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diff --git a/macros/latex/contrib/alterqcm/doc/latex/doc-aq-locales.tex b/macros/latex/contrib/alterqcm/doc/latex/doc-aq-locales.tex new file mode 100644 index 0000000000..63aa4ee13b --- /dev/null +++ b/macros/latex/contrib/alterqcm/doc/latex/doc-aq-locales.tex @@ -0,0 +1,130 @@ +\section{Local options of the macro \tkzcname{AQquestion}} + +\subsection{Local use of \tkzname{pq}} +\Iopt{AQquestion}{pq} + The following table is obtained with the options |lq=85mm| and |size=\wide|. The questions are misplaced. The local option \tkzname{pq} solves this problem, the text can be moved 1mm upwards with \tkzcname{AQquestion[pq=1mm]}. + and by |6mm| for the second. + +\medskip + + + \begin{alterqcm}[lq=55mm,size=\large] + +\AQquestion{If the function $f$ is strictly increasing on $\mathbf{R}$ then the equation $f(x) = 0$ admits :} +{{At least one solution}, +[At most one solution], +{Exactly one solution} +} +\AQquestion{If the $f$ function is continuous and positive on $[a~ ;~ b]$ and $\mathcal{C}_{f}$ its representative curve in an orthogonal system. In units of area, the area $\mathcal{A}$ of the domain delimited by $\mathcal{C}_{f}$, the abscissa axis and the lines of equations $x = a$ 5 and $x = b$ is given by the formula : } +{% +{$\mathcal{A}= \displaystyle \int_{b}^a f(x)\ \text{d}x$}, +{$\mathcal{A}= \displaystyle \int_{a}^b f(x)\ \text{d}x$}, +{$\mathcal{A} = f(b) - f(a)$}} +\end{alterqcm} + +\medskip +\tkzname{Here is the corrected version} + +\begin{alterqcm}[lq=55mm,size=\large] +\AQquestion[pq=1mm]{If the $f$ function is strictly increasing on +$\mathbf{R}$ then the equation $f(x) = 0$ admits...} +{{At least one solution}, +{At most one solution}, +{Exactly one solution} +} +\AQquestion[pq=6mm]{If the $f$ function is continuous and positive on $[a~ ;~ b]$ + and $\mathcal{C}_{f}$ its representative curve in an orthogonal system. + In area units, the $\mathcal{A}$ area of the domain delimited by $\mathcal{C}_{f}$, the abscissa axis and the lines of equations $x = a$ and $x = b$ is given by the formula: } +{{$\mathcal{A}= \displaystyle \int_{b}^a f(x)\ \text{d}x$}, +{$\mathcal{A}= \displaystyle \int_{a}^b f(x)\ \text{d}x$}, +{$\mathcal{A} = f(b) - f(a)$} +} +\end{alterqcm} + +\medskip +\begin{tkzexample}[code only, small] + \begin{alterqcm}[lq=55mm,size=\large] + \AQquestion[pq=1mm]{If the $f$ function is strictly increasing on $\mathbf{R}$ + then the equation $f(x) =0 $ admits... + {{{At least one solution}, + [At most one solution], + {Exactly one solution}} +\end{tkzexample} + +\medskip +\begin{tkzexample}[code only, small] + \AQquestion[pq=6mm]{If the $f$ function is continuous and positive on $[a~ ;~ b]$ and $\mathcal{C}_{f}$ its representative curve in an orthogonal system. + In units of area, the area $\mathcal{A}$ of the domain delimited by $\mathcal{C}_{f}$, the abscissa axis and the lines of equations $x = a$ and $x = b$ is given by the formula: } + {{$\mathcal{A}= \displaystyle \int_{b}^a f(x)\ \text{d}x$}, + {$\mathcal{A}= \displaystyle \int_{a}^b f(x)\ \text{d}x$}, + {$\mathcal{A} = f(b) - f(a)$}} + \end{alterqcm} +\end{tkzexample} + +\subsection{Global