - \ln(X)$ as an extended fixed point. % \begin{macrocode} \cs_new:Npn \@@_ln_significand:NNNNnnnN #1#2#3#4 { \exp_after:wN \@@_ln_x_ii:wnnnn \int_value:w \if_case:w #1 \exp_stop_f: \or: \if_int_compare:w #2 < 4 \exp_stop_f: \@@_int_eval:w 10 - #2 \else: 6 \fi: \or: 4 \or: 3 \or: 2 \or: 2 \or: 2 \else: 1 \fi: ; { #1 #2 #3 #4 } } % \end{macrocode} % \end{macro} % % \begin{macro}[EXP]{\@@_ln_x_ii:wnnnn} % We have thus found $c \in [1,10]$ such that $0.7\leq ac < 1.4$ % in all cases. Compute $ 1 + x = 1 + ac \in [1.7,2.4)$. % \begin{macrocode} \cs_new:Npn \@@_ln_x_ii:wnnnn #1; #2#3#4#5 { \exp_after:wN \@@_ln_div_after:Nw \cs:w c_@@_ln_ \@@_int_to_roman:w #1 _fixed_tl \exp_after:wN \cs_end: \int_value:w \exp_after:wN \@@_ln_x_iv:wnnnnnnnn \int_value:w \@@_int_eval:w \exp_after:wN \@@_ln_x_iii_var:NNNNNw \int_value:w \@@_int_eval:w 9999 9990 + #1*#2#3 + \exp_after:wN \@@_ln_x_iii:NNNNNNw \int_value:w \@@_int_eval:w 10 0000 0000 + #1*#4#5 ; {20000} {0000} {0000} {0000} } %^^A todo: reoptimize (a generalization attempt failed). \cs_new:Npn \@@_ln_x_iii:NNNNNNw #1#2 #3#4#5#6 #7; { #1#2; {#3#4#5#6} {#7} } \cs_new:Npn \@@_ln_x_iii_var:NNNNNw #1 #2#3#4#5 #6; { #1#2#3#4#5 + 1 ; {#1#2#3#4#5} {#6} } % \end{macrocode} % The Taylor series to be used is expressed in terms of % $t = (x-1)/(x+1) = 1 - 2/(x+1)$. We now compute the % quotient with extended precision, reusing some code % from \cs{@@_/_o:ww}. Note that $1+x$ is known exactly. % % To reuse notations from \pkg{l3fp-basics}, we want to % compute $ A / Z $ with $ A = 2 $ and $ Z = x + 1 $. % In \pkg{l3fp-basics}, we considered the case where % both $A$ and $Z$ are arbitrary, in the range $[0.1,1)$, % and we had to monitor the growth of the sequence of % remainders $A$, $B$, $C$, etc. to ensure that no overflow % occurred during the computation of the next quotient. % The main source of risk was our choice to define the % quotient as roughly $10^9 \cdot A / 10^5 \cdot Z$: then % $A$ was bound to be below $2.147\cdots$, and this limit % was never far. % % In our case, we can simply work with $10^8 \cdot A$ and % $10^4 \cdot Z$, because our reason to work with higher % powers has gone: we needed the integer $y \simeq 10^5 \cdot Z$ % to be at least $10^4$, and now, the definition % $y \simeq 10^4 \cdot Z$ suffices. % % Let us thus define $y = \left\lfloor 10^4 \cdot Z \right\rfloor + 1 % \in ( 1.7 \cdot 10^4, 2.4 \cdot 10^4 ] $, and % \[ % Q_{1} % = % \left\lfloor % \frac {\left\lfloor 10^8 \cdot A\right\rfloor} {y} - \frac{1}{2} % \right\rfloor. % \] % (The $1/2$ comes from how \eTeX{} rounds.) As for division, it is % easy to see that $Q_{1} \leq 10^4 A / Z$, \emph{i.e.}, $Q_{1}$ % is an underestimate. % % Exactly as we did for division, we set $B = 10^4 A - Q_{1}Z$. Then % \begin{align*} % 10^4 B % & \leq % A_{1}A_{2}.A_{3}A_{4} % - \left( \frac{A_{1}A_{2}}{y} - \frac{3}{2} \right) 10^4 Z % \\ % & \leq % A_{1}A_{2} \left( 1 - \frac{10^4 Z}{y} \right) + 1 + \frac{3}{2} y % \\ % & \leq % 10^8 \frac{A}{y} + 1 + \frac{3}{2} y % \end{align*} % In the same way, and using $1.7\cdot 10^4\leq y\leq 2.4\cdot 10^4$, % and convexity, we get % \begin{align*} % 10^4 A &= 2\cdot 10^4 \\ % 10^4 B &\leq 10^8 \frac{A}{y} + 1.6 y \leq 4.7\cdot 10^4\\ % 10^4 C &\leq 10^8 \frac{B}{y} + 1.6 y \leq 5.8\cdot 10^4\\ % 10^4 D &\leq 10^8 \frac{C}{y} + 1.6 y \leq 6.3\cdot 10^4\\ % 10^4 E &\leq 10^8 \frac{D}{y} + 1.6 y \leq 6.5\cdot 10^4\\ % 10^4 F &\leq 10^8 \frac{E}{y} + 1.6 y \leq 6.6\cdot 10^4\\ % \end{align*} % Note that we compute more steps than for division: since $t$ is % not the end result, we need to know it with more accuracy % (on the other hand, the ending is much simpler, as we don't % need an exact rounding for transcendental functions, but just % a faithful rounding). % ^^A todo: doc % % \begin{syntax} % \cs{@@_ln_x_iv:wnnnnnnnn} \meta{1 or 2} \meta{8d} |;| \Arg{4d} \Arg{4d} \meta{fixed-tl} % \end{syntax} % The number is $x$. Compute $y$ by adding 1 to the five first digits. % \begin{macrocode} \cs_new:Npn \@@_ln_x_iv:wnnnnnnnn #1; #2#3#4#5 #6#7#8#9 { \exp_after:wN \@@_div_significand_pack:NNN \int_value:w \@@_int_eval:w \@@_ln_div_i:w #1 ; #6 #7 ; {#8} {#9} {#2} {#3} {#4} {#5} { \exp_after:wN \@@_ln_div_ii:wwn \int_value:w #1 } { \exp_after:wN \@@_ln_div_ii:wwn \int_value:w #1 } { \exp_after:wN \@@_ln_div_ii:wwn \int_value:w #1 } { \exp_after:wN \@@_ln_div_ii:wwn \int_value:w #1 } { \exp_after:wN \@@_ln_div_vi:wwn \int_value:w #1 } } \cs_new:Npn \@@_ln_div_i:w #1; { \exp_after:wN \@@_div_significand_calc:wwnnnnnnn \int_value:w \@@_int_eval:w 999999 + 2 0000 0000 / #1 ; % Q1 } \cs_new:Npn \@@_ln_div_ii:wwn #1; #2;#3 % y; B1;B2 <- for k=1 { \exp_after:wN \@@_div_significand_pack:NNN \int_value:w \@@_int_eval:w \exp_after:wN \@@_div_significand_calc:wwnnnnnnn \int_value:w \@@_int_eval:w 999999 + #2 #3 / #1 ; % Q2 #2 #3 ; } \cs_new:Npn \@@_ln_div_vi:wwn #1; #2;#3#4#5 #6#7#8#9 %y;F1;F2F3F4x1x2x3x4 { \exp_after:wN \@@_div_significand_pack:NNN \int_value:w \@@_int_eval:w 1000000 + #2 #3 / #1 ; % Q6 } % \end{macrocode} % We now have essentially % ^^A todo: determine error on $Q_{6}$ (probably $6.7$), % ^^A todo: conclude the final result is off by $<10^{-23}$ % \begin{syntax} % \cs{@@_ln_div_after:Nw} \meta{fixed tl} % \cs{@@_div_significand_pack:NNN} $10^6 + Q_{1}$ % \cs{@@_div_significand_pack:NNN} $10^6 + Q_{2}$ % \cs{@@_div_significand_pack:NNN} $10^6 + Q_{3}$ % \cs{@@_div_significand_pack:NNN} $10^6 + Q_{4}$ % \cs{@@_div_significand_pack:NNN} $10^6 + Q_{5}$ % \cs{@@_div_significand_pack:NNN} $10^6 + Q_{6}$ |;| % \meta{exponent} |;| \meta{continuation} % \end{syntax} % where \meta{fixed tl} holds the logarithm of a number % in $[1,10]$, and \meta{exponent} is % the exponent. Also, the expansion is done backwards. Then % \cs{@@_div_significand_pack:NNN} puts things in the % correct order to add the $Q_{i}$ together and put semicolons % between each piece. Once those have been expanded, we get % \begin{syntax} % \cs{@@_ln_div_after:Nw} \meta{fixed-tl} \meta{1d} |;| \meta{4d} |;| \meta{4d} |;| % ~~\meta{4d} |;| \meta{4d} |;| \meta{4d} |;| \meta{4d} |;| \meta{exponent} |;| % \end{syntax} % ^^A todo: redoc. % Just as with division, we know that the first two digits % are |1| and |0| because of bounds on the final result of % the division $2/(x+1)$, which is between roughly $0.8$ and $1.2$. % We then compute $1-2/(x+1)$, after testing whether $2/(x+1)$ is % greater than or smaller than $1$. % \begin{macrocode} \cs_new:Npn \@@_ln_div_after:Nw #1#2; { \if_meaning:w 0 #2 \exp_after:wN \@@_ln_t_small:Nw \else: \exp_after:wN \@@_ln_t_large:NNw \exp_after:wN - \fi: #1 } \cs_new:Npn \@@_ln_t_small:Nw #1 #2; #3; #4; #5; #6; #7; { \exp_after:wN \@@_ln_t_large:NNw \exp_after:wN + % \exp_after:wN #1 \int_value:w \@@_int_eval:w 9999 - #2 \exp_after:wN ; \int_value:w \@@_int_eval:w 9999 - #3 \exp_after:wN ; \int_value:w \@@_int_eval:w 9999 - #4 \exp_after:wN ; \int_value:w \@@_int_eval:w 9999 - #5 \exp_after:wN ; \int_value:w \@@_int_eval:w 9999 - #6 \exp_after:wN ; \int_value:w \@@_int_eval:w 1 0000 - #7 ; } % \end{macrocode} % % \begin{syntax} % \cs{@@_ln_t_large:NNw} \meta{sign} \meta{fixed tl} % ~~\meta{t_1}|;| \meta{t_2} |;| \meta{t_3}|;| \meta{t_4}|;| \meta{t_5} |;| \meta{t_6}|;| % ~~\meta{exponent} |;| \meta{continuation} % \end{syntax} % Compute the square $|t|^2$, and keep $|t|$ at the end with its % sign. We know that $|t|<0.1765$, so every piece has at most $4$ % digits. However, since we were not careful in \cs{@@_ln_t_small:w}, % they can have less than $4$ digits. % \begin{macrocode} \cs_new:Npn \@@_ln_t_large:NNw #1 #2 #3; #4; #5; #6; #7; #8; { \exp_after:wN \@@_ln_square_t_after:w \int_value:w \@@_int_eval:w 9999 0000 + #3*#3 \exp_after:wN \@@_ln_square_t_pack:NNNNNw \int_value:w \@@_int_eval:w 9999 0000 + 2*#3*#4 \exp_after:wN \@@_ln_square_t_pack:NNNNNw \int_value:w \@@_int_eval:w 9999 0000 + 2*#3*#5 + #4*#4 \exp_after:wN \@@_ln_square_t_pack:NNNNNw \int_value:w \@@_int_eval:w 9999 0000 + 2*#3*#6 + 2*#4*#5 \exp_after:wN \@@_ln_square_t_pack:NNNNNw \int_value:w \@@_int_eval:w 1 0000 0000 + 2*#3*#7 + 2*#4*#6 + #5*#5 + (2*#3*#8 + 2*#4*#7 + 2*#5*#6) / 1 0000 % ; ; ; \exp_after:wN \@@_ln_twice_t_after:w \int_value:w \@@_int_eval:w -1 + 2*#3 \exp_after:wN \@@_ln_twice_t_pack:Nw \int_value:w \@@_int_eval:w 9999 + 2*#4 \exp_after:wN \@@_ln_twice_t_pack:Nw \int_value:w \@@_int_eval:w 9999 + 2*#5 \exp_after:wN \@@_ln_twice_t_pack:Nw \int_value:w \@@_int_eval:w 9999 + 2*#6 \exp_after:wN \@@_ln_twice_t_pack:Nw \int_value:w \@@_int_eval:w 9999 + 2*#7 \exp_after:wN \@@_ln_twice_t_pack:Nw \int_value:w \@@_int_eval:w 10000 + 2*#8 ; ; { \@@_ln_c:NwNw #1 } #2 } \cs_new:Npn \@@_ln_twice_t_pack:Nw #1 #2; { + #1 ; {#2} } \cs_new:Npn \@@_ln_twice_t_after:w #1; { ;;; {#1} } \cs_new:Npn \@@_ln_square_t_pack:NNNNNw #1 #2#3#4#5 #6; { + #1#2#3#4#5 ; {#6} } \cs_new:Npn \@@_ln_square_t_after:w 1 0 #1#2#3 #4; { \@@_ln_Taylor:wwNw {0#1#2#3} {#4} } % \end{macrocode} % \end{macro} % % \begin{macro}{\@@_ln_Taylor:wwNw} % Denoting $T=t^2$, we get % \begin{syntax} % \cs{@@_ln_Taylor:wwNw} % ~~\Arg{T_1} \Arg{T_2} \Arg{T_3} \Arg{T_4} \Arg{T_5} \Arg{T_6} |;| |;| % ~~\Arg{(2t)_1} \Arg{(2t)_2} \Arg{(2t)_3} \Arg{(2t)_4} \Arg{(2t)_5} \Arg{(2t)_6} |;| % ~~|{| \cs{@@_ln_c:NwNw} \meta{sign} |}| % ~~\meta{fixed tl} \meta{exponent} |;| \meta{continuation} % \end{syntax} % And we want to compute % \[ % \ln\left(\frac{1+t}{1-t}\right) % = 2t\left(1 + T \left(\frac{1}{3} + T \left(\frac{1}{5} % + T \left(\frac{1}{7} + T \left( \frac{1}{9} + \cdots % \right)\right)\right)\right)\right) % \] % The process looks as follows % \begin{verbatim} % \loop 5; A; % \div_int 5; 1.0; \add A; \mul T; {\loop \eval 5-2;} % \add 0.2; A; \mul T; {\loop \eval 5-2;} % \mul B; T; {\loop 3;} % \loop 3; C; % \end{verbatim} % ^^A todo: doc % % This uses the routine for dividing a number by a small integer % (${}<10^4$). % \begin{macrocode} \cs_new:Npn \@@_ln_Taylor:wwNw { \@@_ln_Taylor_loop:www 21 ; {0000}{0000}{0000}{0000}{0000}{0000} ; } \cs_new:Npn \@@_ln_Taylor_loop:www #1; #2; #3; { \if_int_compare:w #1 = 1 \exp_stop_f: \@@_ln_Taylor_break:w \fi: \exp_after:wN \@@_fixed_div_int:wwN \c_@@_one_fixed_tl #1; \@@_fixed_add:wwn #2; \@@_fixed_mul:wwn #3; { \exp_after:wN \@@_ln_Taylor_loop:www \int_value:w \@@_int_eval:w #1 - 2 ; } #3; } \cs_new:Npn \@@_ln_Taylor_break:w \fi: #1 \@@_fixed_add:wwn #2#3; #4 ;; { \fi: \exp_after:wN \@@_fixed_mul:wwn \exp_after:wN { \int_value:w \@@_int_eval:w 10000 + #2 } #3; } % \end{macrocode} % \end{macro} % % \begin{macro}{\@@_ln_c:NwNw} % \begin{syntax} % \cs{@@_ln_c:NwNw} \meta{sign} % ~~\Arg{r_1} \Arg{r_2} \Arg{r_3} \Arg{r_4} \Arg{r_5} \Arg{r_6} |;| % ~~\meta{fixed tl} \meta{exponent} |;| \meta{continuation} % \end{syntax} % We are now reduced to finding $\ln(c)$ and $\meta{exponent}\ln(10)$ % in a table, and adding it to the mixture. The first step is to % get $\ln(c) - \ln(x) = - \ln(a)$, then we get $|b|\ln(10)$ and add % or subtract. % % For now, $\ln(x)$ is given as $\cdot 10^0$. Unless both the exponent % is $1$ and $c=1$, we shift to working in units of $\cdot 10^4$, % since the final result is at least $\ln(10/7) \simeq 0.35$. % \begin{macrocode} \cs_new:Npn \@@_ln_c:NwNw #1 #2; #3 { \if_meaning:w + #1 \exp_after:wN \exp_after:wN \exp_after:wN \@@_fixed_sub:wwn \else: \exp_after:wN \exp_after:wN \exp_after:wN \@@_fixed_add:wwn \fi: #3 #2 ; } % \end{macrocode} % \end{macro} % % \begin{macro}{\@@_ln_exponent:wn} % \begin{syntax} % \cs{@@_ln_exponent:wn} % ~~\Arg{s_1} \Arg{s_2} \Arg{s_3} \Arg{s_4} \Arg{s_5} \Arg{s_6} |;| % ~~\Arg{exponent} % \end{syntax} % Compute \meta{exponent} times $\ln(10)$. Apart from the cases where % \meta{exponent} is $0$ or $1$, the result is necessarily at % least $\ln(10) \simeq 2.3$ in magnitude. We can thus drop the least % significant $4$ digits. In the case of a very large (positive or % negative) exponent, we can (and we need to) drop $4$ additional % digits, since the result is of order $10^4$. Naively, one would % think that in both cases we can drop $4$ more digits than we do, % but that would be slightly too tight for rounding to happen correctly. % Besides, we already have addition and subtraction for $24$ digits % fixed point numbers. % \begin{macrocode} \cs_new:Npn \@@_ln_exponent:wn #1; #2 { \if_case:w #2 \exp_stop_f: 0 \@@_case_return:nw { \@@_fixed_to_float_o:Nw 2 } \or: \exp_after:wN \@@_ln_exponent_one:ww \int_value:w \else: \if_int_compare:w #2 > 0 \exp_stop_f: \exp_after:wN \@@_ln_exponent_small:NNww \exp_after:wN 0 \exp_after:wN \@@_fixed_sub:wwn \int_value:w \else: \exp_after:wN \@@_ln_exponent_small:NNww \exp_after:wN 2 \exp_after:wN \@@_fixed_add:wwn \int_value:w - \fi: \fi: #2; #1; } % \end{macrocode} % Now we painfully write all the cases.\footnote{Bruno: do rounding.