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-rw-r--r--Master/texmf-dist/doc/latex/tkz-euclide/TKZdoc-euclide-triangles.tex54
1 files changed, 43 insertions, 11 deletions
diff --git a/Master/texmf-dist/doc/latex/tkz-euclide/TKZdoc-euclide-triangles.tex b/Master/texmf-dist/doc/latex/tkz-euclide/TKZdoc-euclide-triangles.tex
index 5becdf0e2f1..990862afff2 100644
--- a/Master/texmf-dist/doc/latex/tkz-euclide/TKZdoc-euclide-triangles.tex
+++ b/Master/texmf-dist/doc/latex/tkz-euclide/TKZdoc-euclide-triangles.tex
@@ -28,13 +28,17 @@ options & default & definition \\
\midrule
\TOline{two angles= \#1 and \#2}{no defaut}{triangle knowing two angles}
\TOline{equilateral} {equilateral}{equilateral triangle }
+\TOline{half} {equilateral}{B rectangle $AB=2BC$ $AC$ hypothenuse }
\TOline{isosceles right} {equilateral}{isosceles right triangle }
\TOline{pythagore}{equilateral}{proportional to the pythagorean triangle 3-4-5}
+\TOline{pythagoras}{equilateral}{same as above}
+\TOline{egyptian}{equilateral}{same as above}
\TOline{school} {equilateral}{angles of 30, 60 and 90 degrees }
\TOline{gold}{equilateral}{angles of 72, 72 and 36 degrees, $A$ is the apex}
\TOline{euclid} {equilateral}{same as above but $[AB]$ is the base}
\TOline{golden} {equilateral}{B rectangle and $AB/AC = \Phi$}
\TOline{cheops} {equilateral}{AC=BC, AC and BC are proportional to $2$ and $\Phi$.}
+\TOline{swap} {false}{gives the symmetric point with respect to $AB$}
\bottomrule
\end{tabular}
@@ -42,6 +46,22 @@ options & default & definition \\
\tkzcname{tkzGetPoint} allows you to store the point otherwise \tkzname{tkzPointResult} allows for immediate use.
\end{NewMacroBox}
+\subsubsection{Option \tkzname{equilateral}}
+\begin{tkzexample}[latex=7 cm,small]
+\begin{tikzpicture}
+ \tkzDefPoint(0,0){A}
+ \tkzDefPoint(4,0){B}
+ \tkzDefTriangle[equilateral](A,B)
+ \tkzGetPoint{C}
+ \tkzDrawPolygons(A,B,C)
+ \tkzDefTriangle[equilateral](B,A)
+ \tkzGetPoint{D}
+ \tkzDrawPolygon(B,A,D)
+ \tkzMarkSegments[mark=s|](A,B B,C A,C A,D B,D)
+\end{tikzpicture}
+\end{tkzexample}
+
+
\subsubsection{Option \tkzname{two angles}}
\begin{tkzexample}[latex=6 cm,small]
\begin{tikzpicture}
@@ -95,6 +115,23 @@ This triangle has sides whose lengths are proportional to 3, 4 and 5.
\end{tikzpicture}
\end{tkzexample}
+\subsubsection{Option \tkzname{pythagore} and \tkzname{swap}}
+This triangle has sides whose lengths are proportional to 3, 4 and 5.
+
+\begin{tkzexample}[latex=6 cm,small]
+\begin{tikzpicture}
+ \tkzDefPoints{0/0/A,4/0/B}
+ \tkzDefTriangle[pythagore,swap](A,B)
+ \tkzGetPoint{C}
+ \tkzDrawSegments(A,B)
+ \tkzDrawSegments[new](A,C B,C)
+ \tkzMarkRightAngles(A,B,C)
+ \tkzLabelPoint[above,new](C){$C$}
+ \tkzDrawPoints[new](C)
+ \tkzDrawPoints(A,B)
+ \tkzLabelPoints(A,B)
+\end{tikzpicture}
+\end{tkzexample}
\subsubsection{Option \tkzname{golden}}
\begin{tkzexample}[latex=6 cm,small]
@@ -111,22 +148,17 @@ This triangle has sides whose lengths are proportional to 3, 4 and 5.
\end{tikzpicture}
\end{tkzexample}
-\subsubsection{Option \tkzname{equilateral} and \tkzname{isosceles right}}
+\subsubsection{Option \tkzname{isosceles right}}
\begin{tkzexample}[latex=7 cm,small]
\begin{tikzpicture}
\tkzDefPoint(0,0){A}
\tkzDefPoint(4,0){B}
- \tkzDefTriangle[equilateral](A,B)
- \tkzGetPoint{C}
\tkzDefTriangle[isosceles right](A,B)
- \tkzGetPoint{E}
- \tkzDrawPolygons(A,B,C A,B,E)
- \tkzDefTriangle[equilateral](B,A)
- \tkzGetPoint{D}
- \tkzDrawPolygon(B,A,D)
- \tkzMarkRightAngles(B,E,A)
- \tkzDrawPoints(A,B,C,D,E)
- \tkzLabelPoints(A,B,C,D,E)
+ \tkzGetPoint{C}
+ \tkzDrawPolygons(A,B,C)
+ \tkzDrawPoints(A,B,C)
+ \tkzMarkRightAngles(A,C,B)
+ \tkzLabelPoints(A,B,C)
\end{tikzpicture}
\end{tkzexample}