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Diffstat (limited to 'Build/source/texk/web2c/triptrap/mftrap.log')
-rw-r--r-- | Build/source/texk/web2c/triptrap/mftrap.log | 4266 |
1 files changed, 4266 insertions, 0 deletions
diff --git a/Build/source/texk/web2c/triptrap/mftrap.log b/Build/source/texk/web2c/triptrap/mftrap.log new file mode 100644 index 00000000000..23bf114c633 --- /dev/null +++ b/Build/source/texk/web2c/triptrap/mftrap.log @@ -0,0 +1,4266 @@ +This is METAFONT, Version 2.71828 (preloaded base=trap 2002.12.23) 23 DEC 2002 11:57 +** &trap trap +(trap.mf +{if} +{known(0)} +{not(true)} +{false} +{known("")} +{true} + +/*\`'@#->begingroup.message(SUFFIX1)&str(SUFFIX0)&jobname&char.ASCII'`&s +tr(SUFFIX2)!endgroup +(SUFFIX0)<-/*\ +(SUFFIX1)<-`' +(SUFFIX2)<-pass2 +{begingroup} +{message} + +`'->begingroup'`endgroup +(SUFFIX0)<- +(SUFFIX1)<-`' +{begingroup} + +'`->"\*/" +{endgroup} +{("\*/")&("/*\")} +{jobname} +{("\*//*\")&("trap")} + +'`->"\*/" +{ASCII("\*/")} +{char(92)} +{("\*//*\trap")&("\")} +{("\*//*\trap\")&("pass2!")} + +\*//*\trap\pass2! +{endgroup} +{outer} +{let} +{delimiters} + +! Missing symbolic token inserted. +<inserted text> + INACCESSIBLE +l.21 ...t next=\; delimiters ^~7 + ! fi +Sorry: You can't redefine a number, string, or expr. +I've inserted an inaccessible symbol so that your +definition will be completed without mixing me up too badly. + +! Extra tokens will be flushed. +<to be read again> + ! +l.21 ... next=\; delimiters ^~7! + fi +I've just read as much of that statement as I could fathom, +so a semicolon should have been next. It's very puzzling... +but I'll try to get myself back together, by ignoring +everything up to the next `;'. Please insert a semicolon +now in front of anything that you don't want me to delete. +(See Chapter 27 of The METAFONTbook for an example.) + +! Forbidden token found while scanning to the end of the statement. +<inserted text> + ; +<to be read again> + \ +l.22 next\ + ; % the second pass will now compute silently; the ... +A previous error seems to have propagated, +causing me to read past where you wanted me to stop. +I'll try to recover; but if the error is serious, +you'd better type `E' or `X' now and fix your file. + +{\} +{batchmode} + +! An expression can't begin with `endgroup'. +<inserted text> + 0 +<to be read again> + endgroup +l.23 batchmode; ^~7,endgroup + pausing:=1; exitif p exitif bool... +I'm afraid I need some sort of value in order to continue, +so I've tentatively inserted `0'. You may want to +delete this zero and insert something else; +see Chapter 27 of The METAFONTbook for an example. + +! Missing ` INACCESSIBLE' has been inserted. +<to be read again> + endgroup +l.23 batchmode; ^~7,endgroup + pausing:=1; exitif p exitif bool... +I found no right delimiter to match a left one. So I've +put one in, behind the scenes; this may fix the problem. + +! Extra `endgroup'. +<recently read> endgroup + +l.23 batchmode; ^~7,endgroup + pausing:=1; exitif p exitif bool... +I'm not currently working on a `begingroup', +so I had better not try to end anything. + +{pausing:=1} +{exitif} +{exitif} +{pencircle} +{endfor} +! Extra `endfor'. +l.23 ...ean pen pencircle endfor + +I'm not currently working on a for loop, +so I had better not try to end anything. + +{scantokens} +{begingroup} +{message} +{char(0)} +{("^^@")&("watch this")} +^^@watch this +{-(1)} +{char(-1)} +{("pair p[],';")&("^^ff")} +{endgroup} +{pen(future pen)} +{boolean(true)} +{true} +! No loop is in progress. +<to be read again> + pair +<scantokens> pair + p[],';^^ff +<to be read again> + path +l.25 path + p[][]p,w,qw; qw=(1,-2)..(2,-1)..(2.5,0.5)..(1,2)..(... +Why say `exitif' when there's nothing to exit from? + +>> p +! Undefined condition will be treated as `false'. +<to be read again> + pair +<scantokens> pair + p[],';^^ff +<to be read again> + path +l.25 path + p[][]p,w,qw; qw=(1,-2)..(2,-1)..(2.5,0.5)..(1,2)..(... +The expression shown above should have had a definite +true-or-false value. I'm changing it to `false'. + +{false} +! Missing `;' has been inserted. +<to be read again> + pair +<scantokens> pair + p[],';^^ff +<to be read again> + path +l.25 path + p[][]p,w,qw; qw=(1,-2)..(2,-1)..(2.5,0.5)..(1,2)..(... +After `exitif <boolean exp>' I expect to see a semicolon. +I shall pretend that one was there. + +{pair} +! Text line contains an invalid character. +<scantokens> pair p[],';^^ff + +<to be read again> + path +l.25 path + p[][]p,w,qw; qw=(1,-2)..(2,-1)..(2.5,0.5)..(1,2)..(... +A funny symbol that I can't read has just been input. +Continue, and I'll forget that it ever happened. + +{path} +{-(2)} +{-(1)} +{turningnumber((xpart ',ypart '))} +Path at line 25, before choices: +(1,-2){curl 1} + ..(2,-1) + ..(2.5,0.5) + ..(1,2) + ..{curl 1}(0,2.5) + +Path at line 25, after choices: +(1,-2)..controls (1.37755,-1.71404) and (1.71404,-1.37755) + ..(2,-1)..controls (2.33353,-0.55965) and (2.59729,-0.04124) + ..(2.5,0.5)..controls (2.36812,1.23369) and (1.6712,1.65662) + ..(1,2)..controls (0.66821,2.16974) and (0.33485,2.33641) + ..(0,2.5) + +{(unknown path qw)=(path)} +{numeric} +! Enormous number has been reduced. +l.26 ...[$] ]]=10000000000000000 + ; "this string constant is in... +I can't handle numbers bigger than about 4095.99998; +so I've changed your constant to that maximum amount. + +{(p[[ [-1] ]])=(4095.99998)} +## p[[ [-1] ]]=4095.99998 +! Incomplete string token has been flushed. +l.26 ...g constant is incomplete + +Strings should finish on the same line as they began. +I've deleted the partial string; you might want to +insert another by typing, e.g., `I"new string"'. + +{string} +! Declared variable conflicts with previous vardef. +<to be read again> + , +l.27 string foo[]p, + p~if true:[]; p~000=char34&char200&char34; +You can't use, e.g., `numeric foo[]' after `vardef foo'. +Proceed, and I'll ignore the illegal redeclaration. + +{if} +{true} +{true} +{char(34)} +{char(200)} +{(""")&("^^c8")} +{char(34)} +{(""^^c8")&(""")} +{(unknown string p~0)=(""^^c8"")} +{boolean} +{fi} +{showvariable} +boolean.boolean=unknown boolean +! OK. +l.28 ...n; showvariable boolean; + def\\= =end enddef; + +{def} +{picture} +{show} +{scantokens} +{length("^^c8")} +>> 1 +! OK. +<recently read> ; + +l.29 ...w length scantokens p~0; + + +{pen} +! Illegal suffix of declared variable will be flushed. +<to be read again> + [ +<to be read again> + "a" +l.30 pen p~[]~,q["a" + ,qq; p~1~=q=pencircle scaled mexp(-3016.5... +Variables in declarations must consist entirely of +names and collective subscripts, e.g., `x[]a'. +Are you trying to use a reserved word in a variable name? +I'm going to discard the junk I found here, +up to the next comma or the end of the declaration. + +{pencircle} +{-(3016.57654)} +{mexp(-3016.57654)} +{(future pen)scaled(0)} +Pen polygon at line 30 (newly created): +(0.5,0) + .. (0,0.5) + .. (-0.5,0) + .. (0,-0.5) + .. cycle + +{(unknown pen q)=(pen)} +{(unknown pen p~1~)=(pen)} +{transform} +! Illegal suffix of declared variable will be flushed. +<to be read again> + 0 +l.31 transform p,pp0 + ; if p=p:qq=makepen((1,0)..cycle) xscaled... +Variables in declarations must consist entirely of +names and collective subscripts, e.g., `x[]a'. +Explicit subscripts like `x15a' aren't permitted. +I'm going to discard the junk I found here, +up to the next comma or the end of the declaration. + +{if} +{((xpart p,ypart p,xxpart p,xypart p,yxpart p,yypart p))=((xpart p,ypart + p,xxpart p,xypart p,yxpart p,yypart p))} +{true} +Path at line 31, before choices: +(1,0) + ..cycle + +Path at line 31, after choices: +(1,0)..controls (1,0) and (1,0) + ..cycle + +{makepen(path)} +{hex("1000")} +! Number too large (4096). +<to be read again> + ; +l.31 ...cle) xscaled hex "1000"; + fi +I have trouble with numbers greater than 4095; watch out. + +{(future pen)xscaled(4096)} +! Pen too large. +<to be read again> + ; +l.31 ...cle) xscaled hex "1000"; + fi +The cycle you specified has a coordinate of 4095.5 or more. +So I've replaced it by the trivial path `(0,0)..cycle'. + +Pen polygon at line 31 (newly created): +(0,0) + .. cycle + +{(unknown pen qq)=(pen)} +{fi} +Path at line 32, before choices: +(0,0) + ..(1,0) + ..(0,1) + ..(0,0) + ..(1,0) + ..(0,1) + ..cycle + +Path at line 32, after choices: +(0,0)..controls (0.29056,-0.29056) and (0.75859,-0.30772) + ..(1,0)..controls (1.51964,0.66237) and (0.66237,1.51964) + ..(0,1)..controls (-0.30772,0.75859) and (-0.29056,0.29056) + ..(0,0)..controls (0.29056,-0.29056) and (0.75859,-0.30772) + ..(1,0)..controls (1.51964,0.66237) and (0.66237,1.51964) + ..(0,1)..controls (-0.30772,0.75859) and (-0.29056,0.29056) + ..cycle + +{makepen(path)} +! Pen cycle must be convex. +<to be read again> + ; +l.32 ...)..(1,0)..(0,1)..cycle); + +The cycle you specified either has consecutive equal points +or turns right or turns through more than 360 degrees. +So I've replaced it by the trivial path `(0,0)..cycle'. + +Pen polygon at line 32 (newly created): +(0,0) + .. cycle + +{qq:=pen} +{vardef} +! Missing parameter type; `expr' will be assumed. +<to be read again> + ) +l.33 ...ext suffix a,b endtext() + )suffix@=show #@; p.a.b() end... +You should've had `expr' or `suffix' or `text' here. + +{expandafter} +{\} +{let} + +\\->=end +{outer} +{pencircle} +{(future pen)scaled(4.5)} +{(future pen)yscaled(2)} +Pen polygon at line 34 (newly created): +(0.5,-4.5) + .. (1,-4) + .. (2,-2.5) + .. (2.5,0) + .. (2,2.5) + .. (1,4) + .. (0.5,4.5) + .. (-0.5,4.5) + .. (-1,4) + .. (-2,2.5) + .. (-2.5,0) + .. (-2,-2.5) + .. (-1,-4) + .. (-0.5,-4.5) + .. cycle + +{qq:=pen} +{((6,12))-((xpart p7,ypart p7))} +{((0,1))transformed((xpart p,ypart p,xxpart p,xypart p,yxpart p,yypart p +))} +{(x)-(x)} +{(2)/(0)} +>> 2 +! Division by zero. +<to be read again> + , +l.35 ...)transformed p=(2/(x-x), + 3/0)transformed p; +You're trying to divide the quantity shown above the error +message by zero. I'm going to divide it by one instead. + +! Division by zero. +l.35 ...ansformed p=(2/(x-x),3/0 + )transformed p; +I'll pretend that you meant to divide by 1. + +{((2,3))transformed((xpart p,ypart p,xxpart p,xypart p,yxpart p,yypart p +))} +{((linearform,linearform))=((linearform,linearform))} +## yxpart p=-yypart p +## xxpart p=-xypart p +{((-xpart p7+6,-ypart p7+12))=((linearform,linearform))} +## ypart p7=-ypart p-yypart p+12 +## xpart p7=-xpart p-xypart p+6 +{\} +{if} +{string(unknown string p~[-1])} +{true} +{(p0.1 0.2)-(p0.1 0.2)} +! The token `endtext' is no longer a right delimiter. +l.36 ...1.2-p.1.199999,1 endtext + transformed p; +Strange: This token has lost its former meaning! +I'll read it as a right delimiter this time; +but watch out, I'll probably miss it later. + +{((0,1))transformed((xpart p,ypart p,-xypart p,xypart p,-yypart p,yypart + p))} +{((linearform,linearform))=((linearform,linearform))} +## ypart p=-yypart p+6 +#### ypart p7=6 +## xpart p=-xypart p+3 +#### xpart p7=3 +{(unknown path p1 2p)=((3,6))} +{showstopping:=0} +{showvariable} +p=(-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p) +p[]=pair +p[][]=numeric +p[][]p=unknown path +p[][]p~=macro:(SUFFIX2)(SUFFIX3)(EXPR4)<suffix>->begingroup ETC. +p[]~=unknown boolean +p~=path +p~[]=unknown string +p~[]~=unknown pen +p~[]~[][]=unknown picture +p~[-1]=unknown string p~[-1] +p~0=""^^c8"" +p~1~=pen +p[[ [] ]]=numeric +p[[ [-1] ]]=4095.99998 +p0.1 0.2=p0.1 0.2 +p1 2p=path +p7=(3,6) +{((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p))=((-xy +part p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p))} +{let} +{let} +{xxpart((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p)) +} +{(-xypart p)+(0.002)} +{yxpart((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p)) +} +{((xpart p2,ypart p2))-((xpart p1,ypart p1))} +{(1)*((linearform,linearform))} +{((xpart p1,ypart p1))+((linearform,linearform))} +{(y)+(0.00002)} +{yypart((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p)) +} +{xypart((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p)) +} +{((5,y))=((yypart p,xypart p))} +## y=xypart p +## yypart p=5 +#### ypart p=1 +#### yxpart p=-5 +{((5,xypart p+0.00002))=((5,xypart p))} +{((xpart p2,ypart p2))=((5,xypart p))} +## ypart p2=xypart p +## xpart p2=5 +{((-xypart p+0.002,-5))=((5,xypart p))} +## xypart p=-5 +#### ypart p2=-5 +#### y=-5 +#### xpart p=8 +#### xxpart p=5 +! Inconsistent equation (off by -0.002). +<to be read again> + ; +l.38 ...,y)=(yypart p,xypart p); + +The equation I just read contradicts what was said before. +But don't worry; continue and I'll just ignore it. + +Path at line 39, before choices: +(0,0)..controls (15,4) and (-15,-12) + ..(4,0) + ..cycle + +Path at line 39, after choices: +(0,0)..controls (15,4) and (-15,-12) + ..(4,0)..controls (17.52783,8.54388) and (-15.45978,-4.12262) + ..cycle + +{reverse(path)} +{(path)transformed((8,1,5,-5,-5,5))} +{(path)=(unknown path p2 3p)} + +p1 2p~(SUFFIX2)(SUFFIX3)(EXPR4)<suffix>->begingroup.show(SUFFIX0);p(SUFF +IX2)(SUFFIX3)((EXPR4)endgroup +(SUFFIX0)<-p1 2p +(SUFFIX1)<-~ +(SUFFIX2)<- +(SUFFIX3)<-2 3p~ +! A primary expression can't begin with `right delimiter that matches (' +. +<inserted text> + 0 +<to be read again> + ) +l.40 ...000000001]2p~(,[2]3p~,-) + =p~1~2[pausing]; +I'm afraid I need some sort of value in order to continue, +so I've tentatively inserted `0'. You may want to +delete this zero and insert something else; +see Chapter 27 of The METAFONTbook for an example. + +{-(0)} +(EXPR4)<-0 +(SUFFIX5)<- +{begingroup} +{show} +>> Path at line 40: +(3,6) + + +p2 3p~(SUFFIX2)(SUFFIX3)(EXPR4)<suffix>->begingroup.show(SUFFIX0);p(SUFF +IX2)(SUFFIX3)((EXPR4)endgroup +(SUFFIX0)<-p2 3p +(SUFFIX1)<-~ +! Missing `,' has been inserted. +<to be read again> + (0) +p1 2p~->...IX2)(SUFFIX3)((EXPR4) + endgroup +<to be read again> + = +l.40 ...00000001]2p~(,[2]3p~,-)= + p~1~2[pausing]; +I've finished reading a macro argument and am about to +read another; the arguments weren't delimited correctly. +You might want to delete some tokens before continuing. + +(SUFFIX2)<- +! Missing `,' has been inserted. +<to be read again> + (0) +p1 2p~->...IX2)(SUFFIX3)((EXPR4) + endgroup +<to be read again> + = +l.40 ...00000001]2p~(,[2]3p~,-)= + p~1~2[pausing]; +I've finished reading a macro argument and am about to +read another; the arguments weren't delimited correctly. +You might want to delete some tokens before continuing. + +(SUFFIX3)<- +! Missing `)' has been inserted. +<to be read again> + endgroup +<to be read again> + = +l.40 ...00000001]2p~(,[2]3p~,-)= + p~1~2[pausing]; +I've gotten to the end of the macro parameter list. +You might want to delete some tokens before continuing. + +(EXPR4)<-0 +(SUFFIX5)<- +{begingroup} +{show} +>> Path at line 40: +(8,1)..controls (-48.68579,57.68579) and (52.91974,-43.91974) + ..