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author | Karl Berry <karl@freefriends.org> | 2018-07-07 20:45:48 +0000 |
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committer | Karl Berry <karl@freefriends.org> | 2018-07-07 20:45:48 +0000 |
commit | 30ca482fc79a7e14921d0589b73420328f2f311f (patch) | |
tree | c3813050306e32570431c2f43bc7dd0f06078765 /Master/texmf-dist/doc/latex/jnuexam/exam-a.tex | |
parent | eeae341c0a3662936eecc4ac0630a102b6bb928a (diff) |
jnuexam (7jul18)
git-svn-id: svn://tug.org/texlive/trunk@48157 c570f23f-e606-0410-a88d-b1316a301751
Diffstat (limited to 'Master/texmf-dist/doc/latex/jnuexam/exam-a.tex')
-rw-r--r-- | Master/texmf-dist/doc/latex/jnuexam/exam-a.tex | 44 |
1 files changed, 22 insertions, 22 deletions
diff --git a/Master/texmf-dist/doc/latex/jnuexam/exam-a.tex b/Master/texmf-dist/doc/latex/jnuexam/exam-a.tex index 30925233ed4..98ff78f9e60 100644 --- a/Master/texmf-dist/doc/latex/jnuexam/exam-a.tex +++ b/Master/texmf-dist/doc/latex/jnuexam/exam-a.tex @@ -12,8 +12,8 @@ \renewcommand{\niandu}{2017--2018} \renewcommand{\xueqi}{2} \renewcommand{\kecheng}{大学数学} -\renewcommand{\zhuanye}{经管~3~学分} % 可以为空白 -\renewcommand{\jiaoshi}{吕荐瑞} +\renewcommand{\zhuanye}{理工~4~学分} % 可以为空白 +\renewcommand{\jiaoshi}{张三,李四,王五} % 教师姓名 \renewcommand{\shijian}{2018~年~06~月~28~日} \renewcommand{\bixiu}{1} % 1 为必修,0 为选修 \renewcommand{\bijuan}{1} % 1 为闭卷,0 为开卷 @@ -93,10 +93,10 @@ \begin{problem} 下列各排列哪个是偶排列 \pickout{D} -\quaditem{3712456} -\quaditem{36715284} -\quaditem{654321} -\quaditem{41253} +\quaritem{$3712456$} +\quaritem{$36715284$} +\quaritem{$654321$} +\quaritem{$41253$} \end{problem} \vfill @@ -111,10 +111,10 @@ b_1 & b_2 & b_3\\ c_1 & c_2 & c_3 \end{array}\right|=$ \pickout{A} -\quaditem{1} -\quaditem{-1} -\quaditem{2} -\quaditem{-2} +\quaritem{$1$} +\quaritem{$-1$} +\quaritem{$2$} +\quaritem{$-2$} \end{problem} \vfill @@ -126,29 +126,29 @@ 0 & 0 & 1 \end{array}\right)$ 其中两个特征值为 $\lambda_1 = 1$ 和 $\lambda_2 = 2$,则 $x=$ \pickout{B} -\quaditem{2} -\quaditem{1} -\quaditem{0} -\quaditem{-1} +\quaritem{$2$} +\quaritem{$1$} +\quaritem{$0$} +\quaritem{$-1$} \end{problem} \vfill \begin{problem} 二次型 $f = 4 x_1^2 - 2 x_1 x_2 + 6 x_2^2$ 对应的矩阵等于 \pickout{C} -\quaditem{$\left(\begin{array}{cc} +\quaritem{$\left(\begin{array}{cc} 4 & - 2\\ - 2 & 6 \end{array}\right)$} -\quaditem{$\left(\begin{array}{cc} +\quaritem{$\left(\begin{array}{cc} 2 & - 2\\ - 2 & 3 \end{array}\right)$} -\quaditem{$\left(\begin{array}{cc} +\quaritem{$\left(\begin{array}{cc} 4 & - 1\\ - 1 & 6 \end{array}\right)$} -\quaditem{$\left(\begin{array}{cc} +\quaritem{$\left(\begin{array}{cc} 2 & - 1\\ - 1 & 3 \end{array}\right)$} @@ -188,10 +188,10 @@ \begin{problem} 样本平均数$\bar{X}$\CJKunderline{未必是}总体期望值$\mu$的\pickout{A} -\quaditem{最大似然估计} -\quaditem{有效估计} -\quaditem{一致估计} -\quaditem{无偏估计} +\quaritem{最大似然估计} +\quaritem{有效估计} +\quaritem{一致估计} +\quaritem{无偏估计} \end{problem} \vfill |