From b4fc5f639874db951177ec539299d20908adb654 Mon Sep 17 00:00:00 2001 From: Karl Berry Date: Mon, 9 Jan 2006 00:44:40 +0000 Subject: doc 4 git-svn-id: svn://tug.org/texlive/trunk@80 c570f23f-e606-0410-a88d-b1316a301751 --- .../doc/latex/multenum/multienum.article | 428 +++++++++++++++++++++ .../texmf-dist/doc/latex/multenum/multienum.sample | 159 ++++++++ 2 files changed, 587 insertions(+) create mode 100644 Master/texmf-dist/doc/latex/multenum/multienum.article create mode 100644 Master/texmf-dist/doc/latex/multenum/multienum.sample (limited to 'Master/texmf-dist/doc/latex/multenum') diff --git a/Master/texmf-dist/doc/latex/multenum/multienum.article b/Master/texmf-dist/doc/latex/multenum/multienum.article new file mode 100644 index 00000000000..75f7f9c0695 --- /dev/null +++ b/Master/texmf-dist/doc/latex/multenum/multienum.article @@ -0,0 +1,428 @@ +%TUGBoat article A Multienumerate Package + +\documentclass{article} +\usepackage{multicol,multienum} +\pagestyle{headings} +\begin{document} +\title{A Multienumerate Package} +\author{Dennis Kletzing\\Stetson University} \date{\today} +\maketitle +\begin{abstract} +{\it The {\tt multienum.sty} package allows +the user to produce an enumerated array of multiple +columns, each vertically aligned on the counter. An optional +argument provides for consecutive numbering of the array items, +or an even-only or odd-only numbering scheme.} +\end{abstract} +Typesetting the solutions manual for a text frequently involves creating an +enumerated list involving many short answers. Typically these are set with +several items per +line, with no attempt made to vertically align the exercise numbers. The +{\tt multienum.sty} package provides an environment, {\tt multienumerate}, +that produces an enumerated array in which columns are vertically aligned +on the counter. If the user wishes, the enumeration counter can + be changed to give a list of even-only numbers or odd-only + numbers. + +\begin{table}[b] +\caption{An enumerate array of solutions} +\parbox[t]{.99\hsize}{% +\hrule\hrule +\begin{multienumerate} +\mitemxxxx{Not}{Linear}{Not}{Quadratic} +\mitemxxxo{Not}{Linear}{No; if $x=3$, then $y=-2$.} +\mitemxx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or +$(s,3s-6)$}{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} +\mitemx{$(x_1,x_2,x_3,x_4)= (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ +or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} +\mitemxxxx{$(2,-1,3)$}{None}{$(2,1,0,1)$}{$(0,0,0,0)$} +\end{multienumerate}}\hrule +\end{table} + +\section*{What the package does} +Table 1 shows a typical enumerated array. The fourth entry in +the second row is left blank since the next item is too long to +fit in space. The third row has only two entries. To get the +vertical alignment of the counter in column 3, we set row three +as four entries, but left entry 2 and entry 4 blank thus +giving more space for the first and third entries. To produce +the enumerated array shown above, we typed the following: + + + + +\begin{verbatim} + \begin{multienumerate} + \mitemxxxx{Not}{Linear}{Not}{Quadratic} + \mitemxxxo{Not}{Linear}{Not} + \mitemxx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or + $(s,3s-6)$}{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} + \mitemx{$(x_1,x_2,x_3,x_4)= + (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ + or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} + \mitemxxxx{$(2,-1,3)$}{None}{$(2,1,0,1)$}{$(0,0,0,0)$} + \end{multienumerate} +\end{verbatim} +The environment {\tt multienumerate} has an optional argument +for enumerating even-only or odd-only arrays.