% -*- coding: utf-8 -*-
% !TEX program = xelatex
%
% Package epyt: a simple and clean theme for LaTeX beamer class
% Copyright (C) 2013-2015 Zou Hu <zohooo@yeah.net>
%
% Please report bugs, problems, and suggestions via
%     https://github.com/zohooo/epyt
%
% The package may be distributed and/or modified under the conditions
% of the LaTeX Project Public License, either version 1.3 of this
% license or (at your option) any later version. The latest version
% of this license is in
%     http://www.latex-project.org/lppl.txt

\documentclass[14pt]{beamer}

\usetheme[color=white]{epyt} % black, blue, green, white

\usepackage{arev} % use arev sans font

\hypersetup{
  pdfpagemode={FullScreen},
}

\title{Epyt Theme for Beamer}
\author{zohooo@yeah.net}
%\institute{https://github.com/zohooo/epyt}

\begin{document}

\begin{frame}[plain]\transboxout
\titlepage
\end{frame}

\begin{frame}\transboxin
\begin{center}
\tableofcontents[hideallsubsections]
\end{center}
\end{frame}

\epytsetup{color=green}

\section{Introduction}

\begin{frame}{Introduction}
Epyt is a simple but nice theme for Beamer, with the following features: \pause
\begin{itemize}[<+->]
\item simple structure: with page numbers at footer, no head bar and side bar;
\item simple templates: displaying theorems with traditional inline style;
\item simple colors: using only several foreground and background colors.
\end{itemize}
\end{frame}

\epytsetup{color=blue}

\section{Enumerates}

\begin{frame}[fragile]{Ordered Lists}
A Beamer theme consists of the following four parts: \pause
\begin{enumerate}[<+->]
\item outer theme, with \verb!\usebeameroutertheme!;
\item inner theme, with \verb!\usebeamerinnertheme!;
\item color theme, with \verb!\usebeamercolortheme!;
\item font theme, with \verb!\usebeamerfonttheme!.
\end{enumerate}
\end{frame}

\epytsetup{color=black}

\section{Mathmatics}

\begin{frame}{Example}
\begin{example}
Prove the following result:
\[ \lim_{x\to0}\frac{\sin 3x}{\ln(1-2x)}=-\frac{3}{2} \]
\end{example}\pause
\begin{proof}
Since $\sin 3x \sim 3x$ and $\ln(1-2x) \sim -2x$, we have
\[ \lim_{x\to0}\frac{\sin 3x}{\ln(1-2x)}=\lim_{x\to0}\frac{3x}{-2x}=-\frac{3}{2}, \]
and we are done.
\end{proof}
\end{frame}

\end{document}