\documentclass{article} \begin{document} The derivative of the indirect function f[g(x)] is $\{f[g(x)]\}' = f'[g(x)]g'(x)$. For the second derivative of the product of $f(x)$ and $g(x)$ one has $[f(x)g(x)]'' = f''(x)g(x) + 2f'(x)g'(x) + f(x)g''(x)$. \end{document}