\footnote{The +optional arguments works only in \LaTeX2e.} + +\begin{itemize} +\item \verb|\begin{multienumerate} ... \end{multienumerate}| +\item[] produces a consecutively enumerated array +\item \verb|\begin{multienumerate}[evenlist] ...\end{multienumerate}| +\item[] produces an enumerated array using only even numbers +\item \verb|\begin{multienumerate}[oddlist] ...\end{multienumerate}| +\item[] produces an enumerated array using only odd numbers +\end{itemize} + +\section*{Using the package} +Each row of the enumerated array is set using +one of the nine commands: + +\begin{small} +\renewcommand{\arraystretch}{1.2}%1.4 +\begin{tabular}{@{}lp{3in}} +\verb|\mitemx{}|&A single item in the row.\\ +\verb|\mitemxx{}{}|&Two items in the row.\\ +\verb|\mitemxxx{}{}{}|&Three items in the row.\\ +\verb|\mitemxox{}{}|&Three items in the row with the +center item space left blank so the first item can extend +into its space.\\ +\verb|\mitemxxo{}{}|&Three items in the row with the last +item left blank so the second item can extend into + its space.\\ +\verb|\mitemxxxx{}{}{}{}|&Four items in the row.\\ +\verb|\mitemxoxx{}{}{}|& Four items in the row with the +second space left blank so the first item can extend into +its space.\\ +\verb|\mitemxxox{}{}{}|&Four items in the row with the +third space left blank so the second item can extend into +its space.\\ +\verb|\mitemxxxo{}{}{}|&Four items in the row with the +last space left blank so the third item can extend into +its space. +\end{tabular} +\end{small} + +For example, \verb|\mitemxxx{a}{b}{c}| sets three items, a, b, c equally +spaced across the row; \verb|\mitemxox{a}{c}| sets the two +items, a and c, across the row {\em as if\/} there were three items, leaving +the second entry blank so that the first entry can extend into +its space; and \verb|\mitemxxo{a}{b}| sets the two items, a and +b, {\em as if\/} there were three items, but leaves the space +for the third item blank, allowing the second entry to extend +into its space. + +A convenient way to use the multienumerate +package is with a two column layout using multicols. Page 7 +illustrates a typical page from a solutions manual set in +two columns format using multicols and multienumerate. + +A disadvantage of the package is that the user must choose how +to typeset each line in the array rather than letting \TeX\ +decide how to do it. This creates a lot of overhead in the +macro since separate commands are needed for each possibility. +It is not difficult to write a macro that will let + \TeX\ decide how many items to set on each line. This +approach, while the most efficient, does not always give the +visual appearance that the user may want. + + +\section{How the package works} +We illustrate how the package typesets a line +containing two items. The other +situations are similar. + +\noindent +\setlength{\unitlength}{1.3pt} +\begin{picture}(240,50)(0,0) + + +\put(0,0){\framebox(35,10)[b]{\hfill 1.