} % No overflow nor underflow can happen, except when computing \texttt{ln(1)}. % \begin{macrocode} \cs_new:Npn \@@_ln_exponent_one:ww 1; #1; { 0 \exp_after:wN \@@_fixed_sub:wwn \c_@@_ln_x_fixed_tl #1; \@@_fixed_to_float_o:wN 0 } % \end{macrocode} % For small exponents, we just drop one block of digits, and set the % exponent of the log to $4$ (minus any shift coming from leading zeros % in the conversion from fixed point to floating point). Note that here % the exponent has been made positive. % \begin{macrocode} \cs_new:Npn \@@_ln_exponent_small:NNww #1#2#3; #4#5#6#7#8#9; { 4 \exp_after:wN \@@_fixed_mul:wwn \c_@@_ln_x_fixed_tl {#3}{0000}{0000}{0000}{0000}{0000} ; #2 {0000}{#4}{#5}{#6}{#7}{#8}; \@@_fixed_to_float_o:wN #1 } % \end{macrocode} % \end{macro} % % \subsection{Exponential} % % \subsubsection{Sign, exponent, and special numbers} % % \begin{macro}[EXP]{\@@_exp_o:w} % \begin{macrocode} \cs_new:Npn \@@_exp_o:w #1 \s_@@ \@@_chk:w #2#3#4; @ { \if_case:w #2 \exp_stop_f: \@@_case_return_o:Nw \c_one_fp \or: \exp_after:wN \@@_exp_normal_o:w \or: \if_meaning:w 0 #3 \exp_after:wN \@@_case_return_o:Nw \exp_after:wN \c_inf_fp \else: \exp_after:wN \@@_case_return_o:Nw \exp_after:wN \c_zero_fp \fi: \or: \@@_case_return_same_o:w \fi: \s_@@ \@@_chk:w #2#3#4; } % \end{macrocode} % \end{macro} % % \begin{macro}[EXP]{\@@_exp_normal_o:w, \@@_exp_pos_o:Nnwnw, \@@_exp_overflow:NN} % \begin{macrocode} \cs_new:Npn \@@_exp_normal_o:w \s_@@ \@@_chk:w 1#1 { \if_meaning:w 0 #1 \@@_exp_pos_o:NNwnw + \@@_fixed_to_float_o:wN \else: \@@_exp_pos_o:NNwnw - \@@_fixed_inv_to_float_o:wN \fi: } \cs_new:Npn \@@_exp_pos_o:NNwnw #1#2#3 \fi: #4#5; { \fi: \if_int_compare:w #4 > \c_@@_max_exp_exponent_int \token_if_eq_charcode:NNTF + #1 { \@@_exp_overflow:NN \@@_overflow:w \c_inf_fp } { \@@_exp_overflow:NN \@@_underflow:w \c_zero_fp } \exp:w \else: \exp_after:wN \@@_sanitize:Nw \exp_after:wN 0 \int_value:w #1 \@@_int_eval:w \if_int_compare:w #4 < 0 \exp_stop_f: \exp_after:wN \use_i:nn \else: \exp_after:wN \use_ii:nn \fi: { 0 \@@_decimate:nNnnnn { - #4 } \@@_exp_Taylor:Nnnwn } { \@@_decimate:nNnnnn { \c_@@_prec_int - #4 } \@@_exp_pos_large:NnnNwn } #5 {#4} #1 #2 0 \exp:w \fi: \exp_after:wN \exp_end: } \cs_new:Npn \@@_exp_overflow:NN #1#2 { \exp_after:wN \exp_after:wN \exp_after:wN #1 \exp_after:wN #2 } % \end{macrocode} % \end{macro} % % \begin{macro}[EXP]{\@@_exp_Taylor:Nnnwn} % \begin{macro}[EXP]{\@@_exp_Taylor_loop:www, \@@_exp_Taylor_break:Nww} % This function is called for numbers in the range $[10^{-9}, % 10^{-1})$. We compute $10$ terms of the Taylor series. The % first argument is irrelevant (rounding digit used by some other % functions). The next three arguments, at least $16$ digits, % delimited by a semicolon, form a fixed point number, so we pack it % in blocks of $4$ digits. % \begin{macrocode} \cs_new:Npn \@@_exp_Taylor:Nnnwn #1#2#3 #4; #5 #6 { #6 \@@_pack_twice_four:wNNNNNNNN \@@_pack_twice_four:wNNNNNNNN \@@_pack_twice_four:wNNNNNNNN \@@_exp_Taylor_ii:ww ; #2#3#4 0000 0000 ; } \cs_new:Npn \@@_exp_Taylor_ii:ww #1; #2; { \@@_exp_Taylor_loop:www 10 ; #1 ; #1 ; \s_stop } \cs_new:Npn \@@_exp_Taylor_loop:www #1; #2; #3; { \if_int_compare:w #1 = 1 \exp_stop_f: \exp_after:wN \@@_exp_Taylor_break:Nww \fi: \@@_fixed_div_int:wwN #3 ; #1 ; \@@_fixed_add_one:wN \@@_fixed_mul:wwn #2 ; { \exp_after:wN \@@_exp_Taylor_loop:www \int_value:w \@@_int_eval:w #1 - 1 ; #2 ; } } \cs_new:Npn \@@_exp_Taylor_break:Nww #1 #2; #3 \s_stop { \@@_fixed_add_one:wN #2 ; } % \end{macrocode} % \end{macro} % \end{macro} % % \begin{variable}{\c_@@_exp_intarray} % The integer array has $6\times 9\times 4=216$ items encoding the % values of $\exp(j\times 10^i)$ for $j=1,\dots,9$ and $i=-1,\dots,4$. % Each value is expressed as $\simeq 10^p \times 0.m_1m_2m_3$ with % three $8$-digit blocks $m_1$, $m_2$, $m_3$ and an integer % exponent~$p$ (one more than the scientific exponent), and these are % stored in the integer array as four items: $p$, $10^8+m_1$, % $10^8+m_2$, $10^8+m_3$. The various exponentials are stored in % increasing order of $j\times 10^i$. % % Storing this data in an integer array makes it slightly harder to % access (slower, too), but uses $16$ bytes of memory per exponential % stored, while storing as tokens used around $40$ tokens; tokens have % an especially large footprint in Unicode-aware engines. % \begin{macrocode} \intarray_const_from_clist:Nn \c_@@_exp_intarray { 1 , 1 1105 1709 , 1 1807 5647 , 1 6248 1171 , 1 , 1 1221 4027 , 1 5816 0169 , 1 8339 2107 , 1 , 1 1349 8588 , 1 0757 6003 , 1 1039 8374 , 1 , 1 1491 8246 , 1 9764 1270 , 1 3178 2485 , 1 , 1 1648 7212 , 1 7070 0128 , 1 1468 4865 , 1 , 1 1822 1188 , 1 0039 0508 , 1 9748 7537 , 1 , 1 2013 7527 , 1 0747 0476 , 1 5216 2455 , 1 , 1 2225 5409 , 1 2849 2467 , 1 6045 7954 , 1 , 1 2459 6031 , 1 1115 6949 , 1 6638 0013 , 1 , 1 2718 2818 , 1 2845 9045 , 1 2353 6029 , 1 , 1 7389 0560 , 1 9893 0650 , 1 2272 3043 , 2 , 1 2008 5536 , 1 9231 8766 , 1 7740 9285 , 2 , 1 5459 8150 , 1 0331 4423 , 1 9078 1103 , 3 , 1 1484 1315 , 1 9102 5766 , 1 0342 1116 , 3 , 1 4034 2879 , 1 3492 7351 , 1 2260 8387 , 4 , 1 1096 6331 , 1 5842 8458 , 1 5992 6372 , 4 , 1 2980 9579 , 1 8704 1728 , 1 2747 4359 , 4 , 1 8103 0839 , 1 2757 5384 , 1 0077 1000 , 5 , 1 2202 6465 , 1 7948 0671 , 1 6516 9579 , 9 , 1 4851 6519 , 1 5409 7902 , 1 7796 9107 , 14 , 1 1068 6474 , 1 5815 2446 , 1 2146 9905 , 18 , 1 2353 8526 , 1 6837 0199 , 1 8540 7900 , 22 , 1 5184 7055 , 1 2858 7072 , 1 4640 8745 , 27 , 1 1142 0073 , 1 8981 5684 , 1 2836 6296 , 31 , 1 2515 4386 , 1 7091 9167 , 1 0062 6578 , 35 , 1 5540 6223 , 1 8439 3510 , 1 0525 7117 , 40 , 1 1220 4032 , 1 9431 7840 , 1 8020 0271 , 44 , 1 2688 1171 , 1 4181 6135 , 1 4484 1263 , 87 , 1 7225 9737 , 1 6812 5749 , 1 2581 7748 , 131 , 1 1942 4263 , 1 9524 1255 , 1 9365 8421 , 174 , 1 5221 4696 , 1 8976 4143 , 1 9505 8876 , 218 , 1 1403 5922 , 1 1785 2837 , 1 4107 3977 , 261 , 1 3773 0203 , 1 0092 9939 , 1 8234 0143 , 305 , 1 1014 2320 , 1 5473 5004 , 1 5094 5533 , 348 , 1 2726 3745 , 1 7211 2566 , 1 5673 6478 , 391 , 1 7328 8142 , 1 2230 7421 , 1 7051 8866 , 435 , 1 1970 0711 , 1 1401 7046 , 1 9938 8888 , 869 , 1 3881 1801 , 1 9428 4368 , 1 5764 8232 , 1303 , 1 7646 2009 , 1 8905 4704 , 1 8893 1073 , 1738 , 1 1506 3559 , 1 7005 0524 , 1 9009 7592 , 2172 , 1 2967 6283 , 1 8402 3667 , 1 0689 6630 , 2606 , 1 5846 4389 , 1 5650 2114 , 1 7278 5046 , 3041 , 1 1151 7900 , 1 5080 6878 , 1 2914 4154 , 3475 , 1 2269 1083 , 1 0850 6857 , 1 8724 4002 , 3909 , 1 4470 3047 , 1 3316 5442 , 1 6408 6591 , 4343 , 1 8806 8182 , 1 2566 2921 , 1 5872 6150 , 8686 , 1 7756 0047 , 1 2598 6861 , 1 0458 3204 , 13029 , 1 6830 5723 , 1 7791 4884 , 1 1932 7351 , 17372 , 1 6015 5609 , 1 3095 3052 , 1 3494 7574 , 21715 , 1 5297 7951 , 1 6443 0315 , 1 3251 3576 , 26058 , 1 4665 6719 , 1 0099 3379 , 1 5527 2929 , 30401 , 1 4108 9724 , 1 3326 3186 , 1 5271 5665 , 34744 , 1 3618 6973 , 1 3140 0875 , 1 3856 4102 , 39087 , 1 3186 9209 , 1 6113 3900 , 1 6705 9685 , } % \end{macrocode} % \end{variable} % % \begin{macro}[rEXP] % { % \@@_exp_pos_large:NnnNwn , % \@@_exp_large_after:wwn , % \@@_exp_large:NwN , % \@@_exp_intarray:w , % \@@_exp_intarray_aux:w , % } % The first two arguments are irrelevant (a rounding digit, and a % brace group with $8$ zeros). The third argument is the integer part % of our number, then we have the decimal part delimited by a % semicolon, and finally the exponent, in the range $[0,5]$. Remove % leading zeros from the integer part: putting |#4| in there too % ensures that an integer part of $0$ is also removed. Then read % digits one by one, looking up $\exp(\meta{digit}\cdot % 10^{\meta{exponent}})$ in a table, and multiplying that to the % current total. The loop is done by \cs{@@_exp_large:NwN}, whose % |#1| is the \meta{exponent}, |#2| is the current mantissa, and |#3| % is the \meta{digit}. At the end, \cs{@@_exp_large_after:wwn} moves % on to the Taylor series, eventually multiplied with the mantissa % that we have just computed. % \begin{macrocode} \cs_new:Npn \@@_exp_pos_large:NnnNwn #1#2#3 #4#5; #6 { \exp_after:wN \exp_after:wN \exp_after:wN \@@_exp_large:NwN \exp_after:wN \exp_after:wN \exp_after:wN #6 \exp_after:wN \c_@@_one_fixed_tl \int_value:w #3 #4 \exp_stop_f: #5 00000 ; } \cs_new:Npn \@@_exp_large:NwN #1#2; #3 { \if_case:w #3 ~ \exp_after:wN \@@_fixed_continue:wn \else: \exp_after:wN \@@_exp_intarray:w \int_value:w \@@_int_eval:w 36 * #1 + 4 * #3 \exp_after:wN ; \fi: #2; { \if_meaning:w 0 #1 \exp_after:wN \@@_exp_large_after:wwn \else: \exp_after:wN \@@_exp_large:NwN \int_value:w \@@_int_eval:w #1 - 1 \exp_after:wN \scan_stop: \fi: } } \cs_new:Npn \@@_exp_intarray:w #1 ; { + \__kernel_intarray_item:Nn \c_@@_exp_intarray { \@@_int_eval:w #1 - 3 \scan_stop: } \exp_after:wN \use_i:nnn \exp_after:wN \@@_fixed_mul:wwn \int_value:w 0 \exp_after:wN \@@_exp_intarray_aux:w \int_value:w \__kernel_intarray_item:Nn \c_@@_exp_intarray { \@@_int_eval:w #1 - 2 } \exp_after:wN \@@_exp_intarray_aux:w \int_value:w \__kernel_intarray_item:Nn \c_@@_exp_intarray { \@@_int_eval:w #1 - 1 } \exp_after:wN \@@_exp_intarray_aux:w \int_value:w \__kernel_intarray_item:Nn \c_@@_exp_intarray {#1} ; ; } \cs_new:Npn \@@_exp_intarray_aux:w 1 #1#2#3#4#5 ; { ; {#1#2#3#4} {#5} } \cs_new:Npn \@@_exp_large_after:wwn #1; #2; #3 { \@@_exp_Taylor:Nnnwn ? { } { } 0 #2; {} #3 \@@_fixed_mul:wwn #1; } % \end{macrocode} % \end{macro} % % \subsection{Power} % % Raising a number $a$ to a power $b$ leads to many distinct situations. % \begin{center}\def\abs#1{\lvert #1\rvert} % \begin{tabular}{>{$}c<{$}|*8{>{$}l<{$}}} % a^b &-\infty &(-\infty,-0) &-\text{integer} &\pm 0 &+\text{integer} &(0,\infty) &+\infty &\nan \\ \hline % +\infty &+0 &\multicolumn{2}{c}{$+0$} &+1 &\multicolumn{2}{c}{$+\infty$} &+\infty &\nan \\ % (1,\infty) &+0 &\multicolumn{2}{c}{$+\abs{a}^{b}$} &+1 &\multicolumn{2}{c}{$+\abs{a}^{b}$} &+\infty &\nan \\ % +1 &+1 &\multicolumn{2}{c}{$+1$} &+1 &\multicolumn{2}{c}{$+1$} &+1 &+1 \\ % (0,1) &+\infty &\multicolumn{2}{c}{$+\abs{a}^{b}$} &+1 &\multicolumn{2}{c}{$+\abs{a}^{b}$} &+0 &\nan \\ % +0 &+\infty &\multicolumn{2}{c}{$+\infty$} &+1 &\multicolumn{2}{c}{$+0$} &+0 &\nan \\ % -0 &+\infty &\nan &(-1)^b\infty &+1 &(-1)^b 0 &+0 &+0 &\nan \\ % (-1,0) &+\infty &\nan &(-1)^b\abs{a}^{b} &+1 &(-1)^b\abs{a}^{b} &\nan &+0 &\nan \\ % -1 &+1 &\nan &(-1)^b &+1 &(-1)^b &\nan &+1 &\nan \\ % (-\infty,-1) &+0 &\nan &(-1)^b\abs{a}^{b} &+1 &(-1)^b\abs{a}^{b} &\nan &+\infty &\nan \\ % -\infty &+0 &+0 &(-1)^b 0 &+1 &(-1)^b\infty &\nan &+\infty &\nan \\ % \nan &\nan &\nan &\nan &+1 &\nan &\nan &\nan &\nan \\ % \end{tabular} % \end{center} % We distinguished in this table the cases of finite (positive or % negative) integer exponents, as $(-1)^b$ is defined in that case. % One peculiarity of this operation is that $\nan^0 = 1^\nan = 1$, % because this relation is obeyed for any number, even $\pm\infty$. % % \begin{macro}[EXP]+\@@_^_o:ww+ % We cram most of the tests into a single function to save csnames. % First treat the case $b=0$: $a^0=1$ for any $a$, even \texttt{nan}. % Then test the sign of $a$. % \begin{itemize} % \item If it is positive, and $a$ is a normal number, call % \cs{@@_pow_normal_o:ww} followed by the two \texttt{fp} $a$ and $b$. % For $a=+0$ or $+\inf$, call \cs{@@_pow_zero_or_inf:ww} instead, to % return either $+0$ or $+\infty$ as appropriate. % \item If $a$ is a \texttt{nan}, then skip to the next semicolon % (which happens to be conveniently the end of $b$) and return % \texttt{nan}. % \item Finally, if $a$ is negative, compute $|a|^b$ % (\cs{@@_pow_normal_o:ww} which ignores the sign of its first % operand), and keep an extra copy of $a$ and $b$ (the second brace % group, containing \{~$b$~$a$~\}, is inserted between $a$ and $b$). % Then do some tests to find the final sign of the result if it % exists. % \end{itemize} % \begin{macrocode} \cs_new:cpn { @@_ \iow_char:N \^ _o:ww } \s_@@ \@@_chk:w #1#2#3; \s_@@ \@@_chk:w #4#5#6; { \if_meaning:w 0 #4 \@@_case_return_o:Nw \c_one_fp \fi: \if_case:w #2 \exp_stop_f: \exp_after:wN \use_i:nn \or: \@@_case_return_o:Nw \c_nan_fp \else: \exp_after:wN \@@_pow_neg:www \exp:w \exp_end_continue_f:w \exp_after:wN \use:nn \fi: { \if_meaning:w 1 #1 \exp_after:wN \@@_pow_normal_o:ww \else: \exp_after:wN \@@_pow_zero_or_inf:ww \fi: \s_@@ \@@_chk:w #1#2#3; } { \s_@@ \@@_chk:w #4#5#6; \s_@@ \@@_chk:w #1#2#3; } \s_@@ \@@_chk:w #4#5#6; } % \end{macrocode} % \end{macro} % % \begin{macro}[EXP]{\@@_pow_zero_or_inf:ww} % Raising $-0$ or $-\infty$ to \texttt{nan} yields \texttt{nan}. For % other powers, the result is $+0$ if $0$ is raised to a positive % power or $\infty$ to a negative power, and $+\infty$ otherwise. % Thus, if the type of $a$ and the sign of $b$ coincide, the result % is~$0$, since those conveniently take the same possible values, $0$ % and~$2$. Otherwise, either $a=\pm\infty$ and $b>0$ and the result % is $+\infty$, or $a=\pm 0$ with $b<0$ and we have a division by zero % unless $b=-\infty$. % \begin{macrocode} \cs_new:Npn \@@_pow_zero_or_inf:ww \s_@@ \@@_chk:w #1#2; \s_@@ \@@_chk:w #3#4 { \if_meaning:w 1 #4 \@@_case_return_same_o:w \fi: \if_meaning:w #1 #4 \@@_case_return_o:Nw \c_zero_fp \fi: \if_meaning:w 2 #1 \@@_case_return_o:Nw \c_inf_fp \fi: \if_meaning:w 2 #3 \@@_case_return_o:Nw \c_inf_fp \else: \@@_case_use:nw { \@@_division_by_zero_o:NNww \c_inf_fp ^ \s_@@ \@@_chk:w #1 #2 ; } \fi: \s_@@ \@@_chk:w #3#4 } % \end{macrocode} % \end{macro} % % \begin{macro}[EXP]{\@@_pow_normal_o:ww} % We have in front of us $a$, and $b\neq 0$, we know that $a$ is a % normal number, and we wish to compute $\lvert a\rvert^{b}$. If % $\lvert a\rvert=1$, we return $1$, unless $a=-1$ and $b$ is % \texttt{nan}. Indeed, returning $1$ at this point would wrongly % raise \enquote{invalid} when the sign is considered. If $\lvert % a\rvert\neq 1$, test the type of $b$: % \begin{itemize} % \item[0] Impossible, we already filtered $b=\pm 0$. % \item[1] Call \cs{@@_pow_npos_o:Nww}. % \item[2] Return $+\infty$ or $+0$ depending on the sign of $b$ and % whether the exponent of $a$ is positive or not. % \item[3] Return $b$. % \end{itemize} % \begin{macrocode} \cs_new:Npn \@@_pow_normal_o:ww \s_@@ \@@_chk:w 1 #1#2#3; \s_@@ \@@_chk:w #4#5 { \if_int_compare:w \@@_str_if_eq:nn { #2 #3 } { 1 {1000} {0000} {0000} {0000} } = 0 \exp_stop_f: \if_int_compare:w #4 #1 = 32 \exp_stop_f: \exp_after:wN \@@_case_return_ii_o:ww \fi: \@@_case_return_o:Nww \c_one_fp \fi: \if_case:w #4 \exp_stop_f: \or: \exp_after:wN \@@_pow_npos_o:Nww \exp_after:wN #5 \or: \if_meaning:w 2 #5 \exp_after:wN \reverse_if:N \fi: \if_int_compare:w #2 > 0 \exp_stop_f: \exp_after:wN \@@_case_return_o:Nww \exp_after:wN \c_inf_fp \else: \exp_after:wN \@@_case_return_o:Nww \exp_after:wN \c_zero_fp \fi: \or: \@@_case_return_ii_o:ww \fi: \s_@@ \@@_chk:w 1 #1 {#2} #3 ; \s_@@ \@@_chk:w #4 #5 } % \end{macrocode} % \end{macro} % % ^^A todo: check that we compute ln to 21 digits! % \begin{macro}[EXP]{\@@_pow_npos_o:Nww} % We now know that $a\neq\pm 1$ is a normal number, and $b$ is a % normal number too. We want to compute $\lvert a\rvert^{b} = (\lvert % x\rvert\cdot 10^{n})^{y\cdot 10^{p}} = \exp((\ln\lvert x\rvert + n % \ln(10))\cdot y \cdot 10^{p}) = \exp(z)$. To compute the % exponential accurately, we need to know the digits of $z$ up to the % $16$-th position. Since the exponential of $10^{5}$ is infinite, we % only need at most $21$ digits, hence the fixed point result of % \cs{@@_ln_o:w} is precise enough for our needs. Start an integer % expression for the decimal exponent of $e^{\lvert z\rvert}$. If $z$ % is negative, negate that decimal exponent, and prepare to take the % inverse when converting from the fixed point to the floating point result. % \begin{macrocode} \cs_new:Npn \@@_pow_npos_o:Nww #1 \s_@@ \@@_chk:w 1#2#3 { \exp_after:wN \@@_sanitize:Nw \exp_after:wN 0 \int_value:w \if:w #1 \if_int_compare:w #3 > 0 \exp_stop_f: 0 \else: 2 \fi: \exp_after:wN \@@_pow_npos_aux:NNnww \exp_after:wN + \exp_after:wN \@@_fixed_to_float_o:wN \else: \exp_after:wN \@@_pow_npos_aux:NNnww \exp_after:wN - \exp_after:wN \@@_fixed_inv_to_float_o:wN \fi: {#3} } % \end{macrocode} % \end{macro} % %^^A begin[todo] % \begin{macro}[EXP]{\@@_pow_npos_aux:NNnww} % The first argument is the conversion function from fixed point to % float. Then comes an exponent and the $4$ brace groups of $x$, % followed by $b$. Compute $-\ln(x)$. % \begin{macrocode} \cs_new:Npn \@@_pow_npos_aux:NNnww #1#2#3#4#5; \s_@@ \@@_chk:w 1#6#7#8; { #1 \@@_int_eval:w \@@_ln_significand:NNNNnnnN #4#5 \@@_pow_exponent:wnN {#3} \@@_fixed_mul:wwn #8 {0000}{0000} ; \@@_pow_B:wwN #7; #1 #2 0 % fixed_to_float_o:wN } \cs_new:Npn \@@_pow_exponent:wnN #1; #2 { \if_int_compare:w #2 > 0 \exp_stop_f: \exp_after:wN \@@_pow_exponent:Nwnnnnnw % n\ln(10) - (-\ln(x)) \exp_after:wN + \else: \exp_after:wN \@@_pow_exponent:Nwnnnnnw % -(|n|\ln(10) + (-\ln(x))) \exp_after:wN - \fi: #2; #1; } \cs_new:Npn \@@_pow_exponent:Nwnnnnnw #1#2; #3#4#5#6#7#8; { %^^A todo: use that in ln. \exp_after:wN \@@_fixed_mul_after:wwn \int_value:w \@@_int_eval:w \c_@@_leading_shift_int \exp_after:wN \@@_pack:NNNNNw \int_value:w \@@_int_eval:w \c_@@_middle_shift_int #1#2*23025 - #1 #3 \exp_after:wN \@@_pack:NNNNNw \int_value:w \@@_int_eval:w \c_@@_middle_shift_int #1 #2*8509 - #1 #4 \exp_after:wN \@@_pack:NNNNNw \int_value:w \@@_int_eval:w \c_@@_middle_shift_int #1 #2*2994 - #1 #5 \exp_after:wN \@@_pack:NNNNNw \int_value:w \@@_int_eval:w \c_@@_middle_shift_int #1 #2*0456 - #1 #6 \exp_after:wN \@@_pack:NNNNNw \int_value:w \@@_int_eval:w \c_@@_trailing_shift_int #1 #2*8401 - #1 #7 #1 ( #2*7991 - #8 ) / 1 0000 ; ; } \cs_new:Npn \@@_pow_B:wwN #1#2#3#4#5#6; #7; { \if_int_compare:w #7 < 0 \exp_stop_f: \exp_after:wN \@@_pow_C_neg:w \int_value:w - \else: \if_int_compare:w #7 < 22 \exp_stop_f: \exp_after:wN \@@_pow_C_pos:w \int_value:w \else: \exp_after:wN \@@_pow_C_overflow:w \int_value:w \fi: \fi: #7 \exp_after:wN ; \int_value:w \@@_int_eval:w 10 0000 + #1 \@@_int_eval_end: #2#3#4#5#6 0000 0000 0000 0000 0000 0000 ; %^^A todo: how many 0? } \cs_new:Npn \@@_pow_C_overflow:w #1; #2; #3 { + 2 * \c_@@_max_exponent_int \exp_after:wN \@@_fixed_continue:wn \c_@@_one_fixed_tl } \cs_new:Npn \@@_pow_C_neg:w #1 ; 1 { \exp_after:wN \exp_after:wN \exp_after:wN \@@_pow_C_pack:w \prg_replicate:nn {#1} {0} } \cs_new:Npn \@@_pow_C_pos:w #1; 1 { \@@_pow_C_pos_loop:wN #1; } \cs_new:Npn \@@_pow_C_pos_loop:wN #1; #2 { \if_meaning:w 0 #1 \exp_after:wN \@@_pow_C_pack:w \exp_after:wN #2 \else: \if_meaning:w 0 #2 \exp_after:wN \@@_pow_C_pos_loop:wN \int_value:w \else: \exp_after:wN \@@_pow_C_overflow:w \int_value:w \fi: \@@_int_eval:w #1 - 1 \exp_after:wN ; \fi: } \cs_new:Npn \@@_pow_C_pack:w { \exp_after:wN \@@_exp_large:NwN \exp_after:wN 5 \c_@@_one_fixed_tl } % \end{macrocode} % \end{macro} %^^A end[todo] % % \begin{macro}[EXP]{\@@_pow_neg:www, \@@_pow_neg_aux:wNN} % This function is followed by three floating point numbers: $|a|^b$, % $a\in[-\infty,-0]$, and $b$. If $b$ is an even integer (case $-1$), % $a^b=|a|^b$. If $b$ is an odd integer (case $0$), $a^b=-|a|^b$, % obtained by a call to \cs{@@_pow_neg_aux:wNN}. Otherwise, the sign is % undefined. This is invalid, unless $|a|^b$ turns out to be $+0$ or % \texttt{nan}, in which case we return that as $a^b$. In particular, % since the underflow detection occurs before \cs{@@_pow_neg:www} is % called, |(-0.1)**(12345.67)| gives $+0$ rather than complaining % that the sign is not defined. % \begin{macrocode} \cs_new:Npn \@@_pow_neg:www \s_@@ \@@_chk:w #1#2; #3; #4; { \if_case:w \@@_pow_neg_case:w #4 ; \exp_after:wN \@@_pow_neg_aux:wNN \or: \if_int_compare:w \@@_int_eval:w #1 / 2 = 1 \exp_stop_f: \@@_invalid_operation_o:Nww ^ #3; #4; \exp:w \exp_end_continue_f:w \exp_after:wN \exp_after:wN \exp_after:wN \@@_use_none_until_s:w \fi: \fi: \@@_exp_after_o:w \s_@@ \@@_chk:w #1#2; } \cs_new:Npn \@@_pow_neg_aux:wNN #1 \s_@@ \@@_chk:w #2#3 { \exp_after:wN \@@_exp_after_o:w \exp_after:wN \s_@@ \exp_after:wN \@@_chk:w \exp_after:wN #2 \int_value:w \@@_int_eval:w 2 - #3 \@@_int_eval_end: } % \end{macrocode} % ^^A todo: is this \@@_exp_after_o:w necessary? Appropriate? % \end{macro} % % \begin{macro}[rEXP] % { % \@@_pow_neg_case:w, \@@_pow_neg_case_aux:nnnnn, % \@@_pow_neg_case_aux:Nnnw % } % This function expects a floating point number, and determines its % \enquote{parity}. It should be used after \cs{if_case:w} or in an % integer expression. It gives $-1$ if the number is an even integer, % $0$~if the number is an odd integer, and $1$~otherwise. Zeros and % $\pm\infty$ are even (because very large finite floating points are % even), while \texttt{nan} is a non-integer. The sign of normal % numbers is irrelevant to parity. After \cs{@@_decimate:nNnnnn} the % argument |#1| of \cs{@@_pow_neg_case_aux:Nnnw} is a rounding digit, % |0|~if and only if the number was an integer, and |#3| is the $8$ % least significant digits of that integer. % \begin{macrocode} \cs_new:Npn \@@_pow_neg_case:w \s_@@ \@@_chk:w #1#2#3; { \if_case:w #1 \exp_stop_f: -1 \or: \@@_pow_neg_case_aux:nnnnn #3 \or: -1 \else: 1 \fi: \exp_stop_f: } \cs_new:Npn \@@_pow_neg_case_aux:nnnnn #1#2#3#4#5 { \if_int_compare:w #1 > \c_@@_prec_int -1 \else: \@@_decimate:nNnnnn { \c_@@_prec_int - #1 } \@@_pow_neg_case_aux:Nnnw {#2} {#3} {#4} {#5} \fi: } \cs_new:Npn \@@_pow_neg_case_aux:Nnnw #1#2#3#4 ; { \if_meaning:w 0 #1 \if_int_odd:w #3 \exp_stop_f: 0 \else: -1 \fi: \else: 1 \fi: } % \end{macrocode} % \end{macro} % % \begin{macrocode} % % \end{macrocode} % % \end{implementation} % % \PrintChanges % % \PrintIndex