(28,-19)..controls (-7,16) and (63,-54) + ..cycle + +>> (8,1,5,-5,-5,5) +! Isolated expression. +<to be read again> + ( +p2 3p~->...;p(SUFFIX2)(SUFFIX3)( + (EXPR4)endgroup +<to be read again> + endgroup +<to be read again> + = +l.40 ...00000001]2p~(,[2]3p~,-)= + p~1~2[pausing]; +I couldn't find an `=' or `:=' after the +expression that is shown above this error message, +so I guess I'll just ignore it and carry on. + +! Extra tokens will be flushed. +<to be read again> + ( +p2 3p~->...;p(SUFFIX2)(SUFFIX3)( + (EXPR4)endgroup +<to be read again> + endgroup +<to be read again> + = +l.40 ...00000001]2p~(,[2]3p~,-)= + p~1~2[pausing]; +I've just read as much of that statement as I could fathom, +so a semicolon should have been next. It's very puzzling... +but I'll try to get myself back together, by ignoring +everything up to the next `;'. Please insert a semicolon +now in front of anything that you don't want me to delete. +(See Chapter 27 of The METAFONTbook for an example.) + +{endgroup} +{endgroup} +{(vacuous)=(unknown picture p~1~2 1)} +>> vacuous +>> unknown picture p~1~2 1 +! Equation cannot be performed (vacuous=unknown picture). +<to be read again> + ; +l.40 ...2]3p~,-)=p~1~2[pausing]; + +I'm sorry, but I don't know how to make such things equal. +(See the two expressions just above the error message.) + +{vardef} +Runaway definition? +if.p(SUFFIX1)(SUFFIX1)=(SUFFIX1)(SUFFIX1)p.fi +! Forbidden token found while scanning the definition of p~[]. +<inserted text> + enddef +<to be read again> + ; +l.41 ...iary t:=if p@ @=@ @p fi; + vardef p[][]p~[]=BAD; inner ;; +I suspect you have forgotten an `enddef', +causing me to read past where you wanted me to stop. +I'll try to recover; but if the error is serious, +you'd better type `E' or `X' now and fix your file. + +{vardef} +! This variable already starts with a macro. +l.41 ...@p fi; vardef p[][]p~[]= + BAD; inner ;; +After `vardef a' you can't say `vardef a.b'. +So I'll have to discard this definition. + +Runaway definition? +BAD +! Forbidden token found while scanning the definition of a bad variable. +<inserted text> + enddef +<to be read again> + ; +l.41 ...i; vardef p[][]p~[]=BAD; + inner ;; +I suspect you have forgotten an `enddef', +causing me to read past where you wanted me to stop. +I'll try to recover; but if the error is serious, +you'd better type `E' or `X' now and fix your file. + +{inner} +{show} +{-(2)} + +p~[-2]@#<tertiary>->begingroup.if.p(SUFFIX1)(SUFFIX1)=(SUFFIX1)(SUFFIX1) +p.fi.endgroup +(SUFFIX0)<-p~ +(SUFFIX1)<-[-2] +(SUFFIX2)<-~ +! A tertiary expression can't begin with `['. +<inserted text> + 0 +<to be read again> + [ +<to be read again> + (3000) +<to be read again> + , +l.42 show p~[-2]~[3000, + x]++4000>path p3; showvariable p,P; +I'm afraid I need some sort of value in order to continue, +so I've tentatively inserted `0'. You may want to +delete this zero and insert something else; +see Chapter 27 of The METAFONTbook for an example. + +{(x)-(3000)} +{(0)*(x-3000)} +{(3000)+(0)} +{(3000)++(4000)} +(EXPR3)<-4999.99998 +{begingroup} +{if} +{(p[-2][-2])=(-2)} +>> p[-2][-2]+2 +! Unknown relation will be considered false. +<to be read again> + [-2] +p~[-2]->...1)=(SUFFIX1)(SUFFIX1) + p.fi.endgroup +<to be read again> + > +l.42 show p~[-2]~[3000,x]++4000> + path p3; showvariable p,P; +Oh dear. I can't decide if the expression above is positive, +negative, or zero. So this comparison test won't be `true'. + +{false} +! Missing `:' has been inserted. +<to be read again> + [-2] +p~[-2]->...1)=(SUFFIX1)(SUFFIX1) + p.fi.endgroup +<to be read again> + > +l.42 show p~[-2]~[3000,x]++4000> + path p3; showvariable p,P; +There should've been a colon after the condition. +I shall pretend that one was there. + +{endgroup} +{path((xpart p3,ypart p3))} +{(vacuous)>(false)} +>> vacuous +>> false +! Not implemented: (vacuous)>(boolean). +<to be read again> + ; +l.42 ...~[3000,x]++4000>path p3; + showvariable p,P; +I'm afraid I don't know how to apply that operation to that +combination of types. Continue, and I'll return the second +argument (see above) as the result of the operation. + +>> false +{showvariable} +p=(8,1,5,-5,-5,5) +p[]=pair +p[][]=numeric +p[][]p=unknown path +p[][]p~=macro:(SUFFIX2)(SUFFIX3)(EXPR4)<suffix>->begingroup ETC. +p[]~=unknown boolean +p~=path +p~[]@#=macro:<tertiary>->begingroup.if.p(SUFFIX1)(SUFFIX1) ETC. +p[[ [] ]]=numeric +p[[ [-1] ]]=4095.99998 +p[-2][-2]=p[-2][-2] +p0.1 0.2=p0.1 0.2 +p1=(xpart p1,ypart p1) +p1 2p=path +p2=(5,-5) +p2 3p=path +p3=(xpart p3,ypart p3) +p7=(3,6) +> P=tag +{numeric} +{(2)*(alpha)} +{(p3~)=(2alpha)} +## alpha=0.5p3~ +{(1)/(-1)} +{(3)*(beta)} +{(p[-1]~)=(3beta)} +## beta=0.33333p[-1]~ +{begingroup} +{save} +{showvariable} +> p=tag +{(3)*(0.33333(SAVED)p[-1]~)} +{((SAVED)p[-1]~)=(1)} +## (SAVED)p[-1]~=1 +#### beta=0.33333 +{restoring p} +{endgroup} +{showvariable} +p=(8,1,5,-5,-5,5) +p[]=pair +p[][]=numeric +p[][]p=unknown path +p[][]p~=macro:(SUFFIX2)(SUFFIX3)(EXPR4)<suffix>->begingroup ETC. +p[]~=numeric +p~=path +p~[]@#=macro:<tertiary>->begingroup.if.p(SUFFIX1)(SUFFIX1) ETC. +p[[ [] ]]=numeric +p[[ [-1] ]]=4095.99998 +p[-2][-2]=p[-2][-2] +p[-1]~=1 +p0.1 0.2=p0.1 0.2 +p1=(xpart p1,ypart p1) +p1 2p=path +p2=(5,-5) +p2 3p=path +p3=(xpart p3,ypart p3) +p3~=p3~ +p7=(3,6) +{def} +{def} +! Missing `=' has been inserted. +<to be read again> + false +l.45 ...enddef;def!primary!false + ):!fi enddef; +The next thing in this `def' should have been `=', +because I've already looked at the definition heading. +But don't worry; I'll pretend that an equals sign +was present. Everything from here to `enddef' +will be the replacement text of this macro. + +{def} +{(path)scaled(-1)} +Path at line 46, before choices: +(1,-2)..controls (1.37755,-1.71404) and (1.71404,-1.37755) + ..(2,-1)..controls (2.33353,-0.55965) and (2.59729,-0.04124) + ..(2.5,0.5)..controls (2.36812,1.23369) and (1.6712,1.65662) + ..(1,2)..controls (0.66821,2.16974) and (0.33485,2.33641) + ..(0,2.5) + ..(-1,2)..controls (-1.37755,1.71404) and (-1.71404,1.37755) + ..(-2,1)..controls (-2.33353,0.55965) and (-2.59729,0.04124) + ..(-2.5,-0.5)..controls (-2.36812,-1.23369) and (-1.6712,-1.65662) + ..(-1,-2)..controls (-0.66821,-2.16974) and (-0.33485,-2.33641) + ..(0,-2.5) + ..cycle + +Path at line 46, after choices: +(1,-2)..controls (1.37755,-1.71404) and (1.71404,-1.37755) + ..(2,-1)..controls (2.33353,-0.55965) and (2.59729,-0.04124) + ..(2.5,0.5)..controls (2.36812,1.23369) and (1.6712,1.65662) + ..(1,2)..controls (0.66821,2.16974) and (0.33485,2.33641) + ..(0,2.5)..controls (-0.37186,2.68167) and (-0.668,2.25146) + ..(-1,2)..controls (-1.37755,1.71404) and (-1.71404,1.37755) + ..(-2,1)..controls (-2.33353,0.55965) and (-2.59729,0.04124) + ..(-2.5,-0.5)..controls (-2.36812,-1.23369) and (-1.6712,-1.65662) + ..(-1,-2)..controls (-0.66821,-2.16974) and (-0.33485,-2.33641) + ..(0,-2.5)..controls (0.37186,-2.68167) and (0.668,-2.25146) + ..cycle + +{makepen(path)} +Pen polygon at line 46 (newly created): +(1,-2) + .. (2,-1) + .. (2.5,0.5) + .. (1,2) + .. (0,2.5) + .. (-1,2) + .. (-2,1) + .. (-2.5,-0.5) + .. (-1,-2) + .. (0,-2.5) + .. cycle + +{qq:=pen} +{primarydef} +{secondarydef} + +//<expr>-> + +//<expr>-> +{pencircle} +{length(path)} +{(future pen)slanted(1)} +{((3,6))-((5,-5))} + +_aa__<secondary>->if(true +{(0.1)*(15)} +{odd(1.50009)} +{not(false)} +{known((8,1,5,-5,-5,5))} +{(true)and(true)} +(EXPR0)<-true +{if} +{true} + +!<primary>->false):(EXPR0)fi +(EXPR0)<-(5,-5) +{false} +{(true)or(false)} +{true} +{fi} +{-((5,-5))} +{-((5,-5))} +{+(1)} +{-(1)} +>> -1 +! Improper curl has been replaced by 1. +<to be read again> + ) +l.51 {curl- +1) + ..tension atleast1..cycle sqrt2++sqrt2***[[]]; +A curl must be a known, nonnegative number. + +! Missing `}' has been inserted. +<to be read again> + ) +l.51 {curl- +1) + ..tension atleast1..cycle sqrt2++sqrt2***[[]]; +I've scanned a direction spec for part of a path, +so a right brace should have come next. +I shall pretend that one was there. + +Path at line 51, before choices: +(-5,5) + +Path at line 51, after choices: +(-5,5) + +Path at line 51, before choices: +(3,6)..controls (5,-5) and (-5,5) + ..(-5,5)..tension atleast1 + ..{2896.30943,-2896.30934}cycle + +Path at line 51, after choices: +(3,6)..controls (5,-5) and (-5,5) + ..(-5,5)..controls (-3.29726,7.86205) and (0.64516,8.35484) + ..cycle + +! Missing `)' has been inserted. +<to be read again> + sqrt +l.51 ...ion atleast1..cycle sqrt + 2++sqrt2***[[]]; +I found no right delimiter to match a left one. So I've +put one in, behind the scenes; this may fix the problem. + +{((-2,11))subpath(path)} +{reverse(path)} +{makepen(path)} + +**->[[show(EXPR0)*(EXPR1)]] +(EXPR0)<-future pen +(EXPR1)<-future pen +{begingroup} +{show} +{(future pen)*(future pen)} +>> future pen +>> future pen +! Not implemented: (future pen)*(future pen). +<to be read again> + ]] +<to be read again> + sqrt +l.51 ...ion atleast1..cycle sqrt + 2++sqrt2***[[]]; +I'm afraid I don't know how to apply that operation to that +combination of types. Continue, and I'll return the second +argument (see above) as the result of the operation. + +! Pen path must be a cycle. +<to be read again> + ]] +<to be read again> + sqrt +l.51 ...ion atleast1..cycle sqrt + 2++sqrt2***[[]]; +I can't make a pen from the given path. +So I've replaced it by the trivial path `(0,0)..cycle'. + +>> Pen polygon at line 51: +(0,0) + .. cycle + +{endgroup} +(EXPR0)<-vacuous +{sqrt(2)} +{sqrt(2)} +{(1.41422)++(1.41422)} +{begingroup} +{endgroup} + +***->expandafter(EXPR1)scantokens"**oct"(EXPR0) +(EXPR0)<-2 +(EXPR1)<-vacuous +{expandafter} +{scantokens} +{oct(2)} +>> 2 +! Not implemented: oct(known numeric). +<to be read again> + ; +l.51 ...cle sqrt2++sqrt2***[[]]; + +I'm afraid I don't know how to apply that operation to that +particular type. Continue, and I'll simply return the +argument (shown above) as the result of the operation. + + +**->[[show(EXPR0)*(EXPR1)]] +(EXPR0)<-vacuous +(EXPR1)<-2 +{begingroup} +{show} +{(vacuous)*(2)} +>> vacuous +>> 2 +! Not implemented: (vacuous)*(known numeric). +<to be read again> + ]] +<to be read again> + ; +l.51 ...cle sqrt2++sqrt2***[[]]; + +I'm afraid I don't know how to apply that operation to that +combination of types. Continue, and I'll return the second +argument (see above) as the result of the operation. + +>> 2 +{endgroup} +(EXPR0)<-vacuous +{begingroup} +{interim} +{-(20.5)} +{charcode:=-20.5} +{proofing:=-20.5} +{-(2048)} +{chardp:=-2048} +{shipout} +{nullpicture} +! Enormous chardp has been reduced. +<to be read again> + ]] +l.52 ...48;shipout nullpicture]] + ; +Font metric dimensions must be less than 2048pt. + +{restoring proofing=0} +{endgroup} +{if} +{-(275.50002)} +{charexists(-275.50002)} +{known(unknown path p0 0p)} +{(true)>(false)} +{known(path)} +{(true)=(true)} +{true} +{randomseed} +! Missing `:=' has been inserted. +<to be read again> + charcode +l.53 ... p~: randomseed charcode + ; fi +Always say `randomseed:=<numeric expression>'. + +{randomseed:=-20.5} +{fi} +{randomseed} +>> "goof" +! Unknown value will be ignored. +<to be read again> + ; +l.54 randomseed:="goof"; + a[($,18++1+-+18),(2,3)]=b[(3,2),(1,$); +Your expression was too random for me to handle, +so I won't change the random seed just now. + +{(18)++(1)} +{(18.02776)+-+(18)} +{((2,3))-((-1,1))} +{(a)*((3,2))} +{((-1,1))+((3a,2a))} +! Missing `]' has been inserted. +<to be read again> + ; +l.54 ...8),(2,3)]=b[(3,2),(1,$); + +I've scanned an expression of the form `a[b,c', +so a right bracket should have come next. +I shall pretend that one was there. + +{((1,-1))-((3,2))} +{(b)*((-2,-3))} +{((3,2))+((-2b,-3b))} +{((3a-1,2a+1))=((-2b+3,-3b+2))} +## b=-0.66667a+0.33333 +## a=2 +#### b=-1 +{show} +{(^)+(1)} +{(~)+(2)} +{-(1)} +{((^+1,~+2))slanted(-1)} +{-(2)} +{((linearform,~+2))yscaled(-2)} +{-((3,4))} +{((linearform,-2~-4))zscaled((-3,-4))} +>> (-5~-3^-13,10~-4^+16) +{((xpart pp,ypart pp,xxpart pp,xypart pp,yxpart pp,yypart pp))xscaled(9) +} +{((8,1,5,-5,-5,5))transformed((9xpart pp,ypart pp,9xxpart pp,9xypart pp, +yxpart pp,yypart pp))} +>> (9xpart pp+72xxpart pp+9xypart pp,ypart pp+8yxpart pp+yypart pp,45xxp +art pp-45xypart pp,-45xxpart pp+45xypart pp,5yxpart pp-5yypart pp,-5yxpa +rt pp+5yypart pp) +{((xpart pp,ypart pp,xxpart pp,xypart pp,yxpart pp,yypart pp))shifted((1 +,2))} +{((8,1,5,-5,-5,5))transformed((8,1,5,-5,-5,5))} +{((xpart pp+1,ypart pp+2,xxpart pp,xypart pp,yxpart pp,yypart pp))transf +ormed((43,-34,50,-50,-50,50))} +>> (50xpart pp-50ypart pp-7,-50xpart pp+50ypart pp+16,50xxpart pp-50yxpa +rt pp,50xypart pp-50yypart pp,-50xxpart pp+50yxpart pp,-50xypart pp+50yy +part pp) +{(2)-(1)} +{(_0)*(1)} +{(1)+(_0)} +{-(_0+1)} +>> -_0-1 +{show} +{normaldeviate} +{-(-2048)} +{uniformdeviate(2048)} +{angle((-0.41438,761.67789))} +{cosd(90.03117)} +{(200)*(-0.00055)} +{mexp(-0.10986)} +{sqrt(0.99957)} +{mlog(0.99979)} +{sind(-0.05469)} +{floor(-0.00096)} +>> -1 +{string} +{(unknown string s2)=(unknown string s4)} +{(unknown string s1)=(unknown string s2)} +{(unknown string s3)=(unknown string s5)} +{(unknown string s2)=(unknown string s4)} +! Redundant equation. +<to be read again> + ; +l.58 ... s1=s2=s4; s3=s5; s1=s2; + if s1<=s4<>(s1<>s3):show[[ch... +I already knew that this equation was true. +But perhaps no harm has been done; let's continue. + +{if} +{(unknown string s2)<=(unknown string s1)} +{(unknown string s2)<>(unknown string s5)} +>> unknown string s2 +>> unknown string s5 +! Unknown relation will be considered false. +<to be read again> + ) +l.58 ...=s2; if s1<=s4<>(s1<>s3) + :show[[char34=s2:=s3]]fi; +The quantities shown above have not been equated. + +{(true)<>(false)} +{true} +{show} +{begingroup} +{char(34)} +{s2:=unknown string s5} +{(""")=(unknown string s2)} +{endgroup} +{fi} +>> vacuous +{(0.1)point(path)} +{begingroup} +{pencircle} +Pen polygon at line 59 (newly created): +(0.5,0) + .. (0,0.5) + .. (-0.5,0) + .. (0,-0.5) + .. cycle + +{endgroup} +{((3.24413,0.64801))penoffset(pen)} +{((0,-0.5))rotated(540)} +{((0,0.5))/(0.33333)} +{-(1.5)} +! Paths don't touch; `&' will be changed to `..'. +<to be read again> + ) +l.60 ...tcontrol-1.5of(p~&cycle) + -precontrol1/2of p~(p~)=s1:=s... +When you join paths `p&q', the ending point of p +must be exactly equal to the starting point of q. +So I'm going to pretend that you said `p..q' instead. + +Path at line 60, before choices: +(0,0)..controls (15,4) and (-15,-12) + ..