}} +\put(40,0){\framebox(30,10)[b]{}} +\put(75,0){\framebox(50,10)[bl]{stuff}} + +\put(0,30){\makebox(35,10)[b]{\small +\texttt{$\backslash$labelwidth}}} +\put(40,30){\makebox(30,10)[b]{\small +\texttt{$\backslash$labelsep}}} +\put(75,30){\makebox(50,10)[b]{\small +\texttt{$.5\backslash$remainxx}}} + +\put(17.5,20){\vector(-1,0){17.5}} +\put(17.5,20){\vector(1,0){17.5}} + +\put(55,20){\vector(-1,0){15}} +\put(55,20){\vector(1,0){15}} + +\put(100,20){\vector(-1,0){25}} +\put(100,20){\vector(1,0){25}} + +\put(147.5,20){\vector(-1,0){17.5}} +\put(147.5,20){\vector(1,0){17.5}} + +\put(185,20){\vector(-1,0){15}} +\put(185,20){\vector(1,0){15}} + +\put(230,20){\vector(-1,0){25}} +\put(230,20){\vector(1,0){25}} + +\put(130,0){\framebox(35,10)[b]{\hfill 2.}} +\put(170,0){\framebox(30,10)[b]{}} +\put(205,0){\framebox(50,10)[bl]{stuff}} + +\put(130,30){\makebox(35,10)[b]{\small +\texttt{$\backslash$labelwidth}}} +\put(170,30){\makebox(30,10)[b]{\small +\texttt{$\backslash$labelsep}}} +\put(205,30){\makebox(50,10)[b]{\small +\texttt{$.5\backslash$remainxx}}} +\end{picture} + +\bigskip +The total width of the line is then set equal to \verb|\hsize|: +\[\underbrace{2\texttt{$\backslash$labelwidth}+ +2\texttt{$\backslash$labelsep}}_{\texttt{$\backslash$usedxx}}+ +\texttt{$\backslash$remainxx}=\texttt{$\backslash$hsize}\] +\[\texttt{$\backslash$remainxx}= +\texttt{$\backslash$hsize}- +\texttt{$\backslash$usedxx}\] + +\bigskip +In this way the macro determines the width of each box + when two items are typeset on the line. + +\section{The macro} +Here is the package \texttt{multienum.sty}. +\begin{verbatim} +\setlength{\hsize}{\textwidth} + +%First define new lengths + +\newlength{\usedx} +\newlength{\remainx} +\newlength{\usedxx} +\newlength{\remainxx} +\newlength{\usedxxx} +\newlength{\remainxxx} +\newlength{\usedxxxx} +\newlength{\remainxxxx} +\newlength{\remainxox} +\newlength{\remainxoxx} + +%Define new item control sequences + +\newcommand{\itemx}[1]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep% +\parbox[t]{\remainx}{\raggedright #1}\smallskip} + +\newcommand{\itemxx}[2]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{.5\remainxx}{\raggedright #1}\hfill\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.5\remainxx}{\raggedright #2}\smallskip} + +\newcommand{\itemxxx}[3]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep% +\parbox[t]{.3333\remainxxx}{\raggedright #1}\hfill\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep% +\parbox[t]{0.3333\remainxxx}{\raggedright #2}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep% +\parbox[t]{0.3333\remainxxx}{\raggedright #3}\smallskip} + +\newcommand{\itemxxxx}[4]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{.25\remainxxxx}{\raggedright #1}\hfill\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.25\remainxxxx}{\raggedright #2}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.25\remainxxxx}{\raggedright #3}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.25\remainxxxx}{\raggedright #4}\smallskip} + +\newcommand{\itemxox}[2]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{\remainxox}{\raggedright #1}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.3333\remainxxx}{\raggedright #2}\smallskip} + +\newcommand{\itemxxo}[2]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.3333\remainxxx}{\raggedright #1}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{\remainxox}{\raggedright #2}\smallskip} + +\newcommand{\itemxoxx}[3]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{\remainxoxx}{\raggedright #1}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.25\remainxxxx}{\raggedright #2}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.25\remainxxxx}{\raggedright #3}\smallskip} + +\newcommand{\itemxxox}[3]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{.25\remainxxxx}{\raggedright #1}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{\remainxoxx}{\raggedright #2}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{0.25\remainxxxx}{\raggedright #3}\smallskip} + +\newcommand{\itemxxxo}[3]{\parbox[t]% +{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{.25\remainxxxx}{\raggedright #1}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{.25\remainxxxx}{\raggedright #2}\hfill% +\parbox[t]{\labelwidth}{\hfill\labelenumi}\hskip\labelsep +\parbox[t]{\remainxoxx}{\raggedright #3}\smallskip} + +\newcommand{\mitemx}[1]{\item[] \itemx{#1}} +\newcommand{\mitemxx}[2]{\item[] \itemxx{#1}{#2}} +\newcommand{\mitemxxx}[3]{\item[] \itemxxx{#1}{#2}{#3}} +\newcommand{\mitemxox}[2]{\item[] \itemxox{#1}{#2}} +\newcommand{\mitemxxo}[2]{\item[] \itemxxo{#1}{#2}} +\newcommand{\mitemxxxx}[4]{\item[] \itemxxxx{#1}{#2}{#3}{#4}} +\newcommand{\mitemxoxx}[3]{\item[] \itemxoxx{#1}{#2}{#3}} +\newcommand{\mitemxxox}[3]{\item[] \itemxxox{#1}{#2}{#3}} +\newcommand{\mitemxxxo}[3]{\item[] \itemxxxo{#1}{#2}{#3}} +\newcommand{\mitemxxoo}[2]{\item[] \itemxxoo{#1}{#2}} + +%Create counter options + +\newcommand{\oddlist}{\setcounter{enumi}{-1} +\renewcommand{\labelenumi} +{\ifodd\value{enumi}\addtocounter{enumi}{2}% +\arabic{enumi}.\else +\addtocounter{enumi}{1}\arabic{enumi}.% +\addtocounter{enumi}{-2}\fi}} + +\newcommand{\evenlist}{\setcounter{enumi}{0} +\renewcommand{\labelenumi} +{\ifodd\value{enumi}\addtocounter{enumi}{1}\arabic{enumi}.% +\addtocounter{enumi}{-2}\else +\addtocounter{enumi}{2}\arabic{enumi}.\fi}} + +\newcommand{\regularlist}{\setcounter{enumi}{0} +\renewcommand{\labelenumi} +{\addtocounter{enumi}{1}\arabic{enumi}.}} + +\newcommand{\listtype}[1]{#1} + +%Create the environment + +\newenvironment{multienumerate}[1][\regularlist]{% +\listtype{#1} +\begin{trivlist}% +\setlength{\labelwidth}{18pt} +\setlength{\labelsep}{5pt}% +\setlength{\usedx}{\labelwidth}% +\addtolength{\usedx}{\labelsep}% +\setlength{\remainx}{\hsize}% +\addtolength{\remainx}{-\usedx}% +\setlength{\usedxx}{2\labelwidth}% +\addtolength{\usedxx}{2\labelsep}% +\setlength{\remainxx}{\hsize}% +\addtolength{\remainxx}{-\usedxx}% +\setlength{\usedxxx}{3\labelwidth}% +\addtolength{\usedxxx}{3\labelsep}% +\setlength{\remainxxx}{\hsize}% +\addtolength{\remainxxx}{-\usedxxx}% +\setlength{\usedxxxx}{4\labelwidth}% +\addtolength{\usedxxxx}{4\labelsep}% +\setlength{\remainxxxx}{\hsize}% +\addtolength{\remainxxxx}{-\usedxxxx}% +\setlength{\remainxox}{.666\remainxxx}% +\addtolength{\remainxox}{\labelwidth}% +\addtolength{\remainxox}{\labelsep}% +\setlength{\remainxoxx}{.5\remainxxxx}% +\addtolength{\remainxoxx}{\labelwidth}% +\addtolength{\remainxoxx}{\labelsep}% +\setlength{\itemindent}{0pt}}{\end{trivlist}} + +%%End of file `multienum.sty' +\end{verbatim} +\pagebreak + +\markboth{}{SAMPLE} +\subsection*{Answers to Even Exercises} +\begin{multicols}{2} +\subsection*{Chapter 1} +\subsection*{Section 1} +\begin{multienumerate}[evenlist] +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxox{$x^2-3x+7=0$}{Yes} +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxox{$x^2-3x+7=0$}{Yes} +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxox{$x^2-3x+7=0$}{Yes} +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxxx{2}{5}{$-4$} +\end{multienumerate} +\subsection*{Section 2} +\begin{multienumerate}[evenlist] +\mitemxxo{Yes}{$3x^2+x=-2$} +\mitemx{If $x=1$, the only solution is $y=3$.} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxxx{Yes}{No}{No} +\mitemxxx{2}{5}{$-4$} +\mitemxox{$x^2-3x+7=0$}{Yes} +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxox{$x^2-3x+7=0$}{Yes} +\mitemxxx{2}{5}{$-4$} +\newsavebox{\diagonal} +\savebox{\diagonal}{\setlength{\unitlength}{.6pt} +\begin{picture}(70,70)(0,0) +\put(0,0){\framebox(70,70){}} +\put(35,5){\vector(0,1){60}} +\put(5,35){\vector(1,0){60}} +\put(10,10){\line(1,1){50}} +\end{picture}} +\mitemxx{\vskip0pt\usebox{\diagonal}}{\vskip0pt\usebox{\diagonal }} +\mitemx{Johnie should sell 3 red marbles, buy 2 white marbles, and keep the +rest.} +\mitemx{Sarah should buy 2 pounds of squash, 3 pounds of potatoes, and 4 +pounds of fish.} +\end{multienumerate} +\subsection*{Answers to Odd Exercises} \subsection*{Chapter 2} +\subsection*{Section 1} +\begin{multienumerate}[oddlist] +\mitemxxx{Yes}{No}{No} +\mitemxxxx{3}{5}{2}{$-8$} +\mitemxxox{7}{$2x-3y=6$}{1} +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxox{$x^2-3x+7=0$}{Yes} +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxxx{2}{5}{$-4$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxxx{$x=1$}{$y=-7$}{$z=3$} +\mitemxxx{2}{5}{$-4$} +\end{multienumerate} +\end{multicols} + +\end{document} + +\noindent +\rule{\hsize}{2pt} +\begin{multienumerate} +\mitemxxxx{Not}{Linear}{Not}{Quadratic} +\mitemxxxo{Not}{Linear}{No; if $x=3$, then $y=-2$.} +\mitemxx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or +$(s,3s-6)$}{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} +\mitemx{$(x_1,x_2,x_3,x_4)= (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ +or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} +\mitemxxxx{$(2,-1,3)$}{None}{$(2,1,0,1)$}{$(0,0,0,0)$} +\end{multienumerate} +\noindent +\rule{\hsize}{1pt} + + diff --git a/Master/texmf-dist/doc/latex/multenum/multienum.sample b/Master/texmf-dist/doc/latex/multenum/multienum.sample new file mode 100644 index 00000000000..b90f146386d --- /dev/null +++ b/Master/texmf-dist/doc/latex/multenum/multienum.sample @@ -0,0 +1,159 @@ +%This is a 2-page sample illustrating how to use the +%multienum package + +\documentclass{article} +\setlength{\textwidth}{6in} +\setlength{\textheight}{8.5in} +\setlength{\topmargin}{-0.5in} +\setlength{\oddsidemargin}{0.25in} +\usepackage{multicol,multienum} + + + +\begin{document} +\begin{center} +{\Large\bf Sample formating using {\tt multienumerate}} +\end{center} + +\bigskip +Sometimes we want to typeset the solutions to exercises. This +is easy to do using the {\tt multienumerate} environment. +\subsection*{Answers to All Exercises} +\begin{multienumerate} +\mitemxxxx{Not}{Linear}{Not}{Quadratic} +\mitemxxxo{Not}{Linear}{No; if $x=3$, then $y=-2$.} +\mitemxx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or +$(s,3s-6)$}{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} +\mitemx{$(x_1,x_2,x_3,x_4)= (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ +or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} +\mitemxxxx{$(2,-1,3)$}{None}{$(2,1,0,1)$}{$(0,0,0,0)$} +\end{multienumerate} + + +\bigskip +\hrule + +\bigskip + +We can also enumerate the items using an even-only or odd only +counter. +\subsection*{Answers to Even-Numbered Exercises} +\begin{multienumerate}[evenlist] +\mitemxxxx{Not}{Linear}{Not}{Quadratic} +\mitemxxxo{Not}{Linear}{No; if $x=3$, then $y=-2$.