and local use of \tkzname{pq}}\ + \Iopt{AQquestion}{pq} \IoptEnv{alterqcm}{pq} +This time, it is necessary to move several questions, I placed a |pq=2mm| globally, that is to say like this :\tkzcname{begin\{alterqcm\}[lq=85mm,pq=2mm]}. \textbf{All} questions are affected by this option but some questions were well placed and should remain so, so locally I give them back a |pq=0mm|. + +\medskip +\begin{alterqcm}[lq=85mm,pq=2mm] +\AQquestion{A bivariate statistical series. The values of $x$ are 1, 2, 5, 7, 11, 13 and a least squares regression line equation of $y$ to $x$ is $y = 1.35x +22.8$. The coordinates of the mean point are :} +{{$(6,5;30,575)$}, +{$(32,575 ; 6,5)$}, +{$(6,5 ; 31,575)$}} + +\AQquestion[pq=0mm]{$(u_{n})$ is an arithmetic sequence of reason $-5$.\\ Which of these statements is true? } +{{For all $n,~ u_{n+1} - u_{n} = 5$}, +{$u_{10}= u_{2}+ 40$}, +{$u_{3} = u_{7} + 20$} +} +\AQquestion[pq=0mm]{Equality $\ln (x^2 - 1) = \ln (x - 1) + \ln (x+1)$ is true} +{{For all $x$ in $]- \infty~;~-1[ \cup]1~;~+ \infty[$}, +{For all $x$ in $\mathbf{R} - \{-1~ ;~ 1\}$.}, +{For all $x$ in $]1~ ;~+\infty[$} +} +\AQquestion{For all $x$, the number \[\dfrac{\text{e}^x - 1}{\text{e}^x + 2}\hskip12pt \text{equal to :} \] } +{{$-\dfrac{1}{2}$}, +{$\dfrac{\text{e}^{-x} - 1}{\text{e}^{-x} + 2}$}, +{$\dfrac{1 - \text{e}^{-x}}{1 + 2\text{e}^{-x}}$} +} +\AQquestion{Let I $= \displaystyle\int_{\ln 2}^{\ln 3} \dfrac{1}{\text{e}^x - 1}\,\text{d}x$ and J $ = \displaystyle\int_{\ln 2}^{\ln 3} \dfrac{\text{e}^x}{\text{e}^x - 1}\,\text{d}x$ \\ then the number I $-$ J is equal to} +{{$\ln \dfrac{2}{3}$}, +{$\ln \dfrac{3}{2}$}, +{$\dfrac{3}{2}$} +} +\end{alterqcm} + +\medskip +\begin{tkzexample}[code only,vbox,small] + \begin{alterqcm}[lq=85mm,pq=2mm] + \AQquestion[pq=0mm]{Equality $\ln (x^2 - 1) = \ln (x - 1) + \ln (x+1)$ + is true} + {{For all $x$ in $]- \infty~;~-1[ \cup]1~;~+ \infty[$}, + {For all $x$ in $\mathbf{R} - \{-1~ ;~ 1\}$.}, + {For all $x$ in $]1~ ;~+\infty[$}} + \AQquestion{For any real $x$, the number \[\dfrac{\text{e}^x - 1} + {\text{e}^x + 2}\hskip12pt \text{equal to :} \] } + {{$-\dfrac{1}{2}$}, + {$\dfrac{\text{e}^{-x} - 1}{\text{e}^{-x} + 2}$}, + {$\dfrac{1 - \text{e}^{-x}}{1 + 2\text{e}^{-x}}$}} + \end{alterqcm} + \end{tkzexample} + + +\subsection{\tkzname{correction} and \tkzname{br} : rank of good answer} +\Iopt{AQquestion}{br} \Iopt{AQquestion}{correction} +First of all, it is necessary to ask for an answer key. To do this, just include the option \tkzname{correction} which is a boolean, thus set to \tkzname{true}. Then in each question, it is necessary to give the list of correct answers. For example, with \tkzname{br=1} or \tkzname{br=\{1,3\}}. + +Here is the previous year's correction: + +\medskip +\begin{tkzexample}[vbox,small] +\begin{alterqcm}[VF,correction,lq=125mm] + \AQquestion[br=1]{For all $x \in ]-3~;~2],~f'(x) \geqslant 0$.} + \AQquestion[br=2]{The $F$ function has a maximum in $2$} + \AQquestion[br=2]{$\displaystyle\int_{0}^2 f'(x)\:\text{d}x = - 2$} +\end{alterqcm} +\end{tkzexample} + + +\endinput
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