(4,0) + ..cycle + +Path at line 60, after choices: +(0,0)..controls (15,4) and (-15,-12) + ..(4,0)..controls (17.52783,8.54388) and (-15.45978,-4.12262) + ..cycle + +{(-1.5)postcontrol(path)} +{(0.5)precontrol(path)} +{((-2.75,-5))-((3.75,-1))} +! Missing `of' has been inserted for directiontime. +<to be read again> + ( +l.60 ...cle)-precontrol1/2of p~( + p~)=s1:=s4:=s4; +I've got the first argument; will look now for the other. + +{((-6.5,-4))directiontime(path)} +{decimal(0.5)} +{((0,1.50003))substring("0.5")} +{s4:=unknown string s1} +{s1:=unknown string s4} +{("0.")=(unknown string s1)} +{path} +{length(" ")} +! Missing `,' has been inserted. +<to be read again> + } +l.61 ...p~[]; p~1=p2{length" "} + &cycle; p~1=p2=p~0; p2..contr... +I've got the x coordinate of a path direction; +will look for the y coordinate next. + +! An expression can't begin with `}'. +<inserted text> + 0 +<to be read again> + } +l.61 ...p~[]; p~1=p2{length" "} + &cycle; p~1=p2=p~0; p2..contr... +I'm afraid I need some sort of value in order to continue, +so I've tentatively inserted `0'. You may want to +delete this zero and insert something else; +see Chapter 27 of The METAFONTbook for an example. + +Path at line 61, before choices: +(5,-5){4096,0} + ..{4096,0}cycle + +Path at line 61, after choices: +(5,-5)..controls (5,-5) and (5,-5) + ..cycle + +{(unknown path p~1)=(path)} +{((5,-5))=(unknown path p~0)} +{(path)=(path)} +! Redundant or inconsistent equation. +<to be read again> + ; +l.61 ..." "}&cycle; p~1=p2=p~0; + p2..controls-p2..cycle=p~2;(p7 +An equation between already-known quantities can't help. +But don't worry; continue and I'll just ignore it. + +{-((5,-5))} +Path at line 61, before choices: +(5,-5)..controls (-5,5) and (-5,5) + ..cycle + +Path at line 61, after choices: +(5,-5)..controls (-5,5) and (-5,5) + ..cycle + +{(path)=(unknown path p~2)} +{length(path)} +Path at line 62, before choices: +(3,6)..tension 1.2 + ..(5,-5)..controls (5,-5) and (5,-5) + ..(5,-5) + ..(5,-5)..controls (-5,5) and (-5,5) + ..(5,-5){0,4096}..tension 1 and atleast1 + ..cycle + +Path at line 62, after choices: +(3,6)..controls (-3.01212,4.82085) and (-1.0424,-6.01257) + ..(5,-5)..controls (5,-5) and (5,-5) + ..(5,-5)..controls (5,-5) and (5,-5) + ..(5,-5)..controls (-5,5) and (-5,5) + ..(5,-5)..controls (5,0.02791) and (4.99951,6.39217) + ..cycle + +>> x +! Improper tension has been set to 1. +<to be read again> + .. +l.63 x.. + {curl1}-p7{curl hex "IsBad"}..tension.75and.74999..p... +The expression above should have been a number >=3/4. + +{-((3,6))} +{hex("IsBad")} +>> "IsBad" +! String contains illegal digits. +<to be read again> + } +l.63 ...l1}-p7{curl hex "IsBad"} + ..tension.75and.74999..p2{0,1... +I zeroed out characters that weren't hex digits. + +>> 0.74998 +! Improper tension has been set to 1. +<to be read again> + .. +l.63 ...}..tension.75and.74999.. + p2{0,1}&p2{_,'}..cycle:=p +The expression above should have been a number >=3/4. + +>> _ +! Undefined x coordinate has been replaced by 0. +<to be read again> + , +l.63 ...and.74999..p2{0,1}&p2{_, + '}..cycle:=p +I need a `known' x value for this part of the path. +The value I found (see above) was no good; +so I'll try to keep going by using zero instead. +(Chapter 27 of The METAFONTbook explains that +you might want to type `I ???' now.) + +>> (xpart ',ypart ') +! Undefined y coordinate has been replaced by 0. +<to be read again> + } +l.63 ...d.74999..p2{0,1}&p2{_,'} + ..cycle:=p +I need a `known' y value for this part of the path. +The value I found (see above) was no good; +so I'll try to keep going by using zero instead. +(Chapter 27 of The METAFONTbook explains that +you might want to type `I ???' now.) + +Path at line 63, before choices: +(3,6)..controls (-3.01212,4.82085) and (-1.0424,-6.01257) + ..(5,-5)..controls (5,-5) and (5,-5) + ..(5,-5)..controls (5,-5) and (5,-5) + ..(5,-5)..controls (-5,5) and (-5,5) + ..(5,-5)..controls (5,0.02791) and (4.99951,6.39217) + ..(3,6) + ..{curl 1}(-3,-6){curl 2989}..tension 0.75 and 1 + ..{0,4096}(5,-5){curl 1} + ..cycle + +Path at line 63, after choices: +(3,6)..controls (-3.01212,4.82085) and (-1.0424,-6.01257) + ..(5,-5)..controls (5,-5) and (5,-5) + ..(5,-5)..controls (5,-5) and (5,-5) + ..(5,-5)..controls (-5,5) and (-5,5) + ..(5,-5)..controls (5,0.02791) and (4.99951,6.39217) + ..(3,6)..controls (-2.44821,4.93144) and (-5.41408,-1.00029) + ..(-3,-6)..controls (-3.70045,-12.19485) and (5,-11.61679) + ..(5,-5)..controls (12.45406,-3.75087) and (10.41669,7.45464) + ..cycle + +>> path +! Improper `:=' will be changed to `='. +l.63 ...p2{0,1}&p2{_,'}..cycle:= + p +I didn't find a variable name at the left of the `:=', +so I'm going to pretend that you said `=' instead. + +{(path)=(unknown path p~4)} +{-(9)} +{((3.5001,7.00002))subpath(path)} +{((-9,9))subpath(path)} +{(path)=(unknown path p~6)} +{show} +>> Path at line 65: +(-2.5,2.5)..controls (-2.49893,2.49893) and (0.00107,-0.00107) + ..(5,-5)..controls (5,0.02791) and (4.99951,6.39217) + ..(3,6)..controls (-2.44821,4.93144) and (-5.41408,-1.00029) + ..(-3,-6)..controls (-3.70045,-12.19485) and (5,-11.61679) + ..(5,-5)..controls (5.0001,-4.99998) and (5.00021,-4.99997) + ..(5.00032,-4.99995) + +{((1,2))directiontime(path)} +>> 1 +{-(1.00002)} +{((1,-1.00002))directiontime(path)} +>> 3.24937 +Path at line 66, before choices: +(0,0)..controls (1,1) and (0,1) + ..(1,0) + +Path at line 66, after choices: +(0,0)..controls (1,1) and (0,1) + ..(1,0) + +{(unknown path p~3)=(path)} +{show} +Path at line 66, before choices: +(5,-5){-2896.30943,-2896.30934} + ..{1831.78674,3663.57385}cycle + +Path at line 66, after choices: +(5,-5)..controls (5,-5) and (5,-5) + ..cycle + +>> Path at line 66: +(5,-5)..controls (5,-5) and (5,-5) + ..cycle + +{((0.31416,1))subpath(path)} +{((1,1))directiontime(path)} +{(1)-(0.31416)} +{(0.27097)*(0.68584)} +{(0.31416)+(0.18584)} +>> 0.5 +{((0,0.25))subpath(path)} +{((0.25,1))subpath(path)} +Path at line 68, before choices: +(0,0)..controls (0.25,0.25) and (0.375,0.4375) + ..(0.4375,0.5625)..controls (0.625,0.9375) and (0.25,0.75) + ..(1,0) + +Path at line 68, after choices: +(0,0)..controls (0.25,0.25) and (0.375,0.4375) + ..(0.4375,0.5625)..controls (0.625,0.9375) and (0.25,0.75) + ..(1,0) + +! Missing `endtext' has been inserted. +<to be read again> + ; +l.68 ...~3)shifted begintext1,0; + +I found no right delimiter to match a left one. So I've +put one in, behind the scenes; this may fix the problem. + +{(path)shifted((1,0))} +{(unknown path p~5)=(path)} +{(2/3)*((xpart ',ypart '))} +{((0.66667xpart ',0.66667ypart '))zscaled((xpart ',ypart '))} +>> (0,0,xpart ',-ypart ',ypart ',xpart ') +! Transform components aren't all known. +<to be read again> + { +l.69 p~3:=2/3'zscaled'{ + p~3}..controls(2,2/3(3))and penoffset(... +I'm unable to apply a partially specified transformation +except to a fully known pair or transform. +Proceed, and I'll omit the transformation. + +>> 0.66667xpart ' +! Undefined x coordinate has been replaced by 0. +<to be read again> + { +l.69 p~3:=2/3'zscaled'{ + p~3}..controls(2,2/3(3))and penoffset(... +I need a `known' x value for this part of the path. +The value I found (see above) was no good; +so I'll try to keep going by using zero instead. +(Chapter 27 of The METAFONTbook explains that +you might want to type `I ???' now.) + +>> 0.66667ypart ' +! Undefined y coordinate has been replaced by 0. +<to be read again> + { +l.69 p~3:=2/3'zscaled'{ + p~3}..controls(2,2/3(3))and penoffset(... +I need a `known' y value for this part of the path. +The value I found (see above) was no good; +so I'll try to keep going by using zero instead. +(Chapter 27 of The METAFONTbook explains that +you might want to type `I ???' now.) + +>> path +! Undefined coordinates have been replaced by (0,0). +<to be read again> + } +l.69 p~3:=2/3'zscaled'{p~3} + ..controls(2,2/3(3))and penoffset(... +I need x and y numbers for this part of the path. +The value I found (see above) was no good; +so I'll try to keep going by using zero instead. +(Chapter 27 of The METAFONTbook explains that +you might want to type `I ???' now.) + +{(2/3)*(3)} +{(1/2)*(x)} +{((0.5x,-5))penoffset((0,1))} +>> (0.5x,-5) +>> (0,1) +! Not implemented: penoffset(unknown pair)of(pair). +<to be read again> + ( +l.69 ...enoffset(1/2x,y)of(0,1)( + 1,0); +I'm afraid I don't know how to apply that operation to that +combination of types. Continue, and I'll return the second +argument (see above) as the result of the operation. + +! Missing `..' has been inserted. +<to be read again> + ( +l.69 ...enoffset(1/2x,y)of(0,1)( + 1,0); +A path join command should end with two dots. + +Path at line 69, before choices: +(0,0)..controls (2,2) and (0,1) + ..(1,0) + +Path at line 69, after choices: +(0,0)..controls (2,2) and (0,1) + ..(1,0) + +{p~3:=path} +{show} +{reverse(path)} +{(path)intersectiontimes(path)} +>> (0.17227,0.28339) +{(0.17227)point(path)} +>> (0.71329,0.78188) +{(1)-(0.28339)} +{(0.71661)point(path)} +>> (0.7133,0.78189) +{show} +{(path)shifted((0.01,0))} +{(path)intersectiontimes(path)} +{xpart((1.47693,1.18973))} +{(1.47693)point(path)} +{(path)shifted((0.01,0))} +{(path)intersectiontimes(path)} +{ypart((1.47693,1.18973))} +{(1.18973)point(path)} +{((1.50499,0.71521))-((1.495,0.71521))} +>> (0.01,0) +{begingroup} +{interim} +{tracingedges:=1} +{-(1)} +{-(1.00002)} +{(-1)+-+(-1.00002)} +! Pythagorean subtraction 1+-+1.00002 has been replaced by 0. +l.73 ...es:=1; e[-1+-+ -1.00001] + =nullpicture; addto e1 also[[ +Since I don't take square roots of negative numbers, +I'm zeroing this one. Proceed, with fingers crossed. + +{nullpicture} +{(unknown picture e0)=(picture)} +{addto} +{begingroup} +{addto} +{(path)scaled(3)} +Path at line 74, before subdivision into octants: +(3,0)..controls (3.75,0.75) and (4.125,1.3125) + ..(4.3125,1.6875)..controls (4.875,2.8125) and (3.75,2.25) + ..(6,0)..controls (3.75,2.25) and (4.875,2.8125) + ..(4.3125,1.6875)..controls (4.125,1.3125) and (3.75,0.75) + ..cycle + +Cycle spec at line 74, after subdivision: +(3,0) % beginning in octant `NNE' + ..controls (3.75,0.75) and (4.125,1.3125) + ..(4.3125,1.6875) % segment 0 + ..controls (4.5,2.0625) and (4.5,2.25) + ..(4.5,2.25) % segment 1 +% entering octant `NNW' +% entering octant `WNW' +% entering octant `WSW' +% entering octant `SSW' +% entering octant `SSE' + ..controls (4.5,2.25) and (4.5,1.5) + ..(6,0) % segment 1 +% entering octant `ESE' +% entering octant `ENE' +% entering octant `NNE' +% entering octant `NNW' + ..controls (4.5,1.5) and (4.5,2.25) + ..(4.5,2.25) % segment 2 +% entering octant `WNW' +% entering octant `WSW' +% entering octant `SSW' + ..controls (4.5,2.25) and (4.5,2.0625) + ..(4.3125,1.6875) % segment 2 + ..controls (4.125,1.3125) and (3.75,0.75) + ..(3,0) % segment 3 +% entering octant `SSE' +% entering octant `ESE' +% entering octant `ENE' + & cycle + +Tracing edges at line 74: (weight 1) +(4,0)(4,1)(5,1)(5,3)(4,3)(4,1)(5,1)(5,0)(6,0)(6,1)(5,1)(5,3) +(4,3)(4,1)(3,1)(3,0). + +{(unknown picture e1)=(unknown picture e2)} +{(picture)=(unknown picture e1)} +{cull} +{nullpicture} +{endgroup} +{show} +{-(4095)} +{(picture)shifted((4089,-4095))} +>> Edge structure at line 75: +row -4093: | 4093+ 4094- +row -4094: | 4093+ 4094- +row -4095: | 4092+ 4093- 4094+ 4095- + +{-(4095)} +{(picture)shifted((-4095,4092))} +{-(3)} +{(picture)shifted((-3,0))} +>> Edge structure at line 75: +row 4094: -4094+ -4093- -4094+ -4093- | +row 4093: -4094+ -4093- -4094+ -4093- | +row 4092: -4095+ -4092- -4093+ -4094- | + +{-(4095)} +{(picture)shifted((4089,-4095))} +! Too far to shift. +<to be read again> + ]] +l.76 e2 shifted(4089,-4095)]] + ;addto e1 also e2 shifted(-2,$)... +I can't shift the picture as requested---it would +make some coordinates too large or too small. +Proceed, and I'll omit the transformation. + +>> Edge structure at line 76: +row 2: 4+ 5- 4+ 5- | +row 1: 4+ 5- 4+ 5- | +row 0: 3+ 6- 5+ 4- | + +{restoring tracingedges=32767.99998} +{endgroup} +{addto} +{-(2)} +{(picture)shifted((-2,-1))} +{-(4)} +{(picture)shifted((-4,-1))} +{e1:=picture} +{addto} +{(picture)rotated(89.999)} +! That transformation is too hard. +<to be read again> + + +l.77 ...e0 also e1rotated89.999+ + e1scaled$; show e0 xscaled-10... +I can apply complicated transformations to paths, +but I can only do integer operations on pictures. +Proceed, and I'll omit the transformation. + +{(picture)scaled(-1)} +{(picture)+(picture)} +{show} +{-(10)} +{(picture)xscaled(-10)} +{(picture)yscaled(2)} +{(picture)xscaled(82)} +! Scaled picture would be too big. +<to be read again> + yscaled +l.78 yscaled + 683;addto e1 doublepath (0,9) withweight-3 withwe... +I can't xscale the picture as requested---it would +make some coordinates too large or too small. +Proceed, and I'll omit the transformation. + +{(picture)yscaled(683)} +! Scaled picture would be too big. +<to be read again> + ; +l.78 yscaled683; + addto e1 doublepath (0,9) withweight-3 withwe... +I can't yscale the picture as requested---it would +make some coordinates too large or too small. +Proceed, and I'll omit the transformation. + +>> Edge structure at line 78: +row 5: -40- -50+ -40- -50+ | +row 4: -40- -50+ -40- -50+ | +row 3: -30+ 0- -10+ -20- -40- -50+ -40- -50+ | -10+ 0- +row 2: -30+ 0- -10+ -20- -40- -50+ -40- -50+ | -10+ 0- +row 1: 20- 10+ 20- 10+ -20+ -10- -20+ -10- -30- -60+ -50- -40+ | + -10+ -10+ 0- 0- 10+ 20- +row 0: 20- 10+ 20- 10+ -20+ -10- -20+ -10- -30- -60+ -50- -40+ | + -10+ -10+ 0- 0- 10+ 20- +row -1: 20- 10+ 20- 10+ -20+ -10- -20+ -10- | -20+ -10- 0+ 0+ 10- + 10- +row -2: 20- 10+ 20- 10+ -20+ -10- -20+ -10- | -20+ -10- 0+ 0+ 10- + 10- +row -3: 30- 0+ 10- 20+ | 0+ 10- +row -4: 30- 0+ 10- 20+ | 0+ 10- + +{addto} +{-(3)} +{turningnumber(path)} +! Weight must be -3, -2, -1, +1, +2, or +3. +<to be read again> + withpen +l.79 withpen + pencircle xscaled(oct"180"++1) rotated-angle(64... +I'll ignore the bad `with' clause and look for another. + +{pencircle} +{oct("180")} +>> "180" +! String contains illegal digits. +<to be read again> + ++ +l.79 ...ircle xscaled(oct"180"++ + 1) rotated-angle(64,$) shifte... +I zeroed out characters that weren't in the range 0..7. + +{(64)++(1)} +{(future pen)xscaled(64.00781)} +{angle((64,-1))} +{-(-0.89517)} +{(future pen)rotated(0.89517)} +{(future pen)shifted((9,8))} +Pen polygon at line 80 (newly created): +(9,7.5) + .. (37.5,8) + .. (41,8.5) + .. (9,8.5) + .. (-19.5,8) + .. (-23,7.5) + .. cycle + +Path at line 80, before choices: +(-1,-1){curl 1} + ..