} +\mitemxx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or +$(s,3s-6)$}{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} +\mitemx{$(x_1,x_2,x_3,x_4)= (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ +or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} +\mitemxxxx{$(2,-1,3)$}{None}{$(2,1,0,1)$}{$(0,0,0,0)$} +\end{multienumerate} + +\hrule + +\subsection*{Answers to Odd-Numbered Exercises} +\begin{multienumerate}[oddlist] +\mitemxxxx{Not}{Linear}{Not}{Quadratic} +\mitemxxxo{Not}{Linear}{No; if $x=3$, then $y=-2$.} +\mitemxx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or +$(s,3s-6)$}{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} +\mitemx{$(x_1,x_2,x_3,x_4)= (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ +or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} +\mitemxxxx{$(2,-1,3)$}{None}{$(2,1,0,1)$}{$(0,0,0,0)$} +\end{multienumerate} + +\bigskip +\hrule + +\bigskip + +Sometimes we want to create sublists which are +enumerated using an alpha counter. + +\begin{multienumerate} +\mitemx{Which of the following numbers is the solution of the +equation +$x+3=7$:} +\begin{multienumerate} +\mitemxxxx{1}{2}{3}{4} +\end{multienumerate} +\mitemx{The value of $\log_28$ is:} +\begin{multienumerate} +\mitemxxxx{1}{$-1$}{3}{$-3$} +\end{multienumerate} +\end{multienumerate} +\pagebreak + +\begin{multicols}{2} +\subsection*{Answers to All Exercises} +\begin{multienumerate} +\mitemxx{Not}{Linear} +\mitemxx{Not}{Quadratic} +\mitemxx{Not}{Linear} +\mitemx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or +$(s,3s-6)$} +\mitemx{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} +\mitemx{$(x_1,x_2,x_3,x_4)= (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ +or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} +\mitemxx{$(2,-1,3)$}{None} +\mitemxx{$(2,1,0,1)$}{$(0,0,0,0)$} +\mitemxx{Not}{Linear} +\mitemxx{Not}{Quadratic} +\mitemxx{Not}{Linear} +\mitemx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or +$(s,3s-6)$} +\mitemx{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} +\mitemx{$(x_1,x_2,x_3,x_4)= (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ +or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} +\mitemxx{$(2,-1,3)$}{None} +\mitemxx{$(2,1,0,1)$}{$(0,0,0,0)$} +\mitemxx{Not}{Linear} +\mitemxx{Not}{Quadratic} +\mitemxx{Not}{Linear} +\mitemx{$(x_1,x_2)=(2+\frac{1}{3}t,t)$ or +$(s,3s-6)$} +\mitemx{$(x_1,x_2,x_3)=(2+\frac{5}{2}s-3t,s,t)$} +\mitemx{$(x_1,x_2,x_3,x_4)= (\frac{1}{4}+\frac{5}{4}s+\frac{3}{4}t-u,s,t,u)$ +or $(s,t,u,\frac{1}{4}-s+\frac{5}{4}t+\frac{3}{4}u)$} +\mitemxx{$(2,-1,3)$}{None} +\mitemxx{$(2,1,0,1)$}{$(0,0,0,0)$} +\end{multienumerate} + +\subsection*{Multiple Choice} +\begin{multienumerate} +\mitemx{Which of the following numbers is the solution of the +equation +$x+3=7$:} +\begin{multienumerate} +\mitemxxxx{1}{2}{3}{4} +\end{multienumerate} +\mitemx{The value of $\log_28$ is:} +\begin{multienumerate} +\mitemxxxx{1}{$-1$}{3}{$-3$} +\end{multienumerate} +\mitemx{Which of the following numbers is the solution of the +equation +$x+3=7$:} +\begin{multienumerate} +\mitemxxxx{1}{2}{3}{4} +\end{multienumerate} +\mitemx{The value of $\log_28$ is:} +\begin{multienumerate} +\mitemxxxx{1}{$-1$}{3}{$-3$} +\end{multienumerate} +\mitemx{Which of the following numbers is the solution of the +equation +$x+3=7$:} +\begin{multienumerate} +\mitemxxxx{1}{2}{3}{4} +\end{multienumerate} +\mitemx{The value of $\log_28$ is:} +\begin{multienumerate} +\mitemxxxx{1}{$-1$}{3}{$-3$} +\end{multienumerate} +\end{multienumerate} +\end{multicols} + +\end{document} + + + -- cgit v1.2.3