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diff --git a/obsolete/macros/latex/contrib/tkz/tkz-linknodes/examples/latex/system.tex b/obsolete/macros/latex/contrib/tkz/tkz-linknodes/examples/latex/system.tex new file mode 100644 index 0000000000..d9ba5e6445 --- /dev/null +++ b/obsolete/macros/latex/contrib/tkz/tkz-linknodes/examples/latex/system.tex @@ -0,0 +1,91 @@ +\documentclass[]{article} +\usepackage[utf8]{inputenc} +\usepackage[upright]{fourier} +\usepackage{amsmath,tkz-linknodes} + +\thispagestyle{empty} +\begin{document} + +% Show how to find the solution of two simultaneous equations. + +\begin{minipage}{10cm} + Solution of two simultaneous equations. The problem is to find the set of all solutions that satisfies both equations. These are called simultaneous equations. + \displaywidth=.4\linewidth + \begin{NodesList}[dy=3pt,margin=5cm] + \[ \displaywidth=.4\linewidth + \left\{\begin{matrix} + 3x &+& 4y &=& 10\\ + 2x &+& y &=& 5 \AddNode\\ + \end{matrix}\right. \] + + \bigskip + + \[\displaywidth=.4\linewidth \left\{\begin{matrix} + 3x &+& 4y &=& 10\\ + 8x &+& 4y &=& 20 \AddNode\\ + \end{matrix}\right. \] + + \bigskip + + \[\displaywidth=.4\linewidth \left\{\begin{matrix} + 3x &+& 4y &=& 10 \\ + 5x && &=& 10 \AddNode\\ + \end{matrix}\right. \] + + \bigskip + + \[\displaywidth=.4\linewidth \left\{\begin{matrix} + 3(2) &+& 4y &=& 10\\ + x && &=& 2 \AddNode\\ + \end{matrix}\right. \] + + \bigskip + + \[\displaywidth=.4\linewidth \left\{\begin{matrix} + 3(2) &+& 4y &=& 10\AddNode\\ + x && &=& 2 \\ + \end{matrix}\right. \] + + \bigskip + + \[\displaywidth=.4\linewidth \left\{\begin{matrix} + 4y &=& 10-6\AddNode\\ + x &=& 2 \\ + \end{matrix}\right. \] + + \bigskip + + \[\displaywidth=.4\linewidth \left\{\begin{matrix} + y &=& 1 \AddNode\\ + x &=& 2 \\ + \end{matrix}\right. \] + + + \LinkNodes{% + \begin{minipage}{3cm} + both sides of second equation are multiplied by 4 + \end{minipage}} + \LinkNodes{% + \begin{minipage}{3cm} + The first equation is subtracted from second + \end{minipage}} + \LinkNodes{$\div 5$} + \LinkNodes{% + \begin{minipage}{3cm} + As a result, $x = 2$, this value is then substituted in the first equation + \end{minipage}} + \LinkNodes{% + \begin{minipage}{3cm} + $6$ is subtracted from both sides + \end{minipage}} + \LinkNodes{$\div 4$} + \end{NodesList} +\end{minipage} + +The solution is $\{(x=2~;~y=1)\}$ +\end{document} +% Encoding : utf8 +% Author : Alain Matthes (2008) +% Engine : pdfLaTeX (LaTeX only with pdftex >= 1.40) +% Packages : xkeyval, tikz with arrow library, amsmath, etex, ifthen +% Remark : needs two compilations
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