(1,0) + ..(1,1) + ..(-1,0) + ..{curl 1}cycle + +Path at line 80, after choices: +(-1,-1)..controls (-0.18568,-1.14464) and (0.62712,-0.73824) + ..(1,0)..controls (1.16457,0.32584) and (1.21637,0.71506) + ..(1,1)..controls (0.46898,1.69931) and (-0.7587,1.2167) + ..(-1,0)..controls (-1.06546,-0.33012) and (-1.06546,-0.66988) + ..cycle + +{makepen(path)} +{(future pen)xscaled(4095.49998)} +Pen polygon at line 80 (newly created): +(4095.49998,0) + .. (4095.49998,1) + .. (-4095.49998,0) + .. (-4095.49998,-1) + .. cycle + +Path at line 80, before subdivision into octants: +(0,9)..controls (0,9) and (0,9) + ..cycle + +! Curve out of range. +<to be read again> + ; +l.80 ...cycle)xscaled4095.49999; + +At least one of the coordinates in the path I'm about to +digitize was really huge (potentially bigger than 4095). +So I've cut it back to the maximum size. +The results will probably be pretty wild. + +Cycle spec at line 80, after subdivision: +(0,0) % beginning in octant `ENE' +% entering octant `NNE' +% entering octant `NNW' +% entering octant `WNW' +% entering octant `WSW' +% entering octant `SSW' +% entering octant `SSE' +% entering octant `ESE' + & cycle + +Tracing edges at line 80: (weight -3) +@ Octant ENE (2 offsets), from (-4095.49998,-1) to (4095.49998,0) +@ transition line 0, from (-4095.49998,-1) to (-4095.49998,-1) +@ transition line 1, from (-4095.49998,-1) to (4095.49998,0) +@ transition line 2, from (4095.49998,0) to (4095.49998,0) +(0,-1) +@ Octant NNE (1 offset), from (4095.49998,0) to (4095.49998,1) +@ transition line 2, from (4095.49998,0) to (4095.49998,0) +@ transition line 1, from (4095.49998,0) to (4095.49998,1) +(0,0)(4095,0) +@ Octant NNW (0 offsets), from (4095.49998,1) to (4095.49998,1) +@ transition line 0, from (4095.49998,1) to (4095.49998,1) +@ Octant WNW (0 offsets), from (4095.49998,1) to (4095.49998,1) +@ transition line 1, from (4095.49998,1) to (4095.49998,1) +@ Octant WSW (2 offsets), from (4095.49998,1) to (-4095.49998,0) +@ transition line 0, from (4095.49998,1) to (4095.49998,1) +@ transition line 1, from (4095.49998,1) to (-4095.49998,0) +@ transition line 2, from (-4095.49998,0) to (-4095.49998,0) +(4095,1)(0,1) +@ Octant SSW (1 offset), from (-4095.49998,0) to (-4095.49998,-1) +@ transition line 2, from (-4095.49998,0) to (-4095.49998,0) +@ transition line 1, from (-4095.49998,0) to (-4095.49998,-1) +(0,0)(-4095,0) +@ Octant SSE (0 offsets), from (-4095.49998,-1) to (-4095.49998,-1) +@ transition line 0, from (-4095.49998,-1) to (-4095.49998,-1) +@ Octant ESE (0 offsets), from (-4095.49998,-1) to (-4095.49998,-1) +@ transition line 1, from (-4095.49998,-1) to (-4095.49998,-1) +(-4095,-1). + +{show} +>> Edge structure at line 81: +row 1: | 0+ 1- +row 0: 0--- 4095+++ -2+ -1- -2+ -1- | 0+ 1- +row -1: -4095--- 0+++ -2+ -1- -2+ -1- | -1+ 0- 1+ 2- +row -2: -3+ 0- -1+ -2- | + +{totalweight(picture)} +>> -0.37476 +{charcode:=5} +{chardp:=5} +{-(1.5)} +{xoffset:=-1.5} +{shipout} +[5] +Edge structure at line 81 (just shipped out): +row 1: | -1+ 0- +row 0: | -3+ -3+ -2- -2- -1--- -1+ 0- 4094+++ +row -1: | -4096--- -3+ -3+ -2- -2- -2+ -1- -1+++ 0+ 1- +row -2: | -4+ -3- -2+ -1- + +{showstats} +Memory usage 1084&202 (749 still untouched) +String usage 24&92 (1863&21408 still untouched) +{addto} +{(path)yscaled(0.01666)} +Path at line 82, before subdivision into octants: +(0,0)..controls (15,0.06665) and (-15,-0.19995) + ..(4,0)..controls (-15,-0.19995) and (15,0.06665) + ..cycle + +Cycle spec at line 82, after subdivision: +(0,0) % beginning in octant `ENE' + ..controls (1.74272,0.00775) and (2.87802,0.01099) + ..(3.55333,0.01099) % segment 0 +% entering octant `ESE' + ..controls (4.12251,0.01099) and (4.36491,0.00868) + ..(4.36877,0.00482) % segment 0 +% entering octant `SSE' + ..controls (4.3688,0.00479) and (4.36882,0.00476) + ..(4.36882,0.00473) % segment 0 +% entering octant `SSW' + ..controls (4.36882,0.0047) and (4.3688,0.00467) + ..(4.36877,0.00464) % segment 0 +% entering octant `WSW' + ..controls (4.34875,-0.01538) and (-1.88759,-0.07579) + ..(-2.48894,-0.07579) % segment 0 +% entering octant `WNW' + ..controls (-2.5191,-0.07579) and (-2.5351,-0.07564) + ..(-2.53542,-0.07532) % segment 0 +% entering octant `NNW' +% entering octant `NNE' +% entering octant `ENE' + ..controls (-2.53209,-0.07199) and (-0.88672,-0.05144) + ..(4,0) % segment 0 +% entering octant `NNE' +% entering octant `NNW' +% entering octant `WNW' +% entering octant `WSW' + ..controls (-0.88672,-0.05144) and (-2.5321,-0.072) + ..(-2.53542,-0.07532) % segment 1 +% entering octant `SSW' +% entering octant `SSE' +% entering octant `ESE' + ..controls (-2.53511,-0.07562) and (-2.5191,-0.07579) + ..(-2.48894,-0.07579) % segment 1 +% entering octant `ENE' + ..controls (-1.88759,-0.07579) and (4.34877,-0.01537) + ..(4.36877,0.00464) % segment 1 +% entering octant `NNE' + ..controls (4.3688,0.00467) and (4.36882,0.0047) + ..(4.36882,0.00473) % segment 1 +% entering octant `NNW' + ..controls (4.36882,0.00476) and (4.3688,0.00479) + ..(4.36877,0.00482) % segment 1 +% entering octant `WNW' + ..controls (4.36491,0.00868) and (4.12251,0.01099) + ..(3.55333,0.01099) % segment 1 +% entering octant `WSW' + ..controls (2.87802,0.01099) and (1.74272,0.00775) + ..(0,0) % segment 1 +% entering octant `SSW' +% entering octant `SSE' +% entering octant `ESE' + & cycle + +Tracing edges at line 82: (weight 1) +(No new edges added.) + +{(picture)yscaled(0)} +{e3:=picture} +{autorounding:=2} +{addto} +Path at line 83, before choices: +(0.5,0){curl 1} + ..{curl 1}(3.5,1.5) + +Path at line 83, after choices: +(0.5,0)..controls (1.5,0.5) and (2.5,1) + ..(3.5,1.5) + +Path at line 83, before subdivision into octants: +(0.5,0)..controls (1.5,0.5) and (2.5,1) + ..(3.5,1.5)..controls (2.5,1) and (1.5,0.5) + ..cycle + +Cycle spec at line 83, after subdivision and double autorounding: +(0.5,0) % beginning in octant `ENE' + ..controls (1.5,0.5) and (2.5,1) + ..(3.5,1.5) % segment 0 +% entering octant `NNE' +% entering octant `NNW' +% entering octant `WNW' +% entering octant `WSW' + ..controls (2.5,1) and (1.5,0.5) + ..(0.5,0) % segment 1 +% entering octant `SSW' +% entering octant `SSE' +% entering octant `ESE' + & cycle + +Tracing edges at line 83: (weight 2) +(2,0)(2,1)(4,1)(4,2)(4,1)(2,1)(2,0). + +{tracingspecs:=0} +Path at line 84, before choices: +(1,1) + ..cycle + +Path at line 84, after choices: +(1,1)..controls (1,1) and (1,1) + ..cycle + +{makepen(path)} +{(future pen)yscaled(1.5)} +Pen polygon at line 84 (newly created): +(1,1.5) + .. cycle + +{q:=pen} +{((-1,yy))rotated((8,1,5,-5,-5,5))} +>> (8,1,5,-5,-5,5) +! Improper transformation argument. +<to be read again> + { +l.85 p~8=(($,yy)rotated p{ + 0,1}..{0,$}(1,0){0,$}..cycle)scaled... +The expression shown above has the wrong type, +so I can't transform anything using it. +Proceed, and I'll omit the transformation. + +>> yy +! Undefined y coordinate has been replaced by 0. +<to be read again> + { +l.85 p~8=(($,yy)rotated p{ + 0,1}..{0,$}(1,0){0,$}..cycle)scaled... +I need a `known' y value for this part of the path. +The value I found (see above) was no good; +so I'll try to keep going by using zero instead. +(Chapter 27 of The METAFONTbook explains that +you might want to type `I ???' now.) + +Path at line 85, before choices: +(-1,0){0,4096} + ..{0,-4096}(1,0){0,-4096} + ..{0,4096}cycle + +Path at line 85, after choices: +(-1,0)..controls (-1,1.33333) and (1,1.33333) + ..(1,0)..controls (1,-1.33333) and (-1,-1.33333) + ..cycle + +{(path)scaled(2)} +{(path)shifted((1000.49,9))} +{(unknown path p~8)=(path)} +{turningcheck:=1} +{addto} +>> (8,1,5,-5,-5,5) +! Improper type. +<to be read again> + withpen +l.86 ...n q withweight p withpen + cycle p; +Next time say `withweight <known numeric expression>'; +I'll ignore the bad `with' clause and look for another. + +{cycle((8,1,5,-5,-5,5))} +>> false +! Improper type. +<to be read again> + ; +l.86 ...eight p withpen cycle p; + +Next time say `withpen <known pen expression>'; +I'll ignore the bad `with' clause and look for another. + +Tracing edges at line 86: (weight 1) +@ Octant NNE (0 offsets), from (999,10.5) to (999.15451,11.65451) +@ transition line 1, from (999.15451,11.65451) to (999.15451,11.65451) +(999,11) +@ Octant ENE (0 offsets), from (999.15451,11.65451) to (1001,12) +@ transition line 0, from (999.15451,11.65451) to (999.15451,11.65451) +@ Octant ESE (0 offsets), from (1001,12) to (1002.8455,11.6545) +@ transition line 1, from (1002.8455,11.6545) to (1002.8455,11.6545) +@ Octant SSE (0 offsets), from (1002.8455,11.6545) to (1003,10.5) +@ transition line 0, from (1002.8455,11.6545) to (1002.8455,11.6545) +(999,12)(1003,12) +@ Octant SSW (0 offsets), from (1003,10.5) to (1002.84549,9.34549) +@ transition line 1, from (1002.84549,9.34549) to (1002.84549,9.34549) +@ Octant WSW (0 offsets), from (1002.84549,9.34549) to (1001,9) +@ transition line 0, from (1002.84549,9.34549) to (1002.84549,9.34549) +@ Octant WNW (0 offsets), from (1001,9) to (999.1545,9.3455) +@ transition line 1, from (999.1545,9.3455) to (999.1545,9.3455) +@ Octant NNW (0 offsets), from (999.1545,9.3455) to (999,10.5) +@ transition line 0, from (999.1545,9.3455) to (999.1545,9.3455) +(1003,9)(999,9)(999,11). + +Tracing edges at line 86: (weight 1) +@ Octant SSE (0 offsets), from (999,10.5) to (999.15451,9.34549) +@ transition line 0, from (999,10.5) to (999,10.5) +(999,11) +@ Octant ESE (0 offsets), from (999.15451,9.34549) to (1001,9) +@ transition line 1, from (1001,9) to (1001,9) +@ Octant ENE (0 offsets), from (1001,9) to (1002.8455,9.3455) +@ transition line 0, from (1001,9) to (1001,9) +@ Octant NNE (0 offsets), from (1002.8455,9.3455) to (1003,10.5) +@ transition line 1, from (1003,10.5) to (1003,10.5) +(999,9)(1003,9) +@ Octant NNW (0 offsets), from (1003,10.5) to (1002.84549,11.65451) +@ transition line 0, from (1003,10.5) to (1003,10.5) +@ Octant WNW (0 offsets), from (1002.84549,11.65451) to (1001,12) +@ transition line 1, from (1001,12) to (1001,12) +@ Octant WSW (0 offsets), from (1001,12) to (999.1545,11.6545) +@ transition line 0, from (1001,12) to (1001,12) +@ Octant SSW (0 offsets), from (999.1545,11.6545) to (999,10.5) +@ transition line 1, from (999,10.5) to (999,10.5) +(1003,12)(999,12)(999,11). + +{begingroup} +{interim} +{(xx)=(0.1)} +## xx=0.1 +{autorounding:=0.1} +{addto} +Tracing edges at line 87: (weight -2) +@ Octant NNE (0 offsets), from (999,10.5) to (999.38197,11.42706) +@ transition line 1, from (999.38197,11.42706) to (999.38197,11.42706) +@ Octant ENE (0 offsets), from (999.38197,11.42706) to (1001,12) +@ transition line 0, from (999.38197,11.42706) to (999.38197,11.42706) +(999,11) +@ Octant ESE (0 offsets), from (1001,12) to (1002.61804,11.42705) +@ transition line 1, from (1002.61804,11.42705) to (1002.61804,11.42705) +(999,12)(1003,12) +@ Octant SSE (0 offsets), from (1002.61804,11.42705) to (1003,10.5) +@ transition line 0, from (1002.61804,11.42705) to (1002.61804,11.42705) +@ Octant SSW (0 offsets), from (1003,10.5) to (1002.61803,9.57294) +@ transition line 1, from (1002.61803,9.57294) to (1002.61803,9.57294) +@ Octant WSW (0 offsets), from (1002.61803,9.57294) to (1001,9) +@ transition line 0, from (1002.61803,9.57294) to (1002.61803,9.57294) +@ Octant WNW (0 offsets), from (1001,9) to (999.38196,9.57295) +@ transition line 1, from (999.38196,9.57295) to (999.38196,9.57295) +(1003,9)(999,9) +@ Octant NNW (0 offsets), from (999.38196,9.57295) to (999,10.5) +@ transition line 0, from (999.38196,9.57295) to (999.38196,9.57295) +(999,11). + +{restoring autorounding=2} +{endgroup} +{-(14.5)} +{charext:=-14.5} +{chardp:=-14.5} +{chardx:=-14.5} +{shipout} +{-(picture)} +{(picture)-(picture)} +{-(picture)} +{turningnumber(path)} +{(6)*(-1)} +{(picture)shifted((0,-6))} +{(picture)+(picture)} +[5.-14] +Edge structure at line 88 (just shipped out): +row 11: | 998- 998+ 998++ 1002-- 1002- 1002+ +row 10: | 998- 998+ 998++ 1002-- 1002- 1002+ +row 9: | 998- 998+ 998++ 1002-- 1002- 1002+ +row 5: | 998- 998+ 998++ 1002-- 1002- 1002+ +row 4: | 998- 998+ 998++ 1002-- 1002- 1002+ +row 3: | 998- 998+ 998++ 1002-- 1002- 1002+ +row 2: | 3+ 3+ 3+ 3+ 4- 4- 4- 4- +row 1: | -1+ -1+ 0- 0- 1+ 2- 3+ 3+ 3+ 3+ 4- 4- 4- 4- +row 0: | -3+ -3+ -3+ -2- -2- -2- -1+ -1+ 0- 0- 0+ 0+ 1- 1- 2+ 2+ + 3- 3- 4+ 4+ 5- 5- +row -1: | -3+ -3+ -2- -2- -2+ -2+ -1- -1- 0+ 0+ 0+ 1- 1- 1- +row -2: | -4+ -3- -2+ -2+ -1- -1- +row -4: | 3+ 3+ 4- 4- +row -5: | 3+ 3+ 4- 4- +row -6: | 2+ 3- 4+ 5- + +Path at line 89, before choices: +(0,0){curl 1} + ..(1,0.5) + ..(5,1.5) + ..(7,2.5) + ..(12,3.5) + ..{curl 1}(13,4) + +Path at line 89, after choices: +(0,0)..controls (0.3153,0.20053) and (0.6504,0.36807) + ..(1,0.5)..controls (2.29114,0.98723) and (3.72412,0.97192) + ..(5,1.5)..controls (5.68967,1.78545) and (6.30771,2.22081) + ..(7,2.5)..controls (8.58867,3.1407) and (10.3946,2.90645) + ..(12,3.5)..controls (12.3506,3.62962) and (12.68594,3.7973) + ..(13,4) + +{(unknown path p~9)=(path)} +{addto} +Tracing edges at line 89: (weight 1) +(1,0)(1,1)(5,1)(5,2)(7,2)(7,3)(12,3)(12,4)(12,3)(7,3)(7,2)(5,2) +(5,1)(1,1)(1,0). + +{smoothing:=1} +{addto} +Tracing edges at line 90: (weight 1) +(1,0)(1,1)(4,1)(4,2)(8,2)(8,3)(12,3)(12,4)(12,3)(8,3)(8,2)(4,2) +(4,1)(1,1)(1,0). + +{addto} +{-(4095)} +Path at line 91, before choices: +(-4095,0){curl 1}..tension 0.75 and 999 + ..{curl 1}(0,2) + +Path at line 91, after choices: +(-4095,0)..controls (-2275,0.88889) and (-1.36636,1.99933) + ..(0,2) + +Tracing edges at line 91: (weight 1) +(-3071,0)(-3071,1)(-1024,1)(-1024,2)(-1024,1)(-3071,1)(-3071,0). + +{show} +{-(90)} +{(picture)rotated(-90)} +>> Edge structure at line 91: + +{(picture)+(picture)} +{(90)*(-1)} +{(picture)rotated(-90)} +{(picture)rotated(90)} +>> Edge structure at line 91: +row 2: | 4+++ 4+ 5--- 5- +row 1: | 0+++ 0+ 1--- 1- 2++ 3-- 4+++ 4+ 5--- 5- +row 0: | -2+++ -2+++ -1--- -1--- 0+++ 0+ 2--- 2- 3++ 4-- 5++ 6-- +row -1: | -2+++ -2+ 0--- 0- 1+++ 1+++ 2--- 2--- +row -2: | -3++ -2-- -1+++ -1+ 0--- 0- + +{if} +{if} +{elseif} +! Missing `:' has been inserted. +<inserted text> + : +<to be read again> + elseif +l.92 if "a" if "ab">"b" elseif + path reverse (3,4): >="aa":foo... + +{("ab")>("b")} +{false} +{reverse((3,4))} +{path(path)} +{true} +{("a")>=("aa")} +{false} +{if} +{((xpart ',ypart '))-((1,yy))} +{((xpart '-1,linearform))<((xpart ',ypart '))} +{true} +{fi} +{else} +! Extra else. +l.93 ... if '-(1,yy)<': :fi else + def dup text t=[[t;save endd... +I'm ignoring this; it doesn't match any if. + +{def} +{def} +{def} + +||<tertiary>->show.substring(EXPR0)of("a" +(EXPR0)<-(2,-1) +{show} +{("a")&("bc")} +{((2,-1))substring("abc")} +>> "ba" +{tertiarydef} +{def} +{show} +{((23.3,4.5))subpath(path)} +Path at line 100, before choices: +(0,0){curl 2} + ..(13,4)..controls (12.84297,3.89865) and (12.68063,3.80606) + ..(12.51372,3.72261){curl 3} + ..{curl 4}(-1,-1){curl 4} + ..{curl 2}cycle + +Path at line 100, after choices: +(0,0)..controls (-40.15552,-36.7088) and (58.71173,33.50317) + ..(13,4)..controls (12.84297,3.89865) and (12.68063,3.80606) + ..(12.51372,3.72261)..controls (8.00914,2.1484) and (3.50458,0.5742) + ..(-1,-1)..controls (-0.66667,-0.66667) and (-0.33333,-0.33333) + ..cycle + +>> Path at line 100: +(0,0)..controls (-40.15552,-36.7088) and (58.71173,33.50317) + ..(13,4)..controls (12.84297,3.89865) and (12.68063,3.80606) + ..(12.51372,3.72261)..controls (8.00914,2.1484) and (3.50458,0.5742) + ..(-1,-1)..controls (-0.66667,-0.66667) and (-0.33333,-0.33333) + ..cycle + +{numspecial} +{(2)+(3)} + +++->[[dup.showtoken(EXPR0);]];def.x.expr.z.of(EXPR1)=z.enddef;texts(x=(( +EXPR1)+0)(EXPR1)+(EXPR1))("xx",foo((EXPR0)))=0]] +(EXPR0)<-path +(EXPR1)<-5 +{begingroup} + +dup<text>->[[(TEXT0);save +(TEXT0)<-showtoken(path) +{begingroup} +{showtoken} +> (path) +{save} +{restoring ;} +{endgroup} +{def} +! Missing symbolic token inserted. +<inserted text> + INACCESSIBLE +++->...]];def.x.expr.z.of(EXPR1) + =z.enddef;texts(x=((EXPR1)+0)... +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +Sorry: You can't redefine a number, string, or expr. +I've inserted an inaccessible symbol so that your +definition will be completed without mixing me up too badly. + + +texts(TEXT0)(TEXT1)<expr>->for.n:=,for.n"yy":n,length.if.false:endfor(TE +XT1),(TEXT0),:if.string.n:forsuffixes.n=foo1,[foo(n)],':show(TEXT0),(TEX +T1)|(n;exitif.not('<='+((EXPR2),yy))endfor.for.m= :+endfor.for.m=alpha.s +tep-1.1 3$:+m.endfor.fi.endfor +(TEXT0)<-x=((5)+0)(5)+(5) +(TEXT1)<-"xx",foo((path)) +(EXPR2)<-0 +{for} +{for} +! Missing `=' has been inserted. +<to be read again> + "yy" +texts->for.n:=,for.n"yy" + :n,length.if.false:endfor(TEXT1),(TEX... +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +The next thing in this loop should have been `=' or `:='. +But don't worry; I'll pretend that an equals sign +was present, and I'll look for the values next. + +{loop value="yy"} +{if} +{false} +{false} +! Incomplete if; all text was ignored after line 100. +<inserted text> + fi +<to be read again> + ENDFOR +<for("yy")> ....if.false: ENDFOR + +texts->...length.if.false:endfor + (TEXT1),(TEXT0),:if.string.n:... +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +A forbidden `outer' token occurred in skipped text. +This kind of error happens when you say `if...' and forget +the matching `fi'. I've inserted a `fi'; this might work. + +{[repeat the loop]} +{length("xx")} + +foo(TEXT2)->begingroup(TEXT2)endgroup +(SUFFIX0)<- +(SUFFIX1)<-foo +(TEXT2)<-(path) +{begingroup} +{endgroup} + +x<expr>of<primary>->(EXPR0) +{(5)+(0)} +(EXPR0)<-5 +! Missing `of' has been inserted for x. +<to be read again> + (5) +<argument> x=((5)+0)(5) + +(5) +texts->...:endfor(TEXT1),(TEXT0) + ,:if.string.n:forsuffixes.n=f... +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +I've got the first argument; will look now for the other. + +(EXPR1)<-5 +{(5)+(5)} +{loop value="yy"} +{if} +{string("yy")} +{true} +{forsuffixes} +! Missing symbolic token inserted. +<inserted text> + INACCESSIBLE +<for("yy")> ...orsuffixes(EXPR0) + =foo1,[foo((EXPR0))],':show.x... +texts->...3$:+m.endfor.fi.endfor + +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +Sorry: You can't redefine a number, string, or expr. +I've inserted an inaccessible symbol so that your +definition will be completed without mixing me up too badly. + + +foo(TEXT2)->begingroup(TEXT2)endgroup +(SUFFIX0)<- +(SUFFIX1)<-foo +(TEXT2)<-("yy") +{begingroup} +{endgroup} +>> "yy" +! Improper subscript has been replaced by zero. +<for("yy")> ...o1,[foo((EXPR0))] + ,':show.x=((5)+0)(5)+(5),"xx"... +texts->...3$:+m.endfor.fi.endfor + +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +A bracketed subscript must have a known numeric value; +unfortunately, what I found was the value that appears just +above this error message. So I'll try a zero subscript. + +{loop value=foo1} +{show} + +x<expr>of<primary>->(EXPR0) +{(5)+(0)} +(EXPR0)<-5 +! Missing `of' has been inserted for x. +<to be read again> + (5) +<for(foo1)> show.x=((5)+0)(5) + +(5),"xx",foo((path))|(("yy");ex... +<for("yy")> ...'+((0),yy))endfor + .for.m= :+endfor.for.m=alpha.... +texts->...3$:+m.endfor.fi.endfor + +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +I've got the first argument; will look now for the other. + +(EXPR1)<-5 +{(5)+(5)} +>> 10 +>> "xx" +foo(TEXT2)->begingroup(TEXT2)endgroup +(SUFFIX0)<- +(SUFFIX1)<-foo +(TEXT2)<-(path) +{begingroup} +{endgroup} + +|<suffix>->,(SUFFIX0) +! Missing `)' has been inserted. +<to be read again> + ("yy") +<for(foo1)> ...o((path))|(("yy") + ;exitif.not('<='+((0),yy)) EN... +<for("yy")> ...'+((0),yy))endfor + .for.m= :+endfor.for.m=alpha.... +texts->...3$:+m.endfor.fi.endfor + +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +I've gotten to the end of the macro parameter list. +You might want to delete some tokens before continuing. + +(SUFFIX0)<- +>> Path at line 100: +(0,0)..controls (15,4) and (-15,-12) + ..(4,0) + +>> "yy" +{exitif} +{((xpart ',ypart '))+((0,yy))} +{((xpart ',ypart '))<=((xpart ',linearform))} +>> -yy +! Unknown relation will be considered false. +<to be read again> + ) +<for(foo1)> ...ot('<='+((0),yy)) + ENDFOR +<for("yy")> ...'+((0),yy))endfor + .for.m= :+endfor.for.m=alpha.... +texts->...3$:+m.endfor.fi.endfor + +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +Oh dear. I can't decide if the expression above is positive, +negative, or zero. So this comparison test won't be `true'. + +{[repeat the loop]} +{loop value=0} +{not(false)} +{true} +{for} +{for} +>> 0.5p3~ +! Improper initial value has been replaced by 0. +<to be read again> + step +<for("yy")> ....for.m=alpha.step + -1.1 3$:+m.endfor.fi ENDFOR +texts->...3$:+m.endfor.fi.endfor + +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +When you say `for x=a step b until c', +the initial value `a' and the step size `b' +and the final value `c' must have known numeric values. +I'm zeroing this one. Proceed, with fingers crossed. + +{-(1.1)} +! Missing `until' has been inserted. +<to be read again> + 3 +<for("yy")> ...=alpha.step-1.1 3 + $:+m.endfor.fi ENDFOR +texts->...3$:+m.endfor.fi.endfor + +<to be read again> + ]] +<to be read again> + ; +l.100 ...cle;numspecial p~++2+3; + [[ +I assume you meant to say `until' after `step'. +So I'll look for the final value and colon next. + +{(3)*(-1)} +{loop value=0} +{[repeat the loop]} +{loop value=-1.1} +{+(0)} +{[repeat the loop]} +{loop value=-2.20001} +{(0)+(-1.1)} +{[repeat the loop]} +{fi} +{[repeat the loop]} +{loop value=2} +{if} +{string(2)} +{false} +{[repeat the loop]} +{loop value=path} +{if} +{string(path)} +{false} +{[repeat the loop]} +{loop value=10} +{if} +{string(10)} +{false} +{[repeat the loop]} +{(-1.1)+(-2.20001)} +{endgroup} +{begingroup} +{let} +{save} +{def} +{def} + +texts->input +{input} +(trap.mf +if->endinput? +{endinput} +{if} +{known(0)} +{not(true)} +{false} +) +! Incomplete if; all text was ignored after line 2. +<inserted text> + fi +l.101 ...input enddef;texts trap + ]]; +The file ended while I was skipping conditional text. +This kind of error happens when you say `if...' and forget +the matching `fi'. I've inserted a `fi'; this might work. + +{restoring \} +{restoring if} +{endgroup} + +dup<text>->[[(TEXT0);save +Runaway text? +[[def.texts.secondary.x=primarydef.y++y=x@y.enddef;showtoken ETC. +! Forbidden token found while scanning a text argument. +<inserted text> + endgroup +<to be read again> + \ +l.102 ...showtoken++;x enddef]]\ + ; +It seems that a right delimiter was left out, +causing me to read past where you wanted me to stop. +I'll try to recover; but if the error is serious, +you'd better type `E' or `X' now and fix your file. + +(TEXT0)<-[[def.texts.secondary.x=primarydef.y++y=x@y.enddef;showtoken++; +x.enddef]] +{begingroup} +{begingroup} +{def} +{endgroup} +{save} +! Missing symbolic token inserted. +<inserted text> + INACCESSIBLE +<to be read again> + \ +l.102 ...showtoken++;x enddef]]\ + ; +Sorry: You can't redefine my error-recovery tokens. +I've inserted an inaccessible symbol so that your +definition will be completed without mixing me up too badly. + +{\} +{proofing:=1} + +texts<secondary>->primarydef.y++y=(EXPR0)@y.enddef;showtoken++;(EXPR0) +(EXPR0)<-"a" +{primarydef} +{showtoken} +> ++=primarydef'd macro: +("a")@(EXPR1) +{("a")&("b")} +ab +texts<secondary>->primarydef.y++y=(EXPR0)@y.enddef;showtoken++;(EXPR0) +{(1.00002)*(a1)} +{-(1.00002a1)} +(EXPR0)<--1.00002a1 +{primarydef} +{showtoken} +> ++=primarydef'd macro: +(-1.00002a1)@(EXPR1) +{(a2)+(a3)} +{(linearform)+(a4)} +{(linearform)+(a5)} +{(linearform)+(a6)} +{-(linearform)} +{(-1.00002a1)=(linearform)} +## a1=0.99998a6+0.99998a5+0.99998a4+0.99998a3+0.99998a2 +{-((a3,a2))} +{((-a3,-a2))/(0.99998)} +{(a4)+(a5)} +{begingroup} +{showdependencies} +a1=0.99998a6+0.99998a5+0.99998a4+0.99998a3+0.99998a2 +alpha=0.5p3~ +{endgroup} +{(linearform)+(a6)} +{(a3)+(a4)} +{(linearform)+(a5)} +{(linearform)+(a6)} +{-((linearform,linearform))} +{((-1.00002a3,-1.00002a2))=((linearform,linearform))} +## a2=0.99998a6+0.99998a5+0.99998a4+0.99998a3 +## a3=0.99998a6+0.99998a5+0.99998a4 +{restoring INACCESSIBLE} +{endgroup} +{(1.00002)*(0.25a4*4)} +{(0.25a4*4)+(1)} +{(0.25a5*4)+(0.25a6*4)} +{(0.25a4*4+1)=(linearform)} +## a4*4=0.99998a6*4+0.99998a5*4-3.99994 +{(0.9)*(0.5p3~)} +{(0.45p3~)+(7)} +{alpha:=0.45p3~+7} +## alpha=0.45p3~+7 +{showdependencies} +alpha=0.45p3~+7 +a4=0.25a6*4+0.25a5*4-0.99998 +a3=0.49998a6*4+0.49998a5*4-0.99997 +a2=0.99997a6*4+0.99997a5*4-1.99992 +a1=1.99992a6*4+1.99992a5*4-3.99982 +{(0.66667)-(0.25a6*4)} +{(0.25a6*4)=(-0.25a6*4+0.66667)} +## a6*4=1.33334 +{(0.25a5*4)=(0.33333)} +## a5*4=1.33331 +#### a4=-0.33333 +#### a3=0.33333 +#### a2=0.66664 +#### a1=1.33328 +{cull} +{(4)*(0.33333)} +{chardp:=27} +{charcode:=27} +{openwindow} +! Improper `openwindow'. +<to be read again> + ; +l.107 ...) to (0,0) at "whoops"; + addto p; shipout p; cull p; +Say `openwindow k from (r0,c0) to (r1,c1) at (x,y)', +where all quantities are known and k is between 0 and 15. + +{addto} +>> (8,1,5,-5,-5,5) +! Not a suitable variable. +<to be read again> + ; +l.107 ...) at "whoops"; addto p; + shipout p; cull p; +At this point I needed to see the name of a picture variable. +(Or perhaps you have indeed presented me with one; I might +have missed it, if it wasn't followed by the proper token.) +So I'll not change anything just now. + +{shipout} +! Variable p is the wrong type (transform). +<to be read again> + ; +l.107 ...s"; addto p; shipout p; + cull p; +I was looking for a "known" picture variable. +So I'll not change anything just now. + +{cull} +>> (8,1,5,-5,-5,5) +! Not a suitable variable. +<to be read again> + ; +l.107 ...o p; shipout p; cull p; + +At this point I needed to see the name of a picture variable. +(Or perhaps you have indeed presented me with one; I might +have missed it, if it wasn't followed by the proper token.) +So I'll not change anything just now. + +{openwindow} +{-(0.5)} + +Calling BLANKRECTANGLE(0,0,0,0) +Calling UPDATESCREEN +{special} +>> (8,1,5,-5,-5,5) +! Unsuitable expression. +<to be read again> + ; +l.108 ...$) at (0,0); special p; + numspecial "p"; +The expression shown above has the wrong type to be output. + +{numspecial} +>> "p" +! Unsuitable expression. +<to be read again> + ; +l.108 ...cial p; numspecial "p"; + +The expression shown above has the wrong type to be output. + +{openwindow} +{(32)*(1024)} +! Arithmetic overflow. +l.109 ....49999 from (0,32*1024) + to (1,31*1057) at (0,0); shi... +Uh, oh. A little while ago one of the quantities that I was +computing got too large, so I'm afraid your answers will be +somewhat askew. You'll probably have to adopt different +tactics next time. But I shall try to carry on anyway. + +{(31)*(1057)} + +Calling BLANKRECTANGLE(100,100,0,1) +Calling UPDATESCREEN +{shipout} +[27.-14] +Edge structure at line 109 (just shipped out): +row 0: | -3++ -2-- -1++ 4094-- +row -1: | -4096++ -3-- -2++ -1-- + +{openwindow} +Path at line 110, before choices: +(0,0) + +Path at line 110, after choices: +(0,0) + +{length(path)} + +Calling BLANKRECTANGLE(0,2,0,4) +Calling UPDATESCREEN +{openwindow} +{length((-1,0))} +{-(5)} + +Calling BLANKRECTANGLE(1,10,1,3) +Calling UPDATESCREEN +{display} +{nullpicture} +>> picture +! Not a suitable variable. +<to be read again> + ; +l.112 display nullpicture; + display p inwindow 3; display p in... +At this point I needed to see the name of a picture variable. +(Or perhaps you have indeed presented me with one; I might +have missed it, if it wasn't followed by the proper token.) +So I'll not change anything just now. + +{display} +>> 3 +! Bad window number. +<to be read again> + ; +l.112 ...; display p inwindow 3; + display p inwindow 6; +It should be the number of an open window. + +{display} +! Variable p is the wrong type (transform). +<to be read again> + ; +l.112 ...; display p inwindow 6; + +I was looking for a "known" picture variable. +So I'll not change anything just now. + +{display} + +Calling BLANKRECTANGLE(1,10,1,3) +Calling PAINTROW(2,1;4,5,6,10) +Calling UPDATESCREEN +{cull} +! Enormous number has been reduced. +l.113 ...opping (0.1,4095.999999 + ) withweight 3.5 +I can't handle numbers bigger than about 4095.99998; +so I've changed your constant to that maximum amount. + +! Weight must be -3, -2, -1, +1, +2, or +3. +<to be read again> + withweight +l.114 withweight + -3.5; display e0 inwindow 5.5; addto e0 also ... +I'll ignore the bad `with' clause and look for another. + +{-(3.5)} +! Bad culling amounts. +<to be read again> + ; +l.114 withweight-3.5; + display e0 inwindow 5.5; addto e0 also ... +Always cull by known amounts that exclude 0. + +{display} + +Calling BLANKRECTANGLE(1,10,1,3) +Calling PAINTROW(2,1;4,5,6,8,9,10) +Calling PAINTROW(1,1;6,7,8,9) +Calling UPDATESCREEN +{addto} +>> (8,1,5,-5,-5,5) +! Improper `addto'. +<to be read again> + ; +l.114 ...w 5.5; addto e0 also p; + addto e0 contour 0; +This expression should have specified a known picture. +So I'll not change anything just now. + +{addto} +>> 0 +! Improper `addto'. +<to be read again> + ; +l.114 ... p; addto e0 contour 0; + +This expression should have been a known path. +So I'll not change anything just now. + +{display} + +Calling BLANKRECTANGLE(0,2,0,4) +Calling PAINTROW(2,1;0,1) +Calling PAINTROW(1,1;0,1) +Calling PAINTROW(0,1;1,2) +Calling UPDATESCREEN +{addto} +! Not a cycle. +<to be read again> + ; +l.115 ...; addto e0 contour p~9; + +That contour should have ended with `..cycle' or `&cycle'. +So I'll not change anything just now. + +{display} +{(3)+(3)} + +Calling BLANKRECTANGLE(1,10,1,3) +Calling PAINTROW(2,1;4,5,6,10) +Calling UPDATESCREEN +{display} +{begingroup} +{vardef} +{endgroup} +! Variable e0e0 has been obliterated. +<to be read again> + ; +l.116 ...vardef e[]e=enddef;6]]; + +It seems you did a nasty thing---probably by accident, +but nevertheless you nearly hornswoggled me... +While I was evaluating the right-hand side of this +command, something happened, and the left-hand side +is no longer a variable! So I won't change anything. + +{addto} +{display} +Calling PAINTROW(1,1;0,1,2) +Calling PAINTROW(0,0;0,1,2) +Calling UPDATESCREEN +{ligtable} +{display} +{display} +Calling UPDATESCREEN +{show} +{begingroup} +{interim} +{tracingcommands:=0} + +lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en +dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou +ndarychar+51.29999 +(TEXT0)<-"g" +(TEXT1)<-=:| + +lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en +dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou +ndarychar+51.29999 +(TEXT0)<-"h":"i" +(TEXT1)<-|=: +! Character h is already in a ligtable. +<to be read again> + : +<argument> "h": + "i" +lig->...;ligtable(TEXT0):(TEXT0) + (TEXT1)0,skipto255;boundarych... +l.119 ...=:|); lig("h":"i")(|=:) + ; +It's not legal to label a character more than once. +So I'll not change anything just now. + + +lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en +dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou +ndarychar+51.29999 +(TEXT0)<-"j" +(TEXT1)<-|=:> + +lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en +dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou +ndarychar+51.29999 +(TEXT0)<-"k" +(TEXT1)<-=:|> + +lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en +dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou +ndarychar+51.29999 +(TEXT0)<-"l" +(TEXT1)<-|=:|> +{restoring tracingcommands=2.1} +{endgroup} +>> vacuous +{begingroup} +{let} +{vardef} +{endgroup} +! Variable c.a1 has been obliterated. +<to be read again> + ; +l.121 ...;vardef b=enddef;1]] ]; + ligtable"m":0=:0,skipto5; +It seems you did a nasty thing---probably by accident, +but nevertheless you nearly hornswoggled me... +While I was evaluating the suffix of this variable, +something was redefined, and it's no longer a variable! +In order to get back on my feet, I've inserted `0' instead. + +{b1:=0} +! Variable b1 has been obliterated. +<to be read again> + ; +l.121 ...;vardef b=enddef;1]] ]; + ligtable"m":0=:0,skipto5; +It seems you did a nasty thing---probably by accident, +but nevertheless you nearly hornswoggled me... +While I was evaluating the right-hand side of this +command, something happened, and the left-hand side +is no longer a variable! So I won't change anything. + +{ligtable} +! A statement can't begin with `skipto'. +<to be read again> + !! +l.122 !! + ; errhelp 0; errmessage "Be like Jane"; +I was looking for the beginning of a new statement. +If you just proceed without changing anything, I'll ignore +everything up to the next `;'. Please insert a semicolon +now in front of anything that you don't want me to delete. +(See Chapter 27 of The METAFONTbook for an example.) + +! Extra tokens will be flushed. +<to be read again> + !! +l.122 !! + ; errhelp 0; errmessage "Be like Jane"; +I've just read as much of that statement as I could fathom, +so a semicolon should have been next. It's very puzzling... +but I'll try to get myself back together, by ignoring +everything up to the next `;'. Please insert a semicolon +now in front of anything that you don't want me to delete. +(See Chapter 27 of The METAFONTbook for an example.) + +{errhelp} +>> 0 +! Not a string. +<to be read again> + ; +l.122 !!; errhelp 0; + errmessage "Be like Jane"; +A message should be a known string expression. + +{errmessage} +! Be like Jane. +<to be read again> + ; +l.122 ...message "Be like Jane"; + +This error message was generated by an `errmessage' +command, so I can't give any explicit help. +Pretend that you're Miss Marple: Examine all clues, +and deduce the truth by inspired guesses. + +{errhelp} +{errmessage} +! . +<to be read again> + ; +l.123 ...e%%%lp%"; errmessage""; + errhelp ""; errmessage "Anot... +He% +lp + + +{errhelp} +{errmessage} +! Another. +<to be read again> + ; +l.123 ...; errmessage "Another"; + +(That was another `errmessage'.) + +{headerbyte} +>> 0 +! Improper location. +<to be read again> + ; +l.124 headerbyte 0; + headerbyte(48.5)substring(-9,9)of"long"; ... +I was looking for a known, positive number. +For safety's sake I'll ignore the present command. + +{headerbyte} +! Missing `:' has been inserted. +<to be read again> + substring +l.124 ...aderbyte(48.5)substring + (-9,9)of"long"; for\=0:\ +A colon should follow a headerbyte or fontinfo location. + +{-(9)} +{((-9,9))substring("long")} +>> "long" +! Invalid code has been replaced by 0. +<to be read again> + ; +l.124 ...ubstring(-9,9)of"long"; + for\=0:\ +I was looking for a number between 0 and 255, or for a +string of length 1. Didn't find it; will use 0 instead. + +{for} +Runaway loop? +! Forbidden token found while scanning the text of a for loop. +<inserted text> + endfor +<to be read again> + \ +l.124 ...-9,9)of"long"; for\=0:\ + +I suspect you have forgotten an `endfor', +causing me to read past where you wanted me to stop. +I'll try to recover; but if the error is serious, +you'd better type `E' or `X' now and fix your file. + +{loop value=0} +{[repeat the loop]} +{\} +{headerbyte} +{(2)*(0.33333)} +{fontdimen} +{(2)*(0.33333)} +>> "q" +! Improper font parameter. +<to be read again> + ; +l.125 ..."; fontdimen 9:2a6,"q"; + fontdimen 1:2048; +I'm zeroing this one. Proceed, with fingers crossed. + +{fontdimen} +{fontmaking:=1} +{extensible} +! Missing `:' has been inserted. +<to be read again> + 5 +l.126 ...king:=1; extensible 5 5 + ,"c"255.5,"d"; charlist 0:5:"... +I'm processing `extensible c: t,m,b,r'. + +! Missing `,' has been inserted. +<to be read again> + 255.5 +l.126 ...extensible 5 5,"c"255.5 + ,"d"; charlist 0:5:"a":"d"; +I'm processing `extensible c: t,m,b,r'. + +>> 255.5 +! Invalid code has been replaced by 0. +<to be read again> + , +l.126 ...xtensible 5 5,"c"255.5, + "d"; charlist 0:5:"a":"d"; +I was looking for a number between 0 and 255, or for a +string of length 1. Didn't find it; will use 0 instead. + +{charlist} +! Character code 5 is already extensible. +<to be read again> + : +l.126 ...,"d"; charlist 0:5:"a": + "d"; +It's not legal to label a character more than once. +So I'll not change anything just now. + +{ligtable} +! Too far to skip. +l.127 ligtable255:255:: + "a"=:"b","d" kern -2048,"c":0:99.5:"e"... +At most 127 lig/kern steps can separate skipto1 from 1::. + +{-(2048)} +! Character code 0 is already in a charlist. +<to be read again> + : +l.127 ...","d" kern -2048,"c":0: + 99.5:"e"|=:|"f",0kern'; +It's not legal to label a character more than once. +So I'll not change anything just now. + +>> (xpart ',ypart ') +! Improper kern. +<to be read again> + ; +l.127 ...99.5:"e"|=:|"f",0kern'; + +The amount of kern should be a known numeric value. +I'm zeroing this one. Proceed, with fingers crossed. + +{ligtable} +! Character code 5 is already extensible. +<to be read again> + : +l.128 ligtable 5: + 0; def clear(text x)=interim x:=$ enddef; cl... +It's not legal to label a character more than once. +So I'll not change anything just now. + +! Illegal ligtable step. +<to be read again> + ; +l.128 ligtable 5:0; + def clear(text x)=interim x:=$ enddef; cl... +I was looking for `=:' or `kern' here. + +{def} + +clear(TEXT0)->interim(TEXT0):=$ +(TEXT0)<-hppp +{interim} +{hppp:=-1} +{(0)=(0)} +! Redundant equation. +<to be read again> + ; +l.128 ...f; clear(hppp); vppp=0; + +I already knew that this equation was true. +But perhaps no harm has been done; let's continue. + +{begingroup} + +clear(TEXT0)->interim(TEXT0):=$ +(TEXT0)<-tracingmacros +{interim} +{tracingmacros:=-1} +{interim} +{tracingcommands:=-1} +Runaway text? +tracingoutput +! Forbidden token found while scanning a text argument. +<inserted text> + ) +<to be read again> + \ +l.129 ...); clear(tracingoutput\ + ; +It seems that a right delimiter was left out, +causing me to read past where you wanted me to stop. +I'll try to recover; but if the error is serious, +you'd better type `E' or `X' now and fix your file. + +{restoring proofing=1} +{restoring tracingoutput=1} +{restoring tracingcommands=2.1} +{restoring tracingmacros=1} +{endgroup} +{def} +{def} +{addto} +Path at line 139, before choices: +(0,0){4096,0} + ..{4096,0}(1,0){0,-4096} + ..{0,4096}cycle + +Path at line 139, after choices: +(0,0)..controls (0.33333,0) and (0.66667,0) + ..(1,0)..controls (1,-0.66667) and (0,-0.66667) + ..cycle + +> 0 ENE 1 (ESE SSE) SSW WSW WNW NNW 0 (NNE) +! Backwards path (turning number is negative). +<to be read again> + ; +l.139 ....{0,1}cycle withpen qq; + +The path doesn't have a counterclockwise orientation, +so I'll probably have trouble drawing it. +(See Chapter 27 of The METAFONTbook for more help.) + +Tracing edges at line 139: (weight 1) +@ Octant ENE (2 offsets), from (2.5,-0.5) to (1.5,-2) +@ retrograde line from (2.5,-0.5) to (0.5,-2) +(3,0)(3,-1)(1,-1) +@ transition line 0, from (0.5,-2) to (0.5,-2) +@ transition line 1, from (1.5,-2) to (2.5,-1.5) +@ transition line 2, from (2.5,-1.5) to (3.5,-0.5) +(1,-2)(3,-2)(3,-1)(4,-1) +@ retrograde line from (3.5,-0.5) to (1.5,-2) +(4,0)(4,-1)(2,-1) +@ Octant ESE (2 offsets), from (1.5,-2) to (-1,0) +@ retrograde line from (1.5,-2) to (-1,0) +(2,-2)(1,-2)(1,-1)(0,-1) +@ transition line 3, from (-1,0) to (0.5,-1.5) +@ transition line 2, from (0.5,-1.5) to (1.5,-2) +@ transition line 1, from (1.5,-2) to (1.5,-2) +(0,0)(0,-1)(1,-1) +@ retrograde line from (1.5,-2) to (-1,0) +(1,-2)(1,-1)(0,-1) +@ Octant SSE (0 offsets), from (-1,0) to (-1,0) +@ transition line 0, from (-1,0) to (-1,0) +@ Octant SSW (2 offsets), from (-1,0) to (-0.82407,0.67593) +@ retrograde line from (-1,0) to (-0.5,1.5) +(0,0)(-1,0)(-1,1)(0,1) +@ transition line 3, from (-0.5,1.5) to (-0.5,1.5) +@ transition line 2, from (-0.5,1.5) to (-1,0) +@ transition line 1, from (-1.06265,-0.39499) to (-0.56265,1.10501) +@ transition line 2, from (-0.82407,0.67593) to (-1.32407,-0.82407) +@ transition line 1, from (-1.32407,-0.82407) to (-1.32407,-0.82407) +(0,2)(0,1)(-1,1) +@ retrograde line from (-1.32407,-0.82407) to (-0.82407,0.67593) +(-1,-1) +@ Octant WSW (2 offsets), from (-0.82407,0.67593) to (1,2) +@ retrograde line from (-0.82407,0.67593) to (1.17593,2.17593) +(-1,1)(0,1) +@ transition line 0, from (1.17593,2.17593) to (1.17593,2.17593) +@ transition line 1, from (1.17593,2.17593) to (0.17593,1.67593) +@ transition line 2, from (0,1.5) to (-1,0.5) +(0,2) +@ retrograde line from (-1,0.5) to (1,2) +(0,1) +@ Octant WNW (2 offsets), from (1,2) to (3.32407,0.17593) +@ retrograde line from (1,2) to (3.5,0) +(0,2)(2,2)(2,1)(3,1) +@ transition line 3, from (3.5,0) to (2,1.5) +@ transition line 2, from (1.82407,1.67593) to (0.82407,2.17593) +@ transition line 1, from (0.82407,2.17593) to (0.82407,2.17593) +(3,0)(3,1)(2,1) +@ retrograde line from (0.82407,2.17593) to (3.32407,0.17593) +(2,2)(2,1)(3,1) +@ Octant NNW (0 offsets), from (3.32407,0.17593) to (3,1) +@ transition line 0, from (3.32407,0.17593) to (3.32407,0.17593) +(3,0) +@ Octant NNE (2 offsets), from (3,1) to (2.5,-0.5) +@ retrograde line from (3,1) to (2.5,-0.5) +(3,1) +@ transition line 3, from (2.5,-0.5) to (2.5,-0.5) +@ transition line 2, from (2.5,-0.5) to (3,1) +@ transition line 1, from (3,1) to (3,1) +(3,0) +@ retrograde line from (3,1) to (2.5,-0.5) +(3,1)(3,0). + + +f(SUFFIX0)(EXPR1)(EXPR2)(TEXT3)->numeric.w;show(EXPR1);addto(SUFFIX0)con +tour(0,0)..(2,0)..(1,$)..(1,1)..cycle.withpen.qq;addto(SUFFIX0)doublepat +h(0,0){1,1}..{2,1}(2,1)withpen.qq;addto(SUFFIX0)doublepath(($,$){1,0}..( +1,1){1,0})scaled0.5withpen.nullpen;cull(SUFFIX0)keeping(4,4)withweight1. +5; +! Missing `]' has been inserted. +<to be read again> + , +l.140 f(e[3, + w); g(e3,transformed p,penoffset-(1,1.3)of(pencir... +I've seen a `[' and a subscript value, in a suffix, +so a right bracket should have come next. +I shall pretend that one was there. + +(SUFFIX0)<-e3 +(EXPR1)<-unknown path w +! Missing argument to f. +<to be read again> + ; +l.140 f(e[3,w); + g(e3,transformed p,penoffset-(1,1.3)of(pencir... +That macro has more parameters than you thought. +I'll continue by pretending that each missing argument +is either zero or null. + +(EXPR2)<-0 +! Missing argument to f. +<to be read again> + ; +l.140 f(e[3,w); + g(e3,transformed p,penoffset-(1,1.3)of(pencir... +That macro has more parameters than you thought. +I'll continue by pretending that each missing argument +is either zero or null. + +(TEXT3)<- +{numeric} +{show} +>> unknown path %CAPSULE1615 +{addto} +Path at line 140, before choices: +(0,0) + ..(2,0) + ..(1,-1) + ..(1,1) + ..cycle + +Path at line 140, after choices: +(0,0)..controls (0.56189,-0.5286) and (1.43811,0.5286) + ..(2,0)..controls (2.70831,-0.66634) and (1.66634,-1.70831) + ..(1,-1)..controls (0.4714,-0.43811) and (1.5286,0.43811) + ..(1,1)..controls (0.33366,1.70831) and (-0.70831,0.66634) + ..cycle + +> 0 ESE ENE ESE 1 SSE SSW WSW WNW NNW 2 NNE NNW 3 WNW WSW SSW SSE ESE 0 +! Strange path (turning number is zero). +<to be read again> + ; +f->.....(1,1)..cycle.withpen.qq; + addto(SUFFIX0)doublepath(0,0)... +<to be read again> + ; +l.140 f(e[3,w); + g(e3,transformed p,penoffset-(1,1.3)of(pencir... +The path doesn't have a counterclockwise orientation, +so I'll probably have trouble drawing it. +(See Chapter 27 of The METAFONTbook for more help.) + +Tracing edges at line 140: (weight 1) +@ Octant ENE (2 offsets), from (0.26321,-2.6526) to (1.73679,-2.34741) +@ transition line 0, from (0.26321,-2.6526) to (0.26321,-2.6526) +@ transition line 1, from (1.73679,-2.34741) to (2.73679,-1.84741) +@ transition line 2, from (2.73679,-1.84741) to (3.73679,-0.84741) +(1,-3)(1,-2)(3,-2) +@ retrograde line from (3.73679,-0.84741) to (1.73679,-2.34741) +(3,-1) +@ Octant ESE (2 offsets), from (1.73679,-2.34741) to (-0.25465,-0.56029) +@ retrograde line from (1.73679,-2.34741) to (-0.76321,-0.34741) +(3,-2)(1,-2)(1,-1)(-1,-1) +@ transition line 3, from (-0.76321,-0.34741) to (0.73679,-1.84741) +@ transition line 2, from (0.73679,-1.84741) to (1.73679,-2.34741) +@ transition line 1, from (2.05333,-2.41772) to (1.05333,-1.91772) +@ transition line 2, from (1.24535,-2.06029) to (2.24535,-2.56029) +@ transition line 1, from (2.24535,-2.56029) to (2.24535,-2.56029) +(-1,0)(-1,-1)(0,-1)(0,-2)(2,-2) +@ retrograde line from (2.24535,-2.56029) to (-0.25465,-0.56029) +(2,-3)(2,-2)(1,-2) +@ Octant SSE (0 offsets), from (-0.25465,-0.56029) to (0,-1.13196) +@ transition line 0, from (-0.25465,-0.56029) to (-0.25465,-0.56029) +@ Octant SSW (2 offsets), from (0,-1.13196) to (0.25,-0.25) +@ retrograde line from (0,-1.13196) to (0.5,0.36804) +(1,-1)(0,-1) +@ transition line 3, from (0.5,0.36804) to (0.5,0.36804) +@ transition line 2, from (0.5,0.36804) to (0,-1.13196) +@ transition line 1, from (-0.04594,-1.41693) to (0.45406,0.08307) +@ transition line 2, from (0.25,-0.25) to (-0.25,-1.75) +@ transition line 1, from (-0.25,-1.75) to (-0.25,-1.75) +(0,0) +@ retrograde line from (-0.25,-1.75) to (0.25,-0.25) +(0,-2) +@ Octant WSW (2 offsets), from (0.25,-0.25) to (1.63197,1) +@ retrograde line from (0.25,-0.25) to (2.25,1.25) +(0,0)(1,0) +@ transition line 0, from (2.25,1.25) to (2.25,1.25) +@ transition line 1, from (2.25,1.25) to (1.25,0.75) +@ transition line 2, from (1.03186,0.59352) to (2.03186,1.09352) +@ transition line 1, from (1.63197,1) to (0.63197,0.5) +@ transition line 2, from (0.63197,0.5) to (-0.36803,-0.5) +(1,1) +@ retrograde line from (-0.36803,-0.5) to (1.63197,1) +(1,0) +@ Octant WNW (2 offsets), from (1.63197,1) to (3.56024,-0.74529) +@ retrograde line from (1.63197,1) to (4.13197,-1) +(1,1)(2,1)(2,0)(4,0) +@ transition line 3, from (4.13197,-1) to (2.63197,0.5) +@ transition line 2, from (2.63197,0.5) to (1.63197,1) +@ transition line 1, from (1.29863,1.07983) to (2.29863,0.57983) +@ transition line 2, from (2.06024,0.75471) to (1.06024,1.25471) +@ transition line 1, from (1.06024,1.25471) to (1.06024,1.25471) +(4,-1)(4,0)(3,0) +@ retrograde line from (1.06024,1.25471) to (3.56024,-0.74529) +(3,1)(2,1)(2,0)(3,0) +@ Octant NNW (0 offsets), from (3.56024,-0.74529) to (3.3474,-0.23679) +@ transition line 0, from (3.56024,-0.74529) to (3.56024,-0.74529) +(3,-1) +@ Octant NNE (2 offsets), from (3.3474,-0.23679) to (3.65259,1.23679) +@ retrograde line from (3.3474,-0.23679) to (2.8474,-1.73679) +(3,0) +@ transition line 3, from (2.8474,-1.73679) to (2.8474,-1.73679) +@ transition line 2, from (2.8474,-1.73679) to (3.3474,-0.23679) +@ transition line 1, from (3.65259,1.23679) to (3.65259,1.23679) +(3,-2) +@ Octant NNW (0 offsets), from (3.65259,1.23679) to (3.43976,1.74529) +@ transition line 0, from (3.65259,1.23679) to (3.65259,1.23679) +(3,1)(4,1) +@ Octant WNW (2 offsets), from (3.43976,1.74529) to (0.36803,4) +@ transition line 3, from (3.43976,1.74529) to (1.93976,3.24529) +@ transition line 2, from (1.70137,3.42017) to (0.70137,3.92017) +@ transition line 1, from (0.36803,4) to (0.36803,4) +(4,2)(3,2)(3,3)(2,3) +@ Octant WSW (2 offsets), from (0.36803,4) to (-2.25,2.25) +@ transition line 0, from (0.36803,4) to (0.36803,4) +@ transition line 1, from (-0.03186,3.90648) to (-1.03186,3.40648) +@ transition line 2, from (-1.25,3.25) to (-2.25,2.25) +(2,4)(-1,4)(-1,3)(-2,3) +@ Octant SSW (2 offsets), from (-2.25,2.25) to (-3,0.13196) +@ transition line 3, from (-2.25,2.25) to (-2.25,2.25) +@ transition line 2, from (-2.45406,1.91695) to (-2.95406,0.41695) +@ transition line 1, from (-3,0.13196) to (-3,0.13196) +(-2,2)(-3,2) +@ Octant SSE (0 offsets), from (-3,0.13196) to (-2.74533,-0.43973) +@ transition line 0, from (-3,0.13196) to (-3,0.13196) +@ Octant ESE (2 offsets), from (-2.74533,-0.43973) to (0.26321,-2.6526) +@ transition line 3, from (-2.74533,-0.43973) to (-1.24533,-1.93973) +@ transition line 2, from (-1.05331,-2.08229) to (-0.05331,-2.58229) +@ transition line 1, from (0.26321,-2.6526) to (0.26321,-2.6526) +(-3,-1)(-2,-1)(-2,-2)(0,-2)(0,-3). + +{addto} +Path at line 140, before choices: +(0,0){2896.30943,2896.30934} + ..{3663.57385,1831.78674}(2,1) + +Path at line 140, after choices: +(0,0)..controls (0.53566,0.53566) and (1.32689,0.66344) + ..(2,1) + +Tracing edges at line 140: (weight 1) +@ Octant ENE (2 offsets), from (0,-2.5) to (4,0) +@ transition line 0, from (0,-2.5) to (0,-2.5) +@ transition line 1, from (0,-2.5) to (1,-2) +@ transition line 2, from (1.607,-1.57747) to (0.607,-2.07747) +@ transition line 1, from (2,-1.5) to (3,-1) +@ transition line 2, from (3,-1) to (4,0) +(2,-2)(2,-1)(4,-1) +@ Octant NNE (2 offsets), from (4,0) to (4.5,1.5) +@ transition line 3, from (4,0) to (4,0) +@ transition line 2, from (4,0) to (4.5,1.5) +@ transition line 1, from (4.5,1.5) to (4.5,1.5) +(4,1)(5,1) +@ Octant NNW (0 offsets), from (4.5,1.5) to (4.5,1.5) +@ transition line 0, from (4.5,1.5) to (4.5,1.5) +@ Octant WNW (2 offsets), from (4.5,1.5) to (2,3.5) +@ transition line 3, from (4.5,1.5) to (3,3) +@ transition line 2, from (3,3) to (2,3.5) +@ transition line 1, from (2,3.5) to (2,3.5) +(5,2)(4,2)(4,3)(2,3) +@ Octant WSW (2 offsets), from (2,3.5) to (-2,1) +@ transition line 0, from (2,3.5) to (2,3.5) +@ transition line 1, from (0.607,2.92253) to (-0.393,2.42253) +@ transition line 2, from (-1,2) to (-2,1) +(2,4)(2,3)(0,3)(0,2)(-1,2) +@ Octant SSW (2 offsets), from (-2,1) to (-2.5,-0.5) +@ transition line 3, from (-2,1) to (-2,1) +@ transition line 2, from (-2,1) to (-2.5,-0.5) +@ transition line 1, from (-2.5,-0.5) to (-2.5,-0.5) +(-1,1)(-2,1) +@ Octant SSE (0 offsets), from (-2.5,-0.5) to (-2.5,-0.5) +@ transition line 0, from (-2.5,-0.5) to (-2.5,-0.5) +@ Octant ESE (2 offsets), from (-2.5,-0.5) to (0,-2.5) +@ transition line 3, from (-2.5,-0.5) to (-1,-2) +@ transition line 2, from (-1,-2) to (0,-2.5) +@ transition line 1, from (0,-2.5) to (0,-2.5) +(-2,-1)(-1,-1)(-1,-2). + +{addto} +Path at line 140, before choices: +(-1,-1){4096,0} + ..{4096,0}(1,1) + +Path at line 140, after choices: +(-1,-1)..controls (0.10457,-1) and (-0.10457,1) + ..(1,1) + +{(path)scaled(0.5)} +{nullpen} +Tracing edges at line 140: (weight 1) +(0,0)(0,1)(0,0). + +{cull} + +g(SUFFIX0)->show(SUFFIX0) +(SUFFIX0)<-e3 +! Too many arguments to g; + Missing `)' has been inserted. +l.140 f(e[3,w); g(e3, + transformed p,penoffset-(1,1.3)of(pencir... +I'm going to assume that the comma I just read was a +right delimiter, and then I'll begin expanding the macro. +You might want to delete some tokens before continuing. + +{show} +{(picture)transformed((8,1,5,-5,-5,5))} +>> Edge structure at line 140: + +{-((1,1.3))} +{pencircle} +{(future pen)scaled(20)} +{-(0.5)} +{(future pen)yscaled(-0.5)} +Pen polygon at line 140 (newly created): +(1.5,-5) + .. (4.5,-4.5) + .. (6,-4) + .. (8,-3) + .. (9.5,-1.5) + .. (10,-0.5) + .. (10,0.5) + .. (9.5,1.5) + .. (8,3) + .. (6,4) + .. (4.5,4.5) + .. (1.5,5) + .. (-1.5,5) + .. (-4.5,4.5) + .. (-6,4) + .. (-8,3) + .. (-9.5,1.5) + .. (-10,0.5) + .. (-10,-0.5) + .. (-9.5,-1.5) + .. (-8,-3) + .. (-6,-4) + .. (-4.5,-4.5) + .. (-1.5,-5) + .. cycle + +{((-1,-1.3))penoffset(pen)} +>> (-9.5,1.5) +Path at line 141, before choices: +(0,0)..controls (1,1) and (-1,1) + ..(3,0) + +Path at line 141, after choices: +(0,0)..controls (1,1) and (-1,1) + ..(3,0) + +{((0,1))directiontime(path)} +>> 0.33333 +{(3.14159)point(path)} +{((3.14159,4))subpath(path)} +{((7.68668,2.72437))intersectiontimes(path)} +>> (0,0) +Path at line 143, before choices: +(-1,1.1){curl 1} + ..{curl 1}(1,-1) + +Path at line 143, after choices: +(-1,1.1)..controls (-0.33333,0.40001) and (0.33333,-0.3) + ..(1,-1) + +{(-1)precontrol((0,0))} +{(path)intersectiontimes((0,0))} +>> (-1,-1) +{addto} +{-(4094.99998)} +{-(0.00002)} +Path at line 144, before choices: +(-4094.99998,0){curl 1} + ..{curl 1}(4094.99998,-0.00002) + +Path at line 144, after choices: +(-4094.99998,0)..controls (-1365,0) and (1365,-0.00002) + ..(4094.99998,-0.00002) + +{pencircle} +{(0)penoffset(future pen)} +Pen polygon at line 145 (newly created): +(0.5,0) + .. (0,0.5) + .. (-0.5,0) + .. (0,-0.5) + .. cycle + +>> 0 +>> pen +! Not implemented: penoffset(known numeric)of(pen). +<to be read again> + ; +l.145 pencircle; + addto e3 also e3 shifted (0,257); ,"flushed ... +I'm afraid I don't know how to apply that operation to that +combination of types. Continue, and I'll return the second +argument (see above) as the result of the operation. + +Tracing edges at line 145: (weight 1) +@ Octant ESE (1 offset), from (-4095.49998,0) to (4094.99998,-0.50002) +@ transition line 2, from (-4095.49998,0) to (-4094.99998,-0.5) +@ transition line 1, from (4094.99998,-0.50002) to (4094.99998,-0.50002) +(-4095,0) +@ Octant ENE (1 offset), from (4094.99998,-0.50002) to (4095.49998,-0.00 +002) +@ transition line 0, from (4094.99998,-0.50002) to (4094.99998,-0.50002) +@ transition line 1, from (4094.99998,-0.50002) to (4095.49998,-0.00002) +(-4095,-1)(4095,-1) +@ Octant NNE (0 offsets), from (4095.49998,-0.00002) to (4095.49998,-0.0 +0002) +@ transition line 1, from (4095.49998,-0.00002) to (4095.49998,-0.00002) +@ Octant NNW (0 offsets), from (4095.49998,-0.00002) to (4095.49998,-0.0 +0002) +@ transition line 0, from (4095.49998,-0.00002) to (4095.49998,-0.00002) +@ Octant WNW (1 offset), from (4095.49998,-0.00002) to (-4094.99998,0.5) +@ transition line 2, from (4095.49998,-0.00002) to (4094.99998,0.49998) +@ transition line 1, from (-4094.99998,0.5) to (-4094.99998,0.5) +(4095,0)(-4095,0) +@ Octant WSW (1 offset), from (-4094.99998,0.5) to (-4095.49998,0) +@ transition line 0, from (-4094.99998,0.5) to (-4094.99998,0.5) +@ transition line 1, from (-4094.99998,0.5) to (-4095.49998,0) +(-4095,1) +@ Octant SSW (0 offsets), from (-4095.49998,0) to (-4095.49998,0) +@ transition line 1, from (-4095.49998,0) to (-4095.49998,0) +@ Octant SSE (0 offsets), from (-4095.49998,0) to (-4095.49998,0) +@ transition line 0, from (-4095.49998,0) to (-4095.49998,0) +(-4095,0). + +{addto} +{(picture)shifted((0,257))} +! A statement can't begin with `,'. +<to be read again> + , +l.145 ...o e3 shifted (0,257); , + "flushed with pride"; numeric... +I was looking for the beginning of a new statement. +If you just proceed without changing anything, I'll ignore +everything up to the next `;'. Please insert a semicolon +now in front of anything that you don't want me to delete. +(See Chapter 27 of The METAFONTbook for an example.) + +! Extra tokens will be flushed. +<to be read again> + , +l.145 ...o e3 shifted (0,257); , + "flushed with pride"; numeric... +I've just read as much of that statement as I could fathom, +so a semicolon should have been next. It's very puzzling... +but I'll try to get myself back together, by ignoring +everything up to the next `;'. Please insert a semicolon +now in front of anything that you don't want me to delete. +(See Chapter 27 of The METAFONTbook for an example.) + +{numeric} +{def} + +f(EXPR0)(EXPR1)(EXPR2)->showdependencies;tracingcapsules:=1;showdependen +cies;show1/3(3,6)*(((EXPR0)+(EXPR1))+((EXPR1)-(EXPR0))),(1,1)/sqrt2zscal +ed((EXPR0)+1,(EXPR0)+2)-((EXPR0)+1,(EXPR0)+2)rotated45,(0,1)zscaled(1,(E +XPR1)+2)-(1,(EXPR1)+2)rotated90 +{(xx)+(1)} +{(xx+1)/(0.3)} +(EXPR0)<-3.3333xx+3.3333 +{(yy)-(1)} +{(yy-1)/(0.5)} +(EXPR1)<-2yy-2 +(EXPR2)<-(xx,0) +{showdependencies} +alpha=0.45p3~+7 +{tracingcapsules:=1} +{showdependencies} +xpart %CAPSULE1359=xx +%CAPSULE1367=2yy-2 +%CAPSULE1375 = 3.3333xx+3.3333 +alpha=0.45p3~+7 +{show} +{(1/3)*((3,6))} +{(3.3333xx+3.3333)+(2yy-2)} +{(2yy-2)-(3.3333xx+3.3333)} +{(linearform)+(linearform)} +{((1,2))*(4yy-4)} +>> (4yy-4,8yy-8) +{sqrt(2)} +{((1,1))/(1.41422)} +{(3.3333xx+3.3333)+(1)} +{(3.3333xx+3.3333)+(2)} +{((0.7071,0.7071))zscaled((3.3333xx+4.3333,3.3333xx+5.3333))} +{(3.3333xx+3.3333)+(1)} +{(3.3333xx+3.3333)+(2)} +{((3.3333xx+4.3333,3.3333xx+5.3333))rotated(45)} +{((-0.7071,4.71399xx+6.83531))-((-0.7071,4.71399xx+6.83531))} +>> (0,0) +{(2yy-2)+(2)} +{((0,1))zscaled((1,2yy))} +{(2yy-2)+(2)} +{((1,2yy))rotated(90)} +{((-2yy,1))-((-2yy,1))} +>> (0,0) +{(1000)*(o3)} +{(o1)-(o2)} +{(4000)*(linearform)} +{(1000o3)-(linearform)} +{(4000)*(o2)} +{(linearform)+(4000o2)} +{(linearform)+(9)} +{(0.01)*(o3)} +{-(0.01o3)} +{(3)*(ooo)} +{(-0.01o3)+(3ooo)} +{begingroup} +{(o2)+(o4)} +{(linearform)+(o5)} +{(linearform)-(20)} +{(9/10)*(linearform)} +{(oo)=(linearform)} +## oo=0.9o5+0.9o4+0.9o2-18 +{(0.5)*(o2)} +{(o1)+(0.5o2)} +{(8/9)*(linearform)} +{(o5)=(linearform)} +## o5=0.44444o2+0.88889o1 +{(o4)=(linearform)} +## o4=0.44444o2+0.88889o1 +{(0.0001)*(o2)} +{-(0.0001o2)} +{(o6)=(-0.0001o2)} +## o6=-0.0001o2 +{showdependencies} +o6=-0.0001o2 +o4=0.44444o2+0.88889o1 +o5=0.44444o2+0.88889o1 +oo=1.7o2+1.6o1-18 +%CAPSULE382 = 3ooo-0.01o3 +xpart %CAPSULE1049 = 8000o2-4000o1+1000o3+9 +xpart %CAPSULE1383=xpart ' +ypart %CAPSULE1383=ypart ' +alpha=0.45p3~+7 +{numeric} +### 4000o1 = -xpart %CAPSULE1049+8000o2+1000o3+9 +### -4.87383o2 = -oo-0.0004xpart %CAPSULE1049+0.39673o3-17.99643 +#### o6=-0.00027 +### -0.04366o3 = -o4+0.46689oo+8.40439 +### -o4 = -o5 +### 0.22894o5 = -%CAPSULE382+0.10689oo+3ooo+1.92412 +{begingroup} +{pair} +### -alfa=-xpart %CAPSULE1494 +{endgroup} +{xpart((xpart %CAPSULE1494,0))} +### -xpart %CAPSULE17=-%CAPSULE1176 +{endgroup} +{(%CAPSULE382)+(%CAPSULE1176)} +### -%CAPSULE382=-%CAPSULE1893+%CAPSULE1176 +### -%CAPSULE1893=-ypart %CAPSULE1049 +{begingroup} +{save} +{(1)-(p$)} +{restoring p} +### p$=-ypart %CAPSULE604+1 +{endgroup} +{(2/3)*((-ypart %CAPSULE604+1,ypart %CAPSULE604))} +### ypart %CAPSULE604=-xpart %CAPSULE604+1 +### -0.66667xpart %CAPSULE604=-xpart %CAPSULE1889 +{-((xpart %CAPSULE1889,-xpart %CAPSULE1889+0.66667))} +### xpart %CAPSULE1889=-xpart %CAPSULE1172 +{((xpart %CAPSULE1049,ypart %CAPSULE1049))=((xpart %CAPSULE1172,-xpart % +CAPSULE1172-0.66667))} +## xpart %CAPSULE1172=-ypart %CAPSULE1049-0.66667 +## ypart %CAPSULE1049=-xpart %CAPSULE1049-0.66667 +### -xpart %CAPSULE1049=-xpart %CAPSULE1172 +{((xpart ',ypart '))=((xpart %CAPSULE1172,-xpart %CAPSULE1172-0.66667))} +## xpart %CAPSULE1172=-ypart '-0.66667 +## xpart '=-ypart '-0.66667 +{begingroup} +{(0.5)*(ooo)} +{begingroup} +{numeric} +### -ooo=-%CAPSULE1494 +{endgroup} +{(%CAPSULE1494)+(1)} +### -%CAPSULE1494=-%CAPSULE1350+1 +{(1/2)*(%CAPSULE1350)} +### -0.5%CAPSULE1350=-%CAPSULE1367 +{-(%CAPSULE1367)} +### %CAPSULE1367=-%CAPSULE1893 +{(2)*(%CAPSULE1893)} +### -2%CAPSULE1893=-%CAPSULE1885 +{(-0.5%CAPSULE1885-0.5)=(%CAPSULE1885)} +## %CAPSULE1885=-0.33333 +{(oo)=(-0.33333)} +## oo=-0.33333 +{endgroup} +{(4000)*(-0.33333)} +{yoffset:=-1333.31299} +{xoffset:=-1333.31299} +{for} +{sqrt(-1)} +! Square root of -1 has been replaced by 0. +l.153 for @=angle(sqrt$, + mlog$):charext:=uniformdeviate$;charh... +Since I don't take square roots of negative numbers, +I'm zeroing this one. Proceed, with fingers crossed. + +{mlog(-1)} +! Logarithm of -1 has been replaced by 0. +l.153 for @=angle(sqrt$,mlog$) + :charext:=uniformdeviate$;charh... +Since I don't take logs of non-positive numbers, +I'm zeroing this one. Proceed, with fingers crossed. + +{angle((0,0))} +! angle(0,0) is taken as zero. +l.153 for @=angle(sqrt$,mlog$): + charext:=uniformdeviate$;charh... +The `angle' between two identical points is undefined. +I'm zeroing this one. Proceed, with fingers crossed. + +Runaway loop? +charext:=uniformdeviate$;charht:=2048;granularity:=-8; ETC. +! Forbidden token found while scanning the text of a for loop. +<inserted text> + endfor +<to be read again> + endtext +l.163 ... showstats; bye endtext + +I suspect you have forgotten an `endfor', +causing me to read past where you wanted me to stop. +I'll try to recover; but if the error is serious, +you'd better type `E' or `X' now and fix your file. + +{loop value=0} +{uniformdeviate(-1)} +{charext:=-0.00507} +{charht:=2048} +{-(8)} +{granularity:=-8} +{addto} +{-(100)} +{-(99)} +Path at line 163, before choices: +(0,-100)..tension 500 + ..(100,-99)..tension 3000 + ..cycle + +Path at line 163, after choices: +(0,-100)..controls (-36.92659,-103.51175) and (136.98943,-101.7726) + ..(100,-99)..controls (99.9889,-98.99916) and (0.01108,-99.99895) + ..cycle + +Tracing edges at line 163: (weight 1) +(-3,-101)(-3,-102)(71,-102)(71,-101)(99,-101)(99,-100)(103,-100) +(103,-99)(48,-99)(48,-100)(-7,-100)(-7,-101). + +{tracingoutput:=0} +{shipout} +! Enormous charht has been reduced. +<to be read again> + ; +<for(0)> ...=(EXPR0);shipout.e3; + special"bye";interim.char99="... +<inserted text> endfor + +<to be read again> + endtext +l.163 ... showstats; bye endtext + +Font metric dimensions must be less than 2048pt. + +[109] +{special} +{interim} +! The token `char' isn't an internal quantity. +<to be read again> + char +<for(0)> ...al"bye";interim.char + 99="c";true=false;[[clear(tra... +<inserted text> endfor + +<to be read again> + endtext +l.163 ... showstats; bye endtext + +Something like `tracingonline' should follow `interim'. + +{char(99)} +{("c")=("c")} +! Redundant equation. +<to be read again> + ; +<for(0)> ...;interim.char99="c"; + true=false;[[clear(tracingcom... +<inserted text> endfor + +<to be read again> + endtext +l.163 ... showstats; bye endtext + +I already knew that this equation was true. +But perhaps no harm has been done; let's continue. + +{true} +{false} +{(true)=(false)} +! Inconsistent equation. +<to be read again> + ; +<for(0)> ...ar99="c";true=false; + [[clear(tracingcommands);char... +<inserted text> endfor + +<to be read again> + endtext +l.163 ... showstats; bye endtext + +The equation I just read contradicts what was said before. +But don't worry; continue and I'll just ignore it. + +{begingroup} + +clear(TEXT0)->interim(TEXT0):=$ +(TEXT0)<-tracingcommands +{interim} +{tracingcommands:=-1} +! Enormous charht has been reduced. +<to be read again> + ; +<for(0)> ...shipout+nullpicture; + "careful"for.for=(EXPR0)step2... +<inserted text> endfor + +<to be read again> + endtext +l.163 ... showstats; bye endtext + +Font metric dimensions must be less than 2048pt. + +[0] +careful METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT M +ETAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT M +ETAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT M +ETAFONT METAFONT METAFONT METAFONT +{restoring tracingcommands=2.1} +{endgroup} +{scrollmode} + +{char(31)} +{("hello again")&("^^_")} +hello again^^_ +{save} +### -0.45p3~=-alpha+7 +{-(0.043)} +{fillin:=-0.043} +{def} +{begingroup} +{tracingspecs:=1} +{show} +{nullpen} + +>> Pen polygon at line 163: +(0,0) + .. cycle + +{makepath(pen)} + +>> Path at line 163: +(1,-2)..controls (1,-2) and (2,-1) + ..(2,-1)..controls (2,-1) and (2.5,0.5) + ..(2.5,0.5)..controls (2.5,0.5) and (1,2) + ..(1,2)..controls (1,2) and (0,2.5) + ..(0,2.5)..controls (0,2.5) and (-1,2) + ..(-1,2)..controls (-1,2) and (-2,1) + ..(-2,1)..controls (-2,1) and (-2.5,-0.5) + ..(-2.5,-0.5)..controls (-2.5,-0.5) and (-1,-2) + ..(-1,-2)..controls (-1,-2) and (0,-2.5) + ..(0,-2.5)..controls (0,-2.5) and (1,-2) + ..cycle + +{(pen)rotated(1)} +Pen polygon at line 163 (newly created): +(0.97366,1.51723) + .. cycle + +{makepath(pen)} + +>> Path at line 163: +(0.97366,1.51723)..controls (0.97366,1.51723) and (0.97366,1.51723) + ..cycle + +{pencircle} +{makepath(future pen)} +Pen polygon at line 163 (newly created): +(0.5,-0.5) + .. (0.5,0.5) + .. (-0.5,0.5) + .. (-0.5,-0.5) + .. cycle + +{(path)rotated(-1)} + +>> Path at line 163: +(0.4912,-0.50865)..controls (0.4912,-0.50865) and (0.50865,0.4912) + ..(0.50865,0.4912)..controls (0.50865,0.4912) and (-0.4912,0.50865) + ..(-0.4912,0.50865)..controls (-0.4912,0.50865) and (-0.50865,-0.4912) + ..(-0.50865,-0.4912)..controls (-0.50865,-0.4912) and (0.4912,-0.50865) + ..cycle + +{addto} +Path at line 163, before choices: +(0,2){0,-4096} + ..{0,-4096}(0,1){0,-4096} + ..{4096,0}(3,0){4096,0} + ..{4096,0}(4,0){4096,0} + ..{0,-4096}cycle + +Path at line 163, after choices: +(0,2)..controls (0,1.66667) and (0,1.33333) + ..(0,1)..controls (0,-0.20886) and (1.63324,0) + ..(3,0)..controls (3.33333,0) and (3.66667,0) + ..(4,0)..controls (13.63031,0) and (0,10.64238) + ..cycle + +Path at line 163, before choices: +(0,0) + ..(5,2.9) + ..(4,3) + ..cycle + +Path at line 163, after choices: +(0,0)..controls (0.9363,-8.0181) and (11.81119,0.07109) + ..(5,2.9)..controls (4.68596,3.03043) and (4.33879,3.02028) + ..(4,3)..controls (1.86353,2.87216) and (-0.21431,1.83528) + ..cycle + +{makepen(path)} +Pen polygon at line 163 (newly created): +(5,2.9) + .. (4,3) + .. (0,0) + .. cycle + +Path at line 163, before subdivision into octants: +(0,2)..controls (0,1.66667) and (0,1.33333) + ..(0,1)..controls (0,-0.20886) and (1.63324,0) + ..(3,0)..controls (3.33333,0) and (3.66667,0) + ..(4,0)..controls (13.63031,0) and (0,10.64238) + ..cycle + +Cycle spec at line 163, after subdivision and double autorounding: +(1.5,0.00272) % beginning in octant `SSE' + ..controls (1.5,-0.49254) and (1.63411,-0.82727) + ..(1.8592,-1.05237) % segment 1 +% entering octant `ESE' + ..controls (2.23936,-1.43253) and (2.87909,-1.5) + ..(3.57066,-1.5) % segment 1 +% entering octant `ENE' + ..controls (3.95114,-1.5) and (4.3473,-1.47957) + ..(4.72458,-1.47957) % segment 1 + ..controls (5.08287,-1.47957) and (5.44116,-1.47957) + ..(5.79944,-1.47957) % segment 2 + ..controls (7.35368,-1.47957) and (8.34424,-1.12393) + ..(8.90538,-0.56279) % segment 3 +% entering octant `NNE' + ..controls (9.31982,-0.14835) and (9.5,0.37819) + ..(9.5,0.95631) % segment 3 +% entering octant `NNW' + ..controls (9.5,2.00116) and (8.61821,3.4318) + ..(7.41951,4.6305) % segment 3 +% entering octant `WNW' + ..controls (6.32909,5.72092) and (5.11603,6.5) + ..(4.2104,6.5) % segment 3 +% entering octant `WSW' + ..controls (3.64668,6.5) and (3.12122,6.31134) + ..(2.68588,5.876) % segment 3 +% entering octant `SSW' + ..controls (1.97163,5.16176) and (1.5,3.78351) + ..(1.5,1.485) % segment 3 + ..controls (1.5,0.99092) and (1.5,0.49681) + ..(1.5,0.00272) % segment 0 + & cycle + +Tracing edges at line 163: (weight 1) +@ Octant SSE (0 offsets), from (1.5,0.00272) to (1.8592,-1.05237) +@ transition line 0, from (1.5,0.00272) to (1.5,0.00272) +(2,0) +@ Octant ESE (0 offsets), from (1.8592,-1.05237) to (3.57066,-1.5) +@ transition line 1, from (3.57066,-1.5) to (3.57066,-1.5) +@ Octant ENE (2 offsets), from (3.57066,-1.5) to (13.90538,2.3372) +@ transition line 0, from (3.57066,-1.5) to (3.57066,-1.5) +@ transition line 1, from (8.41534,-0.93503) to (13.41534,1.96497) +@ transition line 2, from (13.90538,2.3372) to (13.90538,2.3372) +(2,-1)(9,-1)(9,0)(11,0)(11,1)(13,1) +@ Octant NNE (0 offsets), from (13.90538,2.3372) to (14.5,3.85631) +@ transition line 1, from (14.5,3.85631) to (14.5,3.85631) +(13,2)(14,2) +@ Octant NNW (0 offsets), from (14.5,3.85631) to (12.41951,7.53049) +@ transition line 0, from (14.5,3.85631) to (14.5,3.85631) +(14,6)(13,6)(13,7)(12,7) +@ Octant WNW (2 offsets), from (12.41951,7.53049) to (8.2104,9.5) +@ transition line 3, from (12.41951,7.53049) to (12.41951,7.53049) +@ transition line 2, from (9.38113,9.39124) to (8.38113,9.49124) +@ transition line 1, from (8.2104,9.5) to (8.2104,9.5) +(12,8)(11,8)(11,9)(8,9) +@ Octant WSW (2 offsets), from (8.2104,9.5) to (2.68588,5.876) +@ transition line 0, from (8.2104,9.5) to (8.2104,9.5) +@ transition line 1, from (6.92668,9.08539) to (2.92668,6.08539) +@ transition line 2, from (2.68588,5.876) to (2.68588,5.876) +(8,10)(8,9)(6,9)(6,8)(5,8)(5,7)(3,7) +@ Octant SSW (0 offsets), from (2.68588,5.876) to (1.5,0.00272) +@ transition line 1, from (1.5,0.00272) to (1.5,0.00272) +(3,6)(2,6)(2,0). + +Path at line 163, before subdivision into octants: +(0,2)..controls (0,10.64238) and (13.63031,0) + ..(4,0)..controls (3.66667,0) and (3.33333,0) + ..(3,0)..controls (1.63324,0) and (0,-0.20886) + ..(0,1)..controls (0,1.33333) and (0,1.66667) + ..cycle + +Cycle spec at line 163, after subdivision and double autorounding: +(2.68588,5.876) % beginning in octant `ENE' + ..controls (3.12122,6.31134) and (3.64668,6.5) + ..(4.2104,6.5) % segment 0 +% entering octant `ESE' + ..controls (5.11603,6.5) and (6.32909,5.72092) + ..(7.41953,4.63048) % segment 0 +% entering octant `SSE' + ..controls (8.61824,3.43176) and (9.5,2.00116) + ..(9.5,0.95631) % segment 0 +% entering octant `SSW' + ..controls (9.5,0.37819) and (9.31982,-0.14835) + ..(8.90538,-0.56279) % segment 0 +% entering octant `WSW' + ..controls (8.34425,-1.12392) and (7.35368,-1.47957) + ..(5.79944,-1.47957) % segment 0 + ..controls (5.44116,-1.47957) and (5.08287,-1.47957) + ..(4.72458,-1.47957) % segment 1 + ..controls (4.3473,-1.47957) and (3.95114,-1.5) + ..(3.57066,-1.5) % segment 2 +% entering octant `WNW' + ..controls (2.87909,-1.5) and (2.23936,-1.43253) + ..(1.85919,-1.05235) % segment 2 +% entering octant `NNW' + ..controls (1.6341,-0.82726) and (1.5,-0.49254) + ..(1.5,0.00272) % segment 2 +% entering octant `NNE' + ..controls (1.5,0.49681) and (1.5,0.99092) + ..(1.5,1.485) % segment 3 + ..controls (1.5,3.78351) and (1.97165,5.16177) + ..(2.68588,5.876) % segment 0 + & cycle + +Tracing edges at line 163: (weight 1) +@ Octant ENE (2 offsets), from (7.68588,8.776) to (4.2104,6.5) +@ retrograde line from (7.68588,8.776) to (2.68588,5.876) +(7,9)(7,8)(5,8)(5,7)(4,7) +@ transition line 0, from (2.68588,5.876) to (2.68588,5.876) +@ transition line 1, from (2.68588,5.876) to (7.68588,8.776) +@ transition line 2, from (8.13123,9.12088) to (3.13123,6.22089) +@ transition line 1, from (4.2104,6.5) to (9.2104,9.4) +@ transition line 2, from (9.2104,9.4) to (9.2104,9.4) +(4,6)(4,7)(6,7)(6,8)(8,8) +@ retrograde line from (9.2104,9.4) to (4.2104,6.5) +(8,9)(8,8)(6,8) +@ Octant ESE (0 offsets), from (4.2104,6.5) to (7.41953,4.63048) +@ transition line 1, from (7.41953,4.63048) to (7.41953,4.63048) +(6,7)(4,7)(4,6)(6,6) +@ Octant SSE (0 offsets), from (7.41953,4.63048) to (9.5,0.95631) +@ transition line 0, from (7.41953,4.63048) to (7.41953,4.63048) +(6,5)(8,5)(8,3)(9,3) +@ Octant SSW (0 offsets), from (9.5,0.95631) to (8.90538,-0.56279) +@ transition line 1, from (8.90538,-0.56279) to (8.90538,-0.56279) +@ Octant WSW (2 offsets), from (8.90538,-0.56279) to (7.57066,1.5) +@ retrograde line from (8.90538,-0.56279) to (12.90538,2.43721) +(9,-1)(9,0)(10,0)(10,1)(12,1) +@ transition line 0, from (12.90538,2.43721) to (12.90538,2.43721) +@ transition line 1, from (12.90538,2.43721) to (8.90538,-0.56279) +@ transition line 2, from (8.6665,-0.76936) to (12.6665,2.23064) +@ transition line 1, from (7.57066,1.5) to (3.57066,-1.5) +@ transition line 2, from (3.57066,-1.5) to (3.57066,-1.5) +(12,2)(8,2)(8,1)(6,1)(6,0)(5,0) +@ retrograde line from (3.57066,-1.5) to (7.57066,1.5) +(5,-1)(5,0)(6,0)(6,1)(8,1) +@ Octant WNW (2 offsets), from (7.57066,1.5) to (6.85919,1.84764) +@ retrograde line from (7.57066,1.5) to (8.57066,1.4) +(8,2) +@ transition line 3, from (8.57066,1.4) to (8.57066,1.4) +@ transition line 2, from (8.57066,1.4) to (7.57066,1.5) +@ transition line 1, from (6.95764,1.52585) to (7.95764,1.42584) +@ transition line 2, from (6.85919,1.84764) to (5.85919,1.94765) +@ transition line 1, from (5.85919,1.94765) to (5.85919,1.94765) +(8,1) +@ retrograde line from (5.85919,1.94765) to (6.85919,1.84764) +@ Octant NNW (0 offsets), from (6.85919,1.84764) to (6.5,2.90271) +@ transition line 0, from (6.85919,1.84764) to (6.85919,1.84764) +(8,2)(7,2) +@ Octant NNE (0 offsets), from (6.5,2.90271) to (7.68588,8.776) +@ transition line 1, from (7.68588,8.776) to (7.68588,8.776) +(7,9). + +{tracingonline:=1} + +f<expr>->let)=];let[=(;show._ +(EXPR0)<-xx +{let} +{let} +{show} +>> _1 +{showdependencies} +xpart '=-ypart '-0.66667 +{qq:=pen} +{showstats} +Memory usage 1476&588 (104 still untouched) +String usage 42&168 (1818&17726 still untouched) +{[repeat the loop]} +! A group begun on line 163 never ended. +<to be read again> + endtext +l.163 ... showstats; bye endtext + +I saw a `begingroup' back there that hasn't been matched +by `endgroup'. So I've inserted `endgroup' now. + +{endgroup} + ) +(end occurred when else on line 93 was incomplete) +(end occurred when if on line 36 was incomplete) +(end occurred when elseif on line 21 was incomplete) +Here is how much of METAFONT's memory you used: + 69 strings out of 1887 + 3759 string characters out of 21485 + 2897 words of memory out of 3001 + 289 symbolic tokens out of 2100 + 8i,43n,14r,8p,167b stack positions out of 30i,100n,300r,150p,500b + +(illegal design size has been changed to 128pt) +(some chardp values had to be adjusted by as much as 0.5pt) +(local label 0:: was missing) +(local label 5:: was missing) +(4 font metric dimensions had to be decreased) +(You used 3w,2h,16d,2i,312l,301k,1e,10p metric file positions + out of 256w,16h,16d,64i,5000l,500k,256e,50p) + +Font metrics written on trap.tfm. +Output written on trap.72270gf (5 characters, 